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    Sec.4 - Acid-base 1

    Acid-Base Reactions

    Bronsted-Lowry acid substance that can donate a hydrogen ion (H+)Bronsted-Lowry base substance that can accept a hydrogen ion (H+)

    CH3COOH + OH CH3COO + H2O

    acid base conjugate base conjugate acid

    Lewis acid substance that can accept a pair of electronsLewis base substance that can donate a pair of electrons

    FeBr3 + Br2 FeBr4 + Br+

    Lewis acid Lewis base Lewis base Lewis acid

    Volhardt: 2-1, 2-2, 8-3, 9-1, 13-2, 19-4

    Read section 2-1not covered in notes

    Acid-base movie

    http://acid-base/acid-base.htmlhttp://acid-base/acid-base.htmlhttp://acid-base/acid-base.htmlhttp://acid-base/acid-base.html
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    Sec.4 - Acid-base 2

    pH = -log[H+] pOH = -log[OH]

    kw = [H+][ OH] = 1 x 10-14

    pH + pOH = 14

    neutral solution [H+] = [ OH] = 1 x 10-7 pH = 7acidic solution [H+] > 1 x 10-7 pH range 0 to 7basic solution [H+] < 1 x 10-7 pH range 7 to 14

    Review

    General formula for an acid HA; for a base B

    HA H+ + A B + H2O B+H + OH

    ka = [H+][A ] kb = [ OH][B+H]

    [HA] [B]

    taking the log of both sides

    Henderson-Hasselbalch equations

    pH = pka + log[A ] pOH = pkb + log[B+H]

    [HA] [B]

    strong acid [H+] , ka, pka strong base [ OH] , kb, pkbweak acid [H+] , ka, pka weak base [ OH] , kb, pkb

    relationship between conjugate acid base pairs

    ka x kb = kw =1 x 10-14

    pka + pkb = 14

    Brnsted-Lowryacids and bases

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    Sec.4 - Acid-base 3

    Lewis Acids and Bases

    Makes you think about the electrons and how bonds are formed

    arrow show bond formationarrow show bond breaking

    new bond

    gained two electronsand becomesnegatively charged

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    Sec.4 - Acid-base 4

    Opposite Charges Attract and React

    BF3 has substantial positive charge on the boron

    NH3 has substantial negative charge localized at the lone pair

    -ve goes to+ve

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    Sec.4 - Acid-base 5

    BF3 is sp2 hybridized

    The LUMO (LowestUnoccupied MolecularOrbital) is shown to theright. Most of thevolume of the LUMOcorresponds to theempty p orbital

    The base donates its electrons that occupy the HOMO to theLUMO of the acid to produce a new sigma bond

    NH3 is sp3 hybridized.

    The HOMO (HighestOccupied MolecularOrbital) is shown tothe left and is wherethe nonbonding lonepair resides.

    The van der Waals surface electron density is indicated by the mesh

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    Sec.4 - Acid-base 6

    Why do acids have different acidities? What makes a strong acid astrong acid? An acid is strong if its conjugate base is stable. If the

    base is not stable it is reactive and will react with a proton and shiftthe equilibrium to the left in the following equilibrium.

    HA A + H+

    Hence the strength of an acid is inversely related to the strength of itsconjugate base. What makes the base stable? You must look at thestructure of the molecule. What is the hybridization of the atom? Is thecharge on an electronegative atom? Is the electronegative atom large so

    that the charge is spread over a larger area? Can the charge bedelocalized throughout the molecule? All of these must be considered

    Acidity increases with increasing anion stability

    The first step to organic reactions is understanding acids and bases

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    Sec.4 - Acid-base 7

    1. What atom is the charge on?

    Acidity increases with increasing anion stabilityThe more electronegative an atom, the greater its ability to carry a negative

    charge. Remember, electronegativity is the measure of an elements affinity foran electron or its ability to accept an electron.

