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Copyright © 2017 Oracle and/or its affiliates. All rights reserved.
SQL window functions for MySQL
Dag H. WanvikSenior database engineer,Oracle
2Copyright © 2017 Oracle and/or its affiliates. All rights reserved.
Safe Harbor Statement
The following is intended to outline our general product direction. It is intended forinformation purposes only, and may not be incorporated into any contract. It is nota commitment to deliver any material, code, or functionality, and should not berelied upon in making purchasing decisions. The development, release, andtiming of any features or functionality described for Oracle’s products remains atthe sole discretion of Oracle.
3Copyright © 2017 Oracle and/or its affiliates. All rights reserved.
AgendaQuick intro to window functions
Types of window functions
The window specification
Evaluation and optimizations
More on non-aggregate wfs
Implicit and explicit windows
Q & A
1
2
3
4
5
6
7
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Window functions: what are they?● A window function performs a calculation across a set of rows that are
related to the current row, similar to what can be done with an aggregatefunction.
● But unlike traditional aggregate functions, a window function does notcause rows to become grouped into a single output row.
● So, similar to normal function, but can access values of other rows “inthe vicinity” of the current row
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SELECT name, department_id, salary,
SUM(salary) OVER (PARTITION BY department_id)
AS department_total
FROM employee
ORDER BY department_id, name;
Window function example, no frame
The OVER keywordsignals a window function
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Partitions: 10, 20, 30
+---------+---------------+--------+------------------+| name | department_id | salary | department_total |+---------+---------------+--------+------------------+| Newt | NULL | 75000 | 75000 || Dag | 10 | NULL | 370000 || Ed | 10 | 100000 | 370000 || Fred | 10 | 60000 | 370000 || Jon | 10 | 60000 | 370000 || Michael | 10 | 70000 | 370000 || Newt | 10 | 80000 | 370000 || Lebedev | 20 | 65000 | 130000 || Pete | 20 | 65000 | 130000 || Jeff | 30 | 300000 | 370000 || Will | 30 | 70000 | 370000 |+---------+---------------+--------+------------------+
Partition == disjointset of rows in result set
Here: all rows in partition are peers
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SELECT name, department_id, salary, SUM(salary) AS department_total FROM employee GROUP BY department_id ORDER BY department_id, name;
ERROR 1055 (42000): Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'mysql.employee.name' which is not functionally dependenton columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
With GROUP BY
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SELECT /* name, */ department_id, /* salary,*/ SUM(salary) AS department_total FROM employee GROUP BY department_id ORDER BY department_id /*, name */;
+---------------+------------------+| department_id | department_total |+---------------+------------------+| NULL | 75000 || 10 | 370000 || 20 | 130000 || 30 | 370000 |+---------------+------------------+
With GROUP BY
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SELECT name, department_id, salary,
SUM (salary) OVER (PARTITION BY department_id
ORDER BY name
ROWS 2 PRECEDING) total
FROM employee
ORDER BY department_id, name;
Window function example, frame
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Partitions: 10, 20, 30
ORDER BY name
within each
partition
+---------+---------------+--------+--------+| name | department_id | salary | total |+---------+---------------+--------+--------+| Newt | NULL | 75000 | 75000 || Dag | 10 | NULL | NULL || Ed | 10 | 100000 | 100000 || Fred | 10 | 60000 | 160000 || Jon | 10 | 60000 | 220000 || Michael | 10 | 70000 | 190000 || Newt | 10 | 80000 | 210000 || Lebedev | 20 | 65000 | 65000 || Pete | 20 | 65000 | 130000 || Jeff | 30 | 300000 | 300000 || Will | 30 | 70000 | 370000 |+---------+---------------+--------+--------+
