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5/19/2018 Hydraulic Structures Chap 8 - 12 June 2009
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Department of Civil Engineering
College of Engineering, UNITEN
Assoc Prof Ir Dr Lariyah Mohd Sidek
E-mail: [email protected]
Lecture NotesCEWB223Hydrology & Hydraulic Engineering
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Chapter 8
Hydraulic StructuresWeir
GatesSpillways
Dams
Department of Civil EngineeringCollege of Engineering, UNITEN
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What is Hydraulic Structures?
Hydraulic structures are used to regulate,measure and/or transport water in openchannels.
These structures are called cont ro lstructureswhen there is a fixedrelationship between the water-surface
elevation upstream or downstream of thestructure and the flow rate through thestructure.
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Type of Hydraulic Structures
Hydraulic structures can be group intothree categories:
(1) flow measuring structures, such as
weirs;
(2) regulation structures, such as gates;
and(3) discharge structures, such as
culverts.
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1. Spillwaycrest/bay
2. Pier
3. Spillway
4. Stilling Basin
5. Armored
Scour
Prevention
bed
6. Section
7. Power
Station
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WEIRS
Weirs are elevated structures in openchannels that are used to measure flowand/or control outflow elevations from
basins and channels. There are two types of weirs in common
use:
(1) sharp-crested weirs, and(2) broad-crested weirs.
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Sharp Crested Weir
Sharp-Crested Weirs, or thin-plate, weirs consistof a plastic or metal plate that is set vertically andacross the width of a channel.
The main types of sharp-crested weirs arerectangularand V-notch weirs.
In suppressed (uncontracted) weirs, therectangular opening spans the entire width of achannel;
In unsuppressed (contracted) weirs, therectangular opening spans only a portion of a
channel.
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Rectangular Weirs
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Flow over a Sharp-Crested Weir
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DERIVATION OF WEIR EQUATION
Assuming that the head loss is negligible along a streamline crossing Section 1,at elevation z1 and leaving Section 2 at elevation z2, then
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DERIVATION OF WEIR EQUATION
The estimated flow rate, , across Section 2 can be calculated by integrating the flow rates across element of area b dz2,where b is the width of the rectangular weir. Therefore
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Assumptions
Their weir equation was derived with the following theoreticaldiscrepancies:
(1) the pressure distribution in the water over the crest of the weir is notuniformly atmospheric;
(2) the water surface does not remain horizontal as the waterapproaches the weir; and
(3) viscous effect that cause a non-uniform velocity and a loss of energy
between Section 1 and Section 2 have been neglected. The error in the flow rate resulting from these theoretical discrepancies
is handled by a discharge coefficient, Cd, defined by the relation
Eq. 1
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It can shown by dimensional analysis that ( Franzini and Finnemore, 1997)
where Re is a Reynolds number,We is a Weber number and
Hw
is the height of the crest of the weir above the bottom of the channel .
Experiments have shown thatH/Hw
is the most important variable affectingCd, with We only important at low heads;
Re is usually sufficiently high that viscous effect can be neglected. An empirical formula forCd is (Rouse, 1946; Blevins, 1984)
Which is valid for H/Hw< 5, and is approximate up to H/Hw= 10. For H/Hw> 15, the discharge can becomputed from the critical flow equation by assuming yc= H (Chaudhry, 1993). It is convenient to
express the discharge formula,
where Cw is called the weir coefficient and is related to the discharge coefficient by
Eq. 3
Eq. 2
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Taking Cd = 0.62 in Equation 2 yields Cw =1.83, and Equation 1 becomes
which gives good result ifH/Hw < 0.4, which is within theusual operating range (Franzini and Finnemore, 1997 ).
Eq. 3.1
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Example 8.1 A weir is to be installed to measure flows in the
range of 0.5-1.0m3/s. If the maximum (total)depth of water that can be accommodated at theweir is 1 m and the width of the channel is 4 m,
determine the height of a suppressed weir thatshould be used to measure the flow rate.
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SOLUTION EXAMPLE 8.1
The flow over the weir is illustrated in Figure 2,where the height of the weir is Hw and the flowrate is Q. The height of the water over crest of the
weir, H, is given by
Assuming that H/Hw< 0.4, then Q is related to Hby Equation 3.1 where
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Taking b = 4m, and Q = 1 m3/s (the maximum flow rate willgive the maximum head, H) then
SOLUTION EXAMPLE 8.1
The height of the weir, Hw, is therefore given by
The initial assumption thatH/Hw< 0.4 is therefore validated and height ofthe weir should be 0.735 m.
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V-Notch Weir A V-Notch weir is a sharp-crested weir that has a V-shaped opening
instead of a rectangular-shaped opening.
