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Test - 1 (Code-E) (Answers) All India Aakash Test Series for Medical-2018
1/10
1. (2)
2. (4)
3. (2)
4. (2)
5. (2)
6. (1)
7. (1)
8. (2)
9. (3)
10. (4)
11. (1)
12. (1)
13. (4)
14. (2)
15. (4)
16. (4)
17. (4)
18. (1)
19. (4)
20. (2)
21. (1)
22. (2)
23. (2)
24. (4)
25. (3)
26. (4)
27. (1)
28. (2)
29. (2)
30. (2)
31. (2)
32. (3)
33. (4)
34. (2)
35. (1)
36. (1)
Test Date : 26/11/2017
ANSWERS
TEST - 1 (Code E)
All India Aakash Test Series for Medical - 2018
37. (3)
38. (2)
39. (3)
40. (4)
41. (3)
42. (2)
43. (1)
44. (4)
45. (1)
46. (3)
47. (4)
48. (3)
49. (4)
50. (1)
51. (2)
52. (3)
53. (2)
54. (3)
55. (1)
56. (4)
57. (3)
58. (3)
59. (2)
60. (4)
61. (1)
62. (4)
63. (2)
64. (4)
65. (2)
66. (4)
67. (1)
68. (1)
69. (4)
70. (1)
71. (3)
72. (2)
73. (3)
74. (2)
75. (1)
76. (2)
77. (1)
78. (3)
79. (3)
80. (4)
81. (1)
82. (2)
83. (3)
84. (2)
85. (4)
86. (2)
87. (3)
88. (3)
89. (3)
90. (2)
91. (3)
92. (2)
93. (3)
94. (3)
95. (3)
96. (4)
97. (3)
98. (1)
99. (2)
100. (4)
101. (2)
102. (2)
103. (4)
104. (3)
105. (2)
106. (3)
107. (3)
108. (1)
109. (3)
110. (4)
111. (1)
112. (2)
113. (1)
114. (3)
115. (3)
116. (4)
117. (2)
118. (1)
119. (3)
120. (2)
121. (4)
122. (4)
123. (1)
124. (2)
125. (2)
126. (4)
127. (2)
128. (1)
129. (1)
130. (1)
131. (4)
132. (1)
133. (2)
134. (2)
135. (2)
136. (1)
137. (2)
138. (2)
139. (2)
140. (1)
141. (3)
142. (3)
143. (2)
144. (2)
145. (2)
146 (2)
147. (2)
148. (4)
149. (2)
150. (4)
151. (3)
152. (2)
153. (4)
154. (2)
155. (1)
156. (1)
157. (2)
158. (3)
159. (3)
160. (2)
161. (3)
162. (3)
163. (4)
164. (1)
165. (1)
166. (4)
167. (1)
168. (3)
169. (4)
170. (3)
171. (4)
172. (3)
173. (3)
174. (1)
175. (1)
176. (4)
177. (1)
178. (4)
179. (1)
180. (2)
All India Aakash Test Series for Medical-2018 Test - 1 (Code-E) (Answers & Hints)
2/10
ANSWERS & HINTS
1. Answer (2)
1 1 2
1 1 12 1
2 2 2
M L Tn n
M L T
⎛ ⎞ ⎛ ⎞ ⎛ ⎞
⎜ ⎟ ⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠ ⎝ ⎠
21 1 1
110 10 10
⎛ ⎞ ⎜ ⎟⎝ ⎠
= 1
2. Answer (4)
180° > > 90°
a ta
v
ac
3. Answer (2)
4. Answer (2)
5. Answer (2)
At t = 4.5 s, it is at highest point. At 4 s and 5 s,
it is 0.5 s below the highest point so
Distance = 21
2 0.5 10 0.25 2.5m2g
⎡ ⎤ ⎢ ⎥⎣ ⎦
6. Answer (1)
2 1[ ] [M L T ]E
E h h h ⇒ ⇒
7. Answer (1)
1/2P A
ET
8. Answer (2)
1 2
1 110 4 9 180 m
2 2h gt t
9. Answer (3)
1 2
2[M L T ]
aP
V
10. Answer (4)
13 2
2
X a b c d
X a b c d
13 0.1% 2 0.2% 0.4% 0.4%
2 = 1.3%
11. Answer (1)
100 100 100I V R
I V R
0.1 0.2100 100
20 80
= 0.5 + 0.25
= 0.75%
12. Answer (1)
x = 12t – t3
v = 2
12 3dx
tdt
0 = 12 – 3t2
t = 2 s
x (t = 2 s) = 12(2) – 23 = 24 – 8 = 16 m
x (t = 0 s) = 0
13. Answer (4)
Kads
m
∫
14. Answer (2)
6 5a t
2
26 5 d St
dt
23 5 dSt t
dt
4
2
0
(3 5 ) 104 mS t t dt ∫
15. Answer (4)
max
2 412
2 4v T
⎛ ⎞ ⎜ ⎟ ⎝ ⎠= 16 m/s
[ PHYSICS]
Test - 1 (Code-E) (Answers & Hints) All India Aakash Test Series for Medical-2018
3/10
16. Answer (4)
2 2 2 2 23
x yv v v t
17. Answer (4)
2u b
a c
18. Answer (1)
21
2S at
1 1
2 2
t ht S
t h ⇒
19. Answer (4)
Slope is rate of change of speed = tangential
acceleration
Upward motion
at = –(g + kv)
v at
Downward motion
at = g – kv
v at
20. Answer (2)
21. Answer (1)
h v2
2
1
2h
h
22. Answer (2)
v cos
v
v sinr
d = 50 m
B
2cos cos 20 1
50 2cos
v v v
dr d
= 0.2 rad/s
23. Answer (2)
602 sin 2 20 sin 20 m/s
2 2v v
24. Answer (4)
25. Answer (3)
A2 + B2 + 2ABcos = A2 + B2 – 2AB
= 90°
26. Answer (4)
1 1 1ˆ ˆ ˆA a i b j c k
�
2 2 2ˆ ˆ ˆB a i b j c k
�
If ||A B� �
then 1 1 1
2 2 2
ve
a b c
a b c
27. Answer (1)
28. Answer (2)
v u at �� �
29. Answer (2)
2 2 2
1 2
sin;
2 2
u uh h H
g g
⎛ ⎞ ⎜ ⎟⎜ ⎟⎝ ⎠
30. Answer (2)
vav
(speed) = 0
vav
(velocity) = Total displacement
Total time taken
31. Answer (2)
2 21 1
2 22 2
cos cos 30
cos cos 60
H
H
= 3 : 1
32. Answer (3)
2sin2 u
Rg
33. Answer (4)
40 m/sH
Rv
T
1 2
2 1
sin 3
sin 2
u
u
34. Answer (2)
All India Aakash Test Series for Medical-2018 Test - 1 (Code-E) (Answers & Hints)
4/10
46. Answer (3)
A
B B
1000 0.25 1000m 7.246 molal
M 0.75 46
47. Answer (4)
Na2CO
3 does not decompose on heating.
