Grade 4 Roman Numerals - TestsStep 4 Ghada runs the third leg in XX seconds, or XX = 20 seconds. Step 5 Azra runs the final leg in XVII seconds, or XVII = 17 seconds. Step 6 The total

Grade 4Roman Numerals

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Answer the questions

(1) In the Roman number system, which symbols can never be repeated in a number representation?

(2) Ain is 7 years old and Kalil is 27 years old. What is the difference in their ages (in Roman numbers)?

(3) Add the Roman Numeral VI to XIV.

(4) In Roman Number system, X can be subtracted from ____ and ____ only. (Write the roman numbers inascending order)

(5) In a 4 × 100 m relay race, Imam runs the first 100 meters in XXIV seconds. Jaleel runs the second legin XVI seconds. Ghada runs the 3rd leg in XX seconds and Azra runs the final 100 meters in XVIIseconds. What is the total time they took to run the race (in Roman numerals)?

(6) Write the roman numerals for following:

A) 19 B) 29 C) 35

D) 16 E) 4 F) 16

(7) A grocer bought 20 boxes of guavas, with each box containing a dozen guavas. He paid Dhs11 perguava. He then sold the entire lot at a loss of Dhs240. At what price (in Roman numerals) did he selleach box?

(8) Write the roman numerals for following:

A) 75 B) 95 C) 60

D) 81 E) 100 F) 76

(9) What is the number of days in the month of April (in Roman Numerals)?

(10) Aden brings 23 chocolates to class one day. On the same day, Hamal brings 14 chocolates and Jalilbrings 13 chocolates. How many chocolates did they bring to class in all? (Answer in Romannumerals.)

Choose correct answer(s) from the given choices

(11) We celebrate New Year's Day on ____ January. (Answer in Roman numerals)

a. X b. VI

c. I d. 1

(12) Age of Hakim is 25 years and age of Farook is 30 years. The sum of their age in roman numbers is:

a. LV b. LIV

c. V d. LVI

ID : ae-4-Roman-Numerals [1]

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(13) Compare Roman NumbersMMCCXLI ________ MCMXCVIII (use <, >, =)

a. = b. none

c. > d. <

(14) Which of the following is not correct?

a. XII = 12 b. XLIX = 49

c. XIV = 14 d. XIII = 15

Fill in the blanks

(15) The product of 5 and 7 in Roman Numerals is .

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Answers

(1) V, L and D

In the Roman number system, the symbols V, L, and D that can never be repeated in a numberrepresentation.

(2) XX

Step 1

The difference in their ages is 27 - 7 = 20 years.

Step 2

Now, we know that 20 can be written in Roman form as XX.

(3) XX (20)

Step 1

Let us first convert the roman numerals to numbers:VI = 6XIV = 14

Step 2

Let us now add the numbers 6 and 14.=> 6 + 14 = 20

Step 3

Let us convert the number 20 back to roman numeral ,i.e., XX.

Step 4

Thus, the sum of the roman numerals VI and XIV is XX.

(4) L C

Remember: In Roman Number system, X can be subtracted from L and C only.



(5) LXXVII seconds

Step 1

First let us convert the given Roman numerals into number forms.

Step 2

Imam runs 100 meters in XXIV seconds, or XXIV = 24 seconds.

Step 3

Jaleel runs the second leg in XVI seconds, or XVI = 16 seconds.

Step 4

Ghada runs the third leg in XX seconds, or XX = 20 seconds.

Step 5

Azra runs the final leg in XVII seconds, or XVII = 17 seconds.

Step 6

The total time taken by them is 24 + 16 + 20 + 17 = 77 seconds.

Step 7

The above sum of 77 seconds can be written in Roman form as LXXVII seconds.



(6) A) XIX

Step 1

We should remember following basic rules to form Roman numerals:

a. Repetitioni. Repetition of a Roman numeral means addition.ii. Only I, X, C and M can be repeated.iii. V, L and D can never be repeated.iv. No numeral can be repeated more than three times.

b. Addition and Subtraction of numeralsi. A smaller numeral written to the right of a larger numeral is always added

to the larger numeral.ii. A smaller numeral written to the left of a larger numeral is always

subtracted from the larger numeral.iii. V, L and D are never subtracted.iv. I can be subtracted from V and X.v. X can be subtracted from L and C.vi. When a smaller numeral is placed between two larger numerals , then it is

always subtracted from the larger numeral immediately following it.vii. Only a single symbol can be subtracted from another single symbol.

