Pumps & Turbines 01 150730

8/20/2019 Pumps & Turbines 01 150730

1/156

1

FUNDAMENTALS OFFUNDAMENTALS OFFLUID MECHANICSFLUID MECHANICS

Chapter 12 Pumps andChapter 12 Pumps andTurbinesTurbines

JyhJyh--CherngCherng ShiehShiehDepartment of BioDepartment of Bio--IndustrialIndustrial MechatronicsMechatronics EngineeringEngineering

National Taiwan University National Taiwan University

8/20/2019 Pumps & Turbines 01 150730

2/156

2

MAIN TOPICSMAIN TOPICS

IntroductionIntroduction

Basic Energy ConsiderationsBasic Energy Considerations

Basic Angular Momentum ConsiderationsBasic Angular Momentum Considerations

The Centrifugal PumpThe Centrifugal Pump

Dimensionless Parameters and Similarity LawsDimensionless Parameters and Similarity Laws

AxialAxial--Flow and MixedFlow and Mixed--Flow PumpsFlow Pumps

FansFansTurbinesTurbines

Compressible FlowCompressible Flow TurbomachinesTurbomachines

8/20/2019 Pumps & Turbines 01 150730

3/156

3

Pumps and TurbinesPumps and Turbines

Pumps and turbines: Fluid machines.Pumps and turbines: Fluid machines.

Pumps: Add energy to the fluidPumps: Add energy to the fluid – – they do work on thethey do work on thefluid.fluid.

Turbines: Extract energy from the fluidTurbines: Extract energy from the fluid – – the fluid doesthe fluid does

work on them.work on them.

8/20/2019 Pumps & Turbines 01 150730

4/156

4

Fluid MachinesFluid Machines

Positive displacement machines (denoted as the static type)Positive displacement machines (denoted as the static type)

TurbomachinesTurbomachines (denoted as the dynamic type).(denoted as the dynamic type).

8/20/2019 Pumps & Turbines 01 150730

5/156

5

Positive Displacement MachinesPositive Displacement Machines

Force fluid into or out of aForce fluid into or out of a

chamber by changing thechamber by changing thevolume of the chamber.volume of the chamber.

The pressure developed andThe pressure developed and

the work done are a result ofthe work done are a result ofessentially static forcesessentially static forces

rather than dynamic effects.rather than dynamic effects.

Typical positive displacement pumps: (Typical positive displacement pumps: (aa) tire) tire

pump, ( pump, (bb) human heart, () human heart, (cc) gear pump.) gear pump.

8/20/2019 Pumps & Turbines 01 150730

6/156

6

TurbomachinesTurbomachines

TurbomachinesTurbomachines involve a collection of blades, buckets,involve a collection of blades, buckets,

flow channels, or passages arranged around an axis offlow channels, or passages arranged around an axis ofrotation to form a rotor.rotation to form a rotor.

TurbomachinesTurbomachines are mechanical devices that either extractare mechanical devices that either extract

energy from a fluid (turbine) or add energy to a fluidenergy from a fluid (turbine) or add energy to a fluid(pump) as a result of dynamic interactions between the(pump) as a result of dynamic interactions between the

device and the fluid.device and the fluid.

The fluid used can be either a gas or a liquid.The fluid used can be either a gas or a liquid.

8/20/2019 Pumps & Turbines 01 150730

7/156

7

Operating Principles ofOperating Principles of TurbomachinesTurbomachines

The basic operating principles are the same whether theThe basic operating principles are the same whether the

fluid is a liquid or a gas.fluid is a liquid or a gas.CavitationCavitation may be an important design consideration whenmay be an important design consideration when

liquids are involved if the pressure at any point within theliquids are involved if the pressure at any point within the

flow is reduced to vapor pressure.flow is reduced to vapor pressure.

Compressibility effects may be important when gases areCompressibility effects may be important when gases are

involved if the Mach number becomes large enough.involved if the Mach number becomes large enough.

8/20/2019 Pumps & Turbines 01 150730

8/156

8

Structure ofStructure of TurbomachinesTurbomachines

ManyMany turbomachinesturbomachines contain some type of housing orcontain some type of housing or

casting that surrounds the rotating blades or rotor, thuscasting that surrounds the rotating blades or rotor, thusforming a n internal flow passageway through which theforming a n internal flow passageway through which the

fluid flows.fluid flows.

SomeSome turbomachinesturbomachines include stationary blades or vanes ininclude stationary blades or vanes inaddition to rotor blades. These stationary vanes can beaddition to rotor blades. These stationary vanes can be

arranged to accelerate the flow and thus serve as anarranged to accelerate the flow and thus serve as an

nozzles.nozzles.These vanes can be set to diffuse the flow and act asThese vanes can be set to diffuse the flow and act as

diffusers.diffusers.

8/20/2019 Pumps & Turbines 01 150730

9/156

9

Classification ofClassification of TurbomachinesTurbomachines

AxialAxial--flow machines: The fluid maintains a significantflow machines: The fluid maintains a significant

axialaxial--flow direction component from the inlet to outlet offlow direction component from the inlet to outlet ofthe rotor.the rotor.

MixedMixed--flow machines: There may be significant radialflow machines: There may be significant radial--

and axialand axial--flow velocity components for the flow throughflow velocity components for the flow throughthe rotor row.the rotor row.

RadialRadial--flowflow mahcinesmahcines: The flow across the: The flow across the blads blads involvesinvolves

a substantial radiala substantial radial--flow component at the rotor inlet, exit,flow component at the rotor inlet, exit,or both.or both.

8/20/2019 Pumps & Turbines 01 150730

10/156

10

Basic Energy ConsiderationsBasic Energy Considerations

By considering the basic operation of By considering the basic operation of

Household fan (pump).Household fan (pump).

Windmill (turbine).Windmill (turbine).

8/20/2019 Pumps & Turbines 01 150730

11/156

8/20/2019 Pumps & Turbines 01 150730

12/156

12

Household FanHousehold Fan2/22/2

Idealized flow through a fan: (a) fan blade geometry: (b) absoluIdealized flow through a fan: (a) fan blade geometry: (b) absolutete

velocity, V; relative velocity, W, and blade velocity, U at thevelocity, V; relative velocity, W, and blade velocity, U at the inlet andinlet and

exit of the fan blade section.exit of the fan blade section.

8/20/2019 Pumps & Turbines 01 150730

13/156

13

WindmillWindmill

Consider the windmill. Rather than the rotor being driven by aConsider the windmill. Rather than the rotor being driven by a

motor, it is rotated in the opposite direction by the wind blowimotor, it is rotated in the opposite direction by the wind blowingngthrough the rotor.through the rotor.

Idealized flow through a windmill: (a) windmill blade geometry;Idealized flow through a windmill: (a) windmill blade geometry; (b)(b)

absolute velocity, V; relative velocity, W, and blade velocity,absolute velocity, V; relative velocity, W, and blade velocity, U atU at

the inlet and exit of the windmill blade section.the inlet and exit of the windmill blade section.

8/20/2019 Pumps & Turbines 01 150730

14/156

14

Example 12.1 Drag from Pressure andExample 12.1 Drag from Pressure and

Shear Stress DistributionsShear Stress Distributions

The rotor shown in Fig. E12.1a rotates at a constant angular velThe rotor shown in Fig. E12.1a rotates at a constant angular velocityocity

ofofωω= 100= 100 rad/srad/s. Although the fluid initially approaches the rotor in. Although the fluid initially approaches the rotor inan axial direction, the flow across the blades is primarily radian axial direction, the flow across the blades is primarily radial.al.Measurements indicate that the absolute velocity at the inlet anMeasurements indicate that the absolute velocity at the inlet andd

outlet are Voutlet are V11 = 12= 12 m/sm/s and Vand V22 = 15= 15 m/sm/s, respectively. Is this device a, respectively. Is this device a

pump or a turbine? pump or a turbine?

