19
Chapter 13 Chemical Equilibrium Chemical Equilibrium

Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

  • View
    219

  • Download
    2

Embed Size (px)

Citation preview

Page 1: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Chapter 13

Chemical EquilibriumChemical Equilibrium

Page 2: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–2

Figure 13.1: A molecular representation of the reaction 2NO2(g) N2O4(g) over time in a closed

vessel.

Page 3: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–3

Figure 13.2: The changes in concentrations with time for the reaction H2O(g) + CO(g) H2(g) + CO2(g)

when equimolar quantities of H2O(g) and CO(g) are mixed.

Page 4: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–4

Figure 13.3: (a) H2O and CO are mixed in equal numbers and begin to react (b) to form CO2 and H2. After time has

passed, equilibrium is reached (c) and the numbers of reactant and product molecules then remain

constant over time (d).

Page 5: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–5

Figure 13.4: The changes with time in the rates of forward and reverse reactions for H2O(g) + CO(g)H2(g) + CO2(g) when equimolar quantities of H2O(g) and CO(g) are mixed. The rates do not change in the same

way with time because the forward reaction has a much larger rate constant than the reverse reaction.

Page 6: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–6

Figure 13.5: A concentration profile for the reaction N2(g) + 3H2(g)2NH3(g) when only

N2(g) and H2(g) are mixed initially.

Page 7: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–7

Page 8: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–8

Figure 13.6: The position of the equilibrium CaCO3(s) CaO(s) + CO2(g) does not depend on the amounts of CaCO3(s) and

CaO(s) present.

Page 9: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–9

Hydrated copper (II) sulfate on the left. Water applied to anhydrous copper (II) sulfate, on

the right, forms the hydrated compound.

Page 10: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Figure 13.7: (a) A physical analogy illustrating the difference between thermodynamic and kinetic stabilities. (b) The reactants H2 and O2 have a strong tendency to form H2O.

Page 11: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–11

Apollo II lunar landing module at Tranquility Base, 1969.

Page 12: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–12

Procedure for Solving Equilibrium Problems

Page 13: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–13

Page 14: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–14

Figure 13.8: (a) The initial equilibrium mixture of N2, H2, and NH3. (b) Addition of N2.(c) The new equilibrium position for the system containing more N2 (due to addition of N2),

less H2, and more NH3 than in (a).

Page 15: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–15

Figure 13.9: (a) A mixture of NH3(g), N2(g), and H2(g) at equilibrium. (b) The volume is suddenly decreased. (c) The new equilibrium position for

the system containing more NH3 and less N2 and H2. The reaction N2(g) + 3H2(g) 2NH3(g) shifts to the right (toward the side with

fewer molecules) when the container volume is decreased.

Page 16: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Figure 13.10: (a) Brown NO2(g) and colorless N2O4(g) in equilibrium in a syringe. (b) The volume is suddenly decreased, giving a greater concentration of both N2O4 and NO2 (indicated by the darker brown color). (c) A few seconds after the sudden volume decrease, the color is much lighter brown as the equilibrium shifts the brown NO2(g) to colorless N2O4(g) as predicted by Le Châtelier’s principle, since in the equilibrium2NO2(g) ∆ N2O4(g)the product side has the smaller number of molecules.

Page 17: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–17

Shifting the N2O4(g)    2NO2(g) equilibrium by changing the temperature. (a) At 100ºC the flask is definitely reddish

brown due to a large amount of NO2 present. (b) At 0ºC the equilibrium is shifted toward colorless

N2O4(g).

Page 18: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–18

Page 19: Chapter 13 Chemical Equilibrium. Copyright © Houghton Mifflin Company. All rights reserved.13–2 Figure 13.1: A molecular representation of the reaction

Copyright © Houghton Mifflin Company. All rights reserved. 13–19