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Op Amp compensation The design process involves two distinct activities: Architecture Design – Find an architecture already available and adapt it to present requirements – Create a new architecture that can meet requirements Component Design – Determine transistor sizes – Determine biasing voltages/currents – Design compensation network

Op Amp compensation

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Op Amp compensation

The design process involves two distinct activities:

• Architecture Design – Find an architecture already available and

adapt it to present requirements – Create a new architecture that can meet

requirements • Component Design

– Determine transistor sizes – Determine biasing voltages/currents – Design compensation network

All op amps used as feedback amplifier:

If not compensated well, closed-loop can be oscillatory or unstable. damping ratio ζ ≈ phase margin PM / 100

Value of ζ: 1 0.7 0.6 0.5 0.4 0.3 Overshoot: 0 5% 9.6% 16% 25% 37% PM in deg: 67 61 53 44 35 PM+Mp: 72 71 69 69 72 PM+Mp=70

UGF: frequency at which gain = 1 or 0 dB PM: phase margin = how much the phase is above critical (-180o) at UGF

Closed-loop is unstable if PM < 0

PM

UGF This is the loop-return gain when used in closed-loop. Only in buffer connection this is equal to O.L. gain.

z

UGF

p1 p2

PM

GM

p1 p2 z1

UGF

Types of Compensation • Miller - Use of a capacitor feeding back around a

high-gain, inverting stage. – Miller capacitor only – Miller capacitor with an unity-gain buffer to block the

forward path through the compensation capacitor. Can eliminate the RHP zero.

– Miller with a nulling resistor. Similar to Miller but with an added series resistance to gain control over the RHP zero.

• Self compensating - Load capacitor compensates the op amp (later).

• Feedforward - Bypassing a positive gain amplifier resulting in phase lead. Gain can be less than unity.

VsA2A1

Cc

VoutA

Two stage Miller compensation

v1 v2= AVv1

i

i = (v1-v2)/Zf = v1(1-AV)/Zf = v1/{Zf /(1-AV)} = - v2(1-1/AV)/Zf = - v2/{Zf /(1-1/AV)}

i= v1/Z1

i= -v2/Z2

v1 v2 Miller Effect

Vs+A2-A1

C1

A-A2

C2

B Vout

Vs+A2-A1

C1

A-A3

C2

B Vout

Vs-A2-A1

C1

A+A3

C2

B Vout

-AF1

Vs+A2-A1

C1

A-A3

C2

B Vout

-AF1

+AF2

(a) (b)

(c) (d)

(a) Nested Miller Compensation (NMC), (b) Reverse Nested Miller Compensation (RNMC), (c) Multipath Nested Miller Compensation (MNMC), (d) Nested Gm-Cc Compensation (NGCC)

Vs+A2-A1

A-A3

Cm

B Vout

+gma

-gmf

Ca

HGB

HSB

Vs+A2-A1

A-A3

Cm

B Vout

gmf

Ca

(a) (b)

(a) Active feedback frequency compensation (AFFC), (b) Transconductance with capacitance feedback

frequency compensation (TCFC)

Single ended and differential have very similar Compensation needs

Vi+

Vo1

VBP

VBN

Vo

I2

Vi-

I1

Vi

Vo1

VBP

VBN

Vo

I2

I1

Not quite

VBP

Vi+ Vi-

VBN Vb1

CC CC

Vo+

Vi

Vo1

VBP

Vb1

Vo Vo-

VBP

Vi+ Vi-

VBN

Vb1

CC CC

Vo+ Vi

Vo1

VBP

Vb1

Vo Vo-

If the first stage is cascoded, the analysis stays similar

VBPc

VBNc

Composite MOST with very large ro

IN- IN+

VDD

CC CC

Vo+ Vo-

Folded cascode same thing, except gm is from a different pair

Vi

Vo1

VBP

Vb1

Vo

Generic representative:

Vi- has two components: When Vin=0, When Vo=0

What about β?