CaCO3 CaO + CO
2
100 gm 22.4 L
50 gm 11.2 L
mass of CaCO3 = 50 g
mass of Na2CO
3 = 50 g
[ CHEMISTRY]
35. Answer (1)
If = constant
H u2
R u2
R% = H%
36. Answer (1)
45° 2 2
VRM
VM
2
2
VR
RM R Mv v v � � �
R RM Mv v v � � �
37. Answer (3)
38. Answer (2)
When R = xH, 2
2
16
2 16
uH
g x
Put x = 3 0 52
gu⇒
39. Answer (3)
BA B AV V V � � �
BA
100cos5 hr
| |t
v
A
100 kmvB = 10 km/h
B
10 2
Path of w.r.t B A
40. Answer (4)
|Displacement| Distance
41. Answer (3)
4tan
n
; when R = nH
42. Answer (2)
2 2
x ya a a
43. Answer (1)
uH
= constant
u cos60°= ucos30°
10'
3u⇒ m/s
44. Answer (4)
45. Answer (1)
22
2 2
1 1
c
a vva
R a v
⎛ ⎞ ⇒ ⎜ ⎟
⎝ ⎠
48. Answer (3)
1 L of H2O = 1000 gm =
1000
18 = 55.5 mole
= 55.5 × 6 × 1023 × 3 atoms
22.4 L of CO2
= 1 mole = 3 × 6 × 1023 atoms
44.8 L of O2
= 2 mole = 2 × 2 × 6 × 1023 atoms
11.2 L of SO3 = 0.5 mole = 0.5 × 4 × 6 × 1023 atoms
49. Answer (4)
∵ 2 g oxygen combines with 3 g of metal
8 g oxygen combines with 12 g of metal
EMO
= EM
+ 8 = 12 + 8 = 20 g
Test - 1 (Code-E) (Answers & Hints) All India Aakash Test Series for Medical-2018
5/10
eq.MO
(ml)
n1000 1000M n
V n.f 500
0.030.01 2 n.f 6
n.f ⇒
Molar mass of metal oxide = 20 × 6 = 120 g
50. Answer (1)
(1 2
2O contains 18e– + 16p + 16n = 50)
32 g = 50 NA
16 g = 25 NA
51. Answer (2)
H2SO
4 + Na
2CO
3 Na
2SO
4 + H
2O + CO
2
98 g 106 g
% purity = cal. mass
×100expt. mass
expt. mass = 98 100
122.5 gm80
52. Answer (3)
C3H
8 + 5O
2 3CO
2 +
4H
2O(l)
1 : 5 : 3
20 ml 100 ml 60 ml of CO2 formed
80 ml left unreacted 80 + 60 = 140 ml
53. Answer (2)
Fact – sp3 hybridization
54. Answer (3)
O2, O
3, O
2
2–
B.O. = 2, 1.5, 1
55. Answer (1)
% of ionic character = obs
cal
cal
µ100; e d
µ
56. Answer (4)
Fact
57. Answer (3)
Fact
58. Answer (3)
XeF2 – 3 lone pair and 2 bond pair
–
3I – 3 lone pair and 2 bond pair
59. Answer (2)
4 3 2NH , NH and NH
○ have 0, 1 and 2 non-bonding
electron pairs respectively on nitrogen atom.
60. Answer (4)
Polarising power depends on charge
size of the cation.
61. Answer (1)
BrF5 contains one lone pair on ‘Br’ atom hence no
bond angle is of 90°.
O
SO O 6 lone pairs are present.
5 4PBr (s) [PBr ] [Br ]
⇒
○
Br
PBrBr
Br
sp3 hybrid central atom and all the
bond lengths are equal.
ClO4
–
:
O
Cl O–
O
Osp
3
∵ No p-orbitals are available on central atom hence
all the 3 bonds are formed by d & p orbitals.
62. Answer (4)
Fact
63. Answer (2)
2 2 2 2
1 2 1
2 2 2 2
2 21 2
E n Z 13.6 2 1
E En Z 1 3 ⇒
2
9E 13.6 30.6eV
4⇒
64. Answer (4)
h
mv
65. Answer (2)
–
–
– –
p pe
pep e e
m .v v 1835v
m .v
66. Answer (4)
67. Answer (1)
H2O has more number of hydrogen bonds than that
of HF.
68. Answer (1)
Esep.
= – EActual state
=
2
2
Z13.6
n
All India Aakash Test Series for Medical-2018 Test - 1 (Code-E) (Answers & Hints)
6/10
For H; EActual state
= 1 13.6
13.64 4
For He; EActual state
= 4
13.6 13.64
For Li2+; EActual state
= 9
13.6 13.69
For Be3+; EActual state
= 16
13.6 13.616
Removal of electron from excited H-atom (n = 2)
shall be easiest among them.
