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Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

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Page 1: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

EKT343 –Principle of Communication Engineering

1

Gain, Attenuation, Decibels

Chapter 1(part 2)

Page 2: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

• Most circuits in electronic communication are used to manipulate signals to produce a desired result.

• All signal processing circuits involve:– Gain– Attenuation

Page 3: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Gain– Gain means amplification. It is the ratio of a circuit’s output to its

input.

Figure 2-1: An amplifier has gain.

AV = =output

input

Vout

Vin

Page 4: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

• Most amplifiers are also power amplifiers, so the same procedure can be used to calculate power gain AP where Pin is the power input and Pout is the power output.

Power gain (Ap) = Pout / Pin

• Example:

The power output of an amplifier is 6 watts (W). The power gain is 80. What is the input power?

Ap = Pout / Pin therefore Pin = Pout / Ap

Pin = 6 / 80 = 0.075 W = 75 mW

Page 5: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

• An amplifier is cascaded when two or more stages are connected together.

• The overall gain is the product of the individual circuit gains.

• Example: Three cascaded amplifiers have power gains of 5, 2, and 17.

The input power is 40 mW. What is the output power?

Ap = A1 × A2 × A3 = 5 × 2 × 17 = 170Ap = Pout / Pin therefore Pout = ApPin

Pout = 170 (40 × 10-3) = 6.8W

Page 6: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation, and Decibels

Attenuation – Attenuation refers to a loss introduced by a circuit

or component. If the output signal is lower in amplitude than the input, the circuit has loss or attenuation.

– The letter A is used to represent attenuation– Attenuation A = output/input = Vout/Vin

– Circuits that introduce attenuation have a gain that is less than 1.

– With cascaded circuits, the total attenuation is the product of the individual attenuations.

Page 7: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Figure 2-3: A voltage divider introduces attenuation.

Page 8: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Figure 2-4: Total attenuation is the product of individual attenuations of each cascaded circuit.

Page 9: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Decibels– The decibel (dB) is a unit of measure used to

express the gain or loss of a circuit.• The decibel was originally created to express hearing

response.• A decibel is one-tenth of a bel.

– When gain and attenuation are both converted into decibels, the overall gain or attenuation of a circuit can be computed by adding individual gains or attenuations, expressed in decibels.

Page 10: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Decibels: Decibel Calculations – Voltage Gain or Attenuation

dB = 20 log Vout/ Vin

– Current Gain or AttenuationdB = 20 log Iout/ Iin

– Power Gain or AttenuationdB = 10 log Pout/ Pin

Page 11: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Decibels: Decibel Calculations

• Example:An amplifier has an input of 3 mV and an output of 5

V. What is the gain in decibels?

dB = 20 log 5/0.003 = 20 log 1666.67

= 20 (3.22) = 64.4

Page 12: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Decibels: Decibel Calculations • Example:

A filter has a power input of 50 mW and an output of 2 mW. What is the gain or attenuation?

dB = 10 log (2/50) = 10 log (0.04)

= 10 (−1.398) = −13.98

– If the decibel figure is positive, that denotes a gain.

Page 13: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Decibels: Antilogs – The antilog is the number obtained when the base is

raised to the logarithm which is the exponent. – Antilogs are used to calculate input or output voltage

or power, given the decibel gain or attenuation and the output or input.

– The antilog is the base 10 raised to the dB/10 power.– The antilog is readily calculated on a scientific

calculator.

Page 14: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Example:A power amplifier with a 40 dB gain has an output power of 100 W. What is the input power?Solution: dB = 10 log (Pout/ Pin ) antilog = log^(-1)

dB/10 = log (Pout/ Pin ) 40/10 = log (Pout/ Pin ) 4 = log (Pout/ Pin )

Antilog 4 = antilog (log (Pout/ Pin ) )(Pout/ Pin ) =10^ dB/10

(Pout/ Pin ) =10^4 = 10,000Pin =Pout/10000 = 100/10000 = 0.01 W = 10 mW

Page 15: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Gain, Attenuation,and Decibels

Decibels: dBm and dBc– When a decibel value is computed by comparing a

power value to 1 mW, the result is a value called the dBm. This is a useful reference value.

– The value dBc is a decibel gain attenuation figure where the reference is the carrier.

Page 16: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Exercises

• 1. What is the gain of an amplifier with an output of 1.5V and an input of 30V?

• 2. What is the attenuation of a voltage divider like that in Figure 2.3,where R1 is 3.3K-ohms and R2 is 5.1K-ohms?

• 3. What is the overall gain or attenuation of the combination formed by cascading the circuit described in exercises 1 and 2?

Page 17: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Exercises (cont..)

4. The AM receiver radio have three-stages comprised of two amplifiers and one filter with an input power Pin=-10 dBm , and absolute power gains of Ap1 =100, Ap2=0.7 and Ap3=2000. Determine:

(i) The dB gain of each stage and the overall gain in dB.

(ii) Output power (Po ) in dBm and watts. (iii) What is the difference between a positive and

negative decibel (dB)?

Page 18: Gain, Attenuation, Decibels Chapter 1 (part 2) EKT343 –Principle of Communication Engineering 1

Exercises

• 5. Given a four-stage system with an input power of Pin = -15dBm with the absolute power gain of Ap1 = 400, while Ap2 = 2Ap1, Ap4 = 1x10-4Ap2 and Ap3 = 5Ap4.Determine:

• the overall gain in dB. • the dB gain of each stage. • the output power in dBm and watt.