Vi+

Vo1

Vo Vi- Vin

CL

Rf

Ri

1

1

1 ||

1 ||

fgs

in

in fgs

RsC

VR R

sC+

1

1

1 ||( )1 ||

ings

o

f ings

RsC

VR R

sC

−+

Av(s) +

-

Vin(s)

β(s)

Gin(s) -Vo

Vi-

1 1

1 1

1

1 1|| ||

1 1 ( )|| ||

1

11

( )Note

In the frequency range when the op amp gain is very large,

0. This lea

ds to:( )

f ings gs o

in oo

in f f ings gs

f fo

fin in inin gs

io

o

o

in

R RsC sC VV V

A sR R R RsC sC

R RVRV R RR C sR

s

VVA s

A

−= ≈

−+ =

+ +

= − ≈ −+ +

+

1that this actually depends on , , and .o f in gsA R R C

Vi+

Vo1

Vo Vi-

CL

Rf

Ri

Open loop simulation incorporating feedback loading

VoQ = Vicm

V’o

Obtain freq resp from Vid to V’o

Vi+

Vo1

Vo Vi-

Vin CL

Rf

Ri

Alternative simulation (more reliable)

Vid = Vi+ - Vi- =Vin – Vi- Vi- =β(s)Vo Vo=Avd(s)Vid Vi-

Vin Vid

Vo

VBP

Vi+ Vi-

VBN

Vb1

CC CC

Vo+ Vo-

VBPc

VBNc Rf

Ri

Ri

V’o

VBP

Vi+ Vi-

VBN

Vb1

CC CC

Vo+

VBPc

VBNc

Ri

Ri

Vo-

DC gain of first stage: AV1 = -gm1/(gds2+gds4)= -gm1/(I4(λ2+ λ4)) = -gm1ro1

DC gain of second stage: AV2 = -gm6/(gds6+gds7)=- gm6/(I6(λ6+ λ7)) = -gm6ro

Total DC gain: AV =

gm1gm6 (gds2+gds4)(gds6+gds7)

GBW = gm1/CC

AV = gm1gm6ro1ro

Zf = 1/s(CC+Cgd6) ≈ 1/sCC

When considering p1 (low freq), can ignore CL (including parasitics at vo):

Therefore, AV6 = -gm6/(gds6+gds7)

Z1eq = 1/sCC(1+ gm6/(gds6+gds7)) C1eq=CC(1+ gm6/(gds6+gds7))≈CCgm6/(gds6+gds7)

-p1 = ω1 ≈ (gds2+gds4)/(C1+C1eq) ≈ (gds2+gds4)/(C1+CCgm6/(gds6+gds7)) ≈ (gds2+gds4)(gds6+gds7)/(CCgm6) -p1 = ω1 ≈ 1/(ro1CC|AV6|)

Note: ω1 decreases with increasing CC

At frequencies much higher than ω1, gds2 and gds4 can be viewed as open.

Μ7

C1

CC

CL

vo

Total go at vo:

gds6+gds7+gm6 CC

CC+C1 Total C at vo:

CL+ C1CC CC+C1

-p2=ω2= CCgm6+(C1+CC)(gds6+gds7)

CL(C1+CC)+CCC1

Μ6

Note that when CC=0, ω2 = gds6+gds7 CL

As CC is increased, ω2 increases also.

However, when CC is large, ω2 does not increase as much with CC. ω2 has a upper limit given by: gm6+gds6+gds7

CL+C1

Hence, once CC is large, its main effect is to lower ω1, and hence lower GBW.

≈ gm6 CL+C1

When CC=C1, ω2 ≈ (½gm6+gds6+gds7)/(CL+½C1) ≈ gm6/(2CL+C1)

Also note that, in contrast to single stage amplifiers for which increasing CL improves PM, for the two stage amplifier increasing CL actually reduces ω2 and reduces PM.