69. Answer (4)
h= given
mvv
2 h hv = v
m m ⇒
70. Answer (1)
Mg(g) Mg+(g) + e–; H1=737.76 kJ/mole
Mg+(g) Mg+2(g) + e–; H2=1450.73 kJ/mole
Mg(g) Mg+2(g) + 2e–; H=2188.49 kJ
71. Answer (3)
Fact
72. Answer (2)
Fact
73. Answer (3)
Cl has highest electron affinity value.
74. Answer (2)
75. Answer (1)
I.P. suggest 13th group.
76. Answer (2)
Fact
77. Answer (1)
BeF2 possess vacant p-orbitals on Be atom which
co-ordinates with OH○
ions resulting into formation
of ions which further remains in aqueous state
making BeF2 highly soluble in water.
F Be F + H O2
[BeF (OH) ] + 2H2 2
2–
78. Answer (3)
79. Answer (3)
‘S’ has more electron affinity than ‘O’.
80. Answer (4)
In B2 molecule, valence bonding electrons occupy
-BMOs only.
81. Answer (1)
82. Answer (2)
4th excited state = 5th level
n(n – 1) 5(5 – 1) = = 10
2 2
83. Answer (3)
Frequency
2v Z n
v and r2 n Z
r
2
3
Z
n
2
3He
2H
3
2
322
11
4
84. Answer (2)
2
2 2
1 2
1 1 1v
⎡ ⎤ ⎢ ⎥ ⎢ ⎥⎣ ⎦
R Z
n n for limiting series
n2 =
n1 = 1
85. Answer (4)
70 1.25A 1.25 1
56 1.25 ⇒
30 1.88B 1.875 1.5
16 1.25 ⇒
86. Answer (2)
For 2z
d orbital, m = 0
87. Answer (3)
Lower the ionisation potential smaller will be
threshold frequency of metal.
88. Answer (3)
Fact
89. Answer (3)
5 bonds and 19 bonds
90. Answer (2)
NO (7 + 8e– = 15e–) paramagnetic
NO+ (7 + 8 – 1e– = 14e–) diamagnetic
Test - 1 (Code-E) (Answers & Hints) All India Aakash Test Series for Medical-2018
7/10
91. Answer (3)
92. Answer (2)
93. Answer (3)
94. Answer (3)
95. Answer (3)
Spores of slime mould are dispersed by air currents.
96. Answer (4)
97. Answer (3)
Chrysophytes are photosynthetic.
98. Answer (1)
Protein rich layer – Pellicle
All protozoans are heterotrophs
99. Answer (2)
Entamoeba is an amoeboid protozoan.
100. Answer (4)
Physarum – Heterotroph
101. Answer (2)
Marine forms have silica shell
102. Answer (2)
103. Answer (4)
104. Answer (3)
105. Answer (2)
106. Answer (3)
107. Answer (3)
Sexual reproduction is absent in deuteromycetes.
108. Answer (1)
Asexual spores are endogenously produced.
109. Answer (3)
Zoospores are asexual spores.
110. Answer (4)
Albugo, Mucor.
111. Answer (1)
112. Answer (2)
113. Answer (1)
114. Answer (3)
Lichen do not grow in SO2 polluted area.
Phycobiont provides food and mycobiont provides
shelter.
115. Answer (3)
116. Answer (4)
117. Answer (2)
118. Answer (1)
TMV genetic material – ssRNA
119. Answer (3)
120. Answer (2)
121. Answer (4)
122. Answer (4)
Kingdom Protista
123. Answer (1)
Fruiting body
124. Answer (2)
125. Answer (2)
Monera, Protista and Plantae.
126. Answer (4)
Mycoplasma can survive without oxygen and are
non-motile.
127. Answer (2)
128. Answer (1)
129. Answer (1)
130. Answer (1)
Bacterial structure is very simple but it has complex
behaviour
131. Answer (4)
Actinomycetes (Ray Fungi)
132. Answer (1)
Muscidae – Family
133. Answer (2)
134. Answer (2)
Endospores are formed during unfavourable condition.
135. Answer (2)
Soredia – Involve in asexual reproduction.
136. Answer (1)
– Three germinal layers ecto, meso, endoderm are
formed first in flatworms that belong to phylum
platyhelminthes. Mesoderm is solid or dense in
Platyhelminthes.
– All flatworms can be cut into two identical left
and right halves only in one plane passing
through the central axis.
[ BIOLOGY]
All India Aakash Test Series for Medical-2018 Test - 1 (Code-E) (Answers & Hints)
8/10
– In between ecto and endoderm, there is a solid
mesoderm or dense parenchyma which is
involved in transport of nutrients.
137. Answer (2)
Sponges have a special water transport system
through which water, nutrients, oxygen, enter through
ostia and CO2, nitrogenous wastes, water and
sperms leave through single opening called
osculum.
138. Answer (2)
Nerve cells are loosely aggregated but not compactly
arranged to form a distinct brain in coelenterates.
139. Answer (2)
– Taenia solium (Tape worm) has both hooks and
suckers meant for anchorage or attachment to
the surface of a host.
– Fasciola (Liver fluke) has only suckers but no
hooks for attachment.
– Ascaris (Round worm) belongs to aschelminthes
does not possess hooks and suckers.
140. Answer (1)
– Poriferans have minute openings called ostia and
wide openings for exit called oscula.
– Cnidarians have stinging cells in their epidermis
meant for locomotion, food capturing, anchorage,
offense and defense.
– Ctenophores are characterised by the presence
of eight longitudinal or vertical rows of comb
plates with cilia for locomotion.
– In platyhelminthes, since most of the organ
systems are yet to be formed and not found,
therefore, their body is compressed or flattened
dorsoventrally.
141. Answer (3)
Flame cells found in flat worms help in excretion and
osmoregulation.
142. Answer (3)
– In Aschelminthes, their coelom derived from
blastocoel is occupied by scattered and irregular
pouches of mesoderm, therefore called
pseudocoelom.