moving window frame:
SUM (salary)...ROWS 2 PRECEDING
a frame is a subset of apartition
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SELECT name, department_id, salary, AVG(salary) OVER w AS `avg`, salary - AVG(salary) OVER w AS diff FROM employee WINDOW w as (PARTITION BY department_id) ORDER BY diff DESC;
Window function example
i.e. find the employees with the largest difference between their wageand that of the department average
Note: explicit window definition of “w”
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Partitions: 10, 20, 30
+---------+---------------+--------+-----------+------------+| name | department_id | salary | avg | diff |+---------+---------------+--------+-----------+------------+| Jeff | 30 | 300000 | 185000.00 | 115000.00 || Ed | 10 | 100000 | 74000.00 | 26000.00 || Newt | 10 | 80000 | 74000.00 | 6000.00 || Newt | NULL | 75000 | 75000.00 | 0.00 || Pete | 20 | 65000 | 65000.00 | 0.00 || Lebedev | 20 | 65000 | 65000.00 | 0.00 || Michael | 10 | 70000 | 74000.00 | -4000.00 || Jon | 10 | 60000 | 74000.00 | -14000.00 || Fred | 10 | 60000 | 74000.00 | -14000.00 || Will | 30 | 70000 | 185000.00 | -115000.00 || Dag | 10 | NULL | 74000.00 | NULL |+---------+---------------+--------+-----------+------------+
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Types of window functions
● Aggregates
● Ranking
● Analytical
COUNT, SUM, AVG + more to come
RANK, DENSE_RANK, PERCENT_RANK,
CUME_DIST, ROW_NUMBER
NTILE, LEAD, LAG, NTH, FIRST_VALUE,
LAST_VALUE
Blue ones use frames, all obey partitions
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Anatomy of a window specificationwindow specification ::=
[ existing window name ]
[PARTITION BY expr-1, ... ]
[ORDER BY expr-1, ... [DESC] ]
[ frame clause ]
–
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frame clause boundpartition
CURRENT ROW
UNBOUNDEDPRECEDING
UNBOUNDEDFOLLOWING
n PRECEDING
m PRECEDING
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frame clause frame clause ::= { ROWS | RANGE } { start | between }
start ::= { CURRENT ROW | UNBOUNDED PRECEDING | n PRECEDING}
between ::= BETWEEN bound-1 AND bound-2
bound ::= start | UNBOUNDED FOLLOWING | n FOLLOWING
● “start” form implies upper is CURRENT ROW (or its peer iff RANGE)● An empty OVER () specification, says that all rows in the partition are
peers and included in frame.● An ORDER BY without frame implies frame:
RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
● Limitation: frame exclusion not supported
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frame clause● ROWS or RANGE (GROUPS unit not supported)● ROWS: bounds are physical row offsets● RANGE: logical offset based on current row's valueEx: RANGE BETWEEN INTERVAL 1 WEEK PRECEDING AND CURRENT ROW
● RANGE requires ORDER BY on one numeric expression● Limitation: bounds must be static
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SELECT dat, amount, SUM(amount) OVER w FROM payments WINDOW w AS (ORDER BY dat RANGE BETWEEN INTERVAL 1 WEEK PRECEDING AND CURRENT ROW) ORDER BY dat;
RANGE frame example
i.e. find the sum of payments within the last 7 days
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RANGE frame example
+------------+--------+--------+| dat | amount | sum |+------------+--------+--------+| 2017-01-01 | 100.50 | 300.50 || 2017-01-01 | 200.00 | 300.50 || 2017-01-02 | 200.00 | 500.50 || 2017-01-03 | 200.00 | 700.50 || 2017-01-05 | 200.00 | 900.50 || 2017-01-10 | 200.00 | 700.00 || 2017-01-10 | 100.00 | 700.00 || 2017-01-11 | 200.00 | 700.00 |+------------+--------+--------+
SELECT dat, amount, SUM(amount) OVER w AS `sum` FROM payments WINDOW w AS (ORDER BY dat RANGE BETWEEN INTERVAL 1 WEEK PRECEDING AND CURRENT ROW) ORDER BY dat;
Current row's date is the 10th, so first row in range is the 3rd .Frame cardinality is 4 due to peer in next row.