These weirs, also called triangular weirs, are typically used instead ofrectangular weirs tend to be less accurate.
V-notch weirs are usually limited to flows of 0.28 m3/s (10cfs) or less.The basic theory of V-notch weirs is the same as the rectangular weirs,where the theoretical flow rate over the weir, , is given
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V-Notch Weir Where b is the width of the V-notch weir at elevation z2
and is given by
Eq. 4
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Discharge Coefficient in V-Notch Weirs
Figure 1
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V-Notch Weir
The vertex angles used in V-notch weirs are usually between 10
and90.
Values ofCd for variety of notch angles,, and heads, Hare plotted inFigure 1.
The minimum discharge coefficient correspondent to a notch angle of
90, and minimum value of C for all angles is 0.581. According to Potter and Wiggert (1991) and white (1994), using Cd =
0.58 for engineering calculations is usually acceptable, provided that20 < < 100 andH> (2 in.). For H < 50mm, both viscous andsurface-tension effects may be important and a recommended value
of Cd is given by (White, 1994)
Eq. 5
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Example 8.2 A V-notch weir is to be used to measure channel flows in
the range 0.1 to 0.2 m3/s. What is the maximum head ofwater on the weir for a vertex angle of 45?
Solution:
The maximum head of water results from the maximumflow, so Q = 0.2 m3/s will be used to calculate themaximum head. The relationship between the head andflow rate is given by Equation 4., which can be put in theform
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Example 8.3
The discharge coefficient as a function ofHfor = 45 is given in Figure 1, andsome iteration is necessary to find H. These iterations are summarized in the
following table
Therefore, the maximum depth expected at the V-notch weir is 2.16ft = 0.66m.
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Gates Gates are used to regulate the flow in open channels.
They are designed for either over flow or underflow operation, with
overflow operation appropriate for channels in which there is asignificant amount of floating debris.
Two common types of gates are vertical gates and radial (Tainter)
gates.
Vertical gates are supported by vertical guides with roller wheels, and
large hydrostatic forces usually induce significant frictional resistanceto raising and lowering the gates.
A radial (Tainter) gate consists of an arc-shaped face plate supported
by radial arms that are attached to a central horizontal shaft that
transmit the hydrostatic force to the supporting structure. Since the
vector of the resultant hydrostatic force passes through the axis of the
horizontal shaft, only the weight of the gate need to be lifted to openthe gate.
Tainter gates are economical to install and are widely used in both
underflow and overflow applications. Structural design guidelines for
several types of gates can be found in Sehgal (1996).
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Gates
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Gates
Applying the energy equation to both vertical and Tainter gates, yields
Where Section 1 and 2 are upstream of the gate, respectively and energylosses are neglected. In terms of the flow rate, Q, leads to
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Gates
The depth of flow downstream of the gate, y2, is less than the gate opening, yg,since the streamlines of the flow contract as they move past the gate. Denoting the
ratio of the downstream depth, y2, to the gate opening, yg, by the coefficient ofcontraction, Cc, where
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Gates
The form of the discharge equation expresses the discharge in terms of anoffice-flow velocity,
times the flow area through the gate, byg, times a discharge coefficient, Cd, to account for deviationsfrom the orifice-flow.
The discharge coefficient depends on the amount of the flow contraction as measured by Cc and yg/y1.
In the case of a vertical sluice gate, it has been found that (Chadwick and Morfett, 1993)
Whenever 0 < yg/E1< 0.5 where E1 is the specific energy of the flow upstream ofthe
Tainter Gate
0 < yg/E1< 0.5
Vertical Sluice Gate
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Gate
In cases where the discharge through the gate opening is supercritical
and the depth of flow downstream of the gate exceeds the conjugatedepth of the gate opening, there is the possibility that the outflow will besubmerged and the discharge equation will not be applicable.
An approximate analysis of the submerged flow condition assumes that allhead losses occur in the flow downstream of the gate, between Section 2
and 3, in which case the energy equation can be written as
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Gate Where y is the depth of flow immediately downstream of
the gate. Between Sections 2 and 3, the momentumequation can be written as
And flow rate, Q, can be estimated by simultaneous solution of
Equations above where y1
and y3
are usually known and y2
is
estimated by Ccy
g
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Example 8.3
Water is ponded behind a vertical gate toa height of 4 m in a rectangular channel ofwidth 7 m. Calculate the gate opening that
will release 40m3/s through the gate. Howwould this discharge be affected by adownstream flow depth of 3.5 m?
http://localhost/var/www/apps/conversion/tmp/Hydraulics/Example%208.3.dochttp://localhost/var/www/apps/conversion/tmp/Hydraulics/Example%208.3.dochttp://localhost/var/www/apps/conversion/tmp/Hydraulics/Example%208.3.dochttp://localhost/var/www/apps/conversion/tmp/Hydraulics/Example%208.3.dochttp://localhost/var/www/apps/conversion/tmp/Hydraulics/Example%208.3.doc5/19/2018 Hydraulic Structures Chap 8 - 12 June 2009
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Spillway?