– Their pharynx is muscular to suck food from the
host but the intestine is non-muscular.
– Organ system level of organisation is present.
143. Answer (2)
– In polychaetes annelids, both parapodia and
setae are found. Parapodia help in swimming
and respiration whereas setae help in locomotion
e.g., Nereis (Clam worm), Chaetopterus (Paddle
worms). Aphrodite (Sea mouse)
– In Pheretima (Earthworm) parapodia are absent,
but setae help in locomotion.
– Aplysia, a mollusc has a muscular foot.
144. Answer (2)
145. Answer (2)
Locust & butterfly respire through trachea.
146. Answer (2)
Chitinous exoskeleton helps in conservation of water.
So it played a major role in the success of insects
on land.
147. Answer (2)
Blood vascular system with heart, dorsal and ventral
vessels is seen for the first time in phylum annelida,
148. Answer (4)
Metamerism is seen in annelids, arthropods and
chordates.
149. Answer (2)
Flat worms are first bilaterally symmetrical animals
with blindsac body plan in which digestive system
ends blindly without a separate opening as anus.
150. Answer (4)
Coelenterates have true tissues, most primitive
diffusible nervous system and sensory cells in body
wall to receive a stimulus.
151. Answer (3)
Digestion in sponges is intracellular.
152. Answer (2)
In most of the echinoderms, protective spines are
found throughout their body surface.
153. Answer (4)
Hemichordates have an open blood vascular system
with a dorsal heart.
154. Answer (2)
Notochord is otherwise known as chorda dorsalis,
which is derived from mesoderm. It is seen only in
Chordates.
Test - 1 (Code-E) (Answers & Hints) All India Aakash Test Series for Medical-2018
9/10
155. Answer (1)
– In Schizocoelomates like annelids, arthropods
and molluscs, a mesoderm is formed between
ecto and endoderm.
– Mesoderm is splitted and confined to both
ectoderm and endoderm. A space found between
ectoderm and endoderm lined by mesoderm on
both sides of coelom.
156. Answer (1)
In parasitic nematodes, their body wall contains a
syncytial epidermis with several nuclei scattered in
a common cytoplasm.
157. Answer (2)
Mammals generally have heterodont dentition with
four types of teeth but in lagomorphs like rabbit,
canines are absent.
158. Answer (3)
There are no alveoli in air sacs of birds.
159. Answer (3)
A cartilaginous skull and vertebral column are found
in cyclostomes and chondrichthyes fishes. It is bony
in osteichthyes, amphibians, reptiles, aves and
mammalia.
160. Answer (2)
Cornified skin with epidermal scales prevents loss of
water from their body.
161. Answer (3)
– Mesonephric kidneys are found in pisces and
amphibians.
– Metanephric kidneys are found in reptiles, aves
and mammals.
162. Answer (3)
163. Answer (4)
– Pavo cristatus is the scientific name of our
national bird, peacock.
– Parrot is scientifically known as Psittacula.
– House sparrow is scientifically known as Passer
domesticus.
– Aptenodytes (Penguin) is a flightless bird in polar
regions.
164. Answer (1)
In amphibians, their body is divided into head and
trunk.
165. Answer (1)
Anadromous migration is seen in Petromyzon or
lamprey migrating from marine water to fresh water
for spawning. Myxine or slime eel or hagfish strictly
inhabits marine water.
166. Answer (4)
Notochord persists throughout life in
cephalochordates, cyclostomes and chondrichthyes.
167. Answer (1)
Retrogressive metamorphosis is seen in all
Urochordates or tunicates e.g., ascidian.
168. Answer (3)
– Urochordates (e.g., Salpa, Ascidia)
– Cephalochordates (e.g., Amphioxus are ciliary
feeders).
– Chondrichthyes fishes (e.g., Scoliodon) is a
vertebrate.
169. Answer (4)
Non-chordates possess double ventral solid nerve
cord, chordates possess dorsal single hollow nerve
cord.
170. Answer (3)
Viviparity is seen in reptiles like Chameleon and
Phrynosoma (Horned toad)
171. Answer (4)
– In flying birds, oil glands or preen glands or
uropygial glands are present at tail base which
lubricates feathers and prevent from being wet.
– In flightless birds, oil or preen or uropygial glands
are absent.
172. Answer (3)
In Torpedo (electric ray), electric organs are modified
dorsal muscles generating a voltage current to shock
or stun the prey or predator.
173. Answer (3)
– Ctenophores or combjellies or sea walnuts or
sea goose berries.
– Echinoderms or spiny skinned animals.
– Hemichordates or worm like marine animals or
tongue worms (or) acorn worms are exclusively
marine in their habitat.
174. Answer (1)
175. Answer (1)
176. Answer (4)
– Anadromous migration is seen in marine water
bony fishes like Salmon, Hilsa migrate for
spawning from marine water to fresh water.
– Catadromous migration is seen in Anguilla (eel)
which moves from fresh water or marine water.
All India Aakash Test Series for Medical-2018 Test - 1 (Code-E) (Answers & Hints)
10/10
� � �
– Edible or eatable carps include Labeo rohita
(Rohu), Labeo calabasu (Calabasu), Catla catla
(Thiela or catla).
– Cat fishes living in turbid water include Clarias
batrachus (Indian catfish or magur), Wallago attu
(Malli).
– Man eating shark is Carcharodon or great white
shark.
– Latimeria (coelacanth) is living fossil fish. It is an
oldest living fish surviving today without
undergoing any change during long evolutionary
time period.
177. Answer (1)
In Caecilians or limbless amphibians or blind worms,
have scales in dermis of the skin.
178. Answer (4)
– Urinary bladder is present in lizards but absent
in snakes.
– A hemipenis or paired penis is found in snakes
and lizards.
179. Answer (1)
Balaenoptera (Blue whale) being measured a weight
about 1,36,000 kgs (136 tonnes), it is considered as
the largest animal.
180. Answer (2)
Flying mammals include Pteropus (Flying fox) and
Vespertilio (Vampire bat).