8/20/2019 Pumps & Turbines 01 150730

15/156

15

Example 12.1Example 12.1 SolutionSolution1/21/2

s/m10r Us/m10r U 2211 =ω==ω=

If the tangential component f the force of the blade on the fluid is in

the direction of the blade motion (a pump) or opposite to it (a

turbine).

The inlet and outlet blade

8/20/2019 Pumps & Turbines 01 150730

16/156

16


The inlet velocity triangle The outlet velocity triangle

At the inlet there is no component of absolute velocity in theAt the inlet there is no component of absolute velocity in thedirection of rotation; at the outlet this component is not zero.direction of rotation; at the outlet this component is not zero. That is,That is,

the blade pushes and turns the fluid in the direction of the blathe blade pushes and turns the fluid in the direction of the bladede

motion, thereby doing work on the fluid.motion, thereby doing work on the fluid. This device is a pump.This device is a pump.

8/20/2019 Pumps & Turbines 01 150730

17/156

17

Basic Angular MomentumBasic Angular MomentumConsiderationsConsiderations

8/20/2019 Pumps & Turbines 01 150730

18/156

18

Angular Momentum Considerations Angular Momentum Considerations1/61/6

Work transferred to or from a fluid flowing through aWork transferred to or from a fluid flowing through a

pump or a turbine occurs by interaction between moving pump or a turbine occurs by interaction between movingrotor blades and the fluid.rotor blades and the fluid.

Pump: The shaft toque (the torque that the shaft appliesPump: The shaft toque (the torque that the shaft applies

to the rotor) and the rotation of the rotor are in the sameto the rotor) and the rotation of the rotor are in the samedirection, energy is transferred from the shaft to thedirection, energy is transferred from the shaft to the

rotor and from the rotor to the fluid.rotor and from the rotor to the fluid.

Turbine: The torque exerted by the shaft on the rotor isTurbine: The torque exerted by the shaft on the rotor isopposite to the direction of rotation, the energy transferopposite to the direction of rotation, the energy transfer

is from the fluid to the rotor.is from the fluid to the rotor.

8/20/2019 Pumps & Turbines 01 150730

19/156

19


All of theAll of the turbomachinesturbomachines involve the rotation of aninvolve the rotation of an

impeller or a rotor about a central axis, it is appropriate toimpeller or a rotor about a central axis, it is appropriate todiscuss their performance in terms ofdiscuss their performance in terms of torque and angulartorque and angular

momentummomentum..

8/20/2019 Pumps & Turbines 01 150730

20/156

20


In aIn a turbomachineturbomachine a series of particles (a continuum)a series of particles (a continuum)

passes through the rotor. passes through the rotor.For steady flow, the moment of momentum equationFor steady flow, the moment of momentum equation

applied to a control volumeapplied to a control volume

∫∑ ⋅ρ×=× CS dAnV)Vr ()Fr ( rrrrrr

Sum of the external torquesSum of the external torques

Net rate of flow of moment Net rate of flow of moment--of of --momentum (angular momentum)momentum (angular momentum)

through the control volumethrough the control volume

8/20/2019 Pumps & Turbines 01 150730

21/156

21


Shaft work applied to the contentsShaft work applied to the contentsof the control volumeof the control volume

““++”” : in the same direction as rotation: in the same direction as rotation

““--”” : in the opposite direction as rotation: in the opposite direction as rotation

Applied to the oneApplied to the one--dimensional simplification of flowdimensional simplification of flow

through athrough a turbomachineturbomachine rotor, the axial componentrotor, the axial component

)Vr (m)Vr (mT 2θ221θ11shaft && +−=

EulerEuler turbomachineturbomachine equationequation

(2)(2)

EulerEuler turbomachineturbomachine equationequation : the shaft torque is directly: the shaft torque is directly

proportional to the mass proportional to the mass flowrateflowrate. The torque also depends on the. The torque also depends on the

tangential component of the absolute velocity,tangential component of the absolute velocity, VVθθ..

8/20/2019 Pumps & Turbines 01 150730

22/156

22


(3(3) (4) (5) :The basic governing equations for pumps orThe basic governing equations for pumps orturbines whether the machines are radialturbines whether the machines are radial--, mixed, or axial, mixed, or axial--flowflow

devices and for compressible and incompressible flows.devices and for compressible and incompressible flows.

(2)(2) ω= shaftshaft TW&

21 mmm &&& ==

)VU()VU(m

Ww

2θ21θ1

shaft

shaft +−==

&

&

)VU(m)VU(mW 2θ221θ11shaft &&& +−=

(3)(3)

(4)(4)

(5)(5)

8/20/2019 Pumps & Turbines 01 150730

23/156

23


222x

2x

22 VVVVVV θθ −=+=

(8)(8)

Another useful but more laborious form.Another useful but more laborious form.

Based on the velocity triangles at the entrance or exit.Based on the velocity triangles at the entrance or exit.

222x W)UV(V =−+ θ (7)(7)

(6)+(7)(6)+(7)2

WUVUV

222 −+=θ

(5)(5)2

)WW(UUVVw

212221222122shaft

−−−+−=

TurbomachineTurbomachine work is related to changes in absolute, relative, andwork is related to changes in absolute, relative, and

blade velocities. blade velocities.

(6)(6)

8/20/2019 Pumps & Turbines 01 150730

24/156

24

The Centrifugal PumpThe Centrifugal Pump

8/20/2019 Pumps & Turbines 01 150730

25/156

25

Structure of the Centrifugal PumpStructure of the Centrifugal Pump1/31/3

Centrifugal pump has two main components: an impellerCentrifugal pump has two main components: an impeller

and a stationary casing, housing, or volute.and a stationary casing, housing, or volute.

8/20/2019 Pumps & Turbines 01 150730

26/156

26


An impeller attached to the rotating shaft. The impellerAn impeller attached to the rotating shaft. The impeller

consists of a number of blades, also sometimes calledconsists of a number of blades, also sometimes calledvanes, arranged in a regular pattern around the shaft.vanes, arranged in a regular pattern around the shaft.

((aa) Open impeller, () Open impeller, (bb) enclosed or shrouded impeller ) enclosed or shrouded impeller

Type of impeller Type of impeller

8/20/2019 Pumps & Turbines 01 150730

27/156

27


A stationary casing, housing, or volute enclosing theA stationary casing, housing, or volute enclosing the

impeller.impeller.The casing shape is designed to reduce the velocity asThe casing shape is designed to reduce the velocity as

the fluid leaves the impeller, and this decrease in kineticthe fluid leaves the impeller, and this decrease in kinetic

energy is converted into an increase in pressure.energy is converted into an increase in pressure.The voluteThe volute--shaped casing, with its increase area in theshaped casing, with its increase area in the

direction of flow, is used to produce an essentiallydirection of flow, is used to produce an essentially

uniform velocity distribution as the fluid moves arounduniform velocity distribution as the fluid moves aroundthe casing into the discharge opening.the casing into the discharge opening.

8/20/2019 Pumps & Turbines 01 150730

28/156

28

Operation of the Centrifugal PumpOperation of the Centrifugal Pump

As the impeller rotates, fluid is sucked in through the eyeAs the impeller rotates, fluid is sucked in through the eye

of the casing and flowsof the casing and flows radiallyradially outward.outward.Energy is added to the fluid by the rotating blades, andEnergy is added to the fluid by the rotating blades, and

both pressure and absolute velocity are increased as the both pressure and absolute velocity are increased as the

fluid lows from the eye to the periphery of the blades.fluid lows from the eye to the periphery of the blades.

8/20/2019 Pumps & Turbines 01 150730

29/156

29

Stages of the Centrifugal PumpStages of the Centrifugal Pump

Simple stage pump: Only one impeller is mounted on theSimple stage pump: Only one impeller is mounted on the

shaft.shaft.Multistage pump: Several impellers are mounted on theMultistage pump: Several impellers are mounted on the

same shaft.same shaft.

TheThe flowrateflowrate is the same through all stages.is the same through all stages.

Each stage develops an additional pressure rise.Each stage develops an additional pressure rise.

For a very large discharge pressure.For a very large discharge pressure.

