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Quality Engineering
Quality
• Defined in different terms by different quality Gurus: Deming, Juran, Crosby, Feigenbaum
• Western philosophers explained quality in terms of presence of certain characteristics
• Taguchi defines quality in terms of loss due to absence of quality
• This thinking influenced by Zen philosophy
Quality
• Quality is measured in terms of total loss to society due to functional variation and harmful side effects
• When the product performance meets the target performance, the loss is zero
• Any deviation from the target incurs loss• Greater the deviation, greater the loss• Explained by Taguchi’s Loss Function
• The traditional (Western) model for quality losses– No losses when the product is within the specification limits
Quality Loss Function
• The Taguchi loss function – Quality loss is zero only if the product achieves target specification
Scrap Cost
LSL USLTarget
Cost
Freq.
XTarget USLLSL
1. All products within specifications equally good,2. All products beyond specifications equally bad
A study found U.S. consumers preferred Sony TVs made in Japan to those made in the U.S. Both factories used the same designs & specifications. The difference in quality goals made the difference in consumer preferences.
Sony-Japan
(Target-oriented)
Sony-US (Conformance-oriented)
Fraction Defective Fallacy
Quality Loss FunctionF
req
uen
cy
Target UpperLower
Target-oriented quality yields more product in the "best" category
Distribution of Specifications for Products Produced
Conformance-oriented quality keeps products within 3 standard deviations
Lo
ss
High Loss
Low Loss
Unacceptable
Poor
Fair
Good
Best
Quality Loss Function
• Loss L(y) = k*(y-m)2
• When y=m, Loss = 0
• When functional limits are m±Δ0, and
• Loss at y±Δ0 = A0, then
• k = A0 /Δ02
The repair cost for an engine shaft is Rs. 100. The shaft diameter is required to be 101 mm. On average the produced shafts deviates 0.5 mm from target. Determine the mean quality loss per shaft using the Taguchi QLF.Solution: k = 100/(1)2=100,
L(y) = 100*(0.5)2 = Rs. 25
Quality Loss Function Example 1
The specifications for the diameter of a gear are 25.00 ± 0.25 mm. If the diameter is out of specification, the gear must be scrapped at a cost of Rs. 4.0/ unit. What is the unit loss?
Solution: k = 4/(0.25)2=64,
L(y) = 64*(0.25)2 = Rs. 4
Quality Loss Function Example 2
Different Quality Loss Functions
i. Smaller-the-better: L(y) = ky2
ii. Larger-the-better: L(y) = k/y2
iii. Asymmetric loss function: For example,
L(y) = k1*(y-m)2 , when y > m, and
= k2*(y-m)2 , when y ≤ m
Causes of Variation - Noise Factors
Product variationi. External: Variation
in the environment in which the product is used
ii. Unit-to-unit: Variation due to process
iii. Deterioration: Wear and tear due to usage
Process variationi. External: Environment
in which process is carried out
ii. Non-uniformity of the process: Spatial variation in the output
iii. Process drift: Temporal variation in the output
Average Quality Loss
• Average quality loss Q = k [(μ-m)2+σ2]
• Two components– deviation from target, and – variance around mean
• Adjusting mean of the process is easy, but variation reduction is difficult
Variation Reduction• Three approaches to variation
reductioni. Screening out bad productii. Discovering and eliminating the
cause of malfunction (tolerance tightening)
iii. Applying robust design methods (finding and exploring nonlinearity)
Goal of Robust Design
• To exploit the nonlinearity of the relationships among the parameters, the noise factors and the quality characteristics
• To find a combination of parameter values that result into the smallest variation of the quality characteristic around the target value under nominal noise conditions
Classification of Parameters
Product / ProcessM
Signal factor
z Noise factors
x Control factors
y
Response
Engineering Design Problem
i. Concept design
ii. Parameter design
iii. Tolerance design
• Quality Engineering includes (ii) and (iii)
Stage of product
realization
Quality control activity
Ability to reduce effect of
External var.
Unit-to-unit var.
Drift
Product design
Concept design Y Y YParameter design Y Y YTolerance design Y Y Y
Process design
Concept design N Y NParameter design N Y NTolerance design N Y N
Manufacturing
Detection/ correction N Y NFeed-forward control N Y NScreening N Y N
Usage Warranty / Repair N N N
Assignment No. 1
• Following measurements were taken on two batches of a machined component for which the tolerance limits were 25.00 ± 0.25 mm. The cost of scrapping a nonconforming unit is Rs.4. Construct a histogram, estimate loss per unit part for each size and calculate total loss and average loss for the two batches. Interpret the results.
Batch 1
25.01 24.89 24.98 25.00 24.97
25.04 24.97 24.98 25.01 25.02
25.04 25.01 24.85 25.00 24.97
24.92 25.03 24.98 24.92 25.05
24.90 25.03 25.03 25.02 24.98
24.91 25.01 24.96 25.01 25.10
24.95 24.96 25.02 24.98 24.99
25.10 24.95 25.04 25.06 25.03
24.96 25.03 25.11 25.00 25.04
25.02 25.12 25.01 25.07 25.02
Batch 2
25.09 24.95 24.91 25.02 24.93
25.06 24.87 25.00 25.19 25.18
24.84 25.18 25.16 25.05 25.04
24.99 25.07 24.88 25.01 24.99
24.92 25.01 25.00 24.95 25.04
25.15 25.12 25.11 25.14 25.29
24.72 24.74 24.81 24.90 25.12
24.96 24.99 25.17 25.14 25.11
25.18 24.92 25.09 24.89 24.91
25.18 25.09 25.23 24.72 25.11