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By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

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Page 1: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

By: Kyle Matz, Grant Culbreth, and Matt

DoehringPd. 5&6

Page 2: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

What is a conversion factor?

A number used to multiply or divide

another number to change one system of units to another.

Page 3: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

How to do a conversion factor

When starting a conversion factor put the given value over one. Then multiply that by the multiplier of the new unit over the multiplier of the old unit. Make sure to put the smaller number with the larger

unit and visa versa.

Page 4: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

An example of a conversion factor

Convert 5.27km to Centimeters.

5.27km X 103 cm 1 10-2 km

Don’t Forget about Significant Figures!!!!!!5.27 X 105 cmOld unit cancels

out

Old unit cancels out

= 527000 cm

Page 5: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Significant Figures How you determine Significant figures?

If the decimal point is Present, count from left to right until you are at the first non-zero number and anything after that is your sig fig. If the decimal point is Absent, count from right to left until you are at the first non-zero number and anything after that is your sig fig.

Page 6: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Determine the sig figs in – 003.24

Start on the pacific because the decimal is PRESENT.

Count left to right until first non-zero and there are 3 significant figures in this number.

003.24

Page 7: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Rounding Sig Figs Determine the sig figs in each of the

numbers. 3.24 X 2.365

3.24-3 sig figs 2.365-4 sig figs The answer in multiplication should be

rounded to the same number of sig figs as the number that has the least sig figs.

In this case the number would be rounded to 3 sig figs.

3.24 X 2.365= 7.66206 rounded to 3 sig figs would give the final answer of 7.66

Page 8: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Example usage of the scientific method

PROBLEMNo water is coming out of the hose.

HYPOTHESIS The water is not on.

EXPERIMENT

Look to see if the water is on.

CONCLUSIONFrom my experiment I have concluded that the water was on, thus it is not the cause of the water not working.

If the problem is not solved, you must create a new hypothesis and experiment with it.

There is a kink in the hose.

Check along the length of the hose for kinks.

From my experiment I have concluded that there were kinks in the hose. This is why the water was not flowing through the hose.

Your experiment is complete and your problem is solved.

Page 9: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Does the scientific method detail a scientific law or a

scientific theory?

It defines a theory. There is no need to experiment with

something that is already a law because it has already been

proven.

Page 10: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Variables

Independent Variables are the variables that you control.

Dependent variables are the variables that depend on the independent variables.

Page 11: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Mass (g)

Time (s)

Dependent Variable (depends on time)

Independent Variable (you control)

Page 12: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Mass (g)

Time (s)

Put the dependent variable on the y axis.

Put the independent variable on the x axis.

Page 13: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Time vs Distance

Since the line is straight the relationship is “linear”.

The equation is y=mx+b

Time (s)

Distance (m)

Page 14: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Time vs Distance

Since the line curves upward the relationship is “exponential”.

The equation is ax^2+bx+c.

Time (s)

Distance (m)

Page 15: By: Kyle Matz, Grant Culbreth, and Matt Doehring Pd. 5&6

Time vs Distance

Distance (m)

Time (s)

Since the line curves downward from the top the relationship is an “inverse”.

The equation is y=a/x