    (CH3)3C-H (CH3)2N-H CH3O-H H-F

    B

    2.0C

    2.5N

    3.0O

    3.5F

    4.0

    Al

    1.5Si

    1.8P

    2.1S

    2.5Cl

    3.0

    Ga

    1.8Ge

    2.0As

    2.2Se

    2.6Br

    2.8

    Te

    2.1I

    2.5

    increasing electronegativity of the underlined atom;increasing acid strength

    increasing stability of anion shifts equilibrium to products

    (CH3)3C + H+ (CH3)2N + H

    + CH3O + H+ F + H+

    HA A + H+

    B) HF > CH3OH > CH3)2NH > (CH3)2CH

    A) 1 > 2 > 3 > 4B) 4 > 3 > 2 > 1C) 4 > 2 > 3 > 1D) 1 > 4 > 3 > 2

    1. 2. 3. 4.

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    Sec.4 - Acid-base 8

    1. What atom is the charge on?

    A larger anion can disperse the negative charge over a larger volume and thusincreases the stability of the conjugate base which is more important thanelectronegativity when comparing elements down a column in the periodic

    table.

    H-F H-Cl H-Br H-I

    B

    2.0C

    2.5N

    3.0O

    3.5F

    4.0

    Al

    1.5Si

    1.8P

    2.1S

    2.5Cl

    3.0

    Ga

    1.8

    Ge

    2.0

    As

    2.2

    Se

    2.6

    Br

    2.8Te

    2.1I

    2.5

    Thus use electronegativity when comparing atoms in the samerow and size when comparing atoms in the same column

    F Cl Br I conjugatebase

    HA A + H+

    increasing size of halogen increasing acid strengthincreasing stability of anion

    decreasing electronegativity of halogen

    1. 2. 3. 4.

    E) HI > HBr > HCl > HF

    A) 1 > 2 > 3 > 4B) 4 > 2 > 1 > 3C) 4 > 2 > 3 > 1D) 1 > 4 > 3 > 2E) 4 > 3 > 2 > 1

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    Sec.4 - Acid-base 9

    The electrostatic potential maps show all the hydrohalic acids are polar.The variation in polarity is less significant than the bond strength whichdecreases from 567 kJ/mol for HF to 299 kJ/mol for HI.

    Can also look at bond strength

    For binary acids in the same group, HA bond strength decreases withincreasing size of A, so acidity increases.

    For binary acids in the same row, HA polarity increases with increasingelectronegativity of A, so acidity increases

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    Sec.4 - Acid-base 10

    Order the following compounds in decreasing acidity. (most acid to least acidic)

    B

    2.0C

    2.5N

    3.0O

    3.5F

    4.0

    Al

    1.5Si

    1.8P

    2.1S

    2.5Cl

    3.0

    Ga

    1.8Ge

    2.0As

    2.2Se

    2.6Br

    2.8

    Te

    2.1I

    2.5

    1) CH3OH 2) CH3SH 3) CH3CH3

    A) 1 > 2 > 3B) 3 > 2 > 1C) 2 > 3 > 1D) 2 > 1 > 3E) 1 > 3 >2

    Which of the hydrogens shown in the following moleculewould be most acidic?

    O

    H

    N

    H

    1)

    2)

    A) 1B) 2

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    Sec.4 - Acid-base 11

    2. The proximity of an electronegative atom to an acidic atom canhelp stabilize the conjugate base. (Induction)

    Inductive effects: Electronegative atoms pull electron density through the sigmabond from adjacent carbons making the carbon more positive. If the carbon is closeto the anion this carbon can then pull electron density from the region that has thenegative charge to make it more stable.

    pka

    4.83 4.52 4.05 2.86

    increasing acidity

    increasing anion stability

    H3COH ClCH2CH2OH F3CCH2OH

    pka 15.5 14.3 12.4increasing acidity

    increasing anion stability

    HA A + H+

    OH

    O

    OH

    O

    ClOH

    OCl

    OH

    O

    Cl

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    Sec.4 - Acid-base 12

    2. The proximity of an electronegative atom to an acidic atom canhelp stabilize the conjugate base. (Induction)

    HA A + H+

    A) 1 > 2 > 3 > 4B) 4 > 2 > 1 > 3C) 4 > 2 > 3 > 1D) 2 > 4 > 3 > 1

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    Sec.4 - Acid-base 13

    O

    O

    Cl

    Cl

    Cl

    -

    -

    d+

    d-d-

    d-O

    Cl

    Cl

    Cld+

    d-

    d-d-

    - 1

    The chlorines make the adjacent carbons electron poor. Thecarbon can then pull electron density from the region that has thenegative charge, and this effect will stabilize the negative charge

