12
Term 2 Week 5 Whole numbers Monday 11-05-2020 Addition and subtraction Tuesday 12-05-2020 Multiplication and division Wednesday 13-05-2020 Order of operation (BODMAS) Thursday 14-05-2020 Double and half Friday 15-05-2020 Properties of whole numbers KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER WORK DURING LOCKDOWN TERM 2 WEEK 5 TEACHER: MR. A. DU PLESSIS

KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

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Page 1: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

Term 2 Week 5 – Whole numbers

Monday 11-05-2020 Addition and subtraction

Tuesday 12-05-2020 Multiplication and division

Wednesday 13-05-2020 Order of operation (BODMAS)

Thursday 14-05-2020 Double and half

Friday 15-05-2020 Properties of whole numbers

KWAGGASRAND SCHOOL

MATHEMATICS

YEAR 3

LEARNER WORK DURING LOCKDOWN

TERM 2 WEEK 5

TEACHER: MR. A. DU PLESSIS

Page 2: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

LESSON 16

ADDITION AND SUBTRACTION

1. Solve the following addition and subtraction problems. You are allowed to use a

calculator.

a) 4 506 + 328 + 14 854 = __________________

b) 67 542 – 35 487 + 14 202 = __________________

c) 321 548 – 50 458 – 32 024 = __________________

d) 16 241 + 35 102 – 2 684 = __________________

e) 548 658 – 158 654 – 36 487 = __________________

f) 334 587 + 694 658 + 450 000 = __________________

g) 5 545 321 – 1 000 478 – 354 215 = __________________

h) 225 635 + 22 545 468 – 13 458 654 = __________________

i) 55 658 014 – 25 781 002 + 2 354 = __________________

j) 12 548 + 354 687 + 5 658 471 = __________________

k) 66 545 487 – 658 741 – 60 784 = __________________

l) 350 + 5 684 + 45 689 + 124 784 + 3 521 004 = __________________

m) 35 548 691 – 9 641 027 – 801 258 – 55 689 – 4 321 – 464 = ________________

2. Round the following numbers off to the nearest 10, 100, 1000 and 10 000

Number ≈ 10 ≈ 100 ≈ 1 000 ≈ 10 000

Ex. 45 854 635 45 854 640 45 854 600 45 855 000 45 850 000

a) 12 568

b) 312 584

c) 1 235 892

d) 35 400 158

e) 45 589

f) 33 421

g) 452 312

h) 12 548 355

i) 658 461

Page 3: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

3. Write the following numbers in expanded notation. You can use any method

you have learned.

Example: 12 658 442

10 000 000 + 2 000 000 + 600 000 + 50 000 + 8 000 + 400 + 40 + 2

Or

(1 x 10 000 000) + (2 x 1 000 000) + (6 x 100 000) + (5 x 10 000) + (8 x 1 000)

+ (4 x 100) + (4 x 10) + (2 x 1)

Or

1TM + 2M + 6HTH + 5TTH + 8TH + 4H + 4T + 2U

a) 4 501 = ______________________________________________________

____________________________________________________________

b) 68 410 =_____________________________________________________

____________________________________________________________

c) 126 375 = ____________________________________________________

____________________________________________________________

d) 581 851 = ____________________________________________________

____________________________________________________________

e) 2 305 749 = __________________________________________________

____________________________________________________________

f) 5 483 004 = __________________________________________________

____________________________________________________________

g) 32 548 452 = _________________________________________________

____________________________________________________________

h) 75 620 847 = _________________________________________________

____________________________________________________________

Page 4: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

LESSON 17

MULTIPLICATION AND DIVISION

1. Use long multiplication to solve the following multiplication problems.

You can follow the link below to see an example:

https://www.youtube.com/watch?v=GKetIwxaenA

Example:

a) 365

x 5

______

b) 564

x 23

________

+________

_________

c) 2 358

x 36

__________

+_________

__________

2 2 1

3 4 2

1 1

4 6 9 4

x 3 5 2

19 3 8 8

2 23 4 7 0 0

+ 1 4 0 8 2 0 0

1 6 5 2 2 8 8

Step 1: Multiply all the top digits individually with the 2 (unit place value). 4 x 2 = 8 9 x 2 = 19 (write 9 carry the 1) 6 x 2 = 12 + 1 that was carried = 13 (write 3 carry 1) 4 x 2 = 8 + 1 that was carried = 9

