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Proiect TTM – Cargoplan Utilizand datele individuale si mersul de calcul de mai jos intocmiti cargoplanul initial pentru cargoul de 8700 tdw. Obtineti toate datele si informatiile necesare despre marfa din Thomas’ Stowage (si oricare alt mijloc informational). Prezentati caracteristicile marfii, tipul de ambalare, modul cum se pregateste nava pentru acel tip de marfa, conditiile de manipulare si transport, avarii care pot aparea la marfa (daca este cazul) in timpul manipularii si in timpul transportului, etc. Loading condition: SF = .....0.95......, Tip marfa cotton Dead sea potash, Tip incarcare : magazine 1,3,4 inf bulk On the displacement sheet we calculate it and its centre of gravity: D = ......9620........... T LCG = ....54.73....... M VCG = .....5.62...... M At the displacement of .......10078....... tonnes the following values are determinated by linear interpolation from Chapter XV – HYDROSTATIC PARTICULARS: Corresponding draught, d 0 = ....6.55..... M Transverse metacentre height, TKM = .....7.320.... M Longitudinal centre of buoyancy, LCB = ....62.066...... M Longitudinal centre of flotation, LCF = ....59.906...... M Moment to change trim one cm, MCT = ....118.8...... T ∙ M

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Proiect TTM Cargoplan

Utilizand datele individuale si mersul de calcul de mai jos intocmiti cargoplanul initial pentru cargoul de 8700 tdw.

Obtineti toate datele si informatiile necesare despre marfa din Thomas Stowage (si oricare alt mijloc informational). Prezentati caracteristicile marfii, tipul de ambalare, modul cum se pregateste nava pentru acel tip de marfa, conditiile de manipulare si transport, avarii care pot aparea la marfa (daca este cazul) in timpul manipularii si in timpul transportului, etc.

Loading condition: SF = .....0.95......, Tip marfa cotton Dead sea potash,Tip incarcare : magazine 1,3,4 inf bulkOn the displacement sheet we calculate it and its centre of gravity:

D = ......9620........... T

LCG = ....54.73....... M

VCG = .....5.62...... M

At the displacement of .......10078....... tonnes the following values are determinated by linear interpolation from Chapter XV HYDROSTATIC PARTICULARS:

Corresponding draught, d0 = ....6.55..... M Transverse metacentre height, TKM = .....7.320.... M

Longitudinal centre of buoyancy, LCB = ....62.066...... M

Longitudinal centre of flotation, LCF = ....59.906...... M

Moment to change trim one cm, MCT = ....118.8...... T M

Trimming lever the distance between LCB and LCG; trimming lever = LCB LCG.

When LCG is aft of LCB the trim will be by the stern.

When LCG is forward of LCB the trim will be by the head.

Trimming lever = ... 7.336...... M

Trim, TR

=5.9404Draught on aft perpendicular, daft:

=9.491053 M

=9.491053MDraught on fore perpendicular, dfore:

dfore = daft TR [M]

dfore = ... 2.1550.. M

METACENTRIC HEIGHT (SOLID), GMSOLID

GMSOLID = TKM VCG [M]

GMSOLID = ..... 1.7... M

CORRECTED METACENTRIC HEIGHT (FLUID), GMFLUID

GMFLUID = GMSOLID CORRGM [M], where:

CORRGM is the free surfaces correction

CORRGM = TOTAL FSMGM/D [M]

TOTAL FSMGM = ..1132....T M

CORRGM = .. 0.1176.... M

GMFLUID = . 1.5823..... M

KGCORR = VCG + CORRGM [M]KGCORR = ...5.7376 M

To comply with IMO Resolution A.749 (18), the Master must be sure that the vertical centre of gravity, increased with the free surfaces correction, is less than the permissible KG value (see Chapter XII).KGPERMISSIBLE = ....7.17... M

KGCORR < KGPERMISSIBLE ; 5.7376... M < ...7.17... M

From Chapter XIX IMO WEATHER CRITERION by double linear interpolation for corresponding draught

d0 = ..6.55... M and KGCORR = ...5.7376... M, K = ..5.340.... > 1.

To calculate the righting levers curve the following formula is to be used:

GZSOLID = KN VCG SIN GZLICHID = GZSOLID - CORRGZ ,

CORRGZ = TOTAL FSMGZ / D, where:

KN values will be found by interpolation from Chapter XVI TABULATION OF THE CROSS CURVES OF STABILITY, KN.

CORRGZ is the free surfaces correction for GZ levers from Chapter XIII FREE SURFACES MOMENT.

sin VCG sin KNCORR GZGZ FLUID

100.1740,981,300,020,30

200.3421,922,610,030,65

300.5002,813,810,040,96

400.6433,614,870,041,22

500.7664,315,750,041,41

600.8664,876,330,031,43

700.9405,286,630,031,32

800.9855,546,700,021,14

901.0005,626,550,020,91

The criteria according to IMO Resolution A.749 (18) are evaluated as follows: Actual Value Minimum Required Value

Area under curve up to 30 ....0.25...... M radian 0.055 M radian

Area under curve up to 40 ....0.44...... M radian 0.090 M radian Area between 30 and 40 ....0.19..... M radian 0.030 M radian GZ corresponding to 30 ....0.96..... M 0.200 M

Angle corresponding to GZmax .....60... 25

Initial metacentric height (fluid) .......1.58. M 0.150 M

Weather Criterion ...5.340..... > 1.000

INITIAL METACENTRIC HEIGHT

EFFECTIVE KG

IMO WEATHER CRITERION

THE RIGHTING LEVERS CURVE (GZ CURVE)

STABILITY EVALUATION

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