8/20/2019 Pumps & Turbines 01 150730

30/156

30

Theoretical ConsiderationsTheoretical Considerations1/51/5

The basic theory ofThe basic theory of

operation of a centrifugaloperation of a centrifugal pump can be developed by pump can be developed by

considering the averageconsidering the average

oneone--dimensional flow ofdimensional flow ofthe fluid as it passesthe fluid as it passes

between the inlet and the between the inlet and the

outlet sections of theoutlet sections of theimpeller as the bladesimpeller as the blades

rotate.rotate.

Velocity diagrams at the inlet and exit of a centrifugal pump impeller.

8/20/2019 Pumps & Turbines 01 150730

31/156

31


The moment of momentum equation indicates that theThe moment of momentum equation indicates that the

shaft torque required to rotate the pump impeller isshaft torque required to rotate the pump impeller is

)VUVU(Q)Vr Vr (QTW 1θ12θ21θ12θ2shaftshaft −ρ=−ωρ=ω=&21 mmm

&&&

==

1θ12θ2shaft

shaft VUVUm

Ww −==&

&

)Vr Vr (Q)Vr Vr (mT 1θ12θ21θ12θ2shaft −ρ=−= &

(11)(11)

(12)(12)

The tangential components of the absolute velocityThe tangential components of the absolute velocity

(9) (10)(9) (10)

8/20/2019 Pumps & Turbines 01 150730

32/156

32


The head that a pump adds to the fluid is an importantThe head that a pump adds to the fluid is an important

parameter. The ideal or maximum head rise possible, h parameter. The ideal or maximum head rise possible, hii

ishaft gQhW ρ=&

)VUVU(g1h 1θ12θ2i −=

(14)(14)

(13)(13)+(12)+(12)

g2

)WW()UU()VV(h

22

21

21

22

21

22

i

−+−+−=(8)+(12)(8)+(12)

8/20/2019 Pumps & Turbines 01 150730

33/156

33


An appropriate relationship between theAn appropriate relationship between the flowrateflowrate and theand the

pump ideal head rise: pump ideal head rise:

2r

222

VVUcot θ−=β

g

VUh 2θ2i=

(16)(16)

(15)(15)αα11=90=90ºº +(12)+(12)

g

cotVU

g

Uh 22r 2

22

i

β−=

(15)(15)

(16)+(17)(16)+(17)

2r 22V br 2Q π=

Qg br 2

cotU

g

Uh

22

2222

i πβ

−=

(17)(17)

(18)(18)

8/20/2019 Pumps & Turbines 01 150730

34/156

34


Q

g br 2

cotU

g

Uh

22

2222

i

π

β−=

For a centrifugal pump withFor a centrifugal pump with

backward curved vanes ( backward curved vanes ( ββ22

8/20/2019 Pumps & Turbines 01 150730

35/156

35

Example 12.2 Centrifugal Pump PerformanceExample 12.2 Centrifugal Pump Performance

Based on Inlet/Outlet VelocitiesBased on Inlet/Outlet Velocities

Water is pumped at the rate of 1400Water is pumped at the rate of 1400 gpmgpm through a centrifugal pumpthrough a centrifugal pumpoperating at a speed of 1750 rpm. The impeller has a uniform blaoperating at a speed of 1750 rpm. The impeller has a uniform bladede

length, b, of 2 in. with r length, b, of 2 in. with r 11 = 1.9 in. and r = 1.9 in. and r 22 = 7.0 in., and the exit blade= 7.0 in., and the exit bladeangle isangle isββ=23=23ºº . Assume ideal flow conditions and that the. Assume ideal flow conditions and that thetangential velocity component, Vtangential velocity component, Vθθ11, of the water entering the blade, of the water entering the bladeis zero (is zero (αα11=90=90 ºº). Determine (a) the tangential velocity component,). Determine (a) the tangential velocity component,

VVθθ22, at the exit, (b) the ideal head rise, h, at the exit, (b) the ideal head rise, haa, and (c) the power, ,, and (c) the power, ,transferred to the fluid. Discuss the difference between ideal atransferred to the fluid. Discuss the difference between ideal andndactual head rise. Is the power, ,ideal or actual? Explactual head rise. Is the power, ,ideal or actual? Explain.ain.

shaftW&

shaftW&

8/20/2019 Pumps & Turbines 01 150730

36/156

36


s/ft107min)/s60/rpm1750)(rev/rad2)(ft12/7(r U 22 =π=ω=

The tip velocity of the impeller

s/ft11.5 br 2

Q

VV br 2Q 222r 2r 22 =π=π=

Since the flowrate is given

s/ft0.95cotV2UVV

VUcot 22r 2

2r

222 =β−=⇒

−=β θ

θ

ft316g

VUh 2θ2i ==(15)(15)

8/20/2019 Pumps & Turbines 01 150730

37/156

37


The power transferred to the fluid

hp112...VQUW 22shaft ==ρ= θ&

8/20/2019 Pumps & Turbines 01 150730

38/156

38

Pump Performance CharacteristicsPump Performance Characteristics

1/81/8

Typical experimental arrangement for determining theTypical experimental arrangement for determining the

head rise, hhead rise, haa, gained by a fluid flowing through a pump., gained by a fluid flowing through a pump.Using the energy equation with hUsing the energy equation with haa==hhss--hhLL

g2

V

g2

Vzz

p ph

2

1

2

21212a −+−+γ−

= (19)(19)

8/20/2019 Pumps & Turbines 01 150730

39/156

39


2/82/8

γ

−≈ 12a

p ph (20)(20)The differences in elevationsThe differences in elevations

and velocities are smalland velocities are smallThe power gained by the fluidThe power gained by the fluid

af QhP γ= (21)(21)

550

Qhhorsepower water P af

γ== (22)(22)

Overall efficientOverall efficient

bhp

550/Qh

W

P

pumpthedriving power shaft

fluidthe bygained power a

shaft

f γ===η&

(23)(23)

8/20/2019 Pumps & Turbines 01 150730

40/156

40


3/83/8

The overall pump efficiency is affected by theThe overall pump efficiency is affected by the hydraulic hydraulic

losseslosses in the pump, and in addition, by thein the pump, and in addition, by the mechanical mechanicallosseslosses in the bearings and seals.in the bearings and seals.

There may also be some power loss due to leakage of theThere may also be some power loss due to leakage of the

fluid between the back surface of the impeller hub platefluid between the back surface of the impeller hub plateand the casing, or through other pump components.and the casing, or through other pump components.

This leakage contribution to the overall efficiency is calledThis leakage contribution to the overall efficiency is called

the volumetric loss.the volumetric loss.

8/20/2019 Pumps & Turbines 01 150730

41/156

41


4/84/8

The overall efficiency arises from three source,The overall efficiency arises from three source, thethe

hydraulic efficiency,hydraulic efficiency,ηηh,,h,,thethe mechanical efficiency,mechanical efficiency,ηηm ,m ,,,and the volumetric efficiency,and the volumetric efficiency,ηηvv

ηη==ηηhhηηmmηηvv

8/20/2019 Pumps & Turbines 01 150730

42/156

42

Pump Performance CharacteristicsPump Performance Characteristics 5/85/8

Typical performanceTypical performance

characteristics for a centrifugalcharacteristics for a centrifugal

pump of a given size operating at a pump of a given size operating at aconstant impeller speed.constant impeller speed.

Rising head curveRising head curve

capacitycapacityBest efficiency points (BEP)Best efficiency points (BEP)

Performance characteristics for a given pump geometryPerformance characteristics for a given pump geometry

and operating speed are usually given in the plots of hand operating speed are usually given in the plots of haa,,ηη,,andand bhp bhp versus Q.versus Q.

8/20/2019 Pumps & Turbines 01 150730

43/156

43


Rise head curve:Rise head curve: the head curve continuously rises as thethe head curve continuously rises as theflowrateflowrate decreases.decreases.

Falling head curveFalling head curve:: haha--Q curves initially rise as Q isQ curves initially rise as Q isdecreased from the design value and then fall with adecreased from the design value and then fall with acontinued decrease in Q.continued decrease in Q.