Before starting with step 2, write a 0, because we are working with the tens place value next. Step 2: Multiply all the top digits individually with the 5. 4 x 5 = 20 (write 0 carry the 2) 9 x 5 = 45 + 2 that was carried = 47 (write 7 carry the 4) 6 x 5 = 30 + 4 that was carried = 34 (write 4 carry 3) 4 x 5 = 20 + 3 that was carried = 23

Before starting with step 3, write two zeros, because we are working with the hundreds place value next. Step 3: Multiply all the top digits individually with the 3 (hundreds place value). 4 x 3 = 12 (write 2 carry the 1) 9 x 3 = 27 + 1 that was carried = 28 (write 8 carry the 2) 6 x 3 = 18 + 2 that was carried = 20 (write 0 carry 2) 4 x 3 = 12 + 2 that was carried = 14 Final step. Add the three answers together that you just

calculated.

Page 5: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

d) 3 671

x 3

_______

e) 534

x 243

___________

___________

+__________

___________

f) 2 463

x 348

___________

___________

+__________

___________

g) 3 672

x 582

___________

___________

+__________

___________

h) 6 904

x 449

___________

___________

+__________

___________

i) 3 618

x 257

___________

___________

+__________

___________

j) 2 376

x 342

___________

___________

+__________

___________

Page 6: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

2. Use long division to solve the following problems.

You can follow the link below to see an example:

https://www.youtube.com/watch?v=M3D3L1iIzks

Example: 6 328 ÷ 230

0027 r118 230 6328

- 460 1728 - 1610 0118

a) 256 ÷ 7

__________________

__________________

__________________

__________________

__________________

__________________

b) 3458 ÷ 3

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

You are allowed to use your calculator to assist

you in doing these calculations.

Step 1: 632 ÷ 230 = 2,74782….. the number

infront of the comma tells you how many

times 230 can go into 632. In this case 230

goes into 632, 2 times.

Step 2: 2 x 230 = 460

Step 3: 632 – 460 = 172

Step 4: Bring down the 8.

Repeat all steps above.

Step 1: 1728 ÷ 230 = 7,5130… (write 7)

Step 2: 7 x 230 = 1610

Step 3: 1728 – 1610 = 118

Step 4: No more numbers to bring down. You

are done with the calculation. Whatever is left

becomes your remainder.

No more numbers to bring down. Can

230 go into 118. The answer is no,

therefor it becomes the remainder.

Page 7: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

c) 6814 ÷ 26

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

d) 8435 ÷ 45

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

e) 4594 ÷ 225

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

f) 23584 ÷ 315

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

g) 354924 ÷ 450

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

h) 9648 ÷ 233

__________________

__________________

__________________

__________________

__________________

__________________

__________________

__________________

Page 8: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

LESSON 18 ORDER OF OPERATION (BODMAS)

You can follow the link to see an example:

https://www.youtube.com/watch?v=dAgfnK528RA

1. Complete the following calculations without a calculator.

a) 5 + 2 x 3

_____________________

_____________________

_____________________

_____________________

b) 2 x 2 ÷ 4

_____________________

_____________________

_____________________

_____________________

c) 12 + 28 ÷ 4

_____________________

_____________________

_____________________

_____________________

d) ( 2 + 5 ) x 4

_____________________

_____________________

_____________________

_____________________

e) 12 x (15 – 3)

_____________________

_____________________

_____________________

_____________________

f) 36 ÷ 3 x 8

_____________________

_____________________

_____________________

_____________________

g) (12 x 3 ) – (5 x 5)

_____________________

_____________________

_____________________

_____________________

h) 12 + 8 x 3 + 15

_____________________

_____________________

_____________________

_____________________

i) 16 – 8 ÷ 4 x 5

_____________________

_____________________

_____________________

_____________________

j) 36 ÷ 3 + 5 x 5 - 15

_____________________

_____________________

_____________________

_____________________

k) 5 x 6 + (9 x 15) – 50

_____________________

_____________________

_____________________

_____________________

l) (200 ÷ 4) x 2 – 40 +15

_____________________

_____________________

_____________________

_____________________

( ) OF X +

÷ - Brackets Of Times / divide Plus / Minus

Page 9: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

LESSON 19

DOUBLE AND HALF

Double means we multiply by 2. (___ x 2)

Half means we divide by 2. (___ ÷ 2)

You are allowed to use your calculator.

