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Logarithm Review
ab = c, (a > 0, a ≠ 1) logac = b
Definition
If a = 10, it is called common logarithm
log c = log10c
If a = e = 2.718281828459045 ∙ ∙ ∙, it is called natural logarithm
ln c = logecKeys on your calculator
Properties of Logarithm
ln(xy) = ln(x) + ln(y)
ln(x/y) = ln(x) − ln(y)
ln(xm) = m ln(x)
Also see Appendix I B
x > 0, y > 0
Chapter 11
Liquids, Solids andIntermolecular Forces
continued
Vapor Pressure
Chemistry, continue on
Surface Molecules
Temperature: T Temperature: T
GA, 760 torr = 1 atm
H2O100 °C
NormalBoiling Point
Tibet, 480 torr < 1 atm
H2O85 °C
NormalBoiling Point
(a) The Vapor Pressure of Water, Ethanol, and Diethyl Ether as a Function of Temperature. (b) Plots of In(Pvap) versus 1/T for
Water, Ethanol, and Diethyl Ether
1/T (K−1)
T is in K!
Linear relation: y = kx + C
y
xC: intercept
slope: k = tg θ
θ
ln P = k(1/T) + C
Linear relation: y = kx + C
1/T (K−1)
Heat of vaporization ∆Hvap: energy needed to convert one mole
of liquid to gas. Unit: J/mol or kJ/mol.
∆Hvap > 0
slope k < 0
1ln vapHP C
R T
y x
ln (P)
1/T (K−1)
1
2
ln (P1)
ln (P2)
1/T1 1/T2
1ln vapHP C
R T
1
2 1 2
1 1ln vapHP
P R T T
Clausius-Clapeyron Equation
1ln vapHP C
R T
The vapor pressure of water at 25 °C is 23.8 torr, and the heat
of vaporization of water is 43.9 kJ/mol. Calculate the vapor
pressure of water at 50 °C.
Five: T1, T2, P1, P2, ∆Hvap
Four known, calculate the other.
1
2 1 2
1 1ln vapHP
P R T T
Clausius-ClapeyronequationR = 8.314 J · mol−1 · K−1
Units in ideal gas law
PV = nRT
P — atm, V — L, n — mol, T — K
Option 1
R = 0.082 atm · L · mol−1 · K−1
P — Pa, V — m3, n — mol, T — KOption 2
Chem 1211
Carbon tetrachloride, CCl4, has a vapor pressure of 213 torr at
40 °C and 836 torr at 80 °C. What is the normal boiling point of
CCl4?
1
2 1 2
1 1ln vapHP
P R T T
( Please try to work on this question by yourself. Will review next week)
Liquid potassium has a vapor pressure of 10.00 torr at 443 °C
and a vapor pressure of 400.0 torr at 708 °C. Use these data
to calculate
(a) The heat of vaporization of liquid potassium;
(b) The normal boiling point of potassium;
(c) The vapor pressure of liquid potassium at 100. °C.
( Please try to work on this question by yourself. Will review next week)
1
2 1 2
1 1ln vapHP
P R T T
Clausius-Clapeyron Equation
1ln vapHP C
R T
slope k < 0
1ln vapHP C
R T
y x
Linear relation: y = kx + C
y
xC: intercept
slope: k = tg θ
θ
a
b
c
d
Lines tilt to the right have positive slopes (a and b), left negative(c and d). Steeper line has greater absolute value of slope. In thisgraph, the order of slopes is
a > b > 0 > c > d
y
x
What is the order of heat of vaporization for these three substances?
Solids
Glass (SiO2)
Crystal
Noncrystal
Solid
Basis Crystal structure
The basis may be a single atom or molecule, or a small group of atoms, molecules, or ions.
