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ppr maths nbk 5 CHAPTER 2 : QUADRATIC EXPRESSIONS AND EQUATIONS EXERCISE 1 : Expand : 1. (x - 8) (x + 3) Answer : ……… 2. (x + 3) (x – 3) Answer : ……… 3. m(x + y) – (x + y) Answer : ……… 4. (2x – 1) (x + 3) Answer : ……… 5. 4( x 2 – 2 ) – x( 5x + 1 ) Answer : ……… 6.–2x( x – 3 ) + 4x( x – 6 ) Answer : ……… 7. (x – 8 )( 2x + 5 ) Answer : ……… 8. ( 3u – 2s )( u – s ) Answer : ……… 9. x( 5 – x ) – 4x 2 Answer : ……… 10. 9 – ( u – 3)( u + 2 ) Answer : ………

F4 02 Quadratic Expressions And

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Page 1: F4 02 Quadratic Expressions And

ppr maths nbk

5

CHAPTER 2 : QUADRATIC EXPRESSIONS AND EQUATIONS EXERCISE 1 : Expand : 1. (x - 8) (x + 3) Answer : ……… 2. (x + 3) (x – 3) Answer : ……… 3. m(x + y) – (x + y) Answer : ……… 4. (2x – 1) (x + 3) Answer : ……… 5. 4( x2 – 2 ) – x( 5x + 1 )

Answer : ……… 6.–2x( x – 3 ) + 4x( x – 6 )

Answer : ……… 7. (x – 8 )( 2x + 5 )

Answer : ……… 8. ( 3u – 2s )( u – s )

Answer : ……… 9. x( 5 – x ) – 4x2 Answer : ……… 10. 9 – ( u – 3)( u + 2 ) Answer : ………

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CHAPTER 2 : QUADRATIC EXPRESSIONS AND EQUATIONS EXERCISE 2 Expand : 1.(2p – q)2 – p(p – q) Answer :……………. 2. (p – q)2 – (p2 – q2) Answer :……………. 3. (3f + g)(2f – g) – g2

Answer :……………. 4. (6h + k)(k – 3h) + (h2 – k2) Answer :……………. 5. 2x(x – 1) + (2x + 1)2 Answer :……………. 6. p( p – 4q ) – ( 2p – q )2

Answer :…………….

7. ( x – 5 )2 – ( x + 3 )2 Answer :……………. 8. ( 3x – 1 )2 – 5( x + 1 ) Answer :……………. 9. ( a + 4 )2 – 64a Answer :……………. 10. ( k – 2m )2 – ( m2 – 4k2 ) Answer :…………….

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CHAPTER 2 : QUADRATIC EXPRESSIONS AND EQUATIONS DIAGNOSTIC TEST 1. (2p + q) ( q – 2p) = A. 4p2 – q2 B. q2 – 4p2 C. 4p2 – 4pq – q2 D. 4p2 – 4pq + q2

2. (3m –n) (2m – n) = A. 6m2 – mn + n2 B. 6m2 – 7mn – n2

C. 6m2 – 7mn + n2 D. 6m2 – 5mn + n2

3. (x + 5y)2 – 5xy = A. x2 + 25y2 B. x2 + 5xy + 25y2 C. x2 – 5xy + 25y2 D. x2 – 10xy + 25y2

4. (x + y)2 + (x2– y2) = A. 2x2 + 2xy B. 2x2 – 2xy C. 2x2 + 2xy – 2y2 D. 2x2 – 2xy + 2y2

5. ( 3h – 5 )( 2h + 4 ) = A 6h2 + 2h + 20 B 6h2 + 2h – 20 C 6h2 +12h – 20 D 6h2 –10h + 20 6. m( m – 2 ) – 2m( m + 3 ) = A –m2 – 8m B m2 + 8m C -m2 + 4m D m2 – 6m

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7. ( 3p – m )( p – 4m ) = A 3p2 + 4m2 B 3p2 + 11mp – 4m2 C 3p2 – 13mp – 4m2 D 3p2 + 12mp + 4m2 8. ( p + q )2 – ( 2p2 – q2 ) = A – p2 + 2q2 B – p2 + 2pq C – p2 D – p2 + 2pq + 2q2 9. ( f – 2 )( f + 1 ) + ( 2f – 3 ) = A f2 – 2f B f2 + f – 1 C f2 + f – 5 D f2 – 5 10. 3x( x – 2y ) – ( 2x – y )2 = A 3x2 + 10x + y2 B – x2 – 2xy – y2 C – x2 –10xy – y2 D – x2 + 2xy + y2

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CHAPTER 2 : QUADRATIC EXPRESSIONS AND EQUATIONS EXERCISE 1 1. Factorise completely p2 - 2p 2. Factorise completely 4 x2 – 81

3. Factorise completely r2 – 4r – 12. 4. Solve the quadratic equation k( k – 12 ) + 20 = 0 5. Express the area of the triangle in terms of x. (4x+1)cm 6x cm

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CHAPTER 2 : QUADRATIC EXPRESSIONS AND EQUATIONS EXERCISE 2 1. Solve the quadratic equation 3b ( 2b + 1 ) = 4 – 2b 2. Factorise completely 6 – 17 x - 14 x2

3. Solve the equation 15

32 2

=−

ww

4. Solve the value of m for ( )3

)2(2−+

=+mmm

5. Johan is 3 years older than his sister Aishah and the product of their age is 18. Find the age of Johan.

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CHAPTER 2 : QUADRATIC EXPRESSIONS AND EQUATIONS DIAGNOSTIC TEST

1. Solve the equation 03

2 =−yy

2. Solve the quadratic equation 31

62

2

+=yy

3. Solve the equation 31

332 2

=−

yy

4. Solve the quadratic equation 2

211 52

x x x−= +

2x cm 5. The diagram shows a right-angled triangle ABC. A (a) Form an equation in terms of x using Teorem Phytogoras and show that 9cm x2 – 6x = 0. (x + 9) cm

(b) Hence, find the length of AC.

C