Hence, needs to design for max CL

There are two RHP zeros:

z1 due to CC and M6

z1 = gm6/(CC+Cgd6) ≈ gm6/CC

z2 due to Cgd2 and M2 z2 = gm2/Cgd2 >> z1

z1 significantly affects achievable GBW.

gm6/(CL+C1) f (I6)

z1 ≈ gm6/Cgd6

A0

ω2

-90

-180

ω1 z2 ≈ gm2/Cgd2

No PM

gm6/(CL+C1) f (I6)

z1 ≈ gm6/Cgd6

A0

ω2

-90

-180

ω1

z2 ≈ gm2/Cgd2

No PM

z1 ≈ gm6/Cc

Cc↑

gm6/(CL+C1) f (I6)

z1 ≈ gm6/CC

A0

ω2

-90

-180 PM

ω1

gm1/CC

It is easy to see: PM ≈ 90o – tan-1(UGF/ω2) – tan-1(UGF/z1) To have sufficient PM, need UGF < ω2

and UGF << z1 In such case, UGF ≈ GB ≈ gm1/CC = z1 * gm1/gm6.

PM ≈ 90o – tan-1(GB/ω2) – tan-1(GB/z1)

Hence, need: GB < ω2 GB << z1

PM requirement decides how much lower:

6

,6 6 1 6

66

6 ,1

6 6,

1 max

For a given current ,

2 ,

2( )

This reaches maximum when :

1 12 2

This is the value for |

oxm L L dbp dbn gs L ox

ox

m

L L ox

L ox

m

L L

I

C Wg I C C C C C C C C WLL

C W Ig Lf IC C C C WL

C C WL

g I SRC C L C L

p

µ

µ

µ µ

= + >≈ + + + ≈ +

= ≈+ +

=

= = +

2 | when = .cC ∞

,1 16 1

, ,1 1 6

1

6

6,

1

Since

90 tan (1 ) / tan

To achiev about 50 PM, we need:

0.1

1 12 3

m mL

L L m

m

m

m

L

g gCPM GBC C C C g

gg

gGBC C

− − = ° − + − + +

°

≤ +

61 1 12 3 2

Therefore, to increase GB, use NMOS 2nd stage input, large 2nd stage current, and small L.

L

IL C

µ

<

Possible design steps for max GB • For a given CL and Itot • Assume a current share ratio θ, i.e.

– I6+I5 = Itot, I5 = θI6 , I1 = I2 = I5/2 • Size W6, L6 to achieve max gm6/(CL+Cgs6)

which is > ω2 – C1 ∝ W6*L6, gm6 ∝ (W6/L6)0.5

• Size W1, L1 so that gm1 ≈ 0.1gm6 – this make z1 ≈ 10*GB

• Select CC to achieve required PM – by making gm1/CC < 0.5 ω2

• Check slew rate: SR = I5/CC • Size M5, M7, M3/4 for current ratio, ICMR, etc

Comment • If we run the same total current Itot through

a single stage common source amplifier made of M6 and M7 – Single pole go/CL – Gain gm6/go – Single stage amp GB = gm6/CL >gm6/(CL+C1) > ω2 > gm1/CC = GB of two stage amp

• Two stage amp achieves higher gain but speed is much slower!

• Can the single stage speed be recovered?

Other considerations • Output slew rate: SR = I5/CC

• Output swing range (saturation operation): VSS+Vdssat7 to VDD – Vdssat6

• Min ICM: VSS + Vdssat5 + VTN + Von1 • Max ICM: VDD - |VTP| - Von3 + VTN • Mirror node approx. pole/zero cancellation

– Closed-loop pole stuck near by – Can cause slow settling if pole freq is too low

When vin is short, the D1 node sees a capacitance CM and a conductance of gm3 through the diode con. So: pm = -gm3/CM

When vin is float and vo=0. gm4 generate a current in id4=id2=id1. So the total conductance at D1 is gm3 + gm4. So: zm = -(gm3+gm4)/CM =2*pm

If |pm| << GB, one closed-loop pole stuck nearby, causing slow settling!

