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ejercicios de maquinarias y trabajo de maquinarias y equipos de construcción
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PRACTICA DE CATEDRA
a) Volúmenes de arcilla y piedra
V arcilla=?Volumen de arcilla 1V 1=[ (0.5∗60∗20+0.5∗20∗40+5∗20 )∗500 ]
V 1=550000mc3
Volumen de piedra 2
V 2=[√602+202∗0.5+√202+402∗0.5 ]∗500
V 2=26991.728mc3
CALCULO DE PRODUCCIONES
PRODUCCION DE LA TOPADORA
PRT=(CH
t )∗f
CH=0.8∗L∗H 2=0.8∗3∗1.202=3.456ms3
De tablas
t f =0.20min Transmisión Directa
t v=t 1+ t2+t 3=d1
0.5v1a
+d2ve
+d3vrev
t v=0.012kmh0.5∗3.5km
+ 0.022kmh4.8km
+(0.012+0.022 ) kmh
7.5 km
t v=0.016h
t=t f +t v=0.2060
+0.016=0.0193h
Factor de corrección
f=f t∗f p∗f o∗f a
f t=5060
f p=1−0.02∗i=1−0.02∗25=0.5
f a=1−0.05d230
=1−0.05∗2230
=0.96
f o=0.80
f=5060
∗0.5∗0.96∗0.80
f o=0.32
PRT=( 3.4560.0193 )∗0.32
PRT=57.302ms3
h
PRT para la arcilla
PRT 1=57.302
ms3
h∗1mb
3
1.35ms3
PRT 1=42.446mb3
h
PRT para la piedra
PRT 2=57.302
m s3
h∗1mb
3
1.67ms3
PRT 2=34.313mb3
h
PRODUCCION DE LA RETROEXCAVADORA
Piedra
PRT=(C r
t )∗f
Capacidad real de la cuchara
C r=Cn∗F¿
F ¿=0.675
C r=2ms3∗0.675=1.35ms
3
Tiempo de ciclo
t=0.6 min∗1h60min
=0.01h
Factor de corrección
f=f c∗f t
f t=5060
f c=¿ 0.50
f=5060
∗0.50=0.42
PRT=( 1.35ms
3
0.01h )∗0.42∗1mb3
1.67ms3
PRT=33.952mb3
h
Arcilla
PRT=(C r
t )∗f
Capacidad real de la cuchara
C r=Cn∗F¿
F ¿=0.70
C r=2ms3∗0.70=1.40ms
3
Tiempo de ciclo
t=0.6 min∗1h60min
=0.01h
Factor de corrección
f=f c∗f t
f t=5060
f c=¿ 0.50
f=5060
∗0.50=0.42
PRT=( 1.40ms
3
0.01h )∗0.42∗1mb3
1.35ms3
PRT=43.56mb3
h
PRODUCCION DEL VOLQUETEDatosC v=10ms
3
W volquete vacio=30 ton
t d=2min
Arcilla
F ¿=0.7(Arcilla dura)
C rc=F¿∗Cnc=0.7∗2.00ms3=1.4ms
3
nvc=Cnv
C rc
=10ms
3
1.4ms3=7.14
~¿7VIAJES
C rv=nvc∗Crc=7∗1.40ms3=9.8ms
3<10ms3
t=t a+t c+t d+t r
t c=nvc∗t ce=7∗0.6min¿4.2min
t a=da
va
= 5km18.71km /h
∗60min¿16.03min
t d=2min
t r=dr
vr
= 5km6.75km /h
∗60min¿ 44.44min
t=4.2+16.03+2+44.44=66.67min¿1.11hr
Resistencias:
RT=RR± RP+RI+RA
AcarreoResistencia a la Rodadura
RR=f R∗W T=50kgton
∗(30+1.33∗10 )=2165kg
Resistencia por pendiente
RP=−10∗W T∗i=0
Resistencia Total
RT=RR± RP=2165kg
T D=RT=2165kg
T D=270 nPu
v
v=270nPu
T D
=270∗0.75∗2002165
=18.71km /hr
Retorno:
Resistencia a la Rodadura
RR=f R∗W T=50kgton
∗(30 ton )=1500kg
Resistencia por pendiente
RP=−10∗W T∗i=10∗30∗15=4500kg
Resistencia Total
RT=RR± RP=1500+4500=6000 kg
T D=RT=6000kg
T D=270 nPu
v
v=270nPu
T D
=270∗0.75∗2006000
=6.75km /hr
f t=4560
=0.75 (ruedas )
PRv=( 9.8ms3
1.11hr )∗0.75
PRv=6.62
ms3
hr∗1mb
3
1.35ms3
PRv=4.90mb3
hr
Piedra
F ¿=0.675C rc=F¿∗Cnc=0.675∗2.00ms
3=1.35ms3
nvc=Cnv
C rc
=10ms
3
1.35ms3=7.41
~¿7VIAJES
C rv=nvc∗Crc=7∗1.35ms3=9.45ms
3<10m s3
t=t a+t c+t d+t r
t c=nvc∗t ce=7∗0.6min¿4.2min
t a=da
va
= 5km17.61km /h
∗60min¿17.04min
t d=2min
t r=dr
vr
= 5km6.75km /h
∗60min¿ 44.44min
t=4.2+17.04+2+44.44=67.68min¿1.13hr
Resistencias:
RT=RR± RP+RI+RA
Acarreo
RR=f R∗W T=50kgton
∗(30+1.60∗10 )=2300kg
RP=−10∗W T∗i=0
RT=RR± RP=2300kg
T D=RT=2300kg
T D=270 nPu
v
v=270nPu
T D
=270∗0.75∗2002300
=17.61km /hr
Retorno:
RR=f R∗W T=50kgton
∗(30 ton )=1500kg
RP=−10∗W T∗i=10∗30∗15=4500kg
RT=RR± RP=1500+4500=6000 kg
T D=RT=6000kg
T D=270 nPu
v
v=270nPu
T D
=270∗0.75∗2006000
=6.75km /hr
f t=4560
=0.75 (ruedas )
PRv=( 9.8ms3
1.13hr )∗0.75
PRv=6.50
ms3
hr∗1mb
3
1.65ms3
PRv=3.94mb3
hr
PRODUCCION DE LA MOTONIVELADORA
PRMN=( a∗ln∗t )∗f
a=0.2m
l=3m
n=5
t=t av+t ret
t=dav
vav
+dret
vret
= 500m0.006m
hr
+ 500m
0.01mhr
=0.133hr
f=f t∗f k∗f d
f=4560
∗(1−0 )∗0.85=0.6375
PRMN=( 0.2m∗3m5∗0.133h )∗0.6375
PRMN=0.575m2
hr .x500m
PRMN=287.59mc
3
hrx
1mb3
(1−0.2 ) mc3
PRMN=359.49mb
3
hr
PRODUCCION DE LA COMPACTADORA
PRC=(1000∗a∗vc∗ec
n )∗f
a=2m
vc=6Kmhr
n=5
es=0.2m
ec=es1−C1+E
ec=0.2m1−0.21+0.35
ec=0.1185m
f=f t∗f k∗f d
f=4560
∗(1−0 )∗0.85=0.6375
PRC=(1000∗a∗vc∗ec
n )∗f
PRC=(1000∗2m∗6 Kmhr
∗0.1185m
5 )∗0.6375PRC=181.305
m3c
hr
PRC=226.63mb
3
hr