    O

    H

    F

    H

    How about these hydrogensDo the electronegative atoms

    help stabilize the conjugate base

    F

    O-

    d-

    This is destabilizing. The lone pairs onthe electronegative atom and the lonepair on the carbon repel each other.

    + H+

    + H+

    These protons arenot very acidic

    Take out

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    Sec.4 - Acid-base 14

    What effect do alkyl groups

    CCH3C

    H3C CH3

    O

    OH

    Which compound is more acidic?

    C

    O

    H3C OH

    CC

    H3C

    H3C CH3

    O

    O

    C

    O

    H3C O

    + H+

    + H+

    H

    C

    O

    C

    HH O

    Resonance

    hyperconjugationthrough C-H sigma

    bond. This is notresonance. We willtalk more about

    this later.

    more acidic

    more stable conjugate base

    sp2

    sp2

    sp2sp3

    only one C-H sbond shown

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    Sec.4 - Acid-base 15

    Order the following acids from most acidic to least acidic?

    A) 1 > 2 > 3 > 4

    B) 4 > 2 > 3 > 1C) 2 > 3 > 1 > 4D) 3 > 2 > 1 > 4E) 1 > 4 > 2 > 3

    Alkyl and aryl groups areelectron donating through

    hyperconjugation or inductiveeffects which makes theanion

    hyperconjugationthrough C-H sigmabond. C

    O

    C

    HH

    C

    HH

    H

    H

    H

    H

    A) less stable.B) more stable

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    Sec.4 - Acid-base 16

    B

    2.0C

    2.5N

    3.0O

    3.5F

    4.0

    Al

    1.5Si

    1.8P

    2.1S

    2.5Cl

    3.0

    Ga

    1.8

    Ge

    2.0

    As

    2.2

    Se

    2.6

    Br

    2.8

    Te

    2.1I

    2.5

    Which of the hydrogens shown in the following moleculewould be most acidic?

    HO F

    HO

    1)

    2)

    A) 1B) 2

    1)

    2)N

    H

    NH2

    Which of the hydrogens shown in the following molecule would be most acidic?

    A) 1

    B) 2

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    Sec.4 - Acid-base 17

    3. Resonance Stabilization

    List the following compounds in order of decreasing acidity (Most acidic to leastacidic)

    1)

    Two resonance structures with the negative charge on two electronegativeatoms (oxygen) is more stabilizing than 3 resonance structures with thenegative charge on carbons.

    A) 1 > 2 > 3

    B) 1 > 3 > 2C) 3 > 2 > 1D) 2 > 3 > 1

    2) 3)

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    Sec.4 - Acid-base 18

    O

    O O O

    CH3C

    O

    O CH3C

    O

    O

    CH3O + H+

    + H+

    + H+

    Phenol has more resonance structures than acetic acid but acetic acid is more acidic, why?

    Which atom is able to handle a negative charge better, carbon or oxygen?

    Oxygen can. Thus resonance onto two oxygens is more stabilizing than three carbons

    CH3OH

    C6H5OH

    CH3CO2H

    pKa = 15.5

    pKa = 4.74

    pKa = 9.92

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    Sec.4 - Acid-base 19

    Which of the hydrogens shown in the following moleculewould be most acidic?

