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Powerpoint slides copied from or based upon:
Connally,
Hughes-Hallett,
Gleason, Et Al.
Copyright 2007 John Wiley & Sons, Inc.
Functions Modeling Change
A Preparation for Calculus
Third Edition
INPUT AND OUTPUT
Chapter 2Section 1
2
You will remember the following problem from Chapter 1, Section 1:
3Page 62
The number of gallons of paint needed to paint a house depends on the size of the house. A gallon of paint typically covers 250 square feet.
Thus, the number of gallons of paint, n, is a function of the area to be painted, A ft2. We write n = f(A).
Which is the output and which is the input for:
n = f(A) ?4Page 62
A reminder from Chapter 1:
Output = f(Input)
Or:
Dependent = f(Independent)
5Page 4
Which is the output and which is the input for:
n = f(A) ?
6Page 62
Which is the output and which is the input for:
n = f(A) ?
n=f(A) => output, A => input
7Page 62
n=f(A) => output, A => input
For example, f(20,000) represents ?
8Page 62
n=f(A) => output, A => input
f(20,000) represents the # of gallons of paint to cover a house of 20,000 sq ft.
(ft2)
9Page 62
Using the fact that 1 gallon of paint covers 250 ft2, evaluate the expression f(20,000).
10Page 62 Example 1
( )n f A
11Page 62
2
2
( )
250
n f A
Aftn
ft
gal
12Page 62
2
2
2
2
( )
250
( )
250
n f A
Aftn
ft
gal
Aftf A
ft
gal
13Page 62
2
2
2
2
2
2
( )
250
( )
250
20,000(20,000) ?
250
n f A
Aftn
ft
gal
Aftf A
ftgal
ftf
ft
gal
14Page 62
2
2
2
2
2
2
( )
250
( )
250
20,000(20,000) 80
250
n f A
Aftn
ft
gal
Aftf A
ft
gal
ftf gallons
ft
gal
15Page 62
Area of a circle of radius r: A = q(r) = πr2.
Use the formula to evaluate q(10) and q(20).
What do your results tell you about circles?
16Page 62 Example 2
Area of a circle of radius r: A = q(r) = πr2.
Use the formula to evaluate q(10) and q(20).
2(10) (10)q
17Page 62
Area of a circle of radius r: A = q(r) = πr2.
Use the formula to evaluate q(10) and q(20).
2(10) (10)
(10) (100) 100 314.159
q
q
18Page 62
Area of a circle of radius r: A = q(r) = πr2.
Use the formula to evaluate q(10) and q(20).
2(20) (20)q
19Page 62
Area of a circle of radius r: A = q(r) = πr2.
Use the formula to evaluate q(10) and q(20).
2(20) (20)
(20) (400) 400 1256.637
q
q
20Page 62
Area of a circle of radius r: A = q(r) = πr2.
What do your results tell you about circles?
21Page N/A
Area of a circle of radius r: A = q(r) = πr2.
What do your results tell you about circles?
If we increase the radius by 2x (factor of 2), we increase the Area by 4x (factor of 4).
Or, we double r we quadruple A. 22Page N/A
Let:
Evaluate: g(3), g(-1), g(a)
2 1( )
5
xg x
x
23Page 62 Example 3
g(3):
23 1 10(3) 1.25
5 3 8g
24Page 62
g(-1):
2( 1) 1 2( 1) .50
5 ( 1) 4g
25Page 62
g(a):
2 1( )
5
ag a
a
26Page 62
Let h(x) = x2 − 3x + 5. Evaluate and simplify the following expressions. (a) h(2)(b) h(a − 2)(c) h(a) − 2(d) h(a) − h(2)
27Page 63 Example 4
h(2):
2( ) 3 5h x x x
28Page 63
h(2):
2
2
( ) 3 5
(2) 2 3(2) 5
4 6 5
3
h x x x
h
29Page 63
h(a-2):
2( ) 3 5h x x x
30Page 63
h(a-2):
2
2
2
2
( ) 3 5
( 2) ( 2) 3( 2) 5
4 4 3 6 5
7 15
h x x x
h a a a
a a a
a a
31Page 63
h(a)-2:
2( ) 3 5h x x x
32Page 63
h(a)-2:
2
2
2
( ) 3 5
( ) 2 3 5 2
3 3
h x x x
h a a a
a a
33Page 63
h(a)-h(2):
2( ) 3 5h x x x
34Page 63
h(a)-h(2):
2
2 2
2
2
2
( ) 3 5
( ) (2) ( 3 5) (2 3(2) 5)
( 3 5) (4 6 5)
( 3 5) 3
3 2
h x x x
h a h a a
a a
a a
a a
35Page 63
Finding Input Values: Solving Equations
Given an input, we evaluate the function to find the output. (Input Output)
Sometimes the situation is reversed; we know the output and we want to find the corresponding input. (Output Input)
36Page 63
Back to the "Cricket" function, but now
if T = 76, R = ?
140
4T R
37Page 63 Example 5
140
41
76 4041
76 4041
364
144
T R
R
R
R
R
38Page 63
Area of a circle of radius r (cm.): A = q(r) = πr2.
What is the radius of a circle whose area is 100 cm2?
39Page64 Example 7
2
2
2
2
2
( )
100
100
31.83098862
31.83098862
5.641895835 Are we done?
A q r r
r
r
r
r
r
40Page 64
5.641895835
5.641895835
r
r
Since a circle CAN'T have a negative radius, we conclude:
41Page 64
Finding Output and Input Values from Tables and Graphs
42Page 64
Table 2.1 shows the revenue, R = f(t), received or expected, by the National Football League,1 NFL, from network TV as a function of the year, t, since 1975.
(a) Evaluate and interpret f(25).(b) Solve and interpret f(t) = 1159.
43Page 64 Example 8
R = f(t)
(a) Evaluate and interpret f(25). (b) Solve and interpret f(t) = 1159.
Year, t (since 1975)
0 5 10 15 20 25 30
Revenue, R(million $)
201
364
651
1075
1159
2200
2200
44Page 64
R = f(t)
(a) Evaluate and interpret f(25).
f(25) = 2200.
Therefore, in 2000 (1975+25), revenue was $2,200 million.
Year, t (since 1975)
0 5 10 15 20 25 30
Revenue, R(million $)
201
364
651
1075
1159
2200
2200
45Page 65
R = f(t)
(b) Solve and interpret f(t) = 1159.
Year, t (since 1975)
0 5 10 15 20 25 30
Revenue, R(million $)
201
364
651
1075
1159
2200
2200
46Page 65
R = f(t)
(b) Solve and interpret f(t) = 1159.
When were Revenues $1159 million?Year, t (since 1975)
0 5 10 15 20 25 30
Revenue, R(million $)
201
364
651
1075
1159
2200
2200
47Page 65
R = f(t)
When were Revenues $1159 million?
t=20. Therefore, 1995.Year, t (since 1975)
0 5 10 15 20 25 30
Revenue, R(million $)
201
364
651
1075
1159
2200
2200
48Page 65
End of Section 2.1
49