For Jan 5, the frame cardinality is 5, and sum is 900.50.
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When are they evaluated?● after GROUP BY/ HAVING● before final ORDER BY, DISTINCT, LIMIT● you can have several window functions and several different
windows● To filter on wf's value, use a subquery, e.g.
SELECT * FROM (SELECT SUM(salary) OVER (PARTITION BY department_id) `sum` FROM employee) AS s WHERE `sum` < 100000;+-------+| sum |+-------+| 75000 |+-------+
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Logical flow
JOIN GROUPBY
WINDOW1
WINDOWn
ORDER BY/DISTINCT/
LIMIT
Sort forPARTITION BY
and ORDER BY
● Tmp file between each windowing step(in-mem if result set can fit †)
● Streamable wfs vs buffered● Depends on wf and frame● Buffered: re-read rows ● O(rows * frame size) optimize● Move frame for SUM 1 row: invert by
subtraction, add new row.
† cf. variables tmp_table_size, max_heap_table_size
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Streamable evaluationSELECT name, department_id, salary, SUM(salary) OVER (PARTITION BY department_id ORDER BY name ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS `sum` FROM employee;
+---------+---------------+--------+--------+| name | department_id | salary | sum |+---------+---------------+--------+--------+| Newt | NULL | 75000 | 75000 || Dag | 10 | NULL | NULL || Ed | 10 | 100000 | 100000 | Just accumulate as we see rows| Fred | 10 | 60000 | 160000 || Jon | 10 | 60000 | 220000 || Michael | 10 | 70000 | 290000 || Newt | 10 | 80000 | 370000 || Lebedev | 20 | 65000 | 65000 || Pete | 20 | 65000 | 130000 || Jeff | 30 | 300000 | 300000 || Will | 30 | 70000 | 370000 |+---------+---------------+--------+--------+
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Logical flow
JOIN GROUPBY
WINDOW1
WINDOWn
ORDER BY/DISTINCT/
LIMIT
Row addressable
buffer
in-mem: overflows to disk
Permits re-readingrows when framemoves
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Non-streamable evaluationSELECT name, department_id, salary, SUM(salary) OVER (PARTITION BY department_id ORDER BY name ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) AS `sum` FROM employee;
+---------+---------------+--------+--------+| name | department_id | salary | sum |+---------+---------------+--------+--------+| Newt | NULL | 75000 | 75000 || Dag | 10 | NULL | NULL || Ed | 10 | 100000 | 100000 || Fred | 10 | 60000 | 160000 || Jon | 10 | 60000 | 220000 || Michael | 10 | 70000 | 190000 || Newt | 10 | 80000 | 210000 || Lebedev | 20 | 65000 | 65000 || Pete | 20 | 65000 | 130000 || Jeff | 30 | 300000 | 300000 || Will | 30 | 70000 | 370000 |+---------+---------------+--------+--------+
When eval'ing Michael, subtract Ed'scontribution, add Michael
or just evaluate entire frame over again(non-optimized). In both cases we needre-visit rows.
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Optimizations● Accumulate frames by inversion (discussed; done) ¹● Avoid materializing each step in temporary file if possible (done)● Sort only once for windows with the same PARTITION/ORDER BY
requirements (done)● Sort only once for windows with subset relation on above (not yet)● Eliminate sorts by using indexes (not yet)
¹not done by default for floats due to possible under/-overflow errors, but can be enabled using a variable.Enabling it is crucial for performance for large frames due to the combinatorial hardness.