Shutoff headShutoff head:: the head developed by the pump at zerothe head developed by the pump at zerodischarge. It represents the rise in pressure head across thedischarge. It represents the rise in pressure head across the pump with the discharge valve closed. pump with the discharge valve closed.

Best efficiency points (BEP):Best efficiency points (BEP): the points on the variousthe points on the variouscurves corresponding to the maximum efficiency.curves corresponding to the maximum efficiency.

8/20/2019 Pumps & Turbines 01 150730

44/156

44


AsAs the discharge is increased from zero the brakethe discharge is increased from zero the brakehorsepower increases, with a subsequent fall as thehorsepower increases, with a subsequent fall as themaximum discharge is approachedmaximum discharge is approached..

The efficiency is a function of theThe efficiency is a function of the flowrateflowrate and reaches aand reaches amaximum value at some particular value of themaximum value at some particular value of the flowrateflowrate,,

commonly referred to as the normal or designcommonly referred to as the normal or design flowrateflowrate ororcapacity for the pump.capacity for the pump.

The performance curves are very important to the engineerThe performance curves are very important to the engineer

responsible for the selection of pumps for a particular flowresponsible for the selection of pumps for a particular flowsystem.system.

8/20/2019 Pumps & Turbines 01 150730

45/156

45


Performance curves for a twoPerformance curves for a two--stage centrifugal pump operatingstage centrifugal pump operating

at 3500 rpm. Data given for three different impeller diameters.at 3500 rpm. Data given for three different impeller diameters.

NPSHNPSHRR

Required net positiveRequired net positivesuction headsuction head

Related to conditionsRelated to conditions

on the suction side ofon the suction side of

the pumpthe pump

8/20/2019 Pumps & Turbines 01 150730

46/156

46

Net Positive Suction HeadNet Positive Suction Head 1/21/2

On the suction side of a pump, low pressures areOn the suction side of a pump, low pressures are

commonly encountered, with the concomitant possibilitycommonly encountered, with the concomitant possibilityofof cavitationcavitation occurring within the pump.occurring within the pump.

CavitationCavitation occurs when the liquid pressure at a givenoccurs when the liquid pressure at a given

location is reduced to the vapor pressure of the liquid.location is reduced to the vapor pressure of the liquid.When this occurs, vapor bubbles form; this phenomenonWhen this occurs, vapor bubbles form; this phenomenon

can cause a loss in efficiency as well as structural damagecan cause a loss in efficiency as well as structural damage

to the pump.to the pump.How to characterize the potential forHow to characterize the potential for cavitationcavitation……

8/20/2019 Pumps & Turbines 01 150730

47/156

47

Net Positive Suction HeadNet Positive Suction Head 2/22/2

To characterize the potential forTo characterize the potential for cavitationcavitation, define the net, define the net

positive suction head (NPSH) as positive suction head (NPSH) as

γ−+

γ= v

2ss p

g2

V p NPSH (24)(24)

The total head on theThe total head on the

suction side near thesuction side near the

pump impeller inlet pump impeller inlet

The liquid vaporThe liquid vapor

pressure head pressure head

There are actually two values of NPSH of interest.There are actually two values of NPSH of interest.

8/20/2019 Pumps & Turbines 01 150730

48/156

48

NPSHNPSHRR

and NPSHand NPSH A A

1/31/3

Required NPSHRequired NPSH, denoted NPSH, denoted NPSHR R , that must be, that must be

maintained, or exceeded, so thatmaintained, or exceeded, so that cavitationcavitation will not occur.will not occur.Since pressure lower than those in the suction pipe willSince pressure lower than those in the suction pipe will

develop in the impeller eye, it is usually necessary todevelop in the impeller eye, it is usually necessary to

determine experimentally, for a given pump, the requireddetermine experimentally, for a given pump, the required

NPSH NPSHR R ..

Available NPSHAvailable NPSH, denoted NPSH, denoted NPSHAA, represents the head, represents the head

that actually occurs for the particular flow system. Thisthat actually occurs for the particular flow system. Thisvalue can be determined experimentally, or calculated ifvalue can be determined experimentally, or calculated if

the system parameters are known.the system parameters are known.

8/20/2019 Pumps & Turbines 01 150730

49/156

49

NPSHNPSHRR


2/32/3

For a typical flow systemFor a typical flow system

The energy equation appliedThe energy equation applied

between the free liquid between the free liquid

surface and a point on thesurface and a point on the

suction side of the pump nearsuction side of the pump near

the impeller inletthe impeller inlet

∑++γ=−γ L2ss

1atm h

g2

V pz

p Head losses between the freeHead losses between the free

surface and the pumpsurface and the pump

impeller inlet.impeller inlet.

8/20/2019 Pumps & Turbines 01 150730

50/156

50

NPSHNPSHRR


3/33/3

The head available atThe head available at

the pump impeller inletthe pump impeller inlet

∑−−

γ

=+

γL1

atm2ss hz

p

g2

V p

For proper pump operationFor proper pump operation

γ−−−

γ= ∑ vL1atmA phz p NPSH

R A NPSH NPSH ≥

(25)(25)

8/20/2019 Pumps & Turbines 01 150730

51/156

51

Example 12.3 Net Pressure Suction HeadExample 12.3 Net Pressure Suction Head

A centrifugal pump is to be placed above a large, open water tanA centrifugal pump is to be placed above a large, open water tank,k,

as shown in Fig. 12.13, and is to pump water at a rate of 0.5ftas shown in Fig. 12.13, and is to pump water at a rate of 0.5ft33/s. At/s. At

thisthis flowrateflowrate the required net positive suction head, NPSHthe required net positive suction head, NPSHR R , is 15 ft,, is 15 ft,

as specified by the pump manufacturer. If the water temperatureas specified by the pump manufacturer. If the water temperature isis

8080ººF and atmospheric pressure is 14.7F and atmospheric pressure is 14.7 psi psi, determine the maximum, determine the maximum

height, zheight, z11, that the pump can be located above the water surface, that the pump can be located above the water surfacewithoutwithout cavitationcavitation. Assume that the major loss between the tank and. Assume that the major loss between the tank and

the pump inlet is due to filter at the pipe inlet having a minor the pump inlet is due to filter at the pipe inlet having a minor lossloss

coefficientcoefficient k k LL = 20. Other losses can be neglected. The pipe on the= 20. Other losses can be neglected. The pipe on the

suction side of the pump has a diameter of 4 in. If you were reqsuction side of the pump has a diameter of 4 in. If you were requireduiredto place a valve in the flow path would you place it upstream or to place a valve in the flow path would you place it upstream or

downstream of the pump? Why?downstream of the pump? Why?

8/20/2019 Pumps & Turbines 01 150730

52/156

52

Example 12.3Example 12.3

SolutionSolution

and the maximum value for zand the maximum value for z11 will occur when ZPSHwill occur when ZPSHAA=NPSH=NPSHR R

(25)(25)γ

−−−γ

= ∑ vL1atmA phz p NPSH

R

v

L

atm

max1 NPSH

p

h

p

)z( −γ−−γ= ∑ft2.10...

g2

VK hs/ft73.5

A

QV

2

LL ===== ∑ft65.7... NPSH

ph

p)z( R

vL

atmmax1 ==−γ

−−γ

= ∑

8/20/2019 Pumps & Turbines 01 150730

53/156

53

System Characteristics and Pump SelectionSystem Characteristics and Pump Selection 1/41/4

For a typical flow system in which a pump is usedFor a typical flow system in which a pump is used

The energy equation appliedThe energy equation applied

between points (1) and (2) between points (1) and (2)

∑+−=L12 p hzzh

All friction lossesAll friction lossesand minor lossesand minor lossesThe actual head gainedThe actual head gained

by the fluid from the by the fluid from the

pump. pump.

(26)(26)

8/20/2019 Pumps & Turbines 01 150730

54/156

54


K depends on the pipe sizeK depends on the pipe size

and lengths, friction factors,and lengths, friction factors,

and minor loss coefficients.and minor loss coefficients.

