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Genome closure and finishing

Genome closure and finishing

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Genome closure and finishing. Clone walking. clone insert (from shotgun library). primer locations. Already sequenced. Unsequenced. sequencing primer. direction of extension. tgcatgatcgtgatcat acgtactagcactagtactgtagtcgatgcactgatcgatcgatcgatgctacgatgcatgct. PCR to close gaps. Scaffold. - PowerPoint PPT Presentation

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Page 1: Genome closure and finishing

Genome closure and finishing

Page 2: Genome closure and finishing

Clone walking

Already sequenced

Unsequenced

primer locations

tgcatgatcgtgatcatacgtactagcactagtactgtagtcgatgcactgatcgatcgatcgatgctacgatgcatgct...

clone insert (from shotgun library)

sequencing primer

direction of extension

Page 3: Genome closure and finishing

PCR to close gapsScaffold

Design primers at these locations

• Run PCR for each pair of primers• Primers must be in non-repeat sequences• Primers must be as close as possible to each gap• PCR works best if primers are less than 2kb apart

Page 4: Genome closure and finishing

What about physical gaps?

How to order and orient all scaffolds?

Page 5: Genome closure and finishing
Page 6: Genome closure and finishing

Traditional strategy: combinatorial PCR

• Design primers for each end of each scaffold

• With N/2 scaffolds and N “ends”, run a separate PCR reaction for every pair of ends

• (N choose 2) reactions = N(N-1)/2• Example: 24 physical gaps, 48 ends,

PCR experiments will be:

48

2

⎝ ⎜

⎠ ⎟=1128

Page 7: Genome closure and finishing

Multiplex PCR

actgagatatacgttgagatataa

gcgacgctgctc ccagcgctgttc

Page 8: Genome closure and finishing

Multiplexing more primers

• Up to 12 primers per tube

• If any two primers surround the same gap, they produce a product

• If more than 2 pairs react, we get multiple products

• Let N = number of primers = 48

• K = max primers/tube = 12

Page 9: Genome closure and finishing

POMP:pipette optimized multiplex PCR

• minimize number of laboratory reactions

• with N=48, number of combinatorial PCRs is 1128

• number of pipettings = 2256

• POMP: 28 reactions, 104 pipettings

Page 10: Genome closure and finishing

POMP

• Create pools of size K/2 = 6

• Each of N=48 primers put into 1 pool

• So we create N/(K/2) = 8 pools, P1...P8

• Now create multiplex PCR reactions with all pairs of pools

• (8 choose 2) = 28 reactions needed

Page 11: Genome closure and finishing

POMP

• Guarantees that all primers are tested against all others

• Each reaction tests (12 choose 2) = 66 pairs

• Protocol tests 66*28 = 1848 pairs• Only 1128 distinct pairs, so POMP has

some redundancy - some pairs appear in more than one reaction

Page 12: Genome closure and finishing

Pooling primersACGTCGATGCATCGA

ACGTCGATGCATCGA

ACGTCGATGCATCGA

ACGTCGATGCATCGA

ACGTCGATGCATCGA

GCATGCTCGTACGAT

GCATGCTCGTACGAT

GCATGCTCGTACGAT

GCATGCTCGTACGAT

GCATGCTCGTACGAT

GCATGCTCGTACGATACGTCGATGCATCGA

ATCGTGACAGTGAAC GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

ATCGTGACAGTGAAC

ATCGTGACAGTGAAC

ATCGTGACAGTGAAC

ATCGTGACAGTGAAC

ATCGTGACAGTGAAC

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

GCATCGATGCATGT

Page 13: Genome closure and finishing

Testing all Pools

P1

Page 14: Genome closure and finishing

How many pipette operations?

• 48 pipettings to create the pools (one for each primer)

• 2 pipettings to create each multiplex reaction mix

• Total: 48 + 2(28) = 104

Page 15: Genome closure and finishing

Results: Streptococcus pneumoniae

• N=48 primers, N/2 = 24 scaffolds, 24 gaps• 19 products observed in the first experiment

• Q: how many gaps closed?

Page 16: Genome closure and finishing

Interpreting results

• Case 1: product appears with Pi and Pj, but not in any other lane containing Pi– see P2P6 or P7P8 on previous slide– purify and sequence product directly

• Case 2: product appears in Pi and Pj and also in other lanes containing Pi– thus two primers within Pi reacted– see pool P5 on previous slide

Page 17: Genome closure and finishing

A: Deconvoluting pool P5: eliminate each of the six primers from the pool and run 6 standard PCRs

Answer: p25 and p29

Page 18: Genome closure and finishing

B: Pools P2 and P3 gave two products

• Could run 12 more PCRs: eliminate each of 12 primers and re-run multiplex PCR

• However, 5 of the 12 were eliminated by other results• For example, primer p10 was eliminated by results from P1-P2

•Answers:•p11 in Pool 2 pairs with p13 in Pool 3•p16 in Pool 3 pairs with p8 in Pool 2

Page 19: Genome closure and finishing

POMP requirements• (Ideally) If no restriction on K, choose K

based on N (where N = 2 x (#gaps))• Make pools of size K/2

Reactions:

Pipettings:

Page 20: Genome closure and finishing

POMP summary for S. pneumoniae

• Out of 48 gaps, 42 were closed

• Strategy employs slightly under N/2 reactions, thus expected number of products per tube is ~1

• This was borne out in experiments

• This became a standard lab technique at TIGR

Page 21: Genome closure and finishing