psyc200_0805

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    Distribution of Sample Means

    The distribution of the means of an infinitenumber of samples of a certain size selectedfrom a population

    Before, we talked about distributions of scores, but nowwe are talking about the distribution of all possiblesample means of a specific size from a population

    SAMPLING ERROR:

    The amount of error, or the difference, between asample statistic and the corresponding populationparameter

    If we start with a population, and take a number ofsamples from that population, each of the samplemeans will be different from the population mean invarying degrees

    For samples of size ntaken from a population

    with mean, !, and a standard deviation, !,

    As nincreases, the sampling distribution approaches

    the normal distribution

    Holds for all population distributions in other words, as long as your sample size is large (30

    or above usually) the sampling distribution will benormal even if the population (parent distribution) fromwhich it was sampled is not

    CENTRAL LIMIT THEOREM

    X

    =

    "X

    =

    "

    n

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    Central Limit Theorem

    =100

    Population

    Sampling Distribution

    Though the population

    distribution is skewed thesampling distribution will still be

    normal as long as you have alarge enough n.

    "=20

    "

    X

    =

    20

    n

    X

    =100

    STANDARD ERROR OF THE MEAN: The

    standard deviation of the sample means

    Formula:

    Like the standard deviation, the standarderror of the mean gives an average distancefrom all of the sample means to the

    population mean The tells us how much error, onaverage, you would expect between a samplemean and a population mean

    n

    x

    !

    ! =

    x!

    Distribution of Sample Means

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    As n(sample size) gets larger, the distribution ofsample means will approximate a normal distribution

    -- when n>30, the shape of the sampling distributionis almost perfectly normal regardless of the shape of

    the original distribution

    The mean of the sampling distribution of the mean is

    represented by

    or

    The mean of the sample means ( ) will equal thepopulation mean (!)

    x

    x

    Distribution of Sample Means

    X

    =

    X

    LAW OF LARGE NUMBERS:

    The larger the sample, the more accurately thesample represents the population

    Therefore, the larger the sample size, thesmaller the standard error

    Distribution of Sample Means

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    From the previous class example.

    POPULATION

    20

    50

    30

    40

    p(20) =1

    4

    p(30) =1

    4

    p(40) =1

    4

    p(50) =1

    4

    Sampling Distribution of the Mean

    0

    0.05

    0.1

    0.15

    0.2

    0.25

    0.3

    20 30 40 50

    Sample Means

    p(

    )

    Rectangular

    Distribution

    LAW OF LARGE NUMBERS:

    For samples of size 2.Sampling Distribution of the Mean

    0

    0.05

    0.1

    0.15

    0.2

    0.25

    0.3

    20 25 30 35 40 45 50

    Sample Means

    p(

    )

    Sampling Distribution of the Mean

    0

    2

    4

    6

    8

    10

    12

    14

    20 20.3 2 6.7 30 33.3 3 6.7 40 43.3 4 6.7 50

    Sample Means

    p(

    )

    For samples of size 3.

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    EXAMPLE:

    What is the standard error for a sample ofn=25, !=15?

    The average distance of a sample mean fromthe population mean is 3 points

    35

    15

    25

    15====

    n

    x

    !

    !

    Distribution of Sample Means

    As n increases, the distribution approachesthe normal

    Knowing or assuming the population meanand standard deviation, we can use the tableof the standard normal distribution todetermine the probability of obtainingsample means within any interval or beyondany point

    Thus, we can test simple hypotheses about

    sample means (called the z-test) Calculate z-score for sample mean, zobt Compare to critical z-score, zcrit

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    The primary use of the distribution of sample

    means is to find the probability associatedwith getting a specific sample value

    Because the distribution of sample means is

    normal, we can use the z-score table to findprobabilities associated with given samples

    This is called a z-test

    Formula:

    wherex

    x

    z

    !

    "=

    n

    x

    !

