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  • 1. CALCULO DE MATRICES DE RIGIDEZ DE CADA MIEMBRODatosBarr XN YN XF YF L x y

    1 0 10 0 0 ### 0 -12 0 10 10 0 ### 0.707 -0.7073 0 10 10 10 ### 1 04 0 0 10 0 ### 1 05 0 0 10 10 ### 0.707 0.7076 10 0 10 10 ### 0 1

  • 1 2 3 4 5 6 7 80 0 0 0 0 0 0 0 1

    Barra 1 0 0.1 0 -0.1 0 0 0 0 2x 0.000 0 0 0 0 0 0 0 0 3y ### 1 2 3 4 0 -0.1 0 0.1 0 0 0 0 4L= ### 0 0 0 0 1 0 0 0 0 0 0 0 0 5

    0 ### 0 ### 2 0 0 0 0 0 0 0 0 60 0 0 0 3 0 0 0 0 0 0 0 0 70 ### 0 ### 4 0 0 0 0 0 0 0 0 8

    Barra 2 ### ### 0 0 ### ### 0 0 1x 0.707 ### ### 0 0 ### ### 0 0 2y ### 1 2 6 5 0 0 0 0 0 0 0 0 3L= ### 0.035 ### ### 0.035 1 0 0 0 0 0 0 0 0 4

    ### 0.035 0.035 ### 2 ### ### 0 0 ### ### 0 0 5### 0.035 0.035 ### 6 ### ### 0 0 ### ### 0 0 60.035 ### ### 0.035 5 0 0 0 0 0 0 0 0 7

    0 0 0 0 0 0 0 0 8

    Barra 3x 1.000 0.1 0 0 0 0 0 -0.1 0 1y 0.000 1 2 7 8 0 0 0 0 0 0 0 0 2L= ### ### 0 ### 0 1 0 0 0 0 0 0 0 0 3

    0 0 0 0 2 0 0 0 0 0 0 0 0 4### 0 ### 0 7 0 0 0 0 0 0 0 0 5

    0 0 0 0 8 0 0 0 0 0 0 0 0 6-0.1 0 0 0 0 0 0.1 0 7

    0 0 0 0 0 0 0 0 8Barra 4x 1.000y 0.000 3 4 6 5 0 0 0 0 0 0 0 0 1L= ### ### 0 ### 0 3 0 0 0 0 0 0 0 0 2

    0 0 0 0 4 0 0 0.1 0 0 -0.1 0 0 3### 0 ### 0 6 0 0 0 0 0 0 0 0 4

    0 0 0 0 5 0 0 0 0 0 0 0 0 50 0 -0.1 0 0 0.1 0 0 60 0 0 0 0 0 0 0 7

    Barra 5 0 0 0 0 0 0 0 0 8x 0.707y 0.707 3 4 7 8L= ### ### ### ### ### 3 0 0 0 0 0 0 0 0 1

    ### ### ### ### 4 0 0 0 0 0 0 0 0 2### ### ### ### 7 0 0 0.04 0.04 0 0 0 0 3### ### ### ### 8 0 0 0.04 0.04 0 0 0 0 4

    0 0 0 0 0 0 0 0 50 0 0 0 0 0 0 0 6

    Barra 6 0 0 0 0 0 0 0.04 0.04 7

  • x 0.000 0 0 0 0 0 0 0.04 0.04 8y 1.000 6 5 7 8L= ### 0 0 0 0 6

    0 ### 0 ### 50 0 0 0 7 0 0 0 0 0 0 0 0 10 ### 0 ### 8 0 0 0 0 0 0 0 0 2

    0 0 0 0 0 0 0 0 30 0 0 0 0 0 0 0 40 0 0 0 0.1 0 0 -0.1 50 0 0 0 0 0 0 0 60 0 0 0 0 0 0 0 70 0 0 0 -0.1 0 0 0.1 8

  • 2. MATRIZ DE RIGIDEZ GLOBAL

    1 2 3 4 5 6 7 80.135 -0.035 0 0 0.035 -0.035 -0.100 0 1-0.035 0.135 0 -0.100 -0.035 0.035 0 0 2

    0 0 0.135 0.035 0 -0.100 -0.035 -0.035 30 -0.100 0.035 0.135 0 0 -0.035 -0.035 4

    0.035 -0.035 0 0 0.135 -0.035 0 -0.100 5-0.035 0.035 -0.100 0 -0.035 0.135 0 0 6-0.100 0 -0.035 -0.035 0 0 0.135 0.035 7

    0 0 -0.035 -0.035 -0.100 0 0.035 0.135 8

    3. APLICACIN DE LA TEORIA DEL METODO DE LA RIGIDEZ

    2 0.135 -0.035 0 0 0.035 -0.035 -0.100 0 d1-4 -0.035 0.135 0 -0.100 -0.035 0.035 0 0 d20 0 0 0.135 0.035 0 -0.100 -0.035 -0.035 d30 0 -0.100 0.035 0.135 0 0 -0.035 -0.035 d40 0.035 -0.035 0 0 0.135 -0.035 0 -0.100 d5Q6 -0.035 0.035 -0.100 0 -0.035 0.135 0 0 0Q7 -0.100 0 -0.035 -0.035 0 0 0.135 0.035 0Q8 0 0 -0.035 -0.035 -0.100 0 0.035 0.135 0

    3.1. Calculo de Desplazamientos en los nudos

    d1 8.964 4.998 -1.036 3.962 -1.036 2 -2.064d2 4.998 24.133 -5.002 19.131 4.998 -4 ###d3 -1.036 -5.002 8.964 -6.038 -1.036 0 = 17.936d4 3.962 19.131 -6.038 23.094 3.962 0 ###d5 -1.036 4.998 -1.036 3.962 8.964 0 ###

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  • 3.2.- Calculo de Reacciones

    -2.064Q6 -0.035 0.035 -0.100 0 -0.035 ### -4.000Q7 -0.100 0 -0.035 -0.035 0 17.936 = 2.000Q8 0 0 -0.035 -0.035 -0.100 ### 4.000

    ###

    4.ESFUERZOS EN LOS MIEMBROS

    Barra 1x 0.000 1 2 3 4 -2.064y -1.000 AE 0 1 0 -1 ### -1.79L = 10.000 10 17.936

    ###

    Barra 2x 0.707 -2.070y -0.707 AE -0.707 0.707 0.707 -0.707 ### -3.12L = 14.142 14 0.000

    ###

    Barra 3x 1.000 -2.064y 0.000 AE -1 0 1 0 ### 0.21L = 10.000 10 0.000

    0.000

    Barra 4x 1.000 17.936y 0.000 AE -1 0 1 0 ### -1.79L = 10.000 10 0.000

    ###

    Barra 5x 0.707 17.936y 0.707 AE -0.707 -0.707 0.707 0.707 ### 2.53L = 14.142 14 0.000

    0.000

    ?_?= ?_21 ?_?

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  • Barra 6x 0.000 0.000y 1.000 AE 0 -1 0 1 ### 2.21L = 10.000 10 0.000

    0.000

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