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8/10/2019 PPT Diffusion Logan
1/23
DIFFUSION
Bruce E. Logan
Department of Civil & Environmental Engineering
The Pennsylvania State University
Email: [email protected]
http://www.engr.psu.edu/ce/enve/logan.htm
8/10/2019 PPT Diffusion Logan
2/23
What are the mechanisms for
chemical motion? Advection
Bulk transport by imposed flow. Examples: currentin a stream, flow in a pipe.
Convection Transport due to fluid instability. Examples: air
rising over a hot road. Diffusion- molecular
Scattering of particles (molecules) by randommotion due to thermal energy
Diffusion- turbulent Scattering due to fluid turbuence. Also called
eddy diffusion. This type of diffusion is much
faster than molecular diffusion
8/10/2019 PPT Diffusion Logan
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Diffusion & Dispersion
Diffusion is a method by which a chemical is
dispersed.
Dispersion is the spreading out of a
chemical that can be caused by different
mechanisms
Dont confuse a molecular diffusion
coefficient with a dispersion coefficient (more
on dispersion will come later in the course).
8/10/2019 PPT Diffusion Logan
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Chemical Flux
Molecules move in a
random direction based on
thermal energy
][2
tL
moles
Area
rateflowTotalFlux
Is there a net flux?
8/10/2019 PPT Diffusion Logan
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Chemical Flux
Net flux occurs when
molecules move in a direction
where there are no molecules
to balance their motion back in
the opposite direction.
][2
tL
moles
Area
rateflowTotalFlux
8/10/2019 PPT Diffusion Logan
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Chemical Flux
Net flux occurs when
molecules move in a direction
where there are no molecules
to balance their motion back in
the opposite direction.
][2
tL
moles
Area
rateflowTotalFlux
Direction of net chemical flux
8/10/2019 PPT Diffusion Logan
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Chemical Flux
Net flux occurs when
molecules move in a direction
where there are no molecules
to balance their motion back in
the opposite direction.
][2
tL
moles
Area
rateflowTotalFlux
Direction of net chemical flux
8/10/2019 PPT Diffusion Logan
8/23
We often show chemical flux graphically
as concentration versus time
t=0
t=2
t=4
t=1
Conc.
Distance
t=3
8/10/2019 PPT Diffusion Logan
9/23
Ficks First Law
Fick recognized that there must be a difference in
concentration to drive the net diffusion of a chemical, and
formulated the law:
dz
dxDcj CCwwzCw ,
cw= molar density of water
dxC/dz= molar gradient of C in z-
direction
jCw,z= molar flux of C in z-direction
D= Diffusion constant (fitted
parameter)
8/10/2019 PPT Diffusion Logan
10/23
Ficks First Law
Fick recognized that there must be a difference in
concentration to drive the net diffusion of a chemical, and
formulated the law:
dz
dxDcj CCwwzCw ,
cw= molar density of water
dxC/dz= molar gradient of C in z-
direction
jCw,z= molar flux of C in z-direction
D= Diffusion constant (fitted
parameter)Note negative sign
(flux in directionopposite to gradient)
Gradient in + z-direction
Flux in - direction
Distance (z)
Conc.
8/10/2019 PPT Diffusion Logan
11/23
Ficks First Law
Fick recognized that there must be a difference in
concentration to drive the net diffusion of a chemical, and
formulated the law:
dz
dcDj CwCwzCw ,
cw= molar density of water
dxC/dz= molar gradient of C in z-
direction
jCw,z= molar flux of C in z-direction
D= Diffusion constant (fitted
parameter)
dz
dxDcj CCwwzCw ,
Under isothermal, isobaric conditions,
this can be simplified to:
8/10/2019 PPT Diffusion Logan
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Flux in different directions:
dy
dxDcj CCwwyCw ,
dr
dxDcj CCwwrCw ,
dx
dxDcj CCwwxCw ,
dz
dxDcj CCwwzCw ,
8/10/2019 PPT Diffusion Logan
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Typical values of Diffusion Coefficient
DCw = 10-10 [cm2/s]Solid
DCw = 10-5 [cm2/s]Liquid
DCa = 10-1 [cm2/s]Gas
8/10/2019 PPT Diffusion Logan
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EXAMPLE CALCULATION
A jar of phenol contaminates a room with onlyone cylindrical vent (10 cm diameter, 20 cmdeep)
Neglecting advection, what is the rate ofphenol loss through the vent if the roomconcentration of phenol in air is 0.05%?
