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Hydromechanics: Course Summary
Hydromechanics VVR090
Material Included;
• French: Chapters 1 to 9 and 14 + Sample problems
• Vennard & Street: Chapters 8 + 13, and 11 (part of it)
• Roberson & Crowe: Chapter 11
• Collection of sample problems in open channel flow
Exam:
28th of May 1400 – 1900 in MA10G
2
Fundamental Equations
Conservation of mass:
Q uA=
Conservation of momentum:
2 1( )F Q u u= ρ −∑
Conservation of energy:
2
1 2
2
L
uH z yg
H H h
= + +
= +
Laboratory Experiments
Often difficult to solve fluid flow problems by analytical or numerical methods. Also, data are required for validation.
The need for experiments
Difficult to do experiment at the true size (prototype), so they are typically carried out at another scale (model).
Develop rules for design of experiments and interpretation of measurement results.
3
Similitude and Dimenisional Analysis
Similitude: how to carry out model tests and how to transfer model results to prototype (laws of similarity)
Dimensional analysis: how to describe physical relationships in an efficient, general way so that the extent of necessary experiments is minimized (Buckingham’s P-theorem)
Basic Types of Similitude
• geometric
• kinematic
• dynamic
All of these must be obtained for complete similarity between model and prototype.
= = λp p
m m
d ld l
4
Important Forces for the Flow Field
• pressure (FP)
• inertia (FI)
• gravity (FG)
• viscosity (FV)
• elasticity (FE)
• surface tension (FT)
Dimensionless Numbers
• Reynolds
• Froude
• Cauchy (Mach)
• Weber
• Euler
2 22
2
2
Re/
Fr
C/
W
E2
= =μ ρ ν
=
= = =ρ
ρ=
σρ
=Δ
Vl Vl
Vgl
V V ME c
lV
Vp
Dimensionless numbers same in prototype and model produces dynamic similarity.
5
Dimensional Analysis
Dimensions (e.g., length, mass, time, temperature)
Units (e.g., m, kg, s, K)
Three independent dimensions of primary interest:
• length (L)
• mass (M)
• time (t)
Force: [ ] 2=MLFt
Metric system
Buckingham’s P-Theorem
Buckingham provided a systematic approach to dimensional analysis through his theorem expressed as:
1. If n variables are involved in the problem, then k equations of their exponents can be written
2. In most cases k is the number of independent dimensions (e.g., M, L, t)
3. The functional relationship may be expressed in terms of n-k distinct dimensionless groups
6
Example of Dimensional Analysis
Drag force (D) on a ship. Assume that D is related to length (l), density (ρ), viscosity (m), speed (V), and acceleration due to gravity (g):
{ }, , , , , 0ρ μ =f D l V g
Problem involves n = 6 variables and k = 3 fundamental dimensions Æ k - n = 6 – 3 = 3 dimensionless groups can be formed:
{ }1 2 3' , , 0Π Π Π =f
Many different ways to combine the variables into dimensionless groups – rational approach needed.
Method for Deriving Dimensionless Groups
1. Find the largest number of variables which do not form a dimensionless P-group
2. Determine the number of P-groups to be formed
3. Combine sequentially the variables in 1. with the remaining variables to form P-groups.
Present example: select ρ, V, and l and combine with remaining variables:
{ }{ }{ }
1 1
2 2
3 3
, , ,
, , ,
, , ,
Π = ρ
Π = μ ρ
Π = ρ
f D V l
f V l
f g V l
7
First P-group:
1Π = ρa b c dD V l
Analyze dimensions:
( )0 0 02 3
: 0: 0 3
: 0 2
⎛ ⎞ ⎛ ⎞ ⎛ ⎞= ⎜ ⎟ ⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠ ⎝ ⎠
= += − + += +
a b cdML M LM L t L
t L t
M a bL a b c dt a c
22
= −= −= −
b ac ad a
1 2 2
⎛ ⎞Π = ⎜ ⎟ρ⎝ ⎠
aD
l VResult:
Fluid Flow About Immersed Objects
Flow about an object may induce:
• drag forces
• lift forces
• vortex motion
Asymmetric flow field generates a net force
Drag forces arise from pressure differences over the body (due to its shape) and frictional forces along the surface (in the boundary layer)
8
sin cos= θ + τ θ∫ ∫ oA A
D p dA dA
Drag force:
Pressure drag (Dp) Frictional drag (Df)
(form drag)
Pressure drag function of the body shape and flow separation
Frictional drag function of the boundary layer properties (surface roughness etc)
Results of Dimensional Analysis
{ }
2
3
12Re,M
D o
D
D C AV
C f
= ρ
=
Total drag force:
Total lift force:
{ }
2
4
12
Re,M
L o
L
L C AV
C f
= ρ
=
9
Drag Coefficient for Various Bodies
2D 3D
Example of Drag Force Calculation
• parachute jumping
• sedimentation of particle
• popcorn popper
Basic equation for drag force:
212
= ρD oD C AV
CD obtained from empirical studies
A is the projected area on a plane perpendicular to the flow direction
10
Vortex Shedding
Under certain conditions vortices are generated from the edges of a body in a flow.
