6.alkanes

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    Chapter 2: Alkanes

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    I. Classes of Organic Compounds

    Hydrocarbons (C & H only) Heteroatomic compounds

    aliphatic aromatic

    alkanes

    alkenes

    alkynes

    cyclic compounds

    alcohols

    ethers

    aldehydes

    ketones

    carboxylic acids

    esters

    amines

    amides

    C C

    C C

    C C

    R OH

    R O R'

    R C

    O

    H

    R C

    O

    R'

    R C

    O

    OH

    R CO

    OR'

    R C

    O

    NH2

    R NH2

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    II. Alkanes

    A. General formula: CnH2n + 2

    CH4 methane (natural gas, swamp gas)

    CH3CH3 (C2H6) ethane

    CH3CH2CH3 (C3H8) propane (LPG)

    CH3CH2CH2CH3(C4H10) butane

    75-85% CH4

    5-10% C2H6

    1-5% C3H8

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    II. Alkanes

    B. Isomers: normal and branched alkanes

    n-butane

    straight chain

    branched chain

    isobutane

    CH3 CH2 CH2 CH3

    CH3

    CH CH3

    CH3

    H C C C C H

    H H

    H H

    H H

    H H

    constitutional

    isomers

    C4H10

    butane lighters:

    5% n-butane95% isobutane

    Chem3D

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    II. Alkanes

    B. Isomers: normal and branched alkanes

    C5H12 n-pentane

    isopentane

    neopentane

    CH3 CH2 CH CH3

    CH3

    CH3 C

    CH3

    CH3

    CH3

    CH3 CH2 CH2 CH2 CH3

    C6H14 5 isomers

    C10H22 75 isomers

    C20H42 366,319 isomers

    obviously need system of nomenclature

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    II. Alkanes

    B. Isomers: normal and branched alkanes

    Question 2-1.Draw the constitutional isomers of the following. Click onthe arrow to check your answers.

    C6H14(5)

    C7H16(9)

    CheckAnswer

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    II. Alkanes

    B. Isomers: normal and branched alkanes

    Answer 2-1.Draw the constitutional isomers of the following. Click onthe arrow to check your answers.

    C6H14(5)

    C7H16(9)

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    II. Alkanes

    B. Isomers: normal and branched alkanes

    Types of carbons:

    CH3 CH

    CH3

    CH2 CH3

    methyl carbons

    methylene carbon

    methine carbon

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    II. Alkanes

    C. Structure-property relationships

    Intermolecular attractions: London (or van der Waals) forces (weak)b.p.

    CH4 -160C

    C2H6 -89

    C3H8 -42

    n-C4H10 -0.4n-C5H10 36

    Branching: lowers b.p.

    -0.4C -10.2C

    36C 28C 9C

    vs

    greater surface area

    for attraction

    Chem3D

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    III. IUPAC Nomenclature

    A. Parent chains: normal alkanes

    Parent names:

    CH4 methane n-C11H24 undecane

    CH3CH3 ethane n-C12H26 dodecane

    CH3CH2CH3 propane n-C13H28 tridecaneCH3(CH2)2CH3 butane n-C14H30 tetradecane

    CH3(CH2)3CH3 pentane

    CH3(CH2)4CH3 hexane n-C20H42 icosane

    n-C7H16 heptane n-C30H62 triacontane

    n-C8H18 octane

    n-C40H82 tetracontanen-C9H20 nonane

    n-C10H22 decane etc.

    systematic name: {side groups}parent chain{suffix}

    know

    to here

    (teens)

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    III. IUPAC Nomenclature

    B. Substituents: alkyl groups

    CH3

    CH3 CH2 CH2

    CH3CH2CH2CH2

    CH3 CH CH2

    CH3

    CH3 CH2

    CH3 CH CH3

    CH3CH2CHCH3

    CH3 C CH3

    CH3

    methyl group ethyl group

    propyl isopropyl

    butyl sec-butyl

    isobutyl tert-butyl

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    III. IUPAC Nomenclature

    C. IUPAC rules

    1. Find the longest straight chain = parent chain

    2. Number the parent chain in the direction that gives the lowest number

    to the substituents at the first point of difference.

    3. Two or more identical groups are indicated by di, tri, tetra, etc.

    CH3 CH2 CH2 CH2 CH

    CH2 CH3

    CH3 Longest chain is 7 (not 6).This is 3-methylheptane.

    .

    2,3,6-trimethylheptane (not 2,5,6-trimethyl

    heptane)

    2,2,6,6,7-pentamethyloctane (not

    2,3,3,7,7-pentamethyloctane)

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    4. Different groups are listed in alphabetical order (di, tri, tetra, etc.dont count; n,sec, tertdont count; iso does).

    5. If the numbering is the same in both directions, choose the

    numbering to follow the alphabetical order.

    III. IUPAC Nomenclature

    C. IUPAC rules

    6-ethyl-5-isopropyl-2,2-dimethyloctane

    5-ethyl-6-methyldecane

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    6. When two or more chains compete for the longest, the choice goes tothe one with the greater number of side groups.