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Explain, last query EXPLAIN FORMAT=JSON SELECT name, department_id, salary, SUM(salary) OVER (PARTITION BY department_id ORDER BY name ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) AS `sum` FROM employee;
... "windows": [ {"name": "<unnamed window>", "evalated as #": 1, "using sorting": true, "using temporary file": false, "uses frame buffer": true, "optimized frame evaluation": true, "functions used": [ "sum" ]} ], "buffer_result": { :
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More on non-aggregate wfs● RANK, DENSE_RANK, PERCENT_RANK, CUME_DIST, ROW_NUMBER● LEAD, LAG, FIRST_VALUE, LAST_VALUE, NTH_VALUE
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RANKSELECT name, department_id AS dept, salary, RANK() OVER w AS `rank` FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
+---------+------+--------+------+| name | dept | salary | rank |+---------+------+--------+------+| Newt | NULL | 75000 | 1 || Ed | 10 | 100000 | 1 || Newt | 10 | 80000 | 2 || Fred | 10 | 70000 | 3 || Michael | 10 | 70000 | 3 || Jon | 10 | 60000 | 5 || Dag | 10 | NULL | 6 || Pete | 20 | 65000 | 1 || Lebedev | 20 | 65000 | 1 || Jeff | 30 | 300000 | 1 || Will | 30 | 70000 | 2 |+---------+------+--------+------+
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DENSE_RANKSELECT name, department_id AS dept, salary, RANK() OVER w AS `rank`, DENSE_RANK() OVER w AS dense FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
+---------+------+--------+------+-------+| name | dept | salary | rank | dense |+---------+------+--------+------+-------+| Newt | NULL | 75000 | 1 | 1 || Ed | 10 | 100000 | 1 | 1 || Newt | 10 | 80000 | 2 | 2 || Fred | 10 | 70000 | 3 | 3 || Michael | 10 | 70000 | 3 | 3 || Jon | 10 | 60000 | 5 | 4 || Dag | 10 | NULL | 6 | 5 || Pete | 20 | 65000 | 1 | 1 || Lebedev | 20 | 65000 | 1 | 1 || Jeff | 30 | 300000 | 1 | 1 || Will | 30 | 70000 | 2 | 2 |+---------+------+--------+------+-------+
DENSE_RANK doesn't skip
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ROW_NUMBERSELECT name, department_id AS dept, salary, RANK() OVER w AS `rank`, DENSE_RANK() OVER w AS dense, ROW_NUMBER() OVER w AS `#` FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
+---------+------+--------+------+-------+---+| name | dept | salary | rank | dense | # |+---------+------+--------+------+-------+---+| Newt | NULL | 75000 | 1 | 1 | 1 || Ed | 10 | 100000 | 1 | 1 | 1 || Newt | 10 | 80000 | 2 | 2 | 2 || Fred | 10 | 70000 | 3 | 3 | 3 || Michael | 10 | 70000 | 3 | 3 | 4 || Jon | 10 | 60000 | 5 | 4 | 5 || Dag | 10 | NULL | 6 | 5 | 6 || Pete | 20 | 65000 | 1 | 1 | 1 || Lebedev | 20 | 65000 | 1 | 1 | 2 || Jeff | 30 | 300000 | 1 | 1 | 1 || Will | 30 | 70000 | 2 | 2 | 2 |+---------+------+--------+------+-------+---+
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CUME_DISTSELECT name, department_id AS dept, salary, RANK() OVER w AS `rank`, DENSE_RANK() OVER w AS dense, ROW_NUMBER() OVER w AS `#`, CUME_DIST() OVER w AS cume FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