1. The majority of impounding reservoirs are formed as a result of
the Construction of a dam
2. By its very nature, the stream flow which supplies a reservoir is
variable
3. It follows that there will be times when the reservoir is full and
the stream flow exceeds the demand.
4. The excess water must therefore be discharged safely from
the reservoirs.
5. In many cases to allow the water simply to overtop the dam
would result in a failure of structure.
6. For this reason carefully designed overflow passages known
as spillways are in corporate as part of the dam design
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1. Spillwaycrest/bay
2. Pier
3. Spillway
4. Stilling Basin
5. ArmoredScour
Prevention
bed
6. Section
7. Power
Station
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Spillway?
7. The spillways capacity must be sufficient to accommodate the
largest Flood discharge The probably maximum flood or 1 in
10000 years Flood) likely occur in the life of the dam.
8. Basically spillway is an open channel with large slopes that
allows the excess water to flow over it at super critical
velocities.
9. The ideal longitudinal profile of an overflow spillway should
flow along the same curve as the underside of the tree-falling
water nappe to minimize the pressure on the spillways surface.
10.However, caution must be exercised to avoid any negative
pressure on the surface
11.Negative pressure is caused by separation of the high-speed
flow from the spillway surface, resulting in a ponding action
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Types of Spillway
Chute Spillway
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Types of Spillway
Ogee Spillway
Without Spillway Weir
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Types of Spillway
Bell Mouth/Morning Glory Spillway
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Types of Spillway
Service Spillway
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Types of Spillway
Auxiliary Spillway
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Types of Spillway
Emergency Spillway
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Stilling Basin
Stilling basin is a structure
Without Spillway Weir
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Stilling Basin
Stilling Basin
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Stilling Basin
Baffle Piers
Department of Civil Engineering
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Dams
Definition of DamsAdvantages and Disadvantages of
Dams
Classification of DamsTypes of Dams
Department of Civil Engineering
College of Engineering, UNITEN
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Dams
h t i ?
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What is a Dam?
A dam is a structure built acrossa stream, river or estuary to
retain water.
Dams are made from a varietyof materials such as rock, steel
and wood.
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1. Spillwaycrest/bay
2. Pier
3. Spillway
4. Stilling Basin
5. ArmoredScour
Prevention
bed
6. Section
7. PowerStation
Ad t f D
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Advantages of Dam
Irrigation
Water Supply
Flood Control
Hydroelectric
Recreation
Navigation
Di d t f D
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Disadvantages of Dam
Dams detract from natural settings, ruin nature's workDams have inundated the spawning grounds of fishDams have inhibited the seasonal migration of fishDams have endangered some species of fishDams may have inundated the potential forarchaeological findingsReservoirs can foster diseases if not properlymaintained
Reservoir water can evaporate significantlySome researchers believe that reservoirs can causeearthquakes
Cl ifi ti f D
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Classification of Dams
Storage DamDetention DamDiversion Dam
Coffer DamDebris Dam
Classification based on function
T i l St D
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Typical Storage Dam
Srinagarind Dam
Vajiralongkorn Dam
T i l St D
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Typical Storage Dam
Maeklong Dam
Tha Thung Na Dam
Cl ifi ti f D
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Classification of Dams
Classification based on hydraulic design
Classification based on material of construction
Overflow Dam/Overfall Dam
Non-Overflow Dam
Rigid DamNon Rigid Dam
Cl ifi ti f D
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Classification of Dams
Classification based on structural behavior
Gravity Dam
Arch DamButtress DamEmbankment Dam
G it D
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Gravity Dam
Gravity dams are dams which resistthe horizontal thrust of the water
entirely by their own weight.
Concrete gravity dams are typically
used to block streams throughnarrow gorges.
G it D
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Gravity Dam
Cross Section Plain View
Arch Dam
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Arch Dam
An arch dam is a curved damwhich is dependent upon archaction for its strength.
Arch dams are thinner andtherefore require less material thanany other type of dam.
Arch dams are good for sitesthat are narrow and have strongabutments.
Arch Dam
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Arch Dam
Cross Section Plain View
Buttress Dam
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Buttress Dam
Buttress dams are dams in which theface is held up by a series of
supports.
Buttress dams can take manyforms - the face may be flat orcurved.
