PPT Diffusion Logan

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    DIFFUSION

    Bruce E. Logan

    Department of Civil & Environmental Engineering

    The Pennsylvania State University

    Email: [email protected]

    http://www.engr.psu.edu/ce/enve/logan.htm

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    What are the mechanisms for

    chemical motion? Advection

    Bulk transport by imposed flow. Examples: currentin a stream, flow in a pipe.

    Convection Transport due to fluid instability. Examples: air

    rising over a hot road. Diffusion- molecular

    Scattering of particles (molecules) by randommotion due to thermal energy

    Diffusion- turbulent Scattering due to fluid turbuence. Also called

    eddy diffusion. This type of diffusion is much

    faster than molecular diffusion

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    Diffusion & Dispersion

    Diffusion is a method by which a chemical is

    dispersed.

    Dispersion is the spreading out of a

    chemical that can be caused by different

    mechanisms

    Dont confuse a molecular diffusion

    coefficient with a dispersion coefficient (more

    on dispersion will come later in the course).

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    Chemical Flux

    Molecules move in a

    random direction based on

    thermal energy

    ][2

    tL

    moles

    Area

    rateflowTotalFlux

    Is there a net flux?

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    Chemical Flux

    Net flux occurs when

    molecules move in a direction

    where there are no molecules

    to balance their motion back in

    the opposite direction.

    ][2

    tL

    moles

    Area

    rateflowTotalFlux

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    Chemical Flux

    Net flux occurs when

    molecules move in a direction

    where there are no molecules

    to balance their motion back in

    the opposite direction.

    ][2

    tL

    moles

    Area

    rateflowTotalFlux

    Direction of net chemical flux

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    Chemical Flux

    Net flux occurs when

    molecules move in a direction

    where there are no molecules

    to balance their motion back in

    the opposite direction.

    ][2

    tL

    moles

    Area

    rateflowTotalFlux

    Direction of net chemical flux

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    We often show chemical flux graphically

    as concentration versus time

    t=0

    t=2

    t=4

    t=1

    Conc.

    Distance

    t=3

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    Ficks First Law

    Fick recognized that there must be a difference in

    concentration to drive the net diffusion of a chemical, and

    formulated the law:

    dz

    dxDcj CCwwzCw ,

    cw= molar density of water

    dxC/dz= molar gradient of C in z-

    direction

    jCw,z= molar flux of C in z-direction

    D= Diffusion constant (fitted

    parameter)

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    Ficks First Law

    Fick recognized that there must be a difference in

    concentration to drive the net diffusion of a chemical, and

    formulated the law:

    dz

    dxDcj CCwwzCw ,

    cw= molar density of water

    dxC/dz= molar gradient of C in z-

    direction

    jCw,z= molar flux of C in z-direction

    D= Diffusion constant (fitted

    parameter)Note negative sign

    (flux in directionopposite to gradient)

    Gradient in + z-direction

    Flux in - direction

    Distance (z)

    Conc.

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    Ficks First Law

    Fick recognized that there must be a difference in

    concentration to drive the net diffusion of a chemical, and

    formulated the law:

    dz

    dcDj CwCwzCw ,

    cw= molar density of water

    dxC/dz= molar gradient of C in z-

    direction

    jCw,z= molar flux of C in z-direction

    D= Diffusion constant (fitted

    parameter)

    dz

    dxDcj CCwwzCw ,

    Under isothermal, isobaric conditions,

    this can be simplified to:

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    Flux in different directions:

    dy

    dxDcj CCwwyCw ,

    dr

    dxDcj CCwwrCw ,

    dx

    dxDcj CCwwxCw ,

    dz

    dxDcj CCwwzCw ,

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    Typical values of Diffusion Coefficient

    DCw = 10-10 [cm2/s]Solid

    DCw = 10-5 [cm2/s]Liquid

    DCa = 10-1 [cm2/s]Gas

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    EXAMPLE CALCULATION

    A jar of phenol contaminates a room with onlyone cylindrical vent (10 cm diameter, 20 cmdeep)

    Neglecting advection, what is the rate ofphenol loss through the vent if the roomconcentration of phenol in air is 0.05%?

