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M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16— 38 even, 39—45 odd 2) C 4) B 6) C 8) A 10) 5 12) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2) 18) BC, DC 20) BH = 106, HD = 74 16) 35 18) 125 20) 90 22) 90 24) 65 26) x = 80, y = 100 28) 90 30) 40 32) 46 34) 3 36) 25 38) 6

M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

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Page 1: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39—45 odd2) C 4) B 6) C 8) A 10) 5 12) EF = 40, FG = 50, EH = 24014) (3\2, 2); (5\2) 18) BC, DC 20) BH = 106, HD = 74

16) 35 18) 125 20) 90 22) 9024) 65 26) x = 80, y = 100 28) 9030) 40 32) 46 34) 3 36) 2538) 6

Page 2: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

Chapter 10 Review

Page 3: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

• Angles – Middle Same

• Inside – Add, div 2

• On – Half

• Outside, subtract, div 2

• Segments – Tan congruent

• Inside, part part = part part

• Outside, part whole = part whole pr

• Part whole = whole squared

Page 4: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

PBPAThen

O o tangent tare PB,PA :Given

P

Theorem 10.3

Tangents to a circle from a point are congruent.

O

A

B

Page 5: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

A

B C

DE

F

______

___________

___________

||

40,45:

mED

mFDmFBD

mEFDmFD

Find

BCED

EAFmDBCmGiven

Also state if they are major or minor arcs

Page 6: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

W

R

NG

O

Theorem 10.4

In the same circle or in congruent circles:

1) Congruent arcs have congruent chords.

2) Congruent chords have congruent arcs.

Page 7: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

B

A

N

E

R

Theorem 10.5

A diameter that is perpendicular to a chord bisects the chord and its arc.

Theorem 10.6

If one chord is a perpendicular bisector of another chord, then the first chord is a diameter.

Page 8: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

B

A

N

E

R

Theorem 10.7

In the same circle or in congruent circles.

1) Chords equally distant from the center (or centers) are congruent.

2) Congruent chords are equally distant from the center (or centers)

Remember, shortest distance means perpendicular.

Page 9: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

45

x

y

z

chords bisectsdiameter

4x

segmentscongruent

npythagorea Some

3y

congruent.

aret equidistan Chords

8z

Page 10: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

Def: An inscribed angle is an angle whose vertex is on the circle and sides are chords in the circle.

Theorem: Measure of inscribed angle is half the measure of the intercepted arc.

halfinsc

45

5.22

Page 11: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

Look at the pictures, what can you conclude?

12

1

12

3

4

Two inscribed angles intercept same arc, then they are congruent

21

Angle inscribed in semi circle is 90 degrees

Proof: 180\2

901m

If quadrilateral is inscribed in circle, opposite angles supplementary

supp3,2

supp4,1

arcsameinsc 90semiinsc supoppquadinsc

Page 12: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

80

angle

whole

xy

zsup

100

angleoppquadinsc

90

90

semiangleinsc

90

90

semiangleinsc

Page 13: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)
Page 14: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)
Page 15: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

Theorem 10-12

Measure of angle formed by chord and tangent is half the intercepted arc

Chord tan half arc

45

5.22

Page 16: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

1

Thrm: Measure of angles formed by two chords that intersect inside the circle is equal to half the sum of the measures of the intercepted arcs.

A

B

C

D

)(2

11 mCDmABm

26

50

38

Page 17: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

x

x

x

y

y

y

1

2

3

The measure of an angle formed by two secants, two tangents, or a secant and tangent drawn from a point OUTSIDE the circle is equal to half the difference of the measures of the intercepted arcs.

x y1m )(2

1

x y2m )(2

1

x y3m )(2

1

Page 18: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

40

x

30

y

100

z

80, inscribed angle

25, .5(80-30)

50, .5(100-z)=25

Page 19: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

80, .5(x+160)=120

40, .5(160-80)=y

120xy

160

Page 20: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

10.15 Two chords intersect inside a circle, the product of the segments of one chord equals the product of the segments of the other chord. a

bc

da

bc

d

a

105

30

150=10a

15=a

Page 21: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

b

ca

d

Theorem 10.16: When two secants are drawn from an external point, the product of one secant with external segment is equal to the product of the other secant and external segment.

External Segment

Theorem 10.17: When a secant and tangent are drawn to a circle from an external point, the product of the secant and its external segment is equal to the tangent square.

b

a c

ab=cd

ab=c2

Page 22: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

A

B

C

D

F

E

?

6?

1012

FE

BFBC

CDAB

8

18

Page 23: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

6

816

ECxED

EBAD

4 or 12

A

B

C

D

E

124

)12)(4(0

48160

4816

68)16(

2

2

xorx

xx

xx

xx

xx

Page 24: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

Graphing a circle, give radius, center

(x – 3)2 + (y + 1)2 = 25

(h,k) is the center

r is the radius1)Plot center

2) Find radius

3) Plot points

4) Connect

(3,–1)

525

Page 25: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

Write equation given center and radius

(x – 2)2 + (y + 4)2 = 21

(2,–4)

21

1) Center

2) Radius

(x – 2)2 + (y –(– 4))2 =( )2

(x + 1)2 + (y – 2)2 = 9

(–1,2)

3

1) Center

2) Radius

(x – (– 1))2 + (y – 2)2 = 3221

Page 26: M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39— 45 odd 2) C4) B6) C8) A10) 512) EF = 40, FG = 50, EH = 240 14) (3\2, 2); (5\2)18)

• M—06/01/09—HW #75: Pg 654-655: 1-20, skip 9, 16. Pg 821-822: 16—38 even, 39—45 odd

•