Buttress Dam
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Buttress Dam
Cross Section Plain View
Embankment Dam
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Embankment Dam
Embankment dams are massivedams made of earth or rock.
They rely on their weight toresist the flow of water.
Embankment Dam
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Embankment Dam
Cross Section Plain View
Types of Dam
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Types of Dam
Types of Dam
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Types of Dam
Factors governing selection
of types of dam
A Narrow V-Shaped Valley : Arch DamA Narrow or Moderately with U-ShapedValley : Gravity/Buttress DamA Wide Valley : Embankment Dam
Topography-Valley Shape
Types of Dam
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Types of Dam
Factors governing selection
of types of dam
Solid Rock Foundation : All typesGravel and Coarse Sand Foundation :Embankment/Concrete Gravity Dam(H15 m)
Silt and Fine Sand Foundation :Embankment/Gravity Dam (H8 m)Non-Uniform Foundation : -
Geology and Foundation Condition
Types of Dam
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Types of Dam
Factors governing selection
of types of dam
Climate conditionsAvailability of construction materials
Spillway size and locationEnvironmental considerationsEarthquake zoneOverall cost
General considerations
Hydropower Plant
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Hydropower Plant
InsideHydropower plant
Hydropower Plant
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Hydropower Plant
Hydropower Plant
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Hydropower Plant
Generator
Turbine
Hydropower Energy Calculation
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P
E
= n. .Q.H
T
------------------ 9.1)
PE = Power (kW)
n = Efficiency (%)
= Specific Weight of Water (9.81 kN/m3)
Q = Water Discharge (cms)
HT = Head (m)
E = PE.T ------------------(9.2)
E = Energy (kWh)
T = Time (h)
Hydropower Energy Calculation
Three Gorges Dam
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Three Gorges Dam
Three Gorges Dam
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Three Gorges Dam
Type: Concrete Gravity DamCost: Official cost $25bn - actualcost believed to be much higherWork began: 1993Due for completion: 2009Power generation: 26 turbines onleft and right sides of dam. Sixunderground turbines planned for2010Power capacity: 18,000megawattsReservoir: 660km long,submerging 632 sq km of land.
When fully flooded, water will be175m above sea levelNavigation: Two-way lock systembecame operational in 2004.One-step ship elevator due toopen in 2009.
Three Gorges Dam
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Three Gorges Dam
Three Gorges Dam
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Three Gorges Dam
Shipping Locks
Shipping Locks
CASE STUDY : The Malaysia Mega Project Bakun
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CASE STUDY : The Malaysia Mega Project BakunHydroelectric Project (Bakun HEP) in Rejang River
Basin, Sarawak.
The Bakun dam is a 205-meter-high Concrete Face Rockfill Dam
(CFRD), with a length of crest of 740 meters, a base width of 560meters and a crest width of 12 meters. It can generate 2400MW(max). This makes it one of the highest rockfill dams in the worldafter China. It will flood 69,640 hectares of land, an area as size ofSingapore.
Diversion Inlet
Diversion Outlet Auxiliary Cofferdam
Reservoir
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Engineering contribution to Bakun HEP
This project is fully contributed by latest technology with theknowledge and experience of engineers.
Mechanical Engineers turbine design water flow (penstock) Control gate
Electrical Power Engineers transformer Generator Power line
Civil Engineers Designing Mixture of concrete The strength of tunnel
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Positive Impact to the project
Regulation of river flow
Generates economy
Mitigation of floods
Reduces fossil fuel consumption
Reducing CO2 emissions
Carbon Dioxide Emission and Contribution To Global Warming
Source Environmental & Natural
Resource Implications
Carbon Dioxide
Emission(g/mj)1Relative Ratio of Contribution to
Global Warming
Hydro Clean and renewable 7.1 1
Natural Gas Moderately clean and depletable 171-188 24-26
Fuel Oil Polluting and depletable 204 29
Coal Polluting and depletable 831-1938 117-273
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Negative Impact to the project
Highly cost more than RM 11.36 billions (1994)
Destroying the rainforest affecting 105 species of animals protectedunder Malaysian wildlife legislation and innumerable plant species.
Resettlement - All the 15 affected communities will be resettled inareas near the Belaga River, about 30 kilometres from the Bakun damsite
Reservoir water quality - Decay of submerged forests can upset theecological balance of the area, leading to loss of water quality
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Pergau Hydroelectric Scheme
Type of Dam: Earthfill
Y f C l ti 1996
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Kuala Yong Dam
Year of Completion: 1996
Crest Length: 750m
Height of Dam: 75m
Photo courtesy of En. Mohd Khanil
Taib
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Power Intake
After Reservoir Filling
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