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8/6/2019 Bacb2010
1/7
2009/2010
7 :: :
3
:
))131:I- )1,75(
II - )2,50(2: RLC)4,75(3: )4(
)7( )7(
1)4,25( I:)1,75(
:
1 : *E * R1R2.. *
E : R1R2. ER1. R2
R2 d = 2,8 cm 21.1 .1.2 E2. R2d = 3,5 cm2.1 2.2
0,50,25
0,25
0,25
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:
0,5
0,5
0,5
0,75
0,75
0,75
0,5
0,25
0,25
2.3 ER1R2 R2
R2 ..
)II:)2,50 200418.103 MW .
.
235 .1 .238 235
: ZrCe 235eynxZrCenU 01
10
9140
14258
10
23592 .. ++++
1.11.2 xy .. 235 Mev 1.3235 . 235Mev1g 1.4
.
235)u(0,000551,00866235,04394141,9093190,90565
1u = 1,66.10-27 Kg , 1eV = 1,6.10-19J , C = 3.108 m/s
, M(U) = 235 g/mol, 1u = 931,5MeV/C2 mol-1 :NA = 6,02 10
23
2-)4,75( RLC RLC
3
RLC I1.
t = 0 K1K2 0 Uc 4
. Uc -1.11.2 :Uc = A(1-e-t) A .1.3 RC.1.4 R = 40.
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0,75
0,5
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0,5
1
0,5
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0,25
0,75
0,5
2. RLC..1K2 K1
5 Uc .T 2.1.LC T 2.22.3 R .3.
K1 K2 0 2 t = 0
G U = Ki.3.1- Uc .3.2 K .
3.3 6 Uc(t) . Uc(t).
3-)4(: t= 0s
= 0,91 g/cm3 m = 35gV = 33,5 cm3 :f = K.v
tv = f(t).)7(
0z S .
1 2-
:dv/dt = A-B.v AB.
3 A = 1,29 m/s2g = 10 m/s2.4 B .5- AB
:vi+1 = vi + aitai = A-B.vi :76543210i
0 ,560,480,400,320,240,160,080ti (s)0,1690,1690,1670,1650,1430,102vi (m/s)0,000,000,020,030,200,51ai =dvi/dt (m/s
2)
t1552
53 .
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0,251
0,5
0,5
0,25
0,50,75
0,5
0,75
0,5
1
0,5
:
)7: ( C6H8O6 C .
C500C1000. ..
:1234 .1 C
V = 100ml x8:
1.1 x.1.2 t = 100min.1.3 2. C6H8O6/C6H7O6
-
0,5g 200 ml pH pH = 3
2.1 2.22.3 2.4 .3 C500
C500 100ml VA = 10 ml CB = 2.10
-2mol/L
VB = 14,4ml . 3.13.2 C500. C500 mg 3.3
C500.4.
170gV = 82 ml . :
:C6H8O6 + I2 C6H6O6 + 2I-+ 2H
+
2S2O32-
+ I2 S4O62-
+ 2I-
V1 = 10ml V2 = 10ml
C2 = 5,3 10-3
mol/L C = 5.10-3 mol/L VE= 8,7ml
4.1- 10 ml .
4.2- . :M(C6H8O6) = 176 g.mol-1
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)1,75( :
0,5 1.1 0,25 N = 50 KHz 2 .10,25 = 0,7 cm 2.1 0,25 V = 350 m/s 2.2 0,5 V = 4 N = 4V=1400 m/s 2.3
)2,5( : 0,5 1.1 0,5 y = 6 x = 3 1.2
0,75 E = -194,0873 Mev 1.3 0,75 E = -4,972 Mevm = 814,5 g 1.4
)4,75( RLC :0,75 RC. dUc/dt +Uc =E 1.1 0,5 = 1/RCA = E 1.2
0,25 RC = = 0,75 ms 1.3 0,25 C = 18,75F 1.4 0,25 T = 7,45 ms 2.1 0,25 L = 75mH 2.2 0,5 Wth = -225.10
-6J 2.3
0,75 dUc2/dt
2+ (R-K)/L dUc/dt + Uc/LC = 0 3.1
0,5 R =K 3.2 0,75 Uc(t) = 5.Cos(843t) 3.3
)4( : 0,5 11 A =( m-v)/mB = k/m 2
0,5 A = 1,29 ms-2
3
0,5 vl = 0,17 m/sB = 7,58 s-1
4
0,25 t = 0 ,08s 5.1 0,75 V0 = 0m/sa0 = 1,29 ms
v32- = 0,16m/sa3 = 0,08 ms-2
5.2 0 ,5 v =f(t)
5.3
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)7(
0,25 v = dx /Vdt 1.1 1 v = 1,25 10
-3mmol L
-1min
-1 1.2 0,5 t1/2 = 75 min. 1.3 0,5 C6H8O6 +H2O C6H7O6
-+H3O
+ 2.1
0,25 C = 14,2 mmol/L 2.2 0,5 = 10
-pH/C =0,07 < 1 2.3
0,75 KA = (10-pH
)2/(C-10
-pH) = 75,75.10
-6 2.4
0,5 C6H8O6 +HO- C6H7O6
-+H2O 3.1
0,75 n = 28,8 10-4
mol 3.2 0,5 m = 500mg C500 3.3 1 n = C2V2 ( CVE/2) = 3,125.10
-5mol 4.1
0,5 m = M(C6H8O6). N. 8,2 = 45 mg 4.2
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