Subtraction can not be done with groups of symbols.viii. A symbol can not be subtracted from another one that is more than 10

times greater than it.For example:

We can not write IL to convey 50 - 1 = 49 because L (50 ) is 50times I (1).We can not write LM to convey 1000 - 50 = 950 because M (1000)is 20 times L (50).

Step 2

Based on the above rules, we may break the given number into easy repeating andnon-repeating units of Roman numerals as 10 + 9.

Step 3

The roman numeral for 10 is X and 9 is IX, and since we know that to add two Romannumerals, we write the smaller numeral to the right of the larger numeral. So 19 is XIX.



B) XXIX

Step 1










Step 2

Based on the above rules, we may break the given number into easy repeating andnon-repeating units of Roman numerals as 10 + 10 + 9.

Step 3

The roman numeral for 10 is X and 9 is IX, and since we know that to add two Romannumerals, we write the smaller numeral to the right of the larger numeral. So 29 isXXIX.



C) XXXV

Step 1










Step 2

Based on the above rules, we may break the given number into easy repeating andnon-repeating units of Roman numerals as 10 + 10 + 10 + 5.

Step 3

The roman numeral for 10 is X and 5 is V, and since we know that to add two Romannumerals, we write the smaller numeral to the right of the larger numeral. So 35 isXXXV.



D) XVI

Step 1










Step 2


Step 3

The roman numeral for 10 is X and 6 is VI, and since we know that to add two Romannumerals, we write the smaller numeral to the right of the larger numeral. So 16 is XVI.



E) IV

Step 1










Step 2

As we know there is no direct Roman numeral for 4, and that any Roman numeralcannot be repeated more than three times, another possible way to 4 is 5 - 1.

Step 3

The roman numeral for 5 is V and 1 is I, and since we know that to subtract twoRoman numerals, we write the smaller numeral before the larger one. So 4 is IV.



F) XVI

Step 1










Step 2


Step 3

The roman numeral for 10 is X and 6 is VI, and since we know that to add two Romannumerals, we write the smaller numeral to the right of the larger numeral. So 16 is XVI.



(7) CXX (Dhs120)

Step 1

One box has 12 guavas and the grocer pays Dhs11 per guava. So, the cost for one box = Dhs 11 ×12 = Dhs132.

Step 2

We know that there are 20 such boxes. Therefore, the cost of the entire lot will be equal to Dhs132 × 20 = Dhs2640.

Step 3

According to the question, the loss made on selling the entire lot = Dhs240.Therefore, the selling price = Dhs2640 - Dhs240 = Dhs2400.

Step 4

We know, selling price for 20 boxes = Dhs2400. Therefore, selling price for one box = Dhs 2400

20

= Dhs120.

Step 5

The Roman numeral for 120 is CXX. Hence, the grocer sold each box for CXX.



(8) A) LXXV

Step 1










Step 2


Step 3

The roman numeral for 50 is L, 10 is X and 5 is V, and since we know that to add twoRoman numerals, we write the smaller numeral to the right of the larger numeral. So 75is LXXV.



B) XCV

Step 1










Step 2

Based on the above rules, we may break the given number into easy repeating andnon-repeating units of Roman numerals as 100 - 10 + 5.

Step 3

The roman numeral for 100 is C, 10 is X and 5 is V, and since we know that to add twoRoman numerals, we write the smaller numeral to the right of the larger numeral and tosubtract two roman numerals, we write the smaller numeral to the left of the largernumeral. So 95 is XCV.



C) LX

Step 1










Step 2

Since there is no direct Roman numeral for 60, and that any Roman numeral cannot berepeated more than three times, another possible way to 60 is 50 + 10.

Step 3

The roman numeral for 50 is L and 10 is X, and since we know that to add two Romannumerals, we write the smaller numeral to the right of the larger numeral. So 60 is LX.



