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Mixing in water. Solutions dominated by water (1 L=55.51 moles H 2 O) a A =k H X A where K H is Henry’s Law coefficient – where is this valid? Low concentration of A. 1.0. Raoult’s Law – higher concentration ranges (higher X A ): m A = m A 0 +RTln G A X A - PowerPoint PPT Presentation
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Mixing in water• Solutions dominated by water (1 L=55.51 moles
H2O)
• aA=kHXA where KH is Henry’s Law coefficient – where is this valid? Low concentration of A
Mol fraction AH2O A
Act
ivity
0.0
1.0
0.0 1.0
Ideal mixing
aA
aH2ORaoult’s Law – higher concentration ranges (higher XA):
A=A0+RTlnAXA
where A is Rauolt’s law activity coefficient
Activity
• Activity, a, is the term which relates Gibbs Free Energy to chemical potential:
i-G0i = RT ln ai
• Why is there now a correction term you might ask…– Has to do with how things mix together– Relates an ideal solution to a non-ideal solution
Activity II
• For solids or liquid solutions:ai=Xii
• For gases:
ai=Pii = fi
• For aqueous solutions:
ai=mii
Xi=mole fraction of component iPi = partial pressure of component imi = molal concentration of component i
Activity Coefficients
• Where do they come from??• We think of ‘ideal’ as the standard state, but
for dissolved ions, that is actually an infinitely dilute solution
• Gases, minerals, and bulk liquids (H2O) are usually pretty close to 1 in waters
• Dissolved molecules/ ions are have activity coefficients that change with concentration (ions are curved lines relating concentration and activity coefficients, molecules usually more linear relation)
Application to ions in solution
• Ions in solutions are obviously nonideal mixtures!
• Use activities (ai) to apply thermodynamics and law of mass action
ai = imi
• The activity coefficient, i, is found via some empirical foundations
Dissolved species i
• First must define the ionic strength (I) of the solution the ion is in:
Where mi is the molar concentration of species i and zi is the charge of species I
2
izmI
ii
Activity Coefficients
• Debye-Huckel approximation (valid for I:
• Where A and B are constants (depending on T, see table 10.3 in your book), and a is a measure of the effective diameter of the ion (table 10.4)
2
1
2
12
log
aBII
IAz
Different ways to calculate i
• Limiting law
• Debye-Huckel
• Davies
• TJ, SIT models
• Pitzer, HKW models
Neutral species
• Setchnow equation:
• Logn=ksI
For activity coefficient (see table 4-2 for selected coefficients)
Law of Mass Action
• Getting ‘out’ of the standard state:
• Accounting for free energy of ions ≠ 1:=0 + RT ln P
• Bear in mind the difference between the standard state G0 and 0 vs. the molar property G and (not at standard state 25 C, 1 bar, a mole)
P
P
P
PP
dPRTdG
00
GP – G0 = RT(ln P – ln P0) GP – G0 = RT ln P
Equilibrium Constant
• For a reaction of ideal gases, P becomes:
for aA + bB cC + dD
• Restate the equation as:
GR – G0R = RT ln Q
• AT equilibrium, GR=0, therefore:
G0R = -RT ln Keq
where Keq is the equilibrium constant
QRTPP
PPRT
bB
aA
dD
cC lnln
Assessing equilibrium
IfGR – G0R = RT ln Q, and at equilibrium G0
R = 0, then: Q=K
Q reaction quotient, aka Ion Activity Product (IAP) is the product of all products over product of all reactants at any condition
K aka Keq, same calculation, but AT equilibrium
i
ni
n
reactants
productsK
][
][
i
ni
n
reactants
productsQ
][
][
Solubility Product Constant
• For mineral dissolution, the K is Ksp, the solubility product constant
• Use it for a quick look at how soluble a mineral is, often presented as pK (table 10.1)
G0R = RT ln Ksp
• Higher values more soluble
CaCO3(calcite) Ca2+ + CO32-
Fe3(PO4)2*8H2O 3 Fe2+ + 2 PO43- + 8 H2O
Ion Activity Product
• For reaction aA + bB cC + dD:
• For simple mineral dissolution, this is only the product of the products activity of a solid phase is equal to one
CaCO3 Ca2+ + CO32-
IAP = [Ca2+][CO32-]
1
dc DCIAP
ba
dc
BA
DCIAP
eqR K
QRTG ln
Saturation Index
• When GR=0, then ln Q/Keq=0, therefore Q=Keq.
• For minerals dissolving in water:
• Saturation Index (SI) = log Q/K or IAP/Keq
• When SI=0, mineral is at equilibrium, when SI<0 (i.e. negative), mineral is undersaturated
eq
oR K
QRTG ln
eqR K
QRTG log303.20
Calculating Keq
G0R = -RT ln Keq
• Look up G0i for each component in data tables
(such as Appendix F3-F5 in your book)• Examples:
• CaCO3(calcite) + 2 H+ Ca2+ + H2CO3(aq)
• CaCO3(aragonite) + 2 H+ Ca2+ + H2CO3(aq)
• H2CO3(aq) H2O + CO2(aq)
• NaAlSiO4(nepheline) + SiO2(quartz) NaAlSi3O8(albite)
)reactants()( 000i
iii
iiR GnproductsGnG