Eliminating RHP Zero at gm6/CC

vg= RZCCdvCC/dt +vcc

icc = vg gm6 = CCdvCC/dt

(gm6RZ-1)CCdvCC/dt + gm6vcc=0

Vi

Vo1

VBP

Vb1

Vo

For zero from Vo1 to Vo, Set Vo = 0, float Vo1.

For the zero at M6 and CC, it becomes

z1 = gm6/[CC(1-gm6Rz)]

So, if Rz = 1/gm6, z1 → ∞

For such Rz, its effect on the p1 node can be ignored so p1 remains as before.

Notice that Rz is reference with respect to 1/gm6. Since absolute values of both R and gm can vary significantly, but relative match is more precise, Rz is implemented as a triode transistor.

Realization of Rz: Mz has same Vod as M6, gdsz = gdoz = gm6 * size ratio

vb

Μ8

Μ9

VDD

M6, M8, M9 have same W and L, but their multiplier ratio = current ratio

Another choice of Rz, as in our book, is to make z1 cancel p2:

z1=gm6/CC(1-gm6Rz) ≈ - gm6/(CL+C1)

Rz = gm6CC

CC+CL+C1

= gm6

1 (1+ ) CC

CL+C1

Or: gdsz *( (1+ ) = gm6 CC

CL+C1

Let ID8 = αID6, size M6 and M8 so that VSG6 = VSG8

Then VSGz=VSG9 Assume Mz in triode

gdsz = βz(VSGz – |VT| - VSDz) ≈ βz(VSGz – |VT|) = βz((VSG9 – |VT|) = βz(VSG8 – |VT|) = βz(VSG6 – |VT|) = (βz/β6)gm6 = (mz/m6) gm6

Hence need: mz/m6 =CC/(CC+CL+C1)

gm6/(CL+C1) f (I6)

-z1 ≈

A0

ω2

-90

-180 PM

ω1

gm1/CC

• With the same CC as before – Z1 cancels p2 – P1 not affected much – Phase margin drop due to p2 and z1 nearly

removed – Overall phase margin greatly improved – Effects of other poles and zero become more

important

• Can we reduce CC and improve GB?

Vo1

Vb1

Vo

M6

M7

Cc Rz

'6 01 6 01

1 1 6 1 0

6

1 0 01 1

1 6

' 1 60

1 1 1 1

( ) ( )( ) 01

( )( ) 0

KCL:

1

1

1

cL o o gd o m

z c

co gd o

z c

cgd

z c co

c z c cgd

z c

c m cL o

z c c z c c

sCsC g v sC v v g vsR C

sCsC v sC v vsR CsCsC

sR C Cv v vsC sR C C C CsC sCsR C

sC C g CsC v v vsR C C C C sR C C C C

+ + + − + = + + + − ≈ +

++

= ≈+ ++ +

+

+ ++ + + + 0

'1 1 1 6

2 ' ' '1 1 1 6

62 ' '

1 1' ' '

1 1 1'

1

0

( ) 0

( ) 0

If Rz small:

1 / /

L z c c c m c

L z c L L c c m c

m c

L L c c

L L c c c c Lz

L z c z c

sC sR C C C C sC C g Cs C R C C s C C C C C C g C

g CpC C C C C C

C C C C C C C C C CpC R C C R C

+ + + + =

+ + + + =

− ≈+ +

+ + + +− ≈ ≈

'6 01 6 01

6 01 6 01

26 6 6 6

61

6 6

6 62

Set = 0 in:

( ) ( )( ) 01

We get:

( ) 01

( ( ) 0

When Rz small:

( )

( )

o

cL o o gd o m

z c

cgd m

z c

z c gd gd c m z c m

m

m z c gd c

m z c gd c

z c

vsCsC g v sC v v g v

sR C

sCsC v g vsR C

s R C C s C C sg R C g

gzg R C C Cg R C C C

zR C

+ + + − + =+

− + + =+

− + + + + =

− =− +

− +− =

6

6When >1, both zeros are in left half plane.gd

m z

Cg R

6 6 62 ' ' ' '