    1)

    2)

    NH

    H2NA) 1B) 2

    1)

    2)

    H

    H H

    A) 1B) 2

    CH3

    HH

    H

    H

    CH3

    H

    H

    HNCH3N

    HH

    H

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    Sec.4 - Acid-base 20

    1)

    2)O

    H H

    H H

    A) 1B) 2

    1)

    2)O

    H

    H H

    1)

    2)O

    H

    H

    H

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    Sec.4 - Acid-base 21

    pka > 70 44 26 38

    4. Hybridization

    Order the following compounds from strongest to weakest acid

    1) (CH3)3CH 2) CH2=CH2 3) HCCH 4) NH3

    sp3

    C

    sp2

    C

    sp3

    N

    sp

    C

    A) 1 > 2 > 3 > 4B) 4 > 3 > 2 > 1C) 2 > 3 > 1 > 4D) 3 > 4 > 2 > 1E) 1 > 4 > 2 > 3

    The sp3 negatively charged nitrogen atom is a weaker base thana negatively charged sp3 carbon because it is moreelectronegative. It is also a weaker base than a sp2 carbon.However it is a stronger base than a sp hybridized carbanionbecause the sp hybridization of the carbanion has a greater

    stabilizing effect than increasing electronegativity in this case.

    1) (CH3)3C 2) CH2=CH 3) HCC 4) NH2+ H+ + H+ + H+ + H+

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    Sec.4 - Acid-base 22

    Which of the hydrogens shown in the following molecule would be most acidic?

    1)2)

    H

    H

    H

    H

    A) 1B) 2

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    Sec.4 - Acid-base 23

    OH OH1) 2) 3) CH3SH 4) CH3OHCl

    A) 1 > 2 > 3 > 4B) 4 > 3 > 2 > 1C) 4 > 2 > 3 > 1D) 1 > 4 > 3 > 2

    Order the following compounds from strongest to weakest acid

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    Sec.4 - Acid-base 24

    The concept of base strength can become confusing when we look at a series ofamines in which the base strength varies because of the relative stability of the

    free amine and its conjugate acid.

    R3N + H2O R3NH+ + HO

    Free amine (base) acid conjugate acid conjugate base

    From the above equation we can see that anything that stabilizes the free amine(base) relative to the conjugate acid makes the base less basic (shifts the

    equilibrium to the left).

    Anything that stabilizes the conjugate acid makes the base more basic and willshift the equilibrium to the right.

    Remember that amines are weak bases; there are many other stronger bases forexample RO is a much stronger base.

    Bases Strength of Amines

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    Sec.4 - Acid-base 25

    A) 1 > 2 > 3 > 4B) 4 > 3 > 1 > 2C) 4 > 2 > 3 > 1D) 1 > 4 > 3 > 2

    Order the following compounds from strongest to weakest base

    pKb = 3.3pKb = 9.37pKb = 9.85 pKb = 13

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    Sec.4 - Acid-base 26

    Order the bases from strongest to weakest.

    O

    NH2NH

    2

    N

    HNH

    1 2 3 4

    NH2

    Cl

    5

    A) 4 > 3 > 2 > 5 > 1B) 1 > 3 > 2 > 5 > 4C) 3 > 2 > 5 > 1 > 4D) 2 > 3 > 1 > 4 > 5

    E) 5 > 3 > 2 > 4 > 3

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    Sec.4 - Acid-base 27

    C

    H3C

    O

    NH2

    C

    H3C

    O

    NH2

    C

    H3C

    O

    NH2

    Amides

    +d+

    Very weak bases because of resonance ontoelectronegative oxygen atom.

    pkb = 13.37

    d-

    C

    O

    NH3H3C

    d+

    d-

    Destabilizing

    H+

    In fact the oxygen is protonated with a strong acid not the nitrogen

    C

    O

    NH2H3C

    H

    C

    O

    NHH3C

    H

    resonance stabilized

    pka = 0.6

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    Sec.4 - Acid-base 28

    Order the bases from strongest to weakest

    N H

    Cl

    N

    H

    NO

    H

    N N

    Cl

    pkb = 2.88 pkb = 5.67 pkb = 8.75 pkb = 11.45

    d+

    d+

    d-d+-

    N

    H

    H NO

    H

    H

    H2O

    d+

    d+d-

    N H

    d+d-

    Destabilizing Destabilizing

    A) 1 > 2 > 3 > 4B) 4 > 3 > 2 > 1C) 4 > 2 > 3 > 1D) 1 > 4 > 3 > 2

    1) 2) 3) 4)