+---------+------+--------+------+-------+---+---------------------+| name | dept | salary | rank | dense | # | cume |+---------+------+--------+------+-------+---+---------------------+| Newt | NULL | 75000 | 1 | 2 | 1 | 1 || Ed | 10 | 100000 | 1 | 2 | 1 | 0.16666666666666666 || Newt | 10 | 80000 | 2 | 3 | 2 | 0.3333333333333333 || Fred | 10 | 70000 | 3 | 4 | 3 | 0.6666666666666666 || Michael | 10 | 70000 | 3 | 4 | 4 | 0.6666666666666666 || Jon | 10 | 60000 | 5 | 5 | 5 | 0.8333333333333334 || Dag | 10 | NULL | 6 | 6 | 6 | 1 || Pete | 20 | 65000 | 1 | 2 | 1 | 1 || Lebedev | 20 | 65000 | 1 | 2 | 2 | 1 || Jeff | 30 | 300000 | 1 | 2 | 1 | 0.5 || Will | 30 | 70000 | 2 | 3 | 2 | 1 |+---------+------+--------+------+-------+---+---------------------+
Cumulative distribution
“For a row R, if we assume ascending ordering, CUME_DIST of R is the number of rows with values <= the value of R, divided by the number of rows evaluated in the partition. “
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PERCENT_RANKSELECT name, department_id AS dept, salary, RANK() OVER w AS `rank`, DENSE_RANK() OVER w AS dense, ROW_NUMBER() OVER w AS `#`, CUME_DIST() OVER w AS cume, PERCENT_RANK() OVER w AS p_r FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
+---------+------+--------+------+-------+---+---------------------+-----+| name | dept | salary | rank | dense | # | cume | p_r |+---------+------+--------+------+-------+---+---------------------+-----+| Newt | NULL | 75000 | 1 | 2 | 1 | 1 | 0 || Ed | 10 | 100000 | 1 | 2 | 1 | 0.16666666666666666 | 0 || Newt | 10 | 80000 | 2 | 3 | 2 | 0.3333333333333333 | 0.2 || Fred | 10 | 70000 | 3 | 4 | 3 | 0.6666666666666666 | 0.4 || Michael | 10 | 70000 | 3 | 4 | 4 | 0.6666666666666666 | 0.4 || Jon | 10 | 60000 | 5 | 5 | 5 | 0.8333333333333334 | 0.8 || Dag | 10 | NULL | 6 | 6 | 6 | 1 | 1 || Pete | 20 | 65000 | 1 | 2 | 1 | 1 | 0 || Lebedev | 20 | 65000 | 1 | 2 | 2 | 1 | 0 || Jeff | 30 | 300000 | 1 | 2 | 1 | 0.5 | 0 || Will | 30 | 70000 | 2 | 3 | 2 | 1 | 1 |+---------+------+--------+------+-------+---+---------------------+-----+
(rank - 1) / (total rows - 1)
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NTILESELECT name, department_id AS dept, salary, ... PERCENT_RANK() OVER w AS p_r, NTILE(3) OVER w AS `ntile` FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
+---------+------+--------+------+-------+---+---------------------+-----+-------+| name | dept | salary | rank | dense | # | cume | p_r | ntile |+---------+------+--------+------+-------+---+---------------------+-----+-------+| Newt | NULL | 75000 | 1 | 2 | 1 | 1 | 0 | 1 || Ed | 10 | 100000 | 1 | 2 | 1 | 0.16666666666666666 | 0 | 1 || Newt | 10 | 80000 | 2 | 3 | 2 | 0.3333333333333333 | 0.2 | 1 || Fred | 10 | 70000 | 3 | 4 | 3 | 0.6666666666666666 | 0.4 | 2 || Michael | 10 | 70000 | 3 | 4 | 4 | 0.6666666666666666 | 0.4 | 2 || Jon | 10 | 60000 | 5 | 5 | 5 | 0.8333333333333334 | 0.8 | 3 || Dag | 10 | NULL | 6 | 6 | 6 | 1 | 1 | 3 || Pete | 20 | 65000 | 1 | 2 | 1 | 1 | 0 | 1 || Lebedev | 20 | 65000 | 1 | 2 | 2 | 1 | 0 | 2 || Jeff | 30 | 300000 | 1 | 2 | 1 | 0.5 | 0 | 1 || Will | 30 | 70000 | 2 | 3 | 2 | 1 | 1 | 2 |+---------+------+--------+------+-------+---+---------------------+-----+-------+
Divides an orderedpartition into aspecified number ofgroups aka bucketsand assigns a bucketnumber to each row inthe partition.