1 1 1

' ' '1 1 1

'1 1

6 61

6 6 6

''

6 6

2

1 1 11

( ) ( 1)

When z1 is set to cancel p2,

( 1) , 1

1

1

m c m m

L L c c L L

L L c c c Lz

L z c z z

m m

m z c gd c m z c

Lm z c L m z

c

z

g C g gpC C C C C C C C C

C C C C C C C C CpC R C C R R C

g gzg R C C C g R C

Cg R C C g RC

pp

− ≈ ≈< ≈<+ + +

+ ++ +

− ≈ = >≈

− = ≈− + −

− ≈ ≈ +

>+

'

'1

L

L

c

CC CC

This ratio needs to be sufficiently large for the p/z formula to be approximately right.

When C1 large and Cc small, pz can become lower.

gm6/CL

z1 ≈ p2

A0

ω2

-90

-180

ω1

z2 ≈ gm2/Cgd2

Operate not on this but on this or this z4 ≈ gm6/Cgd6

pz=-1/RZC1

Increasing GB by using smaller CC • It is possible to reduce CC to increase GB if

z1/p2 pole zero cancellation is achieved – Can extend to close to gm6/CL – Or even a little bit higher

• But cannot push up too much higher – Other poles, zeros – Imprecise mirror pole/zero cancellation – P2/z1 cancellation – GB cannot be too high relative to these p/z

cancellation • Z2, z4, and pz=-1/RZC1 must be much higher

than GB

Possible design steps for max GB • For a given CL and Itot • Assume a current share ratio θ, i.e.

– I6+I5 = Itot, I5 = θI6 , I1 = I2 = I5/2 • Size W6, L6 to achieve max single stage GB1 =

gm6/(CL+Co-para) – A good trade off is to size W6 so that Cgs6 ≈ C1 ≈ CL/2 – If L_overlap ≈ 10% L6, this makes z4=gm6/Cgd6 ≈ 20*GB1

• Choose GB = αGB1, e.g. 0.5GB1 • Choose CC to make p2≈GB, e.g. Cc=CL/2, p2≈GB/1.25 • Size W1, L1 and adjust θ so that gm1/CC ≈ GB

– Make z2=gm2/Cgd2 >> GB, i.e. Cgd2 << Cgs2<<Cc • Size Mz so that z1 cancels p2 • Make sure PM at f=GB is sufficient • Size other transistors so that para |p| > GB*(10~20) • Check slew rate, and size other transistors for ICMR,

OSR, etc

Need More Stable Op Amps We can increase Rz and create a LHP zero to improve phase margin

Becomes difficult to manage the location of the Rz over temperature and process variations

Stability of the op amp is becoming a problem because the non-dominant pole associated with the output (f2) is too low Increase f2 requires increase of gm of the output stage

Increase area Increase output stage current (Id2)

Need a more practical way to Compensate Avoid using Miller Compensation

Avoid connecting a compensation capacitor between two high impedance nodes ! Literature has many examples illustrating how to avoid miller connections for high speed

This research develops Indirect Feedback Compensation A more practical way to compensate Feedback compensation current indirectly using

Common Gate Amplifier Cascoded Structures

Improved PSRR Smaller Die Area (Compensation capacitor reduced 4~10 times) Much Faster ..!

