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matthew-crowley
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Alternating Current
voltage
time0
maximum positive voltage (the peak voltage)
maximum negative voltage (peak voltage)
Direction of current and size constantly change. Mains frequency is 50 Hz
Alternating Current 2
Voltage(V)
Time (s)
0
peak voltage
effective voltage
The quoted value ( rms ) or Effective voltage of an a.c. supply is the same as the steady d.c. voltage which would produce the same heating effect in a resistance wire.
The quoted value of the mains voltage in the UK is 230 V. The peak voltage is 325 V.
Effective voltage is measured with a voltmeter. Peak voltage is measured with an oscilloscope.
Alternating Current 3The quoted value of an a.c. supply is also known as the r.m.s. value (root mean square). The peak value is √2 larger than this r.m.s. value. This applies to both voltage and current.
peaksmrpeaksmr IIandVV2
1
2
1......
Voltage
Time
peak value
r.m.s value
Alternating Current 4
2peak
rms
II
AI rms 83.2
Peak and r.m.s. values: Example The period of a sinusoidally varying current is 0.005 s. The peak value of the current is 4·0 A.
Calculate a) the frequencyb) the root mean square value of the current.
Frequency = 1 / Period
Frequency = 1 / 0.005
Frequency = 200 Hz 2
4rmsI
Calculation of frequency
timebase
(s cm –1 )
y input0.02
Find the time for one wave.
This is the period.
frequency = 1/period
ExampleTime base = 0.02 s cm-1
Period = time base setting x no of boxes for 1 cycle
Period = 0.002 x 4 = 0.08 s
Frequency = 1 / period
Frequency = 1 / 0.08 = 12.5 Hz.