NaCl: 1 Na+ ion and 1 Cl− ion
Cu: 1 Cu atom
Zn: 2 Zn atoms
Diamond: 2 C atoms
CO2: 4 CO2 molecules
=Use a point to represent the basis:
Lattice
Lattice point:
Unit cell: 2-D, at least a parallelogram
Unit cell is the building block of the crystal
How many kinds of 2-D unit cells
can we have?
Extend the concept of unit cell to 3-D,
the real crystals.
: 3-D, at least a parallelepiped
How many kinds of 3-D unit cells
can we have?
1. triclinic 2. monoclinic
3. orthorhombic
4. tetragonal5. rhombohedral (trigonal)
6. hexagonal7. cubic
The 14 Bravais lattices
7 crystal systems
a ≠ b ≠ cα ≠ β ≠ γ
a ≠ b ≠ c
α = β = γ = 90°
a = b ≠ cα = β = 90° ,γ = 120°
a = b = cα = β = γ = 90°
a = b ≠ cα = β = γ = 90°
a = b = c90° ≠ α = β = γ < 120°
γ
ab
ca
b
c
(Simple cubic)
Chem 1212: assume a lattice point is a single atom
• Size of the cell X-ray diffraction
Information of a cubic unit cell
The Wave Nature of LightThe Wave Nature of Light
• Number of atoms in a cell
• Size of the cell
• Size of the atoms Soon
X-ray diffraction
Now!
Information of a cubic unit cell
AB
C D
AB
C D E
F
Number of atoms in a unit cell = ¼ x 4 = 1
1 2 4
Number of Atoms in a Cubic Unit Cell
The body-centered cubic unit cell of a particular crystalline
form of iron is 0.28664 nm on each side. Calculate the density
(in g/cm3) of this form of iron. d = 7.8753 g/cm3
The body-centered cubic unit cell of a particular crystalline
form of an element is 0.28664 nm on each side. The density
of this element is 7.8753 g/cm3. Identify the element.
The face-centered cubic unit cell of a particular crystalline
form of platinum is 393 pm on each side. Calculate the
density (in g/cm3) of this form of platinum.
d = 21.4 g/cm3
Closest Packing
a a
aaa
a a
a a
aa
a a
a a a a a
a
a
b b b b
b b b b
b b b b
c c c c
c c c c
c c c c
· · · abab · · ·
· · · abab · · ·
1. triclinic 2. monoclinic
3. orthorhombic
4. tetragonal5. rhombohedral (trigonal)
6. hexagonal7. cubic
The 14 Bravais lattices
7 crystal systems
a ≠ b ≠ cα ≠ β ≠ γ
a ≠ b ≠ c
α = β = γ = 90°
a = b ≠ cα = β = 90° ,γ = 120°
a = b = cα = β = γ = 90°
a = b ≠ cα = β = γ = 90°
a = b = c90° ≠ α = β = γ < 120°
γ
· · · abcabc · · ·
abcabc = Cubic Closest Packing
e.g. Ag, 1 atoms (1 lattice point) in a unit cell
• Number of atoms in a cell
• Size of the cell
• Size of the atoms Soon
X-ray diffraction
Now!
Information of a unit cell
Now!
Example 11.7, page 494
Al crystallizes with a face-centered cubic unit cell. The radius of a Al atom is 143 pm. Calculate the density of solid Al in g/cm3.
r8L
L
r
2r
r
L
d = 2.71 g/cm3
What about simple cubic?
Simple Cubic
r
L
L = 2r
What about body-centeredcubic?
Body centered cubic
D
Body diagonal D = 4r
L
D
L
L F
L
Body diagonal D = 4r
r3
4L
L
Pythagorean theorem
Titanium metal has a body-centered cubic unit cell. Thedensity of titanium is 4.50 g/cm3. Calculate the edge lengthof the unit cell and a value for the atomic radius of titaniumin pm.
L = 328 pm
r = 142 pm
100-mL container
50 % 70 %
50 mL 70 mL
1 2 4
Packing Efficiency: fraction of volume occupied by atoms
74 %52 % 68 %
L = 2r r3
4L r8L
prove