VsA2A1 Buffer

Cc

Differential Amplifier Gain Stage Output Buffer

Vout

iccRi

A

Indirect Feedback - History • First proposed by B.K. Ahuja in “AN IMPROVED FREQUENCY COMPENSATION

TECHNIQUE FOR CMOS OPERATIONAL-AMPLIFIERS,” Ieee Journal of Solid-State Circuits, vol. 18, no. 6, pp. 629-633, 1983

• However it is still seldom used in practice ?? – Looks very similar to Miller compensation – Prompts most designers to use design strategy for Miller-Rz compensation – However the Indirect Compensation Scheme has different pole/zero locations

and conditions that need to be satisfied to tap the true potential of the compensation scheme

– Thus this work Provides analytical model/solution for the architecture Proposes a design procedure based on the analytical results Design Example using the proposed design procedure Simulation Results show the performance is orders of magnitude higher than miller compensation and far better than state of the art

Indirect Feedback Frequency Compensation

Improvements due to a simple change

The compensation current is indirectly fedback from low impedance node VA to V1 The RHP pole zero can be eliminated as the feedforward current is blocked by the common gate amplifier Node V1 is now not loaded by the compensation capacitor (as previously) and thus results in a much faster second stage and increased unity gain frequency

AND MUCH MORE ………

M1 M2

M3 M4

M5

M6c

VDD

VSS

Cc

Vin- Vin+

M9

ic

VA

V1

Mb3M7

Mb1

Isupply

Mb2

Mb4

Mb5 Mb6

Vout

Vbb

Small Signal Analysis Cc

gm1Vd

R1 C1

V1 VA

gmcVA

roc

1/gmc RA CA gm5V1 R2CL

Vout

TAKING KCL AT EACH NODE

Simplified Transfer Function The transfer function can be simplified and approximated as:-

The coefficients can be evaluated as

Evaluating the poles and zeros Assuming the pole |p1| >> |p2|, |p3|

The denominator can now be

approximated

Real Poles Complex Poles

The third order transfer function as 3 poles and 1 zero Dominant Pole location Non-dominant Real Poles location

Condition For Real Poles

LHP Zero Location

bserving the Pole/Zero Locations

Remains at the same location

Large gmc ?

Improves Phase Margin

Analytical Results Summary Pole / Zero Location

Real Poles Condition

Quick Facts Pole p2 moved to much higher frequency Can use much smaller gm5 Less Power LHP zero improves the phase margin Much faster op-amp with lower power and

CC Will EXPLORE more ….

Extended by a factor >1

M1 M2

M3 M4

M5

VDD

VSS

Cc

Vin- Vin+

M9

ic

V1

M7Mb1

Isupply

Mc1 Mc2

Vbb

A

if

Vout

Vcc

Alternative Implementations of Indirect Feedback

The common gate amplifier is embedded in the cascode action Similar to the common gate amplifier analyzed in the previous section, the LHP zero and the three poles are given by Equations provided previously Reduction in Power at cost of Flexibility choosing the transconductance of gmc

M1 M2

M3 M4

M5

VDD

VSS

Cc

Vin- Vin+

M9

ic

V1

M7Mb1

Isupply

Mc1 Mc2

Vbb

A

Vout

Vcc

Similar to cascoded PMOS loads

However additional RHP zero located at:

RHP zero High Frequency

Summarizing the Advantages of Indirect Feedback

Pole splitting can be achieved with a much smaller compensation capacitor (Cc) Faster Op Amp Much Smaller Area Lower Value of second stage transconductance (gm5) value required Lower Power and Less Total Current Required Improved PSRR

Analytically the reason the non-dominant pole shifted to a higher frequency is because the compensation capacitor now does not load the first stage output.

Pre - Design Procedure Guidelines

To quantify how good of a job our transistor does, we can therefore define the following “figure of merits (FOM) Tranconductor Efficiency

Transit Frequency

Good Region For AMI 0.5CN VEB ≈ 0.1-0.2 V

Indirect Feedback Design Procedure Summary

Noise Specification

Slew Rate Specification

Output Swing Specification

Gain-Bandwidth Requirement

Real Poles Requirement

Class A Output Stage Design Bad Output Stage Design

Not Controlling current in the output stage leads to:

Bad input-referred offset Potential for large power dissipation Not controlling output stage gm (and thus stability)