Æ Von Karman’s vortex street
Vortex street behind a cylinder
Vortices at Aleutian IslandIf 6 < Re < 5000, regular vortex sheeding may occur at a frequency ndetermined by Strouhal’s number:
=o
ndSV (S = 0.21 over a wide range of Re)
Boundary Layer on a Flat Plate
Boundary layer: the zone in which the velocity profile is governed by frictional action
11
Drag Coefficient for Smooth, Flat Plates
212f f oD C V A= ρ
A: surface area of plate
Open Channel Flow
Open channel: a conduit for flow which has a free surface
Free surface: interface between two fluids of different density
Characteristics of open channel flow:
• pressure constant along water surface
• gravity drives the motion
• pressure is approximately hydrostatic
• flow is turbulent and unaffected by surface tension
12
Flow Classification
• steady – unsteady
• uniform – non-uniform
• varied flow (= non-uniform):
gradually varied – rapidly varied
Flow Classification
subcritical – supercritical flow
characterized by the Froude number
UFrgL
=
L taken to be the hydraulic depth D=A/T
Fr < 1 subcritical flowFr = 1 critical flowFr > 1 supercritical flow
13
Definition of Channel and Flow Properties
Hydraulic radius (R): ratio of flow area to wetted perimeter
ARP
=
ADT
=
Hydraulic depth (D): ratio of flow area to top width
Energy Equation
2
2= + +
γp uH z
g
Total energy of a parcel of water traveling on a streamline (no friction):
velocity headpressure head
elevation head
+γpz hydraulic grade line
14
Critical Flow
2 2
22 2= +α = +α
u QE y yg gA
Specific energy:
2
1
1
=
= =
ugD
uFrgD
Minimum specific energy yields:
Critical Flow
Rectangular channel of width b:
=
=
Qqbquy
1/32
2
2 223
⎛ ⎞= ⎜ ⎟⎝ ⎠
=
=
c
c c
c c
qyg
u yg
y E
15
Step in Rectangular Channel
2 21 2
1 2
2 1
2 2u uy y zg g
E E z
+ = + + Δ
= −Δ
Bernoulli equation (between upstream and downstream points):
Water Surface Variation from the Energy Equation
Total energy:
2
2uH z yg
= + +
Differentiating with respect to distance:
( )2 / 2= + +
d u gdH dz dydx dx dx dx
21−
=−o fS Sdy
dx FrResulting equation:
16
Momentum Equation
Momentum equation (rectangular channel):
( )2 21 2
2 12 2y y q u u
gγ γ γ
− = −
Hydraulic jump
Momentum equation for rectangular section:
( )2
2 22 1
1 2
1 1 12
q y yg y y⎛ ⎞
− = −⎜ ⎟⎝ ⎠
Solutions:
( )
( )
221
1
212
2
1 1 8 12
1 1 8 12
y Fry
y Fry
= + −
= + −
Energy loss:( )32 1
1 24y y
Ey y−
Δ =
17
Uniform Flow
Uniform occurs when:
1. The depth, flow area, and velocity at every cross section is constant
2. The energy grade line, water surface, and channel bottom are all parallel:
f w oS S S= =
Sf = slope of energy grade line
Sw = slope of water surface
So = slope of channel bed
Uniform Flow Formula
Mannings equation for velocity:
2/31u R Sn
=
Uniform flow rate:
2 /31Q uA AR Sn
= =
Section factor:
Conveyance:
2 /3AR
2/31K ARn
=
(increases with depth)
18
Computation of Uniform Flow
1. Channel cross section and shape, water depth, and slope known => Q or u can be calculated directly
2. Channel cross section and shape, water velcoity or flow, and slope known => water depth may be calculated through some iterative procedure
Roughness known and constant.
0.012
0.014
0.016
Manning’s Roughness n
0.018
0.018
0.020
19
Gradually Varied Flow
Depth of flow varies with longitudinal distance.
Occurs upstream and downstream control sections.
Governing equation:21
−=
−o fS Sdy
dx Fr
Classification of Gradually Varied Flow Profiles
Prevailing conditions:
If y < yN, then Sf > So
If y > yN, then Sf < So
If Fr > 1, then y < yc
If Fr < 1, then y > yc
If Sf = So, then y = yN
Water surface profiles may be classified with respect to:• the channel slope • the relationship between y, yN, and yc
Profile categories:M (mild) 0 < So < ScS (steep) So > Sc > 0C (critical) So = ScA (adverse) So < 0
20
Gradually Varied Flow Profile Classification II
Flow Transition
Subcritical to supercritical
Supercritical to subcritical
21
Strategy for Analysis of Open Channel Flow
1. Start at control points
2. Proceed upstream or downstream depending on whether subcritical or supercritical flow occurs, respectively
Typical approach in the analysis:
Control points typically occur at physical barriers, for example, sluice gates, dams, weirs, drop structures, or changes in channel slope.