    ! =

    Distribution of Sample Means / z-tests

    METHOD 1:

    Step 1: Convert sample mean to zobtStep 2: Compare to zcrit,

    which is either z "for a 1-tailed test, orz"/2for a 2-tailed test

    Step 3: Decide whether or not to reject H0METHOD 2:

    Step 1: Convert sample mean to z

    Step 2: Determine the probability from the z-table

    Step 3: Compare to "

    Step 4: Decide whether or not to reject H0

    Distribution of Sample Means / z-tests

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    EXAMPLE: A population of heights has a !=68and !=4. What is the probability of selecting

    a sample of size n=25 that has a mean of 70or greater?

    Distribution of Sample Means / z-tests

    Summary of Power:

    Power is the sensitivity of an experiment todetect a real effect if there is one.

    Power is the probability the experiment will

    result in rejecting Ho if the IV has a realeffect.

    Power + #= 1

    Power increases with N. Power increases with ".

    Power increases with effect size.

    Power & z-tests

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    Calculating Power

    1. Choose 1-tail or 2-tail test

    2. Set alpha value

    3. Select statistical test

    4. Determine critical values to reject H05. Calculate the probability of obtaining

    those values under a specified H1 That is the power of the test under that

    version of H1

    Power & z-test : N

    1. Choose 1-tail or 2-tail test1-tail

    2. Set alpha value

    0.05

    3. Select statistical testz-test

    From previous example:A population of heights has a !=68 and !=4. What is the probabilityof selecting a sample of size n=25 that has a mean of 70 or greater?

    Calculate the power of this experiment.

    What if we had a sample or size n=100?

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    Power & z-test : N

    4. Determine critical values to rejectH0"=0.05!zcrit=1.645

    zcrit

    =

    Xcrit

    "null

    #X

    Xcrit

    = null

    +"X

    (zcrit

    )!

    80.5

    4

    25

    4====

    n

    x

    !

    !

    "X

    =

    4

    100= 0.4

    Xcrit = 68+ 0.40(1.645)

    Xcrit

    = 68.66

    Xcrit = 68+ 0.80(1.645)

    Xcrit

    = 69.32

    n=25

    n=25

    n=100

    n=100

    Power & z-test : N

    5. Calculate the probability of obtainingthose values under a specified H1 That is the power of the test under that

    version of H1

    z =X

    crit"

    reall

    #X

    z =69.32" 70

    0.80= "0.855

    p= 1-0.1949 = 0.8023

    Power = 0.8023

    - - 2 4 6 8

    z= -0.855

    -4 -2 0 2 4 6 8

    z = 68.66" 70

    0.40= "3.355

    p= 1-0.0005 = 0.9995

    Power = 0.9995

    n=25

    n=25

    n=100

    n=100

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    Power & z-test :

    1. Choose 1-tail or 2-tail test1-tail

    2. Set alpha value

    0.05 & 0.013. Select statistical test

    z-test

    From previous example:A population of heights has a !=68 and !=4. What is the probabilityof selecting a sample of size n=25 that has a mean of 70 or greater?

    Calculate the power of this experiment for "=0.05 and "=0.01

    Power & z-test :

    4. Determine critical values to rejectH0"=0.05!zcrit=1.645

    "=0.01!zcrit=2.335

    zcrit

    =

    Xcrit

    "null

    #X

    Xcrit

    = null

    +"X

    (zcrit

    )!

    Xcrit

    = 68+ 0.80(1.645)

    Xcrit

    = 69.32

    "=0.05

    Xcrit

    = 68+ 0.80(2.335)

    Xcrit

    = 69.87"=0.01

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    Power & z-test :

    5. Calculate the probability of obtainingthose values under a specified H1 That is the power of the test under that

    version of H1

    z =X

    crit"

    reall

    #X

    z =69.32" 70

    0.80= "0.855

    p= 1-0.1949 = 0.8023

    Power = 0.8023

    - - 2 4 6 8

    z= -0.855

    -4 -2 0 2 4 6 8

    p= 1-0.4325 = 0.5675

    Power = 0.5675

    "=0.05

    "=0.05

    "=0.01

    z =69.87 " 70

    0.80= "0.165

    "=0.01