Class A output stages also suffer from poor slew rate

M1 M2

M3 M4

M5

M6c

VDD

VSS

Cc

Vin- Vin+

M9

ic

VA

V1

Mb3M7

Mb1

Isupply

Mb2

Mb4

Mb5 Mb6

Vout

Vbb

M1 M2

M3 M4

M5

VDD

Cc

V1

Mc1 Mc2Vbb

Vout

SR = inf

CLM1 M2

M3 M4

M5

VDD

Cc

V1

Mc1 Mc2Vbb

Vout

Iss2CL

SR =

CL

Class AB Output Stage Design

Class AB Output Stage The Class AB output stage is realized by have a floating current source biased between the output stages transistors behaving like a push pull:

Slew Rate Improved during discharging Controlled output stage current and gm Slew rate limitation shifted to the compensation capacitor which is small in the proposed compensation scheme and thus achieves much higher slew rate

M1 M2

M3 M4

M5

VDD

Cc

V1

Mc1 Mc2Vbb

Vout

CL

Mpcasc

M6

Mncasc

Iss2

M1 M2

M3 M4

M5

VDD

Cc

V1

Mc1 Mc2Vbb

Vout

CL

Mpcasc

M6

Mncasc

Iss2

Figure of Merit (FOM)

To perform a comparison in terms of speed among the many compensation approaches independently of the particular amplifier topology, design choices, and technology, a figure of merit (FOM) that relates the load capacitance CL, the gain-bandwidth product ωGBW, and the total current consumption of the amplifier ITotal has been proposed [ref].

Small Signal FOM

DC Transient FOM

Single Stage Comparison

Total Transcoductance Gm in multi-stage op amp

MHz pfmA

V s pfmA

µ •

Design Example – Op Amp Specifications

Op Amp Specification

Supply Voltages ± 1.25 V

Load Capacitance: CL 100 pF

Total Current (max) 30 μA

DC gain: Ao 70 dB

Unity-gain Frequency: fu 2 MHz

Phase Margin: φM 60°

Slew Rate: SR 1 V/μs

Input Common Mode Range: VCMR ± 1 V

Output Swing: Vout {max,min} ± 0.5 V

Input Referred Noise 15 nV/√Hz

Very Low Power

Large Load

Good Stability

Design Example – Device Sizing

70

Op Amp Sizing

Transistor Multiplier Size (μm)

M1,2 2 4.05/0.9

M3,4 2 3.6/2.4

M5 6 10.05/1.5

M6 12 15/1.05

M7 6 1.65/1.05

M9,b11 10 1.65/4.05

Mb1 1 1.65/4.05

Mb2 1 1.65/1.05

Mb3 12 1.65/1.05

Mb4 1 2.4/1.05

Mb5 1 12/1.05

Mb6 12 12/1.05

Mb7 2 3/1.2

Mb8 1 1.65/1.05

Mb9,10 10 1.95/0.6

Cc - 5 pF

Isupply - 1.25uA

Summary of Simulated Results Simulated Results

Specification Specifications Simulation

DC gain: Ao 70 dB 72.45 dB

Unity-Gain Frequency: fu 2 MHz 2.01 MHz

Phase Margin: φM 60° 61.83°

Slew Rate: SR+/- ± 1 V/μs 1/-2.45 V/μs

Input Common Mode Range:

VCMR + / VCMR= ± 0.5 V 1.1/-0.75 V

Output Swing:

Vout MAX/Vout MIN ± 1 V 1.14/-1.1

ITotal 30 μA 30 μA

Power - 75 μW

High Speed

+

Low Power

AC Frequency Response (CL = 100pf)

Bandwidth Extension

Large Signal Transient Response (CL = 100pf)

Sine Wave Transient Response (CL = 100pf)