Test - 1 (Code-F) (Answers) All India Aakash Test Series for Medical-2018
1/10
1. (1)
2. (4)
3. (1)
4. (2)
5. (3)
6. (4)
7. (3)
8. (2)
9. (3)
10. (1)
11. (1)
12. (2)
13. (4)
14. (3)
15. (2)
16. (2)
17. (2)
18. (2)
19. (1)
20. (4)
21. (3)
22. (4)
23. (2)
24. (2)
25. (1)
26. (2)
27. (4)
28. (1)
29. (4)
30. (4)
31. (4)
32. (2)
33. (4)
34. (1)
35. (1)
36. (4)
Test Date : 26/11/2017
ANSWERS
TEST - 1 (Code F)
All India Aakash Test Series for Medical - 2018
37. (3)
38. (2)
39. (1)
40. (1)
41. (2)
42. (2)
43. (2)
44. (4)
45. (2)
46. (2)
47. (3)
48. (3)
49. (3)
50. (2)
51. (4)
52. (2)
53. (3)
54. (2)
55. (1)
56. (4)
57. (3)
58. (3)
59. (1)
60. (2)
61. (1)
62. (2)
63. (3)
64. (2)
65. (3)
66. (1)
67. (4)
68. (1)
69. (1)
70. (4)
71. (2)
72. (4)
73. (2)
74. (4)
75. (1)
76. (4)
77. (2)
78. (3)
79. (3)
80. (4)
81. (1)
82. (3)
83. (2)
84. (3)
85. (2)
86. (1)
87. (4)
88. (3)
89. (4)
90. (3)
91. (2)
92. (2)
93. (2)
94. (1)
95. (4)
96. (1)
97. (1)
98. (1)
99. (2)
100. (4)
101. (2)
102. (2)
103. (1)
104. (4)
105. (4)
106. (2)
107. (3)
108. (1)
109. (2)
110. (4)
111. (3)
112. (3)
113. (1)
114. (2)
115. (1)
116. (4)
117. (3)
118. (1)
119. (3)
120. (3)
121. (2)
122. (3)
123. (4)
124. (2)
125. (2)
126. (4)
127. (2)
128. (1)
129. (3)
130. (4)
131. (3)
132. (3)
133. (3)
134. (2)
135. (3)
136. (2)
137. (1)
138. (4)
139. (1)
140. (4)
141. (1)
142. (1)
143. (3)
144. (3)
145. (4)
146. (3)
147. (4)
148. (3)
149. (1)
150. (4)
151. (1)
152. (1)
153. (4)
154. (3)
155. (3)
156. (2)
157. (3)
158. (3)
159. (2)
160. (1)
161. (1)
162. (2)
163. (4)
164. (2)
165. (3)
166. (4)
167. (2)
168. (4)
169. (2)
170. (2)
171. (2)
172. (2)
173. (2)
174. (3)
175. (3)
176. (1)
177. (2)
178. (2)
179. (2)
180. (1)
All India Aakash Test Series for Medical-2018 Test - 1 (Code-F) (Answers & Hints)
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ANSWERS & HINTS
1. Answer (1)
22
2 2
1 1
c
a vva
R a v
⎛ ⎞ ⇒ ⎜ ⎟
⎝ ⎠
2. Answer (4)
3. Answer (1)
uH = constant
u cos60°= ucos30°
10'
3u⇒ m/s
4. Answer (2)
2 2
x ya a a
5. Answer (3)
4tan
n
; when R = nH
6. Answer (4)
|Displacement| Distance
7. Answer (3)
BA B AV V V � � �
BA
100cos5 hr
| |t
v
A
100 kmvB = 10 km/h
B
10 2
Path of w.r.t B A
8. Answer (2)
When R = xH, 2
2
16
2 16
uH
g x
Put x = 3 0 52
gu⇒
[ PHYSICS]
9. Answer (3)
10. Answer (1)
45° 2 2
VRM
VM
2
2
VR
RM R Mv v v � � �
R RM Mv v v � � �
11. Answer (1)
If = constant
H u2
R u2
R% = H%
12. Answer (2)
13. Answer (4)
40 m/sH
Rv
T
1 2
2 1
sin 3
sin 2
u
u
14. Answer (3)
2sin2 u
Rg
15. Answer (2)
2 21 1
2 22 2
cos cos 30
cos cos 60
H
H
= 3 : 1
16. Answer (2)
vav (speed) = 0
vav (velocity) = Total displacement
Total time taken
17. Answer (2)
2 2 2
1 2
sin;
2 2
u uh h H
g g
⎛ ⎞ ⎜ ⎟⎜ ⎟⎝ ⎠
Test - 1 (Code-F) (Answers & Hints) All India Aakash Test Series for Medical-2018
3/10
18. Answer (2)
v u at �� �
19. Answer (1)
20. Answer (4)
1 1 1ˆ ˆ ˆA a i b j c k
�
2 2 2ˆ ˆ ˆB a i b j c k
�
If ||A B� �
then 1 1 1
2 2 2
ve
a b c
a b c
21. Answer (3)
A2 + B2 + 2ABcos = A2 + B2 – 2AB
= 90°
22. Answer (4)
23. Answer (2)
602 sin 2 20 sin 20 m/s
2 2v v
24. Answer (2)
v cos
v
v sinr
d = 50 m
B
2cos cos 20 1
50 2cos
v v v
dr d
= 0.2 rad/s
25. Answer (1)
h v2
2
1
2h
h
26. Answer (2)
27. Answer (4)
Slope is rate of change of speed = tangential
acceleration
Upward motion
at = –(g + kv)
v at
Downward motion
at = g – kv
v at
28. Answer (1)
21
2S at
1 1
2 2
t ht S
t h ⇒
29. Answer (4)
2u b
a c
30. Answer (4)
2 2 2 2 23
x yv v v t
31. Answer (4)
max
2 412
2 4v T
⎛ ⎞ ⎜ ⎟ ⎝ ⎠= 16 m/s
32. Answer (2)
6 5a t
2
26 5 d St
dt
23 5 dSt t
dt
4
2
0
(3 5 ) 104 mS t t dt ∫
33. Answer (4)
Kads
m
∫
34. Answer (1)
x = 12t – t3
v = 2
12 3dx
tdt
0 = 12 – 3t2
t = 2 s
x (t = 2 s) = 12(2) – 23 = 24 – 8 = 16 m
x (t = 0 s) = 0
35. Answer (1)
100 100 100I V R
I V R
0.1 0.2100 100
20 80 = 0.5 + 0.25= 0.75%
All India Aakash Test Series for Medical-2018 Test - 1 (Code-F) (Answers & Hints)
4/10
46. Answer (2)
NO (7 + 8e– = 15e–) paramagnetic
NO+ (7 + 8 – 1e– = 14e–) diamagnetic
47. Answer (3)
5 bonds and 19 bonds
48. Answer (3)
Fact
49. Answer (3)
Lower the ionisation potential smaller will be
threshold frequency of metal.