    H2O H2O H2O

    + HO + HO + HO + HO

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    Sec.4 - Acid-base 29

    Predict which way the equilibrium is shifted in the following reactions.Also show the flow of electrons in the acid-base reaction

    A) LeftB) Right

    A) LeftB) Right

    A) LeftB) Right

    A) LeftB) Right

    CH3CH2OH

    HO CH3CH2O

    H

    O H

    HC C H N

    H3CH2C

    H3CH2C

    HC C N

    H3CH2C

    H3CH2C

    H

    H3C

    O

    CH

    HH

    CH3CH2

    O

    CH3CH3

    O

    O

    H

    O

    O

    OO

    + +

    + +

    ++

    + +H

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    Sec.4 - Acid-base 30

    Predict which way the equilibrium is shifted in the following reactions.Also show the flow of electrons in the acid-base reaction

    A) LeftB) Right

    A) LeftB) Right

    A) LeftB) Right

    O

    O

    H

    +

    +

    +

    O

    CCl3Cl3C

    HO

    CH3H3C

    OH

    CH3H3C

    O

    CCl3Cl3C

    +

    S

    S

    O

    O

    +SH

    S

    S

    O

    H3C O

    O

    O

    O

    H+ S

    O

    H3C OH

    O

    O

    O

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    Sec.4 - Acid-base 31

    If one equivalence of NaOH is added to a solution containing the compound whichproton would predominately be removed?

    If one equivalence of LiCH3 is added to a solution containing the compound whichproton would predominately be removed?

    1)

    2)

    OH

    OH

    OHCl

    Cl

    3)

    1)

    2)N N

    H

    H

    A) 1B) 2C) 3

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    Sec.4 - Acid-base 32

    Order the bases from strongest to weakest.

    1 2 3

    HN N

    NH2 A) 1 > 2 > 3B) 1 > 3 > 2C) 3 > 2 > 1

    D) 2 > 3 > 1

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    Sec.4 - Acid-base 33

    HN

    N

    NH2

    NH2

    NHN

    H3C C C

    A) B)

    A) B)

    1) 2) 3)

    A) CH3CH2OH B) CH3CH2OH2+

    A) 1 > 2 > 3B) 1 > 3 > 2C) 3 > 2 > 1D) 2 > 1 > 3

    Strongest base

    Strongest base

    Strongest base

    A) CH3CH2OH B) CH3CH2OStrongest base

    Strongest acid

    St t t k t b

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    Sec.4 - Acid-base 34

    1) CH3ONa 2) CH3SNa 3)CH3OH

    A) 1 > 2 > 3B) 1 > 3 > 2C) 3 > 2 > 1D) 2 > 1 > 3

    1) CH3SH 2) HI 3) CH3NH2

    1) H2SO4 2) C6H5OH 3) CH3CO2H

    A) 1 > 2 > 3B) 1 > 3 > 2C) 3 > 2 > 1D) 2 > 1 > 3

    A) 1 > 2 > 3B) 1 > 3 > 2

    C) 3 > 2 > 1D) 2 > 1 > 3

    Strongest to weakest base.

    Strongest to weakest acid.

    Strongest to weakest acid.

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    Sec 4 Acid base 35

    We are always looking at an equilibrium and which way it isshifted in a specific environment

    HA A + H+

    eqKRTG ln

    G = -ve value the reactionfavors the formation of productsand if smaller than 13 kJ mol-1the is said to go to completion(>99% converted)

    G = +ve value the reactionfavors the reactants and theformation of products isunfavorable.

    G = H - TS

    Exothermic reaction H is -veEndothermic reaction H is +ve

    We will come backto this when welook at reactions

    S is +ve - Change from a more ordered system to less a ordered systemS is -ve - Change from a less ordered system to a more ordered system