    7. Complex side groups (usually > 4 carbons) are named systematicallya. start numbering at the carbon attached to the parent chain

    b. enclose name in parentheses

    c. first letter counts alphabetically, regardless of what it is

    III. IUPAC Nomenclature

    C. IUPAC rules

    2,4,6-trimethyl-5-propyloctane

    4-(1,2-dimethylpropyl)-3-(1-methylethyl)-

    decane

    1

    2

    3

    1

    2

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    Question 2-3.Name the following compounds. Click the arrow tocheck your answers.

    III. IUPAC Nomenclature

    C. IUPAC rules

    CheckAnswer

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    Answer 2-3.The names are here.

    III. IUPAC Nomenclature

    C. IUPAC rules

    6-ethyl-2,2,5,7-tetramethylnonane (not

    6,7-diethyl-2,2,5-trimethyloctane.Did we catchyou? :)

    8-sec-butyl-7-tert-butyl-4-isopropyldodecane

    (hyphenated words arent alphabetized).

    OR

    7-(2,2-dimethylethyl)-4-(1-methylethyl)-

    8-(2-methylpropyl)dodecane

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    8. Cycloalkanes

    III. IUPAC Nomenclature

    C. IUPAC rules

    CH2

    CH2H2C = cyclopropane

    general

    formula:

    CnH2n

    ethylcyclobutane

    1-isopropyl-3-methylcyclopentane

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    Question 2-4. Name the following cycloalkanes. Check your answersby clicking on the arrow.

    III. IUPAC Nomenclature

    C. IUPAC rules

    CheckAnswer

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    Answer 2-4. Name the following cycloalkanes. Check your answersby clicking on the arrow.

    III. IUPAC Nomenclature

    C. IUPAC rules

    1,1,2-trimethycyclohexane

    4-cyclopentyl-2,3-dimethylhexane

    1,2-dicyclopropylethane

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    IV. Chemical Properties of Alkanes

    A. Combustion

    C8H18 +

    Heats (enthalpies) of combustion: DHcomb

    More branchedisomers have lower DHcomb

    , are more stable.

    1307.5 kcal 1306.3 kcal 1304.6 kcal 1303.0 kcal~ ~ ~ ~

    ~~~~

    CO2+ H2O

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    IV. Chemical Properties of Alkanes

    B. Oxidation and reduction in organic molecules

    CH4 + Br2 CH3Br + HBr

    C HH

    H

    HC HH

    OH

    HC

    O

    H HC

    O

    H OHC

    O

    O

    oxidation

    more C-O bonds, fewer C-H bonds

    reduction

    fewer C-O bonds, more C-H bonds

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    IV. Chemical Properties of Alkanes

    B. Oxidation and reduction in organic molecules

    H3C CH3 H2C CH2 HC CH

    oxidation

    fewer C-H bonds

    reduction

    more C-H bonds

    H2C=CH2+ H2O2HOCH2CH2OH

    H2C=CH2+ H2OCH3CH2OH

    H2C=CH2+ H2CH3CH3

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    IV. Chemical Properties of Alkanes

    B. Assigning oxidation numbers:

    1. For each atom in a bond, assign a +1 to the more

    electropositive atom and a -1 to the more electronegative

    atom. (If the atoms are the same, each atom gets a 0.)

    2. Total each atom.

    C O

    Cl-1+1

    -1+1

    H

    -1

    -1

    +1

    +1

    C O

    Cl-1+1

    -1+1

    H

    -1

    -1

    +1

    +1 Oxidation number of carbon is

    +1 +1 +1 -1 = +2

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    IV. Chemical Properties of Alkanes

    Question 2-5. Determine oxidation numbers for the carbons

    in each of the following molecules. Click on the arrow to check

    your answers.

    CheckAnswer

    H C N

    C

    H

    H

    Br

    C

    O

    O H12

    C

    H

    H

    OH

    Cl

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    IV. Chemical Properties of Alkanes

    Answer 2-5. Determine oxidation numbers for the carbons

    in each of the following molecules. Click on the arrow to check

    your answers.

    H C N

    C

    H

    H

    Br

    C

    O

    O H12

    C

    H

    H

    OH

    Cl

    C = +2

    C1= +3; C2= -1

    C = 0

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    IV. Chemical Properties of Alkanes

    Question 2-6. Determine whether the following reactions will

    be oxidation, reduction, or neither. Check your answers by clicking

    on the arrow.

    CheckAnswer

    H2C CH2 + Br2 H2C CH2

    Br Br

    H2C CH2 + H2O C

    H

    H

    H

    C

    H

    H

    OH

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    IV. Chemical Properties of Alkanes

    Answer 2-6. Determine whether the following reactions will

    be oxidation, reduction, or neither. Check your answers by clicking

    on the arrow.

    CheckAnswer

    H2C CH2 + Br2 H2C CH2

    Br Br

    H2C CH2 + H2O C

    H

    H

    H

    C

    H

    H

    OH

    Oxidation: Each carbon

    changes from a -2 to a -1.

    Neither. One carbon changes from a -2 to a -3 (gets

    reduced), but the other carbon goes from a -2 to a -1

    (gets oxidized.) No net change.