50. Answer (2)
For 2z
d orbital, m = 0
51. Answer (4)
70 1.25A 1.25 1
56 1.25 ⇒
30 1.88B 1.875 1.5
16 1.25 ⇒
[ CHEMISTRY]
36. Answer (4)
13 2
2
X a b c d
X a b c d
13 0.1% 2 0.2% 0.4% 0.4%
2 = 1.3%
37. Answer (3)
1 2
2[M L T ]
aP
V
38. Answer (2)
1 2
1 110 4 9 180 m
2 2h gt t
39. Answer (1)
1/2P A
ET
40. Answer (1)
2 1[ ] [M L T ]E
E h h h ⇒ ⇒
41. Answer (2)
At t = 4.5 s, it is at highest point. At 4 s and 5 s,
it is 0.5 s below the highest point so
Distance = 21
2 0.5 10 0.25 2.5m2g
⎡ ⎤ ⎢ ⎥⎣ ⎦
42. Answer (2)
43. Answer (2)
44. Answer (4)
180° > > 90°
a ta
v
ac
45. Answer (2)
1 1 2
1 1 12 1
2 2 2
M L Tn n
M L T
⎛ ⎞ ⎛ ⎞ ⎛ ⎞
⎜ ⎟ ⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠ ⎝ ⎠
21 1 1
110 10 10
⎛ ⎞ ⎜ ⎟⎝ ⎠
= 1
52. Answer (2)
2
2 2
1 2
1 1 1v
⎡ ⎤ ⎢ ⎥ ⎢ ⎥⎣ ⎦
R Z
n n for limiting series
n2 = n1 = 1
53. Answer (3)
Frequency
2v Z n
v and r2 n Z
r
2
3
Z
n
2
3He
2H
3
2
322
11
4
54. Answer (2)
4th excited state = 5th level
n(n – 1) 5(5 – 1) = = 10
2 2
55. Answer (1)
Test - 1 (Code-F) (Answers & Hints) All India Aakash Test Series for Medical-2018
5/10
56. Answer (4)
In B2 molecule, valence bonding electrons occupy
-BMOs only.
57. Answer (3)
‘S’ has more electron affinity than ‘O’.
58. Answer (3)
59. Answer (1)
BeF2 possess vacant p-orbitals on Be atom which
co-ordinates with OH○
ions resulting into formation
of ions which further remains in aqueous state
making BeF2 highly soluble in water.
F Be F + H O2
[BeF (OH) ] + 2H2 2
2–
60. Answer (2)
Fact
61. Answer (1)
I.P. suggest 13th group.
62. Answer (2)
63. Answer (3)
Cl has highest electron affinity value.
64. Answer (2)
Fact
65. Answer (3)
Fact
66. Answer (1)
Mg(g) Mg+(g) + e–; H1=737.76 kJ/mole
Mg+(g) Mg+2(g) + e–; H2=1450.73 kJ/mole
Mg(g) Mg+2(g) + 2e–; H=2188.49 kJ
67. Answer (4)
h= given
mvv
2 h hv = v
m m ⇒
68. Answer (1)
Esep. = – EActual state =
2
2
Z13.6
n
For H; EActual state = 1 13.6
13.64 4
For He; EActual state = 4
13.6 13.64
For Li2+; EActual state = 9
13.6 13.69
For Be3+; EActual state = 16
13.6 13.616
Removal of electron from excited H-atom (n = 2)
shall be easiest among them.
69. Answer (1)
H2O has more number of hydrogen bonds than that
of HF.
70. Answer (4)
71. Answer (2)
–
–
– –
p pe
pep e e
m .v v 1835v
m .v
72. Answer (4)
h
mv
73. Answer (2)
2 2 2 2
1 2 1
2 2 2 2
2 21 2
E n Z 13.6 2 1
E En Z 1 3 ⇒
2
9E 13.6 30.6eV
4⇒
74. Answer (4)
Fact
75. Answer (1)
BrF5 contains one lone pair on ‘Br’ atom hence no
bond angle is of 90°.
O
SO O 6 lone pairs are present.
5 4PBr (s) [PBr ] [Br ]
⇒
○
Br
PBrBr
Br
sp3 hybrid central atom and all the
bond lengths are equal.
ClO4
–
:
O
Cl O–
O
Osp
3
∵ No p-orbitals are available on central atom hence
all the 3 bonds are formed by d & p orbitals.
All India Aakash Test Series for Medical-2018 Test - 1 (Code-F) (Answers & Hints)
6/10
76. Answer (4)
Polarising power depends on charge
size of the cation.
77. Answer (2)
4 3 2NH , NH and NH
○ have 0, 1 and 2 non-bonding
electron pairs respectively on nitrogen atom.