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LEAD, LAGReturns value evaluated at the row that is offset rows after/before the current row within thepartition; if there is no such row, instead return default (which must be of the same type asvalue).
Both offset and default are evaluated with respect to the current row. If omitted, offsetdefaults to 1 and default to null
lead or lag function ::= { LEAD | LAG } ( expr [ , offset [ , default expression>] ] ) [ RESPECT NULLS ]
Note: “IGNORE NULLS” not supported, RESPECT NULLS is default but can be specified.
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+---------+------+--------+-------+| name | dept | salary | lead |+---------+------+--------+-------+| Newt | NULL | 75000 | NULL || Ed | 10 | 100000 | 80000 || Newt | 10 | 80000 | 70000 || Fred | 10 | 70000 | 70000 || Michael | 10 | 70000 | 60000 || Jon | 10 | 60000 | NULL || Dag | 10 | NULL | NULL || Pete | 20 | 65000 | 65000 || Lebedev | 20 | 65000 | NULL || Jeff | 30 | 300000 | 70000 || Will | 30 | 70000 | NULL |+---------+------+--------+-------+
LEADSELECT name, department_id AS dept, salary, LEAD(salary, 1) OVER w AS `lead` FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
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+---------+------+--------+--------+-------+| name | dept | salary | lag | lead |+---------+------+--------+--------+-------+| Newt | NULL | 75000 | NULL | NULL || Ed | 10 | 100000 | NULL | 80000 || Newt | 10 | 80000 | 100000 | 70000 || Fred | 10 | 70000 | 80000 | 70000 || Michael | 10 | 70000 | 70000 | 60000 || Jon | 10 | 60000 | 70000 | NULL || Dag | 10 | NULL | 60000 | NULL || Pete | 20 | 65000 | NULL | 65000 || Lebedev | 20 | 65000 | 65000 | NULL || Jeff | 30 | 300000 | NULL | 70000 || Will | 30 | 70000 | 300000 | NULL |+---------+------+--------+--------+-------+
LAGSELECT name, department_id AS dept, salary, LAG(salary, 1) OVER w AS `lag`, LEAD(salary, 1) OVER w AS `lead` FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY salary DESC);
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FIRST_VALUE, LAST_VALUE, NTH_VALUEReturns value evaluated at the first, last, nth in the frame of the current rowwithin the partition; if there is no nth row (frame is too small), the NTH_VALUEreturns NULL.
first or last value ::= { FIRST_VALUE | LAST_VALUE } ( expr ) [ RESPECT NULLS ]
nth_value ::= NTH_VALUE ( expr, nth-row ) [FROM FIRST] [ RESPECT NULLS ]
Note: “IGNORE NULLS” is not supported, RESPECT NULLS is used but canbe specified.Note: For NTH_VALUE, “FROM LAST” is not supported, FROM FIRST is usedbut can be specified
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SELECT name, department_id AS dept, salary, SUM(salary) OVER w AS `sum`, FIRST_VALUE(salary) OVER w AS `first` FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY name ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) +---------+------+--------+--------+--------+| name | dept | salary | sum | first |+---------+------+--------+--------+--------+| Newt | NULL | 75000 | 75000 | 75000 || Dag | 10 | NULL | NULL | NULL || Ed | 10 | 100000 | 100000 | NULL || Fred | 10 | 60000 | 160000 | NULL || Jon | 10 | 60000 | 220000 | 100000 || Michael | 10 | 70000 | 190000 | 60000 || Newt | 10 | 80000 | 210000 | 60000 || Lebedev | 20 | 65000 | 65000 | 65000 || Pete | 20 | 65000 | 130000 | 65000 || Jeff | 30 | 300000 | 300000 | 300000 || Will | 30 | 70000 | 370000 | 300000 |+---------+------+--------+--------+--------+
FIRST_VALUE “in frame”
Current row: Jon
FIRST_VALUE in frame is: Ed