212 p KQzzh +−=(26)(26)

2L KQh ∝

(27)(27)

(27)(27) is the system equation which shows how the actualis the system equation which shows how the actual

head gained by the fluid from the pump is related to thehead gained by the fluid from the pump is related to the

system parameters.system parameters.

8/20/2019 Pumps & Turbines 01 150730

55/156

55


There is also a uniqueThere is also a unique

relationship between therelationship between theactual pump head gainedactual pump head gained

by the fluid and by the fluid and flowrateflowrate,,

which is governed by thewhich is governed by the

pump design. pump design.

Pipe friction increase duePipe friction increase due

to wall fouling.to wall fouling.(A)(A) (B)(B) flowrateflowrate↓↓

efficiencyefficiency↓↓Utilization of the system curve and theUtilization of the system curve and the

pump performance curve to obtain the pump performance curve to obtain the

operating point for the system.operating point for the system.

8/20/2019 Pumps & Turbines 01 150730

56/156

56


To select a pump for a particular application, it isTo select a pump for a particular application, it is

necessary to utilize both the system curve, determined bynecessary to utilize both the system curve, determined bythe system equation, and the pump performance curve.the system equation, and the pump performance curve.

The intersection of both curves represents the operatingThe intersection of both curves represents the operating

point for the system. point for the system.The operating point wanted to be near the bestThe operating point wanted to be near the best

efficiency point (BEP).efficiency point (BEP).

SP i S i P ll l 1/31/3

8/20/2019 Pumps & Turbines 01 150730

57/156

57

Pumps in Series or ParallelPumps in Series or Parallel 1/31/3

Effect of operating pumps in (Effect of operating pumps in (aa) series and () series and (bb) in parallel.) in parallel.

P i S i P ll lP i S i P ll l 2/32/3

8/20/2019 Pumps & Turbines 01 150730

58/156

58


When two pumps are placed in seriesWhen two pumps are placed in series

The resulting pump performance curve is obtained byThe resulting pump performance curve is obtained byadding heads at the sameadding heads at the same flowrateflowrate..

Both the actual head and theBoth the actual head and the flowrateflowrate are increased butare increased but

neither will be doubled.neither will be doubled.The operating point is moved from (A) to (B).The operating point is moved from (A) to (B).

P i S i P ll lP i S i P ll l 3/33/3

8/20/2019 Pumps & Turbines 01 150730

59/156

59


When two pumps are placed in parallelWhen two pumps are placed in parallel

The combined performance curve is obtained by addingThe combined performance curve is obtained by addingflowrateflowrate at the same head.at the same head.

TheThe flowrateflowrate is increased significantly, but not beis increased significantly, but not be

doubled.doubled.The operating point is moved from (A) to (B).The operating point is moved from (A) to (B).

Example 12.4 Use of Pump PerformanceExample 12.4 Use of Pump Performance

8/20/2019 Pumps & Turbines 01 150730

60/156

60

Example 12.4 Use of Pump Performancep p

CurvesCurves 1/21/2

Water is to be pumped from one large, open tank to a second largWater is to be pumped from one large, open tank to a second large,e,

open tank as shown in Fig. E12.4a. The pipe diameter throughoutopen tank as shown in Fig. E12.4a. The pipe diameter throughout isis

6 in. and the total length of the pipe between the pipe entrance6 in. and the total length of the pipe between the pipe entrance andandexit is 200 ft. Minor loss coefficients for the entrance, exit,exit is 200 ft. Minor loss coefficients for the entrance, exit, and theand the

elbow are shown on the figure, and the friction factor for the pelbow are shown on the figure, and the friction factor for the pipeipe

can be assumed constant and equal to 0.02. A certain centrifugalcan be assumed constant and equal to 0.02. A certain centrifugal pump having the performance characteristics shown in Fig. E12.4b pump having the performance characteristics shown in Fig. E12.4b

is suggested as a good pump for this flow system. With this pumpis suggested as a good pump for this flow system. With this pump,,

what would be thewhat would be the flowrateflowrate between the tanks? Do you think this between the tanks? Do you think this

pump would be a good choice? pump would be a good choice?

Example 12.4 Use of Pump PerformanceExample 12.4 Use of Pump Performance

8/20/2019 Pumps & Turbines 01 150730

61/156

61

p pp p

CurvesCurves 2/22/2

Example 12 4Example 12 4 SolutionSolution1/21/2

8/20/2019 Pumps & Turbines 01 150730

62/156

62


Application of the energy equation between the two free surfacesApplication of the energy equation between the two free surfaces,,

points (1) and (2) as indicated, given points (1) and (2) as indicated, given

∑++++γ=++γ g2V

K g2

V

Df z

g2

V pz

g2

V p 2

L

2

2

222

1

211 l

With pWith p11=p=p22=0, V=0, V11=V=V22=0, z=0, z22--zz11=10ft, f=0.02, D=6/12ft, and=10ft, f=0.02, D=6/12ft, and ll =200ft=200ft

s/ftinisQQ43.410h..A

QV

)s/ft2.32(2

V)0.15.15.0(

)ft12/6(

)ft200(02.010h

32 p

2

2

p

+===

⎥⎦

⎤

⎢⎣

⎡++++=

Example 12 4Example 12 4 SolutionSolution2/22/2

8/20/2019 Pumps & Turbines 01 150730

63/156

63


With Q in gal/minWith Q in gal/min

With intersection occurring at Q=1600 gal/minWith intersection occurring at Q=1600 gal/min

With the corresponding actual head gainedWith the corresponding actual head gainedequal to 66.5ftequal to 66.5ft

25 p Q1020.210h −×+=

2 p Q43.410h +=

System equation for thisSystem equation for this

particular flow system and particular flow system and

reveals how much actual headreveals how much actual headthe fluid will need to gain fromthe fluid will need to gain from

the pump to maintain a certainthe pump to maintain a certain

flowrateflowrate..

With Q in ftWith Q in ft33/s/s

Eq. (3)

Eq. (4)

8/20/2019 Pumps & Turbines 01 150730

64/156

64

Dimensionless Parameters andDimensionless Parameters and

Similarity LawsSimilarity Laws

Dimensionless ParametersDimensionless Parameters 1/41/4

8/20/2019 Pumps & Turbines 01 150730

65/156

65


The principal, dependent pump variablesThe principal, dependent pump variables

Actual head riseActual head rise hhaa

Shaft power EfficiencyShaft power Efficiencyηη

The important variablesThe important variables

Characteristic diameterCharacteristic diameter DD Pertinent lengthsPertinent lengths lliiSurface roughnessSurface roughnessεε FlowrateFlowrate QQ

Pump shaft rotational speedPump shaft rotational speed ωω

Fluid viscosityFluid viscosityμμFluid densityFluid densityρρ

shaftW&


8/20/2019 Pumps & Turbines 01 150730

66/156

66


),,,Q,,,D(f

,W,h:iablesvar dependent

i

shafta

ρμωε=

η

l

&

⎟⎟ ⎠

⎞

⎜⎜⎝

⎛

μρω

ω

εφ=

2

3i D

,D

Q

,D,Dterm pidependent

l


8/20/2019 Pumps & Turbines 01 150730

67/156

67

Dimensionless ParametersDimensionless Parameters

⎟⎟ ⎠

⎞⎜⎜⎝

⎛

μρω

ω

εφ=

ω=

2

3i

122a

HD

,D

Q,

D,

DD

ghC

l

The dependent pi term may beThe dependent pi term may be

Head rise coefficientHead rise coefficient

⎟⎟ ⎠

⎞⎜⎜⎝

⎛ μ

ρωω

εφ=ρω

=2

3i

253shaft

pD

,D

Q,

D,

DD

WC

l&Power coefficientPower coefficient

⎟⎟ ⎠ ⎞

⎜⎜⎝ ⎛

μρω

ωεφ=ρ=η 2

3i

3shaft

a D,D

Q,D

,DW

gQh l&

EfficiencyEfficiency


8/20/2019 Pumps & Turbines 01 150730

68/156

68

Dimensionless ParametersDimensionless Parameters

For simplicity,For simplicity,εε/D can be neglected in pumps since the/D can be neglected in pumps since thehighly irregular shape of the pump chamber is usually thehighly irregular shape of the pump chamber is usually the

dominant geometry factor rather than the surfacedominant geometry factor rather than the surface

roughness.roughness.