78. Answer (3)
XeF2 – 3 lone pair and 2 bond pair
–
3I – 3 lone pair and 2 bond pair
79. Answer (3)
Fact
80. Answer (4)
Fact
81. Answer (1)
% of ionic character = obs
cal
cal
µ100; e d
µ
82. Answer (3)
O2, O3, O22–
B.O. = 2, 1.5, 1
83. Answer (2)
Fact – sp3 hybridization
84. Answer (3)
C3H8 + 5O2 3CO2 + 4H2O(l)
1 : 5 : 3
20 ml 100 ml 60 ml of CO2 formed
80 ml left unreacted 80 + 60 = 140 ml
85. Answer (2)
H2SO4 + Na2CO3 Na2SO4 + H2O + CO2
98 g 106 g
% purity = cal. mass
×100expt. mass
expt. mass = 98 100
122.5 gm80
86. Answer (1)
(1 2
2O contains 18e– + 16p + 16n = 50)
32 g = 50 NA
16 g = 25 NA
87. Answer (4)
∵ 2 g oxygen combines with 3 g of metal
8 g oxygen combines with 12 g of metal
EMO = EM + 8 = 12 + 8 = 20 g
eq.MO
(ml)
n1000 1000M n
V n.f 500
0.030.01 2 n.f 6
n.f ⇒
Molar mass of metal oxide = 20 × 6 = 120 g
88. Answer (3)
1 L of H2O = 1000 gm = 1000
18 = 55.5 mole
= 55.5 × 6 × 1023 × 3 atoms
22.4 L of CO2 = 1 mole = 3 × 6 × 1023 atoms
44.8 L of O2 = 2 mole = 2 × 2 × 6 × 1023 atoms
11.2 L of SO3 = 0.5 mole = 0.5 × 4 × 6 × 1023 atoms
89. Answer (4)
Na2CO3 does not decompose on heating.
CaCO3 CaO + CO2
100 gm 22.4 L
50 gm 11.2 L
mass of CaCO3 = 50 g
mass of Na2CO3 = 50 g
90. Answer (3)
A
B B
1000 0.25 1000m 7.246 molal
M 0.75 46
[ BIOLOGY]
91. Answer (2)
Soredia – Involve in asexual reproduction.
92. Answer (2)
Endospores are formed during unfavourable condition.
93. Answer (2)
94. Answer (1)
Muscidae – Family
95. Answer (4)
Actinomycetes (Ray Fungi)
96. Answer (1)
Bacterial structure is very simple but it has complex
behaviour
Test - 1 (Code-F) (Answers & Hints) All India Aakash Test Series for Medical-2018
7/10
97. Answer (1)
98. Answer (1)
99. Answer (2)
100. Answer (4)
Mycoplasma can survive without oxygen and are
non-motile.
101. Answer (2)
Monera, Protista and Plantae.
102. Answer (2)
103. Answer (1)
Fruiting body
104. Answer (4)
Kingdom Protista
105. Answer (4)
106. Answer (2)
107. Answer (3)
108. Answer (1)
TMV genetic material – ssRNA
109. Answer (2)
110. Answer (4)
111. Answer (3)
112. Answer (3)
Lichen donot grow in SO2 polluted area.
Phycobiont provides food and mycobiont provides
shelter.
113. Answer (1)
114. Answer (2)
115. Answer (1)
116. Answer (4)
Albugo, Mucor.
117. Answer (3)
Zoospores are asexual spores.
118. Answer (1)
Asexual spores are endogenously produced.
119. Answer (3)
Sexual reproduction is absent in deuteromycetes.
120. Answer (3)
121. Answer (2)
122. Answer (3)
123. Answer (4)
124. Answer (2)
125. Answer (2)
Marine forms have silica shell
126. Answer (4)
Physarum – Heterotroph
127. Answer (2)
Entamoeba is an amoeboid protozoan.
128. Answer (1)
Protein rich layer – Pellicle
All protozoans are heterotrophs
129. Answer (3)
Chrysophytes are photosynthetic.
130. Answer (4)
131. Answer (3)
Spores of slime mould are dispersed by air currents.
132. Answer (3)
133. Answer (3)
134. Answer (2)
135. Answer (3)
136. Answer (2)
Flying mammals include Pteropus (Flying fox) and
Vespertilio (Vampire bat).
137. Answer (1)
Balaenoptera (Blue whale) being measured a weight
about 1,36,000 kgs (136 tonnes), it is considered as
the largest animal.
138. Answer (4)
– Urinary bladder is present in lizards but absent
in snakes.
– A hemipenis or paired penis is found in snakes
and lizards.
139. Answer (1)
In Caecilians or limbless amphibians or blind worms,
have scales in dermis of the skin.
140. Answer (4)
– Anadromous migration is seen in marine water
bony fishes like Salmon, Hilsa migrate for
spawning from marine water to fresh water.
– Catadromous migration is seen in Anguilla (eel)
which moves from fresh water or marine water.
All India Aakash Test Series for Medical-2018 Test - 1 (Code-F) (Answers & Hints)
8/10
– Edible or eatable carps include Labeo rohita
(Rohu), Labeo calabasu (Calabasu), Catla catla
(Thiela or catla).
– Cat fishes living in turbid water include Clarias
batrachus (Indian catfish or magur), Wallago attu
(Malli).
– Man eating shark is Carcharodon or great white
shark.
– Latimeria (coelacanth) is living fossil fish. It is an
oldest living fish surviving today without
undergoing any change during long evolutionary
time period.
141. Answer (1)
142. Answer (1)
143. Answer (3)
– Ctenophores or combjellies or sea walnuts or
sea goose berries.
– Echinoderms or spiny skinned animals.
– Hemichordates or worm like marine animals or
tongue worms (or) acorn worms are exclusively
marine in their habitat.
144. Answer (3)
In Torpedo (electric ray), electric organs are modified
dorsal muscles generating a voltage current to shock
or stun the prey or predator.
145. Answer (4)
– In flying birds, oil glands or preen glands or
uropygial glands are present at tail base which
lubricates feathers and prevent from being wet.
