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ASE324: Aerospace Materials Laboratory
Instructor: Rui Huang
Dept of Aerospace Engineering and Engineering MechanicsThe University of Texas at Austin
Fall 2003
Introduction to composite materials
• Two approaches can be used to engineer mechanical properties of materials:– Intrinsic modification (e.g., alloying)– Extrinsic modification (composite)
– Nanomaterials: nanocrystals and nanocomposites
Composite approach
• Certain property (e.g., strength) of a material may be improved by mixing with other materials.
• The host material commonly known as matrix and the other material(s) known as reinforcement(s).
• Almost infinite arrays of properties can be designed via composite approach.
Examples of composite materials
• Wood is a natural composite that consists of hemi-cellulose fibers in a matrix of lignin.
• Concrete is an artificial composite that consists of sand, cement, and stone.
• More commonly, polymer matrix composites are reinforced with glass or carbon fibers (e.g., pole vaults, tennis racquets)
Matrix materials
• Polymer: reinforced to improve stiffness and strength
• Metal: reinforced to provide creep resistance at high temperature
• Ceramic: reinforced to improve fracture toughness
Types of composite materials• Fiber-reinforced composites
– Wood: cellulose fibers in lignin matrix
• Laminated composites– Plywood, sandwich panels
• Particulate composites– Rocket propellant: aluminum particles in polyurethane
• Hybrids, such as laminated fiber-reinforced composites
Laminated fiber-reinforced composites
• Laminae: flat layers, each with unidirectional fibers.
• Laminate: a stack of laminae of various fiber orientations.
• Tailor the directional dependence of material properties (anisotropy)
Mechanical properties of composites
• Inhomogeneous: properties depend on position (micro-mechanics)
• Anisotropic: properties depend on direction (macro-mechanics)
Elastic modulus• Fiber-reinforced composites
Direction 1
Direction 2
)1(1 fmff VEVEE −+=1
2
1−
−+=
m
f
f
f
EV
EV
E
Direction 1
• Same strain in fibers and matrix.• But different stresses (inhomogeneity).
• Total force:• Average stress:• Average modulus:
mmff AAP σσ +=
)1(1 fmffmf
VVAA
P−+=
+= σσσ
)1(1
11 fmff VEVEE −+==
εσ
Direction 2
• Total elongation:• Total strain:• Average modulus:
mmff hh εεδ +=
)1(2 fmffmf
VVhh
−+=+
= εεδε
1
2
22
1−
−+==
m
f
f
f
EV
EV
Eεσ
•Same stress in fibers and matrix•But different strains
Elastic anisotropy
σ
Matrix
Composite Ef
Em
E1E2
Fiber
ε
E1 = E2 if Ef = Em (homogeneous, no reinforcement)
Particulate composites• E1 and E2 are the upper and lower limits for the
elastic modulus of particulate composites.
Poisson’s ratio
Transverse strains:
fff ενε −=' mmm ενε −=' 1εεε == mf
)1(''2 fmff VV −+= εεε
Major Poisson’s ratio:)1(
1
221 fmff VV −+=−= νν
εεν
2112 νν ≠Minor Poisson’s ratio:
Shear modulus
σ12σ12
σ21
σ21
Composite shear strain:)1(12 fmff VV −+= γγγ
Composite shear modulus: 1
12
1212
1−
−+==
m
f
f
f
GV
GV
Gγσ
Compliance matrix• Under plane-stress condition:
=
12
2
1
333231
232221
131211
12
2
1
σσσ
γεε
sssssssss
compliance
For isotropic elastic materials:
Ess 1
2211 ==G
s 133 = E
ss ν−== 2112 032312313 ==== ssss
Two independent constants: E, G, or ν (independent of orientation)
( )ν+=12EG ( )121133 2 sss −=
Composite complianceDirection 2
=
12
2
1
33
2221
1211
12
2
1
0000
σσσ
γεε
sssss
Direction 1
• Four independent elastic constants (plane orthotropic)
111
1E
s =2
221E
s =12
331G
s =
1
2121 Es ν
−=2
1212 Es ν
−=
1221 ss =2
21
1
12
EEνν
=