With these simplicity and for geometrically similar pumps,With these simplicity and for geometrically similar pumps,the dependent pi terms are function of only Q/the dependent pi terms are function of only Q/ωωDD33..

⎟

⎠

⎞⎜

⎝

⎛

ω

φ=

ω3122

a

D

Q

D

gh⎟

⎠

⎞⎜

⎝

⎛

ω

φ=

ρω3253

shaft

D

Q

D

W&

⎟

⎠

⎞⎜

⎝

⎛

ωφ=η

33 D

Q

(29)(29)

(30)(30)

(31)(31) Flow coefficient CFlow coefficient CQQ

Similarity LawsSimilarity Laws 1/31/3

8/20/2019 Pumps & Turbines 01 150730

69/156

69


23

13 D

Q

D

Q⎟ ⎠

⎞⎜⎝

⎛

ω=⎟

⎠

⎞⎜⎝

⎛

ω

Above three equations provide the desired similarityAbove three equations provide the desired similarity

relationship among a family of geometrically similar pumpsrelationship among a family of geometrically similar pumps

If If

ThenThen2

22a

122

a

D

gh

D

gh⎟ ⎠

⎞⎜⎝

⎛

ω=⎟

⎠

⎞⎜⎝

⎛

ω2

53shaft

153

shaft

D

W

D

W

⎟⎟ ⎠

⎞⎜⎜⎝

⎛

ρω=⎟

⎟ ⎠

⎞⎜⎜⎝

⎛

ρω

&&

21 η=η

Where the subscripts 1 and 2 refer to any two pumps fromWhere the subscripts 1 and 2 refer to any two pumps from

the family of geometrically similar pumps.the family of geometrically similar pumps.

(32)(32)

(33)(33) (34)(34)

(35)(35)


8/20/2019 Pumps & Turbines 01 150730

70/156

70


With these soWith these so--called pump scaling laws, it is possible tocalled pump scaling laws, it is possible to

experimentally determine the performance characteristicsexperimentally determine the performance characteristics

of one pump in laboratory and then use these data toof one pump in laboratory and then use these data to

predict the corresponding characteristics for other pumps predict the corresponding characteristics for other pumps

within the family under different operating conditions.within the family under different operating conditions.

From these curves of the performance of differentFrom these curves of the performance of different--

sized, geometrically similar pumps can be predicted.sized, geometrically similar pumps can be predicted.


8/20/2019 Pumps & Turbines 01 150730

71/156

71


Typical performance data for a centrifugal pump:Typical performance data for a centrifugal pump:

((aa) characteristic curves for a 12) characteristic curves for a 12--in. centrifugal pumpin. centrifugal pump

operating at 1000 rpm, (operating at 1000 rpm, (bb) dimensionless characteristic curves.) dimensionless characteristic curves.

Example 12.5 Use of Pump Scaling LawsExample 12.5 Use of Pump Scaling Laws

8/20/2019 Pumps & Turbines 01 150730

72/156

72

Example 12.5 Use of Pump Scaling LawsExample 12.5 Use of Pump Scaling Laws

An 8An 8--in.in.--diameter centrifugal pump operating at 1200 rpm isdiameter centrifugal pump operating at 1200 rpm is

geometrically similar to the 12geometrically similar to the 12--in.in.--diameter pump having thediameter pump having the

performance characteristics of Fig. 12.17a and 12.17b while performance characteristics of Fig. 12.17a and 12.17b whileoperating at 1000 rpm. For peak efficiency, predict the dischargoperating at 1000 rpm. For peak efficiency, predict the discharge,e,

actual head rise, and shaft horsepower for this smaller pump. Thactual head rise, and shaft horsepower for this smaller pump. Thee

working fluid is water at 60working fluid is water at 60 ººF.F.


8/20/2019 Pumps & Turbines 01 150730

73/156

73

Example 12.5Example 12.5 SolutionSolution

For a given efficiency the flow coefficient has

the same value for a given family of pumps.

At peak efficiency CQ=0.0625

(31)(31)

Fig. 12.17(b)Fig. 12.17(b)

gpm1046min)/s60)(ft/gal48.7)(s/ft33.2(

s/ft33.2DCQ

33

33Q

==

=ω=

The actual head rise and the shaft horsepower can be determined in a

similar manner since at peak efficiency CH=0.019 and C p=0.014


8/20/2019 Pumps & Turbines 01 150730

74/156

74

Example 12.5a p e 5 SolutionSo u o

hp0.13s/lbft7150...DCW

ft6.41...

g

DCh

53 pshaft

22H

a

=⋅==ρω=

==ω

=

&

Special Pump Scaling LawsSpecial Pump Scaling Laws 1/61/6

8/20/2019 Pumps & Turbines 01 150730

75/156

75

p p gp p g

How a change in the operating speed,How a change in the operating speed,ωω, for a given, for a given pump, affects pump characteristics. pump, affects pump characteristics.

2

1

2

1

Q

Q

ωω

=(32)(32) (36)(36)

For the same flow coefficientFor the same flow coefficientwith Dwith D11=D=D22

Where the subscripts 1 and 2 refer toWhere the subscripts 1 and 2 refer to

the same pump operating at twothe same pump operating at two

different speeds at the same flowdifferent speeds at the same flow

coefficientcoefficient

22

2

12a1a

h

h

ω

ω=(33)(33) (37)(37) 3

2

31

2shaft

1shaft

W

W

ω

ω

=&

&

(34)(34) (38)(38)


8/20/2019 Pumps & Turbines 01 150730

76/156

76

p p gp p g

These scaling laws are useful in estimating the effect ofThese scaling laws are useful in estimating the effect of

changing pump speed when some data are available fromchanging pump speed when some data are available from

a pump test obtained by operating the pump at a particulara pump test obtained by operating the pump at a particular

speed.speed.


8/20/2019 Pumps & Turbines 01 150730

77/156

77

p p gp p g

How a change in the impeller diameter, D, of aHow a change in the impeller diameter, D, of a

geometrically similar family of pumps, operating at ageometrically similar family of pumps, operating at a

given speed, affects pump characteristics.given speed, affects pump characteristics.

3

2

31

2

1

D

D

Q

Q=(32)(32) (39)(39)

ωω11==ωω22

22

2

12a1a

D

D

h

h

=(33)(33) (40)(40) 52

51

2shaft

1shaft

D

D

W

W

=&

&

(34)(34) (41)(41)


8/20/2019 Pumps & Turbines 01 150730

78/156

78

p p gp p g

With these scaling laws are based on the condition that, asWith these scaling laws are based on the condition that, as

the impeller diameter is changed, all other importantthe impeller diameter is changed, all other important

geometric variables are properly scaled to maintaingeometric variables are properly scaled to maintain

geometric similarity.geometric similarity.

Geometric scaling is not always possibleGeometric scaling is not always possible

(39)~(41) will not, in general, be valid.(39)~(41) will not, in general, be valid.


8/20/2019 Pumps & Turbines 01 150730

79/156

79

p p g

However, experience has shown that if the impellerHowever, experience has shown that if the impeller

diameter change is not too large, less than about 20%,diameter change is not too large, less than about 20%,

these scaling relationships can still be used to estimate thethese scaling relationships can still be used to estimate the

effect of a change in the impeller diameter.effect of a change in the impeller diameter.

(36)~(41) are sometimes referred to as the(36)~(41) are sometimes referred to as the pump affinitypump affinity

lawlaw..