– In flightless birds, oil or preen or uropygial glands
are absent.
146. Answer (3)
Viviparity is seen in reptiles like Chameleon and
Phrynosoma (Horned toad)
147. Answer (4)
Non chordates possess double ventral solid nerve
cord, chordates possess dorsal single hollow nerve
cord.
148. Answer (3)
– Urochordates (e.g., Salpa, Ascidia)
– Cephalochordates (e.g., Amphioxus are ciliary
feeders).
– Chondrichthyes fishes (e.g., Scoliodon) is a
vertebrate.
149. Answer (1)
Retrogressive metamorphosis is seen in all
Urochordates or tunicates e.g., ascidian.
150. Answer (4)
Notochord persists throughout life in
cephalochordates, cyclostomes and chondrichthyes.
151. Answer (1)
Anadromous migration is seen in Petromyzon or
lamprey migrating from marine water to fresh water
for spawning. Myxine or slime eel or hagfish strictly
inhabits marine water.
152. Answer (1)
In amphibians, their body is divided into head and
trunk.
153. Answer (4)
– Pavo cristatus is the scientific name of our
national bird, peacock.
– Parrot is scientifically known as Psittacula.
– House sparrow is scientifically known as Passer
domesticus.
– Aptenodytes (Penguin) is a flightless bird in polar
regions.
154. Answer (3)
155. Answer (3)
– Mesonephric kidneys are found in pisces and
amphibians.
– Metanephric kidneys are found in reptiles, aves
and mammals.
156. Answer (2)
Cornified skin with epidermal scales prevents loss of
water from their body.
157. Answer (3)
A cartilaginous skull and vertebral column are found
in cyclostomes and chondrichthyes fishes. It is bony
in osteichthyes, amphibians, reptiles, aves and
mammalia.
158. Answer (3)
There are no alveoli in air sacs of birds.
159. Answer (2)
Mammals generally have heterodont dentition with
four types of teeth but in lagomorphs like rabbit,
canines are absent.
160. Answer (1)
In parasitic nematodes, their body wall contains a
syncytial epidermis with several nuclei scattered in
a common cytoplasm.
Test - 1 (Code-F) (Answers & Hints) All India Aakash Test Series for Medical-2018
9/10
161. Answer (1)
– In Schizocoelomates like annelids, arthropods
and molluscs, a mesoderm is formed between
ecto and endoderm.
– Mesoderm is splitted and confined to both
ectoderm and endoderm. A space found between
ectoderm and endoderm lined by mesoderm on
both sides of coelom.
162. Answer (2)
Notochord is otherwise known as chorda dorsalis,
which is derived from mesoderm. It is seen only in
Chordates.
163. Answer (4)
Hemichordates have an open blood vascular system
with a dorsal heart.
164. Answer (2)
In most of the echinoderms, protective spines are
found throughout their body surface.
165. Answer (3)
Digestion in sponges is intracellular.
166. Answer (4)
Coelenterates have true tissues, most primitive
diffusible nervous system and sensory cells in body
wall to receive a stimulus.
167. Answer (2)
Flat worms are first bilaterally symmetrical animals
with blindsac body plan in which digestive system
ends blindly without a separate opening as anus.
168. Answer (4)
Metamerism is seen in annelids, arthropods and
chordates.
169. Answer (2)
Blood vascular system with heart, dorsal and ventral
vessels is seen for the first time in phylum annelida,
170. Answer (2)
Chitinous exoskeleton helps in conservation of water.
So it played a major role in the success of insects
on land.
171. Answer (2)
Locust & butterfly respire through trachea.
172. Answer (2)
173. Answer (2)
– In polychaetes annelids, both parapodia and
setae are found. Parapodia help in swimming
and respiration whereas setae help in locomotion
e.g., Nereis (Clam worm), Chaetopterus (Paddle
worms). Aphrodite (Sea mouse)
– In Pheretima (Earthworm) parapodia are absent,
but setae help in locomotion.
– Aplysia, a mollusc has a muscular foot.
174. Answer (3)
– In Aschelminthes, their coelom derived from
blastocoel is occupied by scattered and irregular
pouches of mesoderm, therefore called
pseudocoelom.
– Their pharynx is muscular to suck food from the
host but the intestine is non-muscular.
– Organ system level of organisation is present.
175. Answer (3)
Flame cells found in flat worms help in excretion and
osmoregulation.
176. Answer (1)
– Poriferans have minute openings called ostia and
wide openings for exit called oscula.
– Cnidarians have stinging cells in their epidermis
meant for locomotion, food capturing, anchorage,
offense and defense.
– Ctenophores are characterised by the presence
of eight longitudinal or vertical rows of comb
plates with cilia for locomotion.
– In platyhelminthes, since most of the organ
systems are yet to be formed and not found,
therefore, their body is compressed or flattened
dorsoventrally.
177. Answer (2)
– Taenia solium (Tape worm) has both hooks and
suckers meant for anchorage or attachment to
the surface of a host.
– Fasciola (Liver fluke) has only suckers but no
hooks for attachment.
– Ascaris (Round worm) belongs to aschelminthes
does not possess hooks and suckers.
All India Aakash Test Series for Medical-2018 Test - 1 (Code-F) (Answers & Hints)
10/10
� � �
178. Answer (2)
Nerve cells are loosely aggregated but not compactly
arranged to form a distinct brain in coelenterates.
179. Answer (2)
Sponges have a special water transport system
through which water, nutrients, oxygen, enter through
ostia and CO2, nitrogenous wastes, water and
sperms leave through single opening called
osculum.
180. Answer (1)
– Three germinal layers ecto, meso, endoderm are
formed first in flatworms that belong to phylum
platyhelminthes. Mesoderm is solid or dense in
Platyhelminthes.
– All flatworms can be cut into two identical left
and right halves only in one plane passing
through the central axis.
– In between ecto and endoderm, there is a solid
mesoderm or dense parenchyma which is
involved in transport of nutrients.