Advanced Supplementary LevelPaper 1

lexo(0.01 kg)(lO m S-2)

5Nm-1

0.02m

~lex22 I

2 (0.01 kg)(10 m S-2)

5Nm-1

0.04m

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(c) mg- lex = mx

kxo - lex = mx C: mg = lexo)

-k(x - xc) = mx

[Or Put y = x - Xo , mg - k (y + xc) = my- ky = my C: mg = lexo)]

(5 N m-I)(0.04 m)0.2N

Amplitude increases (doubled) because equilibrium position lowered.I

Frequency of oscillation decreases (by a factor of .fi) as the mass of the system

(doubled).(m2 =~)m

(b) (i) ()= (273 °39' - 224°30')/2 = 24.58 °1 0

Percentage error in ()= [- 724.58 O]x 100%=0.07%60

(ii) Eliminate the systematic error, if any, associated with the central position reading.Or Reduce the percentage error in B.

First-order diffraction angle () A (run) sin ()

Red 24.58° 656.3 0.416Cyan 17.94° 486.1 0.308Blue 15.96° 434.1 0.275

Violet 15.07° 410.2 0.260

AI run

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4000.26

Axes labelled with appropriate scalesPoints correctly plottedCorrect graph

Grating spacing = slope of the graph

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(= _1_ if sin () Vs A is plotted)slope

sinS = nA = n 410.2 :51d 1571

n ~ 3.83, highest order is 3.

(b) No, the length L is measuring the p.d. across the resistance box or the terminal p.d. of the battery.Or No, it is measuring E - Ir since there is internal resistance r.

E = I (r + R)

E = rkL + kLR

Ell 1--=-+-krL R r1 1 1

- = constant x ---R L r

The negative intercept on the ~ axis = 0.01 a-IR

1The internal resistance of the battery r = --= 100 a

0.01

(e) Unchanged.The p.d. VAC corresponds to the same L.

pV nRT(1.00x 105 Pa)(300x 10-{jm3) = n (8.31 J mo1-1 K-I)(273 + 27 K)

n = 0.012 (mole)

I -pV =-Nmcz

3

,f;f = 3 (1.00 x 105 Pa)(300x 10-6 m 3)

(0.012 mol)(4.00x 10-3 kg morl)

=1.369x103 ms-I

v; Vz-=-T; Tz

20 em h(273 + 27K) (273 + 90K)

h = 24.2 em

!!l.. _-!!2.(or PIV] = P2V2)

T] T2

1.00x105Pa P2(273+ 27K) (273+90K)

P2 =1.21x105pa

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t1p = mgA

(1.21-1.00)xl05pax 300 xlO-4m2

m= 2010 m 5-2

2Paper2 Section B

Q.l Please refer to Q.l of Paper 2B of A-level

Q.2 Please refer to Q.2 of Paper 2B of A-level

Q.3 Please refer to Q.3 of Paper 2B of A-level

2 Q.4 Please refer to Q.4 of Paper 2B of A-level