Upload
vladimir-holman
View
70
Download
0
Embed Size (px)
DESCRIPTION
Equipment Design. Done by Ahmad Boland Supervised by: Prof. Mohamed Fahim Eng. Yusuf Ismail. Content:. 2 Heat Exchanger ( 1 & 2 ) Cooler (E-100) Compressor (K-102) Trans-alkylation reaction. Shell and tube heat exchanger. - PowerPoint PPT Presentation
Citation preview
Equipment Design
Content:2 Heat Exchanger ( 1 & 2 )Cooler (E-100)Compressor (K-102)Trans-alkylation reaction
Shell and tube heat exchangerObjective : to cooled the stream out from reactor by exchange heat with benzene comes from benzene column.
Assumptions:Use shell and tube heat exchanger, one shell and two tube passes.
The value of the overall heat transfer coefficient was assumed to be 535 w/m2.s.
Assume the outer, the inner diameter and the length of the tube.
Main design procedure:
1-Heat load ,(kW)
Q = (m Cp ΔT)hot =(m Cp ΔT)cold
2- Tube side flow , (kg/hr)
cold
hotcold TCp
Qm
lmtm
lm
TFT
tT
ttS
tt
TTR
tTtT
tTtTT
11
12
12
21
12
21
1221
;
ln
3-Log mean Temperature, (˚C)
4-Provisional Area, (m2)
mo TU
QA
Number of tube:
Bundle and Shell Diameter
DensityPassArea
FlowRateuvelocity
areatoncrossPasstubespassArea
dareaSectioncross
sesAssumedPas
tubesPassTubes
ubeareaOfOneT
totalAreatubes
LdubeAreaOfOneT
t
i
o
*/
sec//
25.0
#/
#
2
10.12.Re
.,; 11
1
1
1
FigadingDD
PassesNofnKK
NdD
bs
nt
ob
Tube side Heat Transfer Coefficient
Shell side heat Transfer Coefficient
i
fi
ih
wh
pit
d
kNuh
d
LfjjNu
k
cdu
)(;PrRe
Pr;Re
14.033.0
e
fs
hw
h
pes
oto
e
ss
t
Bsots
d
kNuh
cutbufflefjjNu
k
cdu
dpd
d
A
FlowRateu
p
lDdpA
_Re,;PrRe
Pr;Re
917.01.1
14.033.0
22
Overall Coefficient
Tube Side pressure drop
Shell side Pressure Drop
ii
o
w
i
oo
oo hd
d
k
ddd
hU
1
2
ln11
25.28
2t
m
wifpt
u
d
LjNP
28
214.0
s
wBe
sfs
u
l
L
d
DjP
Thickness
cj
j
j
CPSE
t
Dr
6.0
Pr2
Equipment NameShell & tube heat exchanger
Objective to cooled the stream out from reactor by exchange heat with benzene comes from benzene column
Equipment Number E-105
Material of Construction
Carbon steel
Insulation Glass wool
Cost)$( 111672
Operating Condition
Shell Side
Inlet temperature (oC) 193Outlet temperature (oC) 265
Tube Side
Inlet temperature (oC)444Outlet temperature (oC)
361
Number of Tubes 838.754Shell Diameter (m) 1.264
Tube bundle Diameter (m) 1.189 LMTD (oC) 173.44
Q total (kw) 3.51e4 Heat Exchanger Area (m2)
385.76
U (W/m2. oC) 537.6
Assumptions:For second heat exchanger:Use shell and tube heat exchanger, one shell and two tube passes.
The value of the overall heat transfer coefficient was assumed to be 800 w/m2.s.
Assume the outer, the inner diameter and the length of the tube.
ResultsEquipment NameShell & tube heat exchanger
Objective to cooled the stream out from reactor by exchange heat with benzene comes from benzene column
Equipment Number E-107
Material of Construction
Carbon steel
Insulation Glass wool
Cost)$( 58752
Operating ConditionShell Side
Inlet temperature (oC) 193Outlet temperature (oC) 260
Tube Side
Inlet temperature (oC)361Outlet temperature (oC)271
Number of Tubes 284.36Shell Diameter (m) .788
Tube bundle Diameter (m) .728 LMTD (oC) 89.005
Q total (kw) 6.29e3 Heat Exchanger Area (m2)
98.090
U (W/m2. oC) 801.54
Assumptions:For cooler:
Use shell and tube heat exchanger, one shell and two tube passes.
The value of the overall heat transfer coefficient was assumed to be 221 w/m2.s.
Assume the outer, the inner diameter and the length of the tube.
ResultsEquipment NameShell & tube heat exchanger
Objective to cooled the stream out from first bed reactor by using cold water
Equipment Number E-100
Material of Construction
Carbon steel
Insulation Glass wool
Cost)$( 69000
Operating ConditionShell Side
Inlet temperature (oC) 701.88Outlet temperature (oC) 200
Tube Side
Inlet temperature (oC)25Outlet temperature (oC)80
Number of Tubes 211.48Shell Diameter (m) .788
Tube bundle Diameter (m) 1.135LMTD (oC) 352.4
Q total (kw) 15310Heat Exchanger Area (m2)
202.64
U (W/m2. oC) 222.96
Compressor (K-102)
Objective:
Compressor is a device in which a gas is compressed to increase its pressure.
Compressor (K-102) is employed to increase the pressure from Pin=(179.3psia) to (Pout=530.4psia)
Design procedure:
1.Calculate n from P1/P2 = ( T1/T2)^(n/n-1)
2. Calculate work doneBtu/lb-moleW = (n*R*(T1-T2))/(1-n)
R=Cp/Cv
3. Calculate horse power,ftlbf/lbmHp=( (Z1*R*T1)/Mw)*(n/n-1)*(Rc^(n-
1/n) – 1)
P1 T1
P2T2
where Rc = P2/P1
4. Calculate the efficiency from (n/n-1) = (K/K-1)*Ep ,
WhereK = (Mw*Cp)/(Mw*Cp – 1.986)Ep=efficiency of the compressorCp=heat capacity, Btu/lboF
Results:K-102
Inlet Temp.(oR)837.6
Outlet Temp.(oR)968.1
Inlet Pressure(Psia)179.3
Outlet Pressure(Psia)530.4
Efficiency%44.85%
Power(HP)332.848
Cost ($)= 251600
Type of compressor: reciprocating
Trans-alkylation reaction
Objective:
The aim from trans-alkylation reaction is to convert PEB to EB.
PEB EB
Main design procedure:
1) Design Equation:
2) Rate Law:
-rA = K CA
Arrhenius equation
3) Stoichiometry
4) Energy Balance
5) Dimensions of the Reactor Assuming L/D = 4
6) Height of reactor= L+D+(2*space)7) Weight of cat. = vol. of reactor (1- ϵ)* ρcat
8) Area of reactor= 2*(3.14)*r*H
9) t = (P r i / (S E-0.6P) ) + CcWhere:t: shell thickness(in)P: internal pressurer i (Rs): internal radius of shell (in)E: efficiency of jointS: working stress stain SteelCc: allowance for corrosion
Results:K = 37.6675 s-1
From Polymath the volume of reactor V = 13.3 m3
Dimensions of the ReactorD = 1.61764 m L = 6.470559 m
Material of Construction: 316 carbon steelCost : 154800 $
H(reactor)=21.23 ft W= 232.0318 kgcatA = 353.309 ft^2
t= 1.38e-1 m
Thank you