    Assume: constant temperature of 20oC; alinear concentration gradient in the vent;Dpa=10

    -1 cm2/s.

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    Solution

    3

    32521

    ,

    10

    )20(

    )79)(/101.2)(/10(

    cm

    L

    cm

    cmLmolscmW zPa

    )0(

    )0(

    2

    1,

    ,z

    cD

    z

    cD

    dz

    dcD

    dz

    dyDcj PaPa

    PaPa

    PaPa

    CPaazPa

    L

    mol

    L

    molecyc aPPa

    5

    1, 101.2)

    1.24

    )(0005.0(

    222 79)10(44

    cmcmdA

    2

    1,

    ,,:z

    AcDAjWRate PaPazPazPa

    WPa,z = 8.210-9 mol/s

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    Ficks Second Law

    What is the effect of time on the flux? Or how does the

    flux change over time?

    distance

    gradientconc.concinchange

    t

    2

    2

    )/(zcD

    zzcD

    tc

    zzcD

    tc

    )/(

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    Ficks Second Law

    constantdz

    dcCwand we have that

    0

    t

    cCwAt steady state,

    For a chemical in water:2

    2

    z

    cD

    t

    c CwCw

    Cw

    so this becomes2

    2

    0 z

    c

    Dt

    c CwCw

    Cw

    This tells us that at steady

    state, the flux is constant, i.e. dx

    dxDcj CCwwxCw ,

    Ficks

    First Law

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    How to calculate Diffusion Coefficients?

    General Approaches

    Tabulated values- best approach

    Correlations- many can exist

    Experimental- can be time consuming

    Air Correlations for DCa Kinetic theory of gases: many limitations, such as

    binary mixture.

    Hirshfelder correlation: requires a lot of constants

    Fuller correlation: best approach

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    FULLER CORRELATION: Diffusivities from Structure

    Chemical C in gas g

    Where: [these units must be used]

    DCa= diffusion coefficient [cm2/s]

    T= temperature [K]

    P= pressure [atm]

    MC= molecular weight of chemical [g/mol]

    Mg= molecular weight of gas [g/mol]

    VC,d= atomic diffusion volume (from formula and

    tabulated values) [cm3]

    2/1

    23/1

    ,

    3/1

    ,

    375.1 11)(

    10

    gCdgdC

    CgMMVVP

    TD

    For chemicals

    in air:2/1

    23/1

    ,

    375.1

    0345.01

    )73.2(

    10

    CdC

    CaMVP

    TD

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    Table 3.1: Logan, Environmental Transport processes, p. 63.

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    How to calculate Diffusion Coefficients?

    Water: more on this later

    Solids Less information available

    Chemical in porous medium is in liquid phase:

    hindered diffusion

    Chemical adsorbed to soil is in solid phase:

    surface diffusion

    For hindered and surface diffusion, need to know

    diffusion constant in water

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    Examples: Diffusion constants in/on solids

    surCwhCwsurhCw

    DKDD

    ,

    ,,

    *)1(

    Where:

    DCw,h+sur= overall surface diffusion coefficient

    DCw,sur= surface diffusion coefficient

    K*= dimensionless adsorption partition coefficient

    Surface diffusion

    hCwpmCw DD ,,

    Where:

    DCw,pm= diffusion coefficient in porous medium

    DCw,h= diffusion coefficient in a single pore

    = porosity; typically 0.3

    = tortuosity factor; typically 3

    Hindered diffusion

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    Diffusion constants: summary

    Tabulated values always best

    For air, simple correlations should besufficient for level of our calculations

    In a porous medium, porosity and tortuosity

    factors probably more important than correctvalue for molecular diffusion in air.

    For water, situation is much more complex

    more on that next.