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CHAPTER 9 NOTES KONICHEK

CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

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Page 1: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

CHAPTER 9 NOTES

KONICHEK

Page 2: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

• I. Impulse and change in momentum• A. Newton wrote his 3 laws in terms of momentum- quantity of

motion• B. Momentum is the product of the mass and the velocity of an

object.• 1. symbol is p, so p=mv vector quantity• a. units: Kgm/s• C. If a single body has no net forces acting on it, its momentum is

conserved.• D. Impulse theorem- Ft=p Newton’s 2nd law can be derived

from this• 1. (F)Δt= M(V2 – V1)• 2. Often the force isn’t constant during exertion. Therefore

average force is used in the equation

Page 3: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

• 3. A large change in momentum occurs when there is a large impulse force

• a. a large impulse can result can result from a large force acting over a short time

• 1. a car crash-The air bags increase the contact time against the dash, so the impulse force isn’t as great.

Page 4: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

• SAMPLE PROBLEM- A BASEBALL OF MASS .14Kg moving at 35m/s

• a. find the momentum of the baseball• p=mv- p= (.14Kg)35m/s=4.9Kgm/s• b. find the velocity at which a bowling ball

mass of 7.26Kg would have to equal the momentum of the baseball

• 4.9Kgm/s=7.26KgVbb =.67m/s• •

Page 5: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

ANOTHER PROBLEM

• An engine of the orbital maneuvering system (OMS) on a space shuttle exerts a force of 30000 N j for 4.00 s, exhausting a negligible mass of fuel relative to the 95,000 kg mass of the shuttle. (a) What is the impulse of the force for this 4.00 s?

• (b) What is the shuttle's change in momentum from this impulse? (c) What is the shuttle's change in velocity from this impulse? (d) Why can't we find the resulting change in kinetic energy of the shuttle?

•  

Page 6: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

• Answer to Example Impulse Problems•  • a. Impulse = Ft = 30000(4) = 120000 N-s

b. change in momentum = impulse(FΔt) = 120000 N-s

c. FΔt = m∆v

120000 = (95000)∆v

∆v = 1.26 m/s

d. We do not know the initial velocity.•  

Page 7: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

SAMPLE PROBLEM- IMPULSE AND MOMENTUM

• A .02Kg golf ball strikes a guy in the head with a velocity of 90m/s. The ball strikes and bounce off in .06s. Find the impulse forces off their head.

• FΔt= MΔV F= M( V2-V1)/Δt

• F= .2Kg(0-90m/s)/.06s= -300N

• 1. like getting hit with a 13 pound club in the head

Page 8: CHAPTER 9 NOTES KONICHEK. I. Impulse and change in momentum A. Newton wrote his 3 laws in terms of momentum- quantity of motion B. Momentum is the product

• II. ANGULAR MOMENTUM• A. the quantity of angular motion that is similar

to linear momentum• 1. No torque. The angular momentum is

constant• 2. angular momentum is the product of the

mass , velocity, and the distance from the center of rotaion, and the distance perpendicular to that distance.

• a. IiI= Iff I= angular momentum, is angular velocity