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SELECT name, department_id AS dept, salary, SUM(salary) OVER w AS `sum`, FIRST_VALUE(salary) OVER w AS `first`, LAST_VALUE(salary) OVER w AS `last` FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY name ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) +---------+------+--------+--------+--------+--------+| name | dept | salary | sum | first | last |+---------+------+--------+--------+--------+--------+| Newt | NULL | 75000 | 75000 | 75000 | 75000 || Dag | 10 | NULL | NULL | NULL | NULL || Ed | 10 | 100000 | 100000 | NULL | 100000 || Fred | 10 | 60000 | 160000 | NULL | 60000 || Jon | 10 | 60000 | 220000 | 100000 | 60000 || Michael | 10 | 70000 | 190000 | 60000 | 70000 || Newt | 10 | 80000 | 210000 | 60000 | 80000 || Lebedev | 20 | 65000 | 65000 | 65000 | 65000 || Pete | 20 | 65000 | 130000 | 65000 | 65000 || Jeff | 30 | 300000 | 300000 | 300000 | 300000 || Will | 30 | 70000 | 370000 | 300000 | 70000 |+---------+------+--------+--------+--------+--------+
LAST_VALUE “in frame”
Current row: Jon
LAST_VALUE in frame is: Jon
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SELECT name, department_id AS dept, salary, SUM(salary) OVER w AS `sum`, NTH_VALUE(salary, 2) OVER w AS nth FROM employee WINDOW w AS (PARTITION BY department_id ORDER BY name ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) +---------+------+--------+--------+--------+| name | dept | salary | sum | nth |+---------+------+--------+--------+--------+| Newt | NULL | 75000 | 75000 | NULL || Dag | 10 | NULL | NULL | NULL || Ed | 10 | 100000 | 100000 | 100000 || Fred | 10 | 60000 | 160000 | 100000 || Jon | 10 | 60000 | 220000 | 60000 || Michael | 10 | 70000 | 190000 | 60000 || Newt | 10 | 80000 | 210000 | 70000 || Lebedev | 20 | 65000 | 65000 | NULL || Pete | 20 | 65000 | 130000 | 65000 || Jeff | 30 | 300000 | 300000 | NULL || Will | 30 | 70000 | 370000 | 70000 |+---------+------+--------+--------+--------+
NTH_VALUE “in frame”
Current row: Jon
NTH_VALUE(.., 2) in frame is: Fred
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Implicit and explicit windows● Windows can be implicit and unnamed:
COUNT(*) OVER (PARTITION BY DEPARTMENT_ID)● Windows can be defined and named via the windows clause clause:
SELECT COUNT(*) OVER w FROM t WINDOW w as (PARTITION BY department_id)
● This allows easy sharing of windows between several window functions
and also avoids redundant windowing steps since more functions can be
evaluated in the same step. ● Limitation: equivalent windows are not yet merged
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Implicit and explicit windows● A window definition can inherit from another window definition in its
specification, adding detail (no override)
SELECT name, department_id, COUNT(*) OVER w1 AS cnt1, COUNT(*) over w2 AS cnt2 FROM employee WINDOW w1 AS (PARTITION BY department_id), w2 AS (w1 ORDER BY name) ORDER BY department_id, name;
+---------+---------------+------+------+| name | department_id | cnt1 | cnt2 |+---------+---------------+------+------+| Newt | NULL | 1 | 1 || Dag | 10 | 6 | 1 || Ed | 10 | 6 | 2 || Fred | 10 | 6 | 3 || Jon | 10 | 6 | 4 || Michael | 10 | 6 | 5 || Newt | 10 | 6 | 6 || Lebedev | 20 | 2 | 1 || Pete | 20 | 2 | 2 || Jeff | 30 | 2 | 1 || Will | 30 | 2 | 2 |+---------+---------------+------+------+
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Time-line● Work in progress, no due date yet
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Q & A
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