Uniform Channel
Prismatic channel with constant slope and resistance coefficient.
Apply energy equation over a small distance Dx:
2
2 o fd uy S Sdx g
⎛ ⎞+ = −⎜ ⎟
⎝ ⎠
Express the equation in difference form:
( )2
2 o fuy S S xg
⎛ ⎞Δ + = − Δ⎜ ⎟⎝ ⎠
2 2
4/3fn uSR
=
22
Dxi
Reach i
x
yi yi+1
( ) ( )( )
2 2
12 2 4 /3
1/ 2
/ 2 / 2
/i i
io i
y u g y u gx
S n u R+
+
+ − +Δ =
−
All quantities known at i. Assume yi+1 and compute Dxi (ui+1 given by the continuity equation).
ui
ui+1
Computation of Gradually Varied Flow
Trial-and-Error Approach
Well-suited for computations in non-prismatic channels.
Channel properties (e.g., resistance coefficient and shape) are a function of longitudinal distance.
Depth is obtained at specific x-locations.
Apply energy equation between two stations located Dxapart (z is the elevation of the water surface):
2
2 21 2
1 2
2
2 2
f
f
uz S xg
u uz z S xg g
⎛ ⎞Δ + = − Δ⎜ ⎟⎝ ⎠
+ = + + Δ
23
Equation is solved by trial-and-error (from 2 to 1):
1. Assume y1 Æ u1 (continuity equation)
2. Compute Sf
3. Compute y1 from governing equation. If this value agrees with the assumed y1, the solution has been found. Otherwise continue calculations.
Estimate of frictional losses:
( )1 212f f fS S S= +
Examples of Gradually Varied Flow
Flow in channel between two reservoirs (lakes):
1. Steep slope, low downstream water level
2. Steep slope, high downstream water level
3. Mild slope, long channel
4. Mild slope, short channel
5. Sluice gate located in the channel
Study flow situation that develops + calculation procedure
24
Spatially Varied Flow
Flow varies with longitudinal distance.
Examples: side-channel spillways, side weirs, channels with permeable boundaries, gutters for conveying storm water runoff, and drop structures in the bottom of channels.
Two types of flow:
• discharge increases with distance
• discharge decreases with distance
Different principles govern => different analysis approach
Increasing discharge: use momentum equation
(hard to quantify energy losses)
Decreasing discharge: use energy equation
2
22QH z ygA
= + +
2 21 1 ( ) ( ) 02 2o a a ay b y b Q x u xγ − γ = ρ −
25
Weirs
Types of weirs (classified according to shape):
• rectangular
• V-notch
• trapezoidal
• parabolic
• special type (e.g., Cipoletti, Sutro)
Distinguish between:
• Broad-crested
• Sharp-crested
Discharge Formula for Rectangular Broad-Crested Weir
Apply Bernoulli equation between upstream section and the control section (critical depth occurs here).
h1
1/ 23/ 21
2 23 3D vQ C C g Th⎛ ⎞= ⎜ ⎟⎝ ⎠
26
Discharge Formula for Sharp-Crested Weirs
h1
z
( )1/ 2 3/ 21
2 23 eQ C g bh=
( ) ( )1/ 2 5/ 21
8 2 tan / 215 eQ C g h= θ
Rectangular:
Triangular:
Parshall Flume
Critical flow occurs in the flumethroat followed by a hydraulic jumpdownstream.
BaQ AWH=General discharge formula:
27
Venturimeters
Involves a constriction in the flow. The constriction produces an accelerated flow and a fall in the hydraulic grade line (pressure) directly related to the flow rate.
( )2 1 2
1 222 1
21 /
vC A p pQ g z zA A
⎛ ⎞= + − −⎜ ⎟γ γ⎝ ⎠−
Orifices
Used for many purposes in engineering, including measuring the flow rate.
A difference compared to nozzles is that the minimum flow section does not occur at the orifice but some distance downstream (in vena contracta).
Flow rate is given by:
( )1 2
1 2221
21 /
v c
c
C C A p pQ g z zC A A
⎛ ⎞= + − −⎜ ⎟γ γ⎝ ⎠−
Area in vena contracta is:2 cA C A=
28
Submerged Orifice
Discharge from one large reservoir to another:
2 2c vQ C C A gh CA gh= =
Discharge to the atmosphere:
( )1 22c vQ C C A g h h= −
Sluice Gate
Special case of orifice flow: only contraction on the top of the jet.
Pressure in vena contracta is assumed to be hydrostatic.
( )( )1 22
2 1
21 /
v cC C AQ g y yy y
= −−