D) LXXXI

Step 1










Step 2

Based on the above rules, we may break the given number into easy repeating andnon-repeating units of Roman numerals as 50 + 10 + 10 + 10 + 1.

Step 3

The roman numeral for 50 is L, 10 is X and 1 is I, and since we know that to add twoRoman numerals, we write the smaller numeral to the right of the larger numeral. So 81is LXXXI.



E) C

Step 1










Step 2

As we know there is direct Roman numeral for 100 that is C.



F) LXXVI

Step 1










Step 2


Step 3

The roman numeral for 50 is L, 10 is X and 6 is VI, and since we know that to add twoRoman numerals, we write the smaller numeral to the right of the larger numeral. So 76is LXXVI.



(9) XXX

Step 1

We know that the number of days in the month of April is 30. Now let us write 30 in Romannumerals.

Step 2



b. Addition and Subtraction of numeralsi. A smaller numeral written to the right of a larger numeral is always added to the

larger numeral.ii. A smaller numeral written to the left of a larger numeral is always subtracted from the

larger numeral.iii. V, L and D are never subtracted.iv. I can be subtracted from V and X.v. X can be subtracted from L and C.vi. When a smaller numeral is placed between two larger numerals , then it is always

subtracted from the larger numeral immediately following it.vii. Only a single symbol can be subtracted from another single symbol. Subtraction can

not be done with groups of symbols.viii. A symbol can not be subtracted from another one that is more than 10 times greater

than it.For example:

We can not write IL to convey 50 - 1 = 49 because L (50 ) is 50 times I (1).We can not write LM to convey 1000 - 50 = 950 because M (1000) is 20 timesL (50).

Step 3

Since there is no direct Roman numeral for 30, let us break into numbers that have one. So 30 canbe written as 10 + 10 + 10.

Step 4

The roman numeral for 10 is X, and since we know that to add two Roman numerals, we write thesmaller numeral to the right of the larger numeral. So 30 is XXX.



(10) L

Step 1

The total number of chocolates Aden, Hamal, and Jalil brought to the class is equal to 23 + 14 + 13= 50.

Step 2

We know that 50 can be written using the Roman numerals as L.

(11) c. I

Step 1

We know that New Year's Day is celebrated on 1 of January. We are basically being asked toconvert 1 into Roman numeral. Now let us write 1 in Roman numerals.

Step 2










Step 3

As we know there is direct Roman numeral for 1 that is I.



(12) a. LV

Step 1

Let us first find the sum of their ages in numeral form: 25 + 30 = 55 years.

Step 2

Now we will covert 55 into Roman numerals.

Step 3










Step 4

Based on the above rules, we may break the given number into easy repeating and non-repeatingunits of Roman numerals as 50 + 5.

Step 5

The roman numeral for 50 is L, 10 is X and 5 is V, and since we know that to add two Romannumerals, we write the smaller numeral to the right of the larger numeral. So 55 is LV.

(13) c. >



(14) d. XIII = 15

Step 1

In Roman Number system, we know that XLIX is equal to 49, XII is equal to 12, and XIV is equalto 14. But XIII is equal to 13.

Step 2

Thus, option d. is not correct.



(15) XXXV

Step 1

We know that 5 and 7 in roman numerals can be written as V and VII respectively. But since thereis no method to multiply Roman numbers directly, let us multiply the given natural numbers andconvert their product to Roman numerals.

Step 2

The product of 5 and 7 is 35. Now let us write 35 in Roman numerals.

Step 3










Step 4

Based on the above rules, we may break the given number into easy repeating and non-repeatingunits of Roman numerals as 10 + 10 + 10 + 5.

Step 5

The roman numeral for 10 is X and 5 is V, and since we know that to add two Roman numerals,we write the smaller numeral to the right of the larger numeral. So 35 is XXXV.



Documents

Grade 4 Roman Numerals - TestsStep 4 Ghada runs the third leg in XX seconds, or XX = 20 seconds. Step 5 Azra runs the final leg in XVII seconds, or XVII = 17 seconds. Step 6 The total