Do an Tot Ngiep Nguyen Van Cuong 5-1-2016 2

8/15/2019 Do an Tot Ngiep Nguyen Van Cuong 5-1-2016 2

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TRƯỜNG ĐẠI HỌC BÁCH KHOA HÀ NỘI

VIỆN ĐIỆN TỬ - VIỄN THÔNG

ĐỒ ÁN

TỐT NGHIỆP ĐẠI HỌC

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TRƯỜNG ĐẠI HỌC BÁCH KHOA HÀ NỘI

VIỆN ĐIỆN TỬ - VIỄN THÔNG

ĐỒ ÁN

TỐT NGHIỆP ĐẠI HỌC

Đề tài:

PHÁT TRIỂN ỨNG DỤNG ĐO STRSS

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11/77




12/77


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14/77


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16/77


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17/77


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18/77


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19/77


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H}#$ oM Du#+ tL# $i)5 PPG

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H}#$ o T$5 tL# $i)5 PPG @€ .r#+ YD %à PD ;P$=t=.xtx(t=>

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28/77


H}#$ o T$5 tL# $i)5 PPG t (ExE 8i)# t$=ui



29/77


oo ‚5E# $) +iE @tx@@ %à PPG

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&1 5 4(c& b 4|: w &1b8

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:(M 2% :5 4'&1 :6`&1 E>F :6 :6h 1(F M) :z 4_ e%M :u&1 :&6 6 :66) q&

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30/77


H}#$ o CK# 1ƒ#+ $) t$•# Ai#$ t' ($z %à 1iB# t$i #$s3 ti „MM…

T?&1 M(& :Z& k] p6ˆ F :& 6(c> (D& :6(& &6rp :(M :Xp :?>&1 6 D> :?&1

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M(& :Z& k] :6p 2% M(& :Z& k] FQ e% p6S^&1 p65p 65 :(& X 2% &6F&6 19& 4h

45&6 1(5 6: 4'&1 F 6c :6Z& (&6 :b 6 2% e% ^ kw 4h 45&6 1(5 M 4' k:?•kk

F & &1Sm( §**¨8

oo C0( #+$i (Q5 %ề 80#$ +i0 @tx@@ .'E %à= PPG/6S^&1 p65p 45&6 1(5 k:?•kk bF :?& /6:pe•:6kM1?FM J//GQ bF :?& kb

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kF&1 Y 2% L•• &†6>&1) C6>&1†A&1 U&(2•?k(:) H%& £>] §!¨) k:?•kk 4( ‡M

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p6[& :6 :& 6(c> :?&1 M(& :6m( 1(F& 2% M(& :Z& k]8 C5 :6`&1 k] Sớ eSP&1 4SP

4 Xp 4D& 1=M7

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31/77


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32/77


H}#$ ov H}#$ ^wt 82 3$W#+ #J#+ F,#+ t=#+ iề# t•# @ Y‡ %à H‡

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T?&1 M`( :?Sm&1 :6S 1(&) 6: 4'&1 F :6Z& (&6 1(F M e%M LŠ\HŠ 1(M8

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33/77


@( k:?•kk 4]( 2ớ( k 6a• & &1Sm( 2% 4SF ?F 5 p6S^&1 p65p 4 :?&1 :6b :D

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34/77


CHghNG THIeT e HỆ THỐNG ĐÁNH GIÁ STRSS

Tz &6l&1 ef :6>D: :?&1 /6Z& I) 4= 5& n[ b&1 6c :6]&1 45&6 1(5 k:?•kk8 Hc

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oM Gii t$i)5 tW#+ 45E#

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38*8



35/77


H}#$ oM ‚56 t}#$ 80#$ +i0 @tx@@

o T$5 . Fi)5 t (ExE 8i)# t$=ui

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36/77


W8 ;5> :ớ( :ª&6 M68

!8 ;5> :?w 2 :[M &6ª p6(8

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MF M68 CFM•?F kƒ :6• @( kb (D& 4ˆ( &% }&1 56 45&6 1(5 M 4' p6& n)

6 n) 6p :6 6( 5&6 k5&1 4( E>F M5> 1(%> n 2% &16‡ n8 Vd y :6>X: &%

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4SP :&6 &6S kF>7



37/77


b ( t )=∑i=0

m−1

∑ j=0

n−1

a(i , j)

m∗n (1.1)

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38/77


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6`&1 Z& :6(D:8

o T$5wt t=0# Œ€ FooM Y( #$i5 %à Fà s#

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&6(g> n>&18

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Sớ( &17 Y ´ „ µ & 2ớ( Y7 &6 E>F& k5:) „7 &6 1] 2% & e% &6(g>8

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39/77


M(& :Z& k] F 2% 1(l e( :& 6(c> :?&1 M(& :Z& k] Z& :6(D: 2ớ( M 46 k{ &18

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f ( t )= 1W t ∑k =0

W t −1

ak PPG [ t +k ] (1.3)

//GJ:Q 7 CSm&1 4' //G F :: 5 4(hM &6 :?&1 :z&1 6>&1 6d&68

ŽJ:Q 7 ĐZ> ?F F ' e98

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f [1 ]=1∗b [1 ]+2∗b [2 ]+3∗b [3 ]+4∗b [4 ]+3∗b [5 ]+2∗b [6 ]+1∗b [7 ]

7

(3.11)

V(c ( 6>h& {F kˆ :?>&1 d&6 _ 6(> %( ] 4r&6 : &6}M e%M Mr& 5 (D&

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:?&1 Hd&6 38*i8



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( f )=∑n=0

N −1

X (n ) e−i2πfn(3.1)

DFT x¿

P ( f )= 1 N |∑n=0

N −1

X (n)e−i2πfk / L|2

(3.2)

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P M (f )= 1

MU |∑n=0 M −1

X (n ) w (n)e−i2πfn|2

i=0,1… , L−1(3.3)



44/77


U = 1

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n=0

M −1

w2(n)(3.4)

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VLŠ) Mk+ 4' (D& :6(& &6rp :(M w :Z& k] :6p :?&1 6&1 :Z& k] 08003†

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:® k] _ 1(5 :?r :?&1 45&6 1(5 [& }&1 6: 4'&1 1(F M 2% p6_ 1(F M) D> :]

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5%n v4 PWng th+c Hmiền tần s(K

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Do an Tot Ngiep Nguyen Van Cuong 5-1-2016 2