Robustness of Analytical Results

Small Error

Alternative Indirect Feedback Compensation Scheme Results

Comparison of Alternative Indirect Feedback Compensation

Specification Common Gate Cascode NMOS Cascode

PMOS

DC gain: Ao 72.45 dB 91.1 dB 86.1 dB

Unity-Gain

Frequency: fu 2.01 MHz 1.99 MHz 2.2 MHz

Phase Margin: φM 61.83˚ 61.29˚ 61.7˚

M1 M2

M3 M4

M5

VDD

VSS

Cc

Vin- Vin+

M9

ic

V1

M7Mb1

Isupply

Mc1 Mc2

Vbb

A

Vout

Vcc

M1 M2

M3 M4

M5

VDD

VSS

Cc

Vin- Vin+

M9

ic

V1

M7Mb1

Isupply

Mc1 Mc2

Vbb

A

if

Vout

Vcc

M1 M2

M3 M4

M5

M6c

VDD

VSS

Cc

Vin- Vin+

M9

ic

VA

V1

Mb3M7

Mb1

Isupply

Mb2

Mb4

Mb5 Mb6

Vout

Vbb

Common Gate Cascode PMOS Cascode NMOS

Improved gain due To cascoding

Performance Comparison to Miller Compensation and Single Stage Amplifiers

M1 M2

M3 M4

M5

M6c

VDD

VSS

Cc

Vin- Vin+

M9

ic

VA

V1

Mb3M7

Mb1

Isupply

Mb2

Mb4

Mb5 Mb6

Vout

Vbb

Indirect Feedback

Comparison with Miller Compensation and Single Stage Amplifiers

Specification Single Stage Single Miler

Compensation

Indirect Feedback

Compensation

DC gain: Ao 36.93 dB 70.45 dB 72.45

Unity-Gain

Frequency: fu 1.098 MHz 293.1 KHz 2.01 MHz

Phase Margin: φM 90˚ 60.29˚ 61.7˚

Cc Required -NA- 35 pF 5 pF

Miller Compensation Single Stage

Winner

Performance Comparison to Literature

Conference Author Total Id (mA) GBW (MHz) Slew Rate (V/μs) CL (pf) IFOMs (MHz•pf)/mA IFOML ((V/μs)•pf)/mA

ECCTD -2007 [25] Pennisi 1.950 700.00 2000.00 0.3 107.69 307.69

TCAS - 2005 [24] Mahattanakul 0.076 5.00 6.00 5 330.69 396.83

WESEAS -2006 [26] Franz 12.800 1060.00 863.00 4 331.25 269.69

JCSC 2008 [27] Hamed 7.667 300.00 -NA- 8.5 332.61 -NA-

JSSC - 1995 [28] Kovacs 0.110 4.50 -NA- 10 409.09 -NA-

AICSP - 2009 [29] Pugliese 0.318 27.10 25.00 10 851.71 785.71

TCAS - 1997 [6] Palumbo 0.158 28.00 6.59 5 886.08 208.54

E-Letter 2007 [30] Pugliese 0.032 6.70 1.00 10 2125.96 317.31

ECCTD - 2005 [31] Loikkanen 0.210 6.80 6.40 200 6476.19 6095.24

TCAS - 2008 [18] Palumbo 0.150 9.89 -NA- 100 6593.33 -NA-

This Work - Cascode NMOS Kumar 0.025 1.99 1.50 100 7960.00 6000.00

This Work - Common Gate Kumar 0.025 2.00 2.00 100 8000.00 8000.00This Work - Cascode PMOS Kumar 0.025 2.20 2.00 100 8800.00 8000.00

Floor Planning

Diff Input

TAIL CURRENT

PMOS OUT

CURRENT SOURCE CG

NMOS OUT

RESISTOR AVSS

AVDD

BIAS PMOS

BIAS NMOS

SIGNAL PATH

COMPENSATION CAPACITOR

PMOS LOAD

PMOS LOAD

CMFB PMOS CG LOAD

CG AMPLIFIER

SIGNAL PATH

SIGNAL PATHSIGNAL PATH

FLOOR PLANNING

INP

INNVOUT

Considerations Orientation of Transistors Power Distribution Routing Ease Current Mirror Matching

Final Layout