Assume: constant temperature of 20oC; alinear concentration gradient in the vent;Dpa=10
-1 cm2/s.
8/10/2019 PPT Diffusion Logan
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Solution
3
32521
,
10
)20(
)79)(/101.2)(/10(
cm
L
cm
cmLmolscmW zPa
)0(
)0(
2
1,
,z
cD
z
cD
dz
dcD
dz
dyDcj PaPa
PaPa
PaPa
CPaazPa
L
mol
L
molecyc aPPa
5
1, 101.2)
1.24
)(0005.0(
222 79)10(44
cmcmdA
2
1,
,,:z
AcDAjWRate PaPazPazPa
WPa,z = 8.210-9 mol/s
8/10/2019 PPT Diffusion Logan
16/23
Ficks Second Law
What is the effect of time on the flux? Or how does the
flux change over time?
distance
gradientconc.concinchange
t
2
2
)/(zcD
zzcD
tc
zzcD
tc
)/(
8/10/2019 PPT Diffusion Logan
17/23
Ficks Second Law
constantdz
dcCwand we have that
0
t
cCwAt steady state,
For a chemical in water:2
2
z
cD
t
c CwCw
Cw
so this becomes2
2
0 z
c
Dt
c CwCw
Cw
This tells us that at steady
state, the flux is constant, i.e. dx
dxDcj CCwwxCw ,
Ficks
First Law
8/10/2019 PPT Diffusion Logan
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How to calculate Diffusion Coefficients?
General Approaches
Tabulated values- best approach
Correlations- many can exist
Experimental- can be time consuming
Air Correlations for DCa Kinetic theory of gases: many limitations, such as
binary mixture.
Hirshfelder correlation: requires a lot of constants
Fuller correlation: best approach
8/10/2019 PPT Diffusion Logan
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FULLER CORRELATION: Diffusivities from Structure
Chemical C in gas g
Where: [these units must be used]
DCa= diffusion coefficient [cm2/s]
T= temperature [K]
P= pressure [atm]
MC= molecular weight of chemical [g/mol]
Mg= molecular weight of gas [g/mol]
VC,d= atomic diffusion volume (from formula and
tabulated values) [cm3]
2/1
23/1
,
3/1
,
375.1 11)(
10
gCdgdC
CgMMVVP
TD
For chemicals
in air:2/1
23/1
,
375.1
0345.01
)73.2(
10
CdC
CaMVP
TD
8/10/2019 PPT Diffusion Logan
20/23
Table 3.1: Logan, Environmental Transport processes, p. 63.
8/10/2019 PPT Diffusion Logan
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How to calculate Diffusion Coefficients?
Water: more on this later
Solids Less information available
Chemical in porous medium is in liquid phase:
hindered diffusion
Chemical adsorbed to soil is in solid phase:
surface diffusion
For hindered and surface diffusion, need to know
diffusion constant in water
8/10/2019 PPT Diffusion Logan
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Examples: Diffusion constants in/on solids
surCwhCwsurhCw
DKDD
,
,,
*)1(
Where:
DCw,h+sur= overall surface diffusion coefficient
DCw,sur= surface diffusion coefficient
K*= dimensionless adsorption partition coefficient
Surface diffusion
hCwpmCw DD ,,
Where:
DCw,pm= diffusion coefficient in porous medium
DCw,h= diffusion coefficient in a single pore
= porosity; typically 0.3
= tortuosity factor; typically 3
Hindered diffusion
8/10/2019 PPT Diffusion Logan
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Diffusion constants: summary
Tabulated values always best
For air, simple correlations should besufficient for level of our calculations
In a porous medium, porosity and tortuosity
factors probably more important than correctvalue for molecular diffusion in air.
For water, situation is much more complex
more on that next.