1. Double each of the following numbers.

a) 25 = ______ b) 33 = ______ c) 45 = ______

d) 63 = ______ e) 243 = ______ f) 368 = ______

g) 89 = ______ h) 122 = ______ i) 146 = ______

j) 435 = ______ k) 622 = ______ l) 1 242 = ________

m) 2 458 = _________ n) 6 845 = _________ o) 34 548 = _________

p) 54 584 = _________ q) 248 124 = _________ r) 515 021 = _________

s) 1 014 584

= _______________

t) 2 358 685

= ________________

u) 52 684 210

= ________________

2. Half each of the following numbers.

a) 16 = ______ b) 42 = ______ c) 66 = ______

d) 86 = ______ e) 122 = ______ f) 268 = ______

g) 462 = ______ h) 844 = ______ i) 1 054 = ______

j) 1 566 = ______ k) 4 568 = ______ l) 8 432 = ________

m) 15 610 = _________ n) 24 578 = _________ o) 46 946 = _________

p) 79 136 = _________ q) 154 332 = _________ r) 339 750 = _________

s) 1 014 584

= _______________

t) 2 358 680

= ________________

u) 52 684 218

= ________________

Page 10: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

LESSON 20

PROPERTIES OF WHOLE NUMBERS

- Addition and subtraction are inverse operations of one another, meaning

that they are opposites of one another.

6 + 4 = 10

10 – 6 = 4

- Multiplication and division are inverse operations of one another, meaning

that they are opposites of one another.

6 x 2 = 12

12 ÷ 6 = 2

You can follow the link to see how inverse operations work.

https://www.youtube.com/watch?v=D695SVFf8As

- The word identity element simply means that whatever number you are

working with will remain the same. The number does not change.

You can follow the link to see an explanation.

https://www.youtube.com/watch?v=Vkk1SjfE6mI

- 0 is the identity element for addition: t + 0 = t

(t represents any number)

t = 50

then

t + 0 = t

is actually

50 + 0 = 50

- 1 is the identity element for multiplication: t x 1 = t

(t represents any number)

t = 50

then

t x 1 = t

is actually

50 x 1 = 50

Page 11: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

1. Find the missing numbers by make use of the inverse operation method.

a) 5 + ____ = 15

15 - ____ = 5

b) 20 - ____ = 5

5 + ____ = 20

c) ____ + 25 = 40

40 - ____ = 25

d) ____ - 30 = 40

40 + 30 = ____

e) 150 + 75 = _____

_____ - 75 = 150

f) _____ + 450 = 750

750 – _____ = 450

g) 1 500 – 350 = _______

_______ + 350 = 1500

h) 5 675 + _______ = 6 000

6 000 – 5 675 = _______

i) 12 584 - ________ = 2 584

2 584 + ________ = 12 584

j) 60 846 + 24 584 = __________

__________ - 60 846 = 24 584

k) 4 x 5 = _____

_____ ÷ 5 = 4

l) 15 ÷ ____ = 5

5 x ____ = 15

m) _____ x 10 = 200

200 ÷ _____ = 10

n) 125 ÷ 5 = _____

_____ x 5 = 125

o) 136 x _____ = 816

816 ÷ 136 = _____

p) 234 ÷ 26 = _____

_____ x 26 = 234

q) ______ x 6 = 3 108

3 108 ÷ 6 = _______

r) _______ ÷ 45 = 358

358 x 45 = ________

s) 60 x 550 = __________

________ ÷ 550 = 60

t) 256 152 ÷ 78 = _________

_________ x 78 = 256 152

Page 12: KWAGGASRAND SCHOOL MATHEMATICS YEAR 3 LEARNER … 3... · t 13 43 67 142 333 657 2 457 31 567 425 789 = 13 1 x t = t t 23 52 87 93 153 634 6 789 12 435 843 124 = 23 . Author: Ghost

2. Complete the following tables by replace the t with the given numbers.

t + 0 = t

t 1 25 63 243 536 1 021 5 200 10 215 251 684

= 1

0 + t = t

t 43 62 422 674 2 341 3 687 9 423 13 487 321 543

= 43

t x 1 = t

t 13 43 67 142 333 657 2 457 31 567 425 789

= 13

1 x t = t

t 23 52 87 93 153 634 6 789 12 435 843 124

= 23