7/13/2019 18 Preliminary Design of Concrete Shear Wall for Tall Buildings 23052014 1

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Section Properties

D = mm

* t t = mm

D =

B = mm

Gravity load Wu per floor .: Pu = N*Ta*Wu =

t Nos of Floors = n .:

Ta = Tributary area

B + * t /2 Wind Load P =

B' = Tributary width for wind

B' = Tributary Width h = height between each floor

Preliminary Design of Concrete Shear Wall

Prep By : A B Quadri- Abq Consultants - 9959010210 - em-abquadri@yahoo.com-12-2-826/2 Royal Residency, Besides Amba talkies, Mehdipatnam , Hyderabad-India. 500028-w.abqconsultants.com

Required moment of

inertia of wall E*Iw46267200 kn.m2

Required Iw =

1.7973 m4

Required Sw' =

p*B'(n*h^2)/(0.14*fc')2.5714 m3 ok

ok

0.5323 n/mm2

12.00

Fb = Bending stress

due to wind = Mw/Sw1.71 n/mm2

3.00 m fa = Ultimate axial

stress in wall =3.00 m

20 Mw = (PB')*(n*h^2)/2 5400.00 Kn.m

9.00 m2 Fa =Permissible axial

stress in wall = 0.4fc'1.00 Kn/m2 n/mm2

m3

8.00 Kn/m2 1440.00 Kn

3006

3006 Area A = 2Bt + tD 2.7054

1.000 Section Modulus Sw = tD^2/6 + BtD 3.1626

m2

300 Mom Of Inertia Iw = tD^3/12 + BtD^2/2 4.7534 m4

mpa

Ref Calculation Output

mpa E steel 204980 mpa

mpa E conc 25743

fc'

fy

30

410

Subject : Description :

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cont'd :

Prepared by : Date : Job no : Sheet No :