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DESCRIPTION
Quantum Mechanics
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HYDROGENMOLECULE ION
-e
+e
+e
r1
r2
R
HYDROGENMOLECULE ION
π» = ββ2
2ππ»2 β
π2
4ππ0(1
π1+
1
π2)
π = π΄ π0 π1 β π0 π2
π0 π =1
ππ3πβ π π
1 = πβ2π3π
1 = π΄ 2 π0(π12π3π + π0(π2
2π3π β 2 π0(π1 π0(π2 π3π
1 1π0
I
π΄ 2 =1
2(1 β πΌ
πΌ = π0(π1 π0(π2 π3π
=1
ππ3 πβ(π1+π2 π π3π
ππ = ππ + πΉπ β πππΉππππ½
ππ = π
πΉ
πΌ =1
ππ3 πβ π ππβ π2+π 2β2ππ πππ π π π2π πππππππππ
π 2π
π π¦ = π2 + π 2 β 2ππ πππ π. π π¦2 = 2π¦ππ¦ = 2ππ π πππππ
0
π
πβ π2+π 2β2ππ πππ π π π πππππ
π = π
π = 0 π¦ = π β π
π¦ = π + π =
1
ππ πβπ
π+π
πβ π¦ π π¦ππ¦
= βπ
ππ πβ
πβπ π π + π + π β πβ
πβπ π ( π β π + π
0
β
πβππ₯π₯π ππ₯ =π!
ππ
πΌ =2
π2π βπβ π π
0
β
π + π + π πβ2ππ πππ + πβ
π π
0
π
π β π + π πππ + π π π π
β
π β π + π πβ2 π ππππ
πΌ = πβ π π 1 +π
π+1
3
π
π
2
π» = ββ2
2ππ»2 β
π2
4ππ0(1
π1+
1
π2)
ΓΆ π»π = πΈπ
ββ2
2ππ»2 β
π2
4ππ0π1,2π0 π1,2 = πΈ1π0(π1,2)
π»πβ = π΄ ββ2
2ππ»2 β
π2
4ππ0(1
π1+1
π2π0 π1 β π0 π2 = πΈ1π β π΄(
π2
4ππ0 π0 π1π1
βπ0 π2π2
π0(π1,2
π» = πΈ1 β π π΄ 2(π2
4ππ0 π0 π1
1
π2π0 π1 β π0 π1
1
π1π0 π2
π· = π0 π1π
π2π0 π1
π = π0 π1π
π1π0 π2
π· =π
π β (1 +
π
π πβ2 π π
π = (1 +π
π πβ π π
π» = 1 + 2π· β π
1 β πΌπΈ1
πΌ = πβ π π 1 +π
π+1
3
π
π
2
πππ =π2
4ππ0
1
π = β
2π
π πΈ1
πΈπ‘ππ‘ = π» + πππ
πΈπ‘ππ‘ = 1 + 2π· β π
1 β πΌβ2π
π πΈ1
πΉ π₯ =πΈπ‘ππ‘βπΈ1
πΉ π₯ = β1
πΈ11 + 2
π· β π
1 β πΌβ2π
π πΈ1 =
2π
π β 1 β 2
π· β π
1 β πΌ
πΉ π₯ = β1 +2
π₯β 2
1π₯ β 1 +
1π₯ πβ2π₯ β (1 + π₯ πβπ₯
1 β πβπ₯(1 + π₯ +π₯2
3
= β1 +2
π₯
1π₯ β 1 + π₯ +
π₯2
3 πβπ₯ β 1 + π₯ + 1 πβ2π₯ + (π₯ + π₯2 πβπ₯
1 β πβπ₯(1 + π₯ +π₯2
3
πΉ π₯ = β1 +2
π₯
2π₯2
3β 1 πβπ₯ + (1 + π₯ πβ2π₯
1 β πβπ₯(1 + π₯ +π₯2
3
-1.2
-1
-0.8
-0.6
-0.4
-0.2
0
0 1 2 3 4 5 6 7 8 9
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