WAVE SPEED ON A STRINGBy: Aysha Allard Brown

WAVE SPEED ON A STRING

The speed of a wave depends on the elastic and inertial properties of the medium it is in

We can determine the elastic property of a string by finding the tension force in the string (Ft)

We can determine the inertial property by finding the linear mass density (μ)

Increasing the tension, also referred to as the restoring force, increases the movement of the string

As we increase the linear mass density, the amount of inertia increases which decreases the movement of the string

EQUATIONS

Linear Mass Density (units: kg/m)

mass (kg)

length (m)

Centripetal Acceleration (units: m/s²)

v- speed (m/s)

R- radius (m)

EQUATIONS

Wave Speed (m/s)

Ft- tension force (N)

m- mass (kg)

L-length (m)

μ- linear mass density (kg/m)

QUESTION #1

A guitar string has a mass of 230g and a length of 1.2m. What must the tension of the string be to send a wave along the string at a speed of 45.0 m/s?

SOLUTION (PT.1)• The first step is to convert

each variable into the correct units (length in m, mass in kg, and velocity in m/s).

• Next, we can use the following equation to solve for the linear mass density.

SOLUTION (PT.2)

We can substitute the value we obtained for μ into the following equation:

Next, we can rearrange this equation in order to solve for the tension force.

Lastly, we plug in the values we have for the speed and the linear mass density of the string in order to solve for the tension force.

QUESTION #2

Two children are playing with a jump rope which is attached at one end to a pole. The first child moves his hands up and down, which creates a steady pulse in the jump rope. They decide to have a competition to see who can make the pulse move the fastest. How can the second child make the pulse in the jump rope move faster?

A. He could tighten the string tension.

B. He could loosen the string tension.

C. He could move their hand up and down slower.

D. He could move their hands up and down a larger distance as they generate the pulse.

E. He could use a heavier string.

F. He could use a lighter string.

SOLUTIONA. He could tighten the string tension.

B. He could loosen the string tension.

C. He could move their hand up and down slower.

D. He could move their hands up and down a larger distance as they generate the pulse.

E. He could use a heavier string.

F. He could use a lighter string.

As we can see from equation 1, the speed of the wave is directly proportional to the tension force. Therefore, as we ↑ the tension force we ↑ the speed of the wave.

From equation 2, we can see that mass is directly proportional to the linear mass density. This means that as we ↓ the mass we ↓ the linear mass density.

In equation 1, the speed of the wave is inversely proportional to linear mass density. Therefore, when we plug in this new (↓) value for linear mass density from equation 2 into equation 1, the speed of the wave ↑.

(1)

(2)

YOUTUBE VIDEO

https://www.youtube.com/watch?v=oAd0BTgGwJw

Thank you.