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EML 4230 Introduction to Composite Materials
Chapter 2 Macromechanical Analysis of a LaminaFailure Theories
Dr. Autar KawDepartment of Mechanical Engineering
University of South Florida, Tampa, FL 33620
Tsai-Wu Failure Theory
Tsai-Wu applied the failure theory to a lamina in plane stress. A lamina is considered to be failed if
Is violated. This failure theory is more general than the Tsai-Hill failure theory because it distinguishes between the compressive and tensile strengths of a lamina.
The components H1 – H66 of the failure theory are found using the five strength parameters of a unidirectional lamina.
H1σ1+H2σ2+H6τ12+H11
+H22
+H66
+2H12σ1σ2< 1
12 211221266
2222
21111262211 HHHHHHH
Components of Tsai-Wu Fail
0,0, 12211 ultT to a unidirectional lamina, the lamina will fail.
Equation(2.152) reduces to
.=σH+σH ultT
ultT 1
211111
a) Apply
0,0, 12211 ultC to a unidirectional lamina, the lamina will fail.
Equation(2.152) reduces to
.=σH+σH ultC
ultC 1
211111
b) Apply
From Equations (2.153) and (2.154),
,σσ
=Hult
Cult
T11
111
,σσ
=Hult
Cult
T11
111
Components of Tsai-Wu Fail
0,,0 12221 ultT to a unidirectional lamina, the lamina will fail.
Equation(2.152) reduces to
.=σH+σH ultT
ultT 1
222222
c) Apply
0,,0 12221 ultC to a unidirectional lamina, the lamina will fail.
Equation(2.152) reduces to
.=σH+σH ultC
ultC 1
222222
d) Apply
From Equations (2.157) and (2.158),
,σσ
=Hult
Cult
T22
211
,σσ
=Hult
Cult
T22
221
Components of Tsai-Wu Fail
ult121221 ,0,0 to a unidirectional lamina, the lamina will fail. Equation
(2.152) reduces to .=H+H ultult 12
1266126
e) Apply
to a unidirectional lamina, the lamina will fail. Equation
(2.152) reduces to
.=H+H ultult 121266126
f) Apply
From Equations (2.157) and (2.158),
,=H 06
,=H
ult
212
66
1
ult121221 ,0,0
Determination of
12 211221266
2222
21111262211 HHHHHHH
Apply equal tensile loads along the two material axes in a unidirectional composite. If
,=τ= σ σ=σ xyyx 0 is the load at which the lamina fails, then
.=σH+H+Hσ+H+H 12 212221121
The solution of the Equation (2.165) gives
.σ)H+H()σH+H-(σ
H 2221121212 1
2
1
Determination of
H1σ1+H2σ2+H6τ12+H11 21 +H22 2
2 +H66 212 +2H12σ1σ2< 1
Take a 450 lamina under uniaxial tensionσ x. The stress σ x at failure is noted.
If this stress is 0σ x then using Equation (2.94), the local stresses at failure are
21
22
212
Substituting the above local stresses in Equation (2.152),
.=H+H+H+Hσ+
σH+H 12
4212662211
2
21
.H+H+Hσ
H + H
σ=H 662211
21
2122
12
Empirical Models of
)σ(H
Tult1212
2
1
)σ()σ(H
ultC
ultT
1112 2
1
)σ ()σ ()σ ()σ( H
ultC
ultT
ultC
ultT
221112
1
2
1
as per Tsai-Hill failure theory8,
as per Hoffman criterion10,
as per Mises-Hencky criterion11.
Example 2.19
Find the maximum value of
0S if a stress
3S- = 2S, = yx and 4S = xy
are applied to a 600 lamina of Graphite/Epoxy. Use Tsai-Wu failure theory. Use the properties of a unidirectional Graphite/Epoxy lamina from Table 2.1.
Example 2.19
Using Equation (2.94), the stresses in the local axes are
S.
.-
.-
.
=
S
S-
S
.-..-
.-..
...
=
τ
σ
σ
1041650
1027140
1017140
4
3
2
500004330043300
866002500075000
866007500025000
1
1
1
12
2
1
Example 2.19
H
12=
,Pa H -1661 0
101500
1
101500
1
,Pa .H -- 18662 100932
10246
1
1040
1
,Pa H -16 0
,Pa.)) ( (
H -- 2166622 1001621
102461040
1
,Pa.))( (
H -- 2196611 1044444
101500101500
1
,Pa.)(
H -- 216
6 266 10162621068
1
.Pa.. ..-H ---- 2181619 2
1
12 1036031001621104444450
Example 2.19
Substituting these values in Equation (2.152), we obtain S.-.+S. - 714210093271410 8
219 7141104444416540 S..+S.-+
216216 1654101626271421001621 S..+S.- .+ -
,S.-S..-+ - 1714271411036032 18
or
MPa.S< 3922
Example 2.19
If one uses the other two empirical criteria for H12 as per Equation (2.171), one obtains
,)σ(
HMPa for.S<ult
T 21
122
14922
.)σ()σ(
HMPa for.S<ult
Cult
T11
121
2
14922
Summarizing the four failure theories for the same stress-state, the value of S obtained is
S = 16.33 (Maximum Stress failure theory), = 16.33 (Maximum Strain failure theory), = 10.94 (Tsai-Hill failure theory), = 16.06 (Modified Tsai-Hill failure theory), = 22.39 (Tsai-Wu failure theory).