8/20/2019 Pumps & Turbines 01 150730

80/156

80

It has been found that as the pump size decreases theseIt has been found that as the pump size decreases these

effects more significantly influence efficiency because ofeffects more significantly influence efficiency because of

smaller clearance and blade size.smaller clearance and blade size.

An approximate, empirical relationship to estimate theAn approximate, empirical relationship to estimate the

influence of diminishing size on efficiency isinfluence of diminishing size on efficiency is

5/1

2

1

2

1

D

D

1

1⎟⎟

⎠

⎞⎜⎜

⎝

⎛ =

η−η−

(42)(42)

Specific SpeedSpecific Speed 1/51/5

8/20/2019 Pumps & Turbines 01 150730

81/156

81

Specific speed is a useful pi term obtained by eliminatingSpecific speed is a useful pi term obtained by eliminating

diameter D between the low coefficient and the head risediameter D between the low coefficient and the head rise

coefficientcoefficient

Specific speed varies with flow coefficient just as theSpecific speed varies with flow coefficient just as the

other coefficients and efficiency.other coefficients and efficiency.

4/3a4/322a

2/13

s )gh(

Q

)D/gh(

)D/Q( N

ω=

ω

ω= (43)(43)


8/20/2019 Pumps & Turbines 01 150730

82/156

82

For nay pump it is customary to specify a value of specificFor nay pump it is customary to specify a value of specific

speed at the flow coefficient corresponding to peakspeed at the flow coefficient corresponding to peak

efficiency only.efficiency only.

In the United States a modified, dimensional form ofIn the United States a modified, dimensional form of

specific speed,specific speed, N Nsdsd

4/3

a

sd)]ft(h[

)gpm(Q)rpm( N

ω= (44)(44)


8/20/2019 Pumps & Turbines 01 150730

83/156

83

N Nsdsd is expressed in U.S. customary units.is expressed in U.S. customary units.

Typical value ofTypical value of N Nsdsd are in the range 500 to 4000 forare in the range 500 to 4000 forcentrifugal pumps.centrifugal pumps.

Both NBoth Nss andand N Nsdsd have the same physical meaning, but theirhave the same physical meaning, but their

magnitudes will differ by a constant conversion factormagnitudes will differ by a constant conversion factor N Nsdsd=2733N=2733Nss whenwhenωωis expressed inis expressed in rad/srad/s..


8/20/2019 Pumps & Turbines 01 150730

84/156

84

Variation in specific speed with type of pump.Variation in specific speed with type of pump.


8/20/2019 Pumps & Turbines 01 150730

85/156

85

Each family or class of pumps has a particular range ofEach family or class of pumps has a particular range of

values of specific speed associated with it.values of specific speed associated with it.

Pumps that have lowPumps that have low--capacity, highcapacity, high--head characteristicshead characteristics

will have specific speed that are smaller than that havewill have specific speed that are smaller than that have

highhigh--capacity, lowcapacity, low--head characteristics.head characteristics.

AsAs N Nsdsd increases beyond about 2000 the peak efficiency ofincreases beyond about 2000 the peak efficiency of

the purely radialthe purely radial--flow centrifugal pump starts to fall off,flow centrifugal pump starts to fall off,

and other type of more efficient pump design are preferred.and other type of more efficient pump design are preferred.

Suction Specific SpeedSuction Specific Speed 1/21/2

8/20/2019 Pumps & Turbines 01 150730

86/156

86

Suction specific speed is definedSuction specific speed is defined

In the United States a modified, dimensional form ofIn the United States a modified, dimensional form ofsuction specific speed,suction specific speed, SSsdsd

4/3R

s)] NPSH(g[

QS ω= (45)(45)

4/3R

sd)]ft( NPSH[

)gpm(Q)rpm(

S

ω

= (44)(44)

Suction Specific SpeedSuction Specific Speed 2/22/2

8/20/2019 Pumps & Turbines 01 150730

87/156

87

Typical values forTypical values for SSsdsd fall in the range 7000 to 12000.fall in the range 7000 to 12000.

Note that Note that

SS

sdsd=2733S=2733S

ss ,with,withωω

expressed inexpressed in

rad/srad/s

.

.

8/20/2019 Pumps & Turbines 01 150730

88/156

88

AxialAxial--Flow andFlow and

MixedMixed--Flow PumpsFlow Pumps

Axial Axial--Flow and MixedFlow and Mixed--Flow PumpsFlow Pumps 1/21/2

8/20/2019 Pumps & Turbines 01 150730

89/156

89

Centrifugal pumps are radialCentrifugal pumps are radial--flow machines that operateflow machines that operatemost efficiently for applications requiring high heads atmost efficiently for applications requiring high heads at

relatively lowrelatively low flowrateflowrate..For many applications, such as those associate withFor many applications, such as those associate with

drainage and irrigation, highdrainage and irrigation, high flowrateflowrate at low head areat low head are

required.required.Centrifugal pumps are not suitable.Centrifugal pumps are not suitable.

AxialAxial--flow pumps are commonly used.flow pumps are commonly used.

AxialAxial--flow pump, consists of a propeller confined within aflow pump, consists of a propeller confined within acylindrical casing, is often called propeller pump.cylindrical casing, is often called propeller pump.

Axial Axial--Flow and MixedFlow and Mixed--Flow PumpsFlow Pumps 2/22/2

8/20/2019 Pumps & Turbines 01 150730

90/156

90

Schematic diagram of an axial-flow pump arranged for

vertical operation.

A rotor is connectedA rotor is connectedto a motor through ato a motor through a

shaft.shaft.

As the rotor rotatesAs the rotor rotates

the fluid is sucked inthe fluid is sucked in

through the inlet.through the inlet.

Centrifugal Pump vs. AxialCentrifugal Pump vs. Axial--Flow PumpFlow Pump 1/21/2

8/20/2019 Pumps & Turbines 01 150730

91/156

91

At design capacityAt design capacity

(maximum efficiency)(maximum efficiency)

the head and brakethe head and brake

horsepower are thehorsepower are the

same for the two pumps.same for the two pumps.

As theAs the flowrateflowrate

decreases, the powerdecreases, the power

input to the centrifugalinput to the centrifugal

pump falls to 180 hp at pump falls to 180 hp at

shutoff.shutoff.

Centrifugal Pump vs. AxialCentrifugal Pump vs. Axial--Flow PumpFlow Pump 2/22/2

8/20/2019 Pumps & Turbines 01 150730

92/156

92

Whereas for the axialWhereas for the axial--flow pump the power inputflow pump the power input

increases to 520 hp at shutoff.increases to 520 hp at shutoff.

The axialThe axial--flow pump can cause overloading of the driveflow pump can cause overloading of the drive

motor if themotor if the flowrateflowrate is reduced significantly from theis reduced significantly from the

design capacity.design capacity.

The head curve for the axialThe head curve for the axial--flow pump is much steeperflow pump is much steeper

than that fir the centrifugal pump.than that fir the centrifugal pump.

Except at design capacity, the efficiency of the axialExcept at design capacity, the efficiency of the axial--flowflow pump is lower than that o the centrifugal pump. pump is lower than that o the centrifugal pump.

Comparison of Different Types ofComparison of Different Types of

ImpellersImpellers

8/20/2019 Pumps & Turbines 01 150730

93/156

93

ImpellersImpellers

8/20/2019 Pumps & Turbines 01 150730

94/156

94

FansFans

FansFans 1/31/3

8/20/2019 Pumps & Turbines 01 150730

95/156

95

Fans: used to move the fluid.Fans: used to move the fluid.

Types of fans varying from small fan used for coolingTypes of fans varying from small fan used for cooling

desktop computers to large fans used in many industrialdesktop computers to large fans used in many industrial

applications.applications.

Fan are also called blowers, boosters, and exhaustersFan are also called blowers, boosters, and exhaustersdepending on the location within the system.depending on the location within the system.

As in the case for pumps, fans designs include centrifugalAs in the case for pumps, fans designs include centrifugal

(radial(radial--flow) fans, mixedflow) fans, mixed--flow and axialflow and axial--flow (propeller)flow (propeller)fans.fans.

FansFans 2/32/3

8/20/2019 Pumps & Turbines 01 150730

96/156

96

Analysis of fans performance closely follows thatAnalysis of fans performance closely follows that

previously described for pumps. previously described for pumps.

Scaling relationships for fans are the same as thoseScaling relationships for fans are the same as those

developed for pumps, that is, equations (32)~(35) apply todeveloped for pumps, that is, equations (32)~(35) apply to

fans and pumps.fans and pumps.

For FansFor Fans

Replace the head, hReplace the head, haa, with pressure head p, with pressure head paa//ρρgg

2

22a

1

22a

D

p

D

p

⎟⎟

⎠

⎞⎜⎜

⎝

⎛

ρω

=⎟⎟

⎠

⎞⎜⎜

⎝

⎛

ρω

(33)(33) (47)(47)

FansFans 3/33/3

8/20/2019 Pumps & Turbines 01 150730

97/156

97

Equations (47), (32) and (34) are called the fan laws andEquations (47), (32) and (34) are called the fan laws and

can be used to scale performance characteristics betweencan be used to scale performance characteristics between

members of a family of geometrically similar fans.members of a family of geometrically similar fans.

8/20/2019 Pumps & Turbines 01 150730

98/156

98

TurbinesTurbines

TurbinesTurbines 1/61/6

8/20/2019 Pumps & Turbines 01 150730

99/156

99

Turbines are devices that extract energy from a flowingTurbines are devices that extract energy from a flowing

fluid.fluid.

The geometry of turbines is such that the fluid exerts aThe geometry of turbines is such that the fluid exerts a

torque on the rotor in the direction of its rotation.torque on the rotor in the direction of its rotation.

The shaft power generated is available to derive generatorsThe shaft power generated is available to derive generators

or other devices.or other devices.

The two basic types of hydraulic turbines areThe two basic types of hydraulic turbines are impulseimpulse

and reaction turbines.and reaction turbines.


8/20/2019 Pumps & Turbines 01 150730

100/156

100

For hydraulic impulseFor hydraulic impulse

turbines, the pressure dropturbines, the pressure drop

across the rotor is zero; all ofacross the rotor is zero; all ofthe pressure drop across thethe pressure drop across the

turbine stages occurs in theturbine stages occurs in the

nozzle row.nozzle row.

TheThe PeltonPelton whellwhell is ais a

classical example of anclassical example of an

impulse turbines.impulse turbines.


8/20/2019 Pumps & Turbines 01 150730

101/156

101

Diagram shows a reactionDiagram shows a reaction

turbine.turbine.


8/20/2019 Pumps & Turbines 01 150730

102/156

102

For impulse turbinesFor impulse turbines

The total head of the incoming fluid is converted into aThe total head of the incoming fluid is converted into a

large velocity head at the exit of the supply nozzle.large velocity head at the exit of the supply nozzle.

Both the pressure drop across the bucket (blade) andBoth the pressure drop across the bucket (blade) and

the change in relative speed of the fluid across thethe change in relative speed of the fluid across the

bucket are negligible. bucket are negligible.

The space surrounding the rotor is not completely filledThe space surrounding the rotor is not completely filled

with fluid.with fluid.The individual jets of fluid striking the buckets thatThe individual jets of fluid striking the buckets that

generates the torque.generates the torque.


8/20/2019 Pumps & Turbines 01 150730

103/156

103

For reaction turbinesFor reaction turbines

There is both a pressure drop and a fluid relative speedThere is both a pressure drop and a fluid relative speed

change across the rotor.change across the rotor.

Guide vanes act as nozzle to accelerate the flow andGuide vanes act as nozzle to accelerate the flow and

turn it in the appropriate direction as the fluid enters theturn it in the appropriate direction as the fluid enters the

rotor.rotor.

Part of the pressure drop occurs across the guide vanesPart of the pressure drop occurs across the guide vanes

and part occurs across the rotor,and part occurs across the rotor,


8/20/2019 Pumps & Turbines 01 150730

104/156

104

SummarySummary

Impulse turbines: HighImpulse turbines: High--head, lowhead, low flowrateflowratedevices.devices.

Reaction turbines: LowReaction turbines: Low--head, highhead, high--flowrateflowrate

devices.devices.

Impulse TurbinesImpulse Turbines 1/61/6

8/20/2019 Pumps & Turbines 01 150730

105/156

105

The easiest type of impulse turbinesThe easiest type of impulse turbines

design is thedesign is the PeltonPelton wheel.wheel.

LesterLester PeltonPelton (1829~1908), an(1829~1908), an

American mining engineer duringAmerican mining engineer during

the California goldthe California gold--mining days, ismining days, is

responsible for many of stillresponsible for many of still--usedused

features of this type of turbine.features of this type of turbine.


8/20/2019 Pumps & Turbines 01 150730

106/156

106

A highA high--speed jet of water strikes thespeed jet of water strikes the PeltonPelton wheel bucketswheel buckets

and is deflected.and is deflected.

The water enters and leaves the control volumeThe water enters and leaves the control volume

surrounding the wheel as free jet.surrounding the wheel as free jet.

A person riding on the bucket would note that the speed ofA person riding on the bucket would note that the speed of

the water doest not change as it slides across the buckets.the water doest not change as it slides across the buckets.

That is, the magnitude of the relative velocity does notThat is, the magnitude of the relative velocity does not

change, but its direction does.change, but its direction does.


8/20/2019 Pumps & Turbines 01 150730

107/156

107

Ideally, the fluid enters and leaves the control volume withIdeally, the fluid enters and leaves the control volume with

no radial component of velocity.no radial component of velocity.

The buckets would ideallyThe buckets would ideally

turn the relative velocityturn the relative velocity

through a 180through a 180ºº turn, butturn, but

physical constraints dictate physical constraints dictate

thatthatββ, the angle of the, the angle of theexit edge of the blade, isexit edge of the blade, is

less than 180less than 180 ºº


8/20/2019 Pumps & Turbines 01 150730

108/156

108

Flow as viewed by an observerFlow as viewed by an observer

riding on theriding on the PeltonPelton wheelwheel – –

relative velocitiesrelative velocities

Inlet and exit velocity triangles for aInlet and exit velocity triangles for a

PeltonPelton wheel turbine.wheel turbine.

UWVV 111 +==θ (48)(48) UcosWV 22 +β=θ (49)(49)

With WWith W11=W=W22 (48)+(49)(48)+(49))cos1)(VU(VV 112 β−−=− θθ (50)(50)


8/20/2019 Pumps & Turbines 01 150730

109/156

109

)cos1)(VU(Um

TW

1

shaftshaft

β−−=ω=

&

&

(50)+(2)+(4)(50)+(2)+(4) )cos1)(VU(r mT 1mshaft β−−= &

(51)(51)

Typical theoretical and experimental powerTypical theoretical and experimental powerand torque for aand torque for a PeltonPelton wheel turbine as awheel turbine as a

function of bucket speed.function of bucket speed.


8/20/2019 Pumps & Turbines 01 150730

110/156

110

From above results:From above results:

The power is a function ofThe power is a function of ββ. A typical value of. A typical value of

ββ=165=165ºº results in a relatively small reduction in powerresults in a relatively small reduction in powersince 1since 1--cos165cos165ºº=1.966.=1.966.

Although torque is maximum when the wheel isAlthough torque is maximum when the wheel is

stopped (U=0), there is no power under this conditionstopped (U=0), there is no power under this condition – –

to extract power one needs force and motion.to extract power one needs force and motion.

The power output is a maximum when U=V/2.The power output is a maximum when U=V/2.

The maximum speed occurs whenThe maximum speed occurs when TTshaftshaft=0.=0.

(52)(52)

Example 12.6Example 12.6 PeltonPelton Wheel TurbineWheel Turbine

CharacteristicsCharacteristics

d i l h l i li d h h i f l k

8/20/2019 Pumps & Turbines 01 150730

111/156

111

Water to drive aWater to drive a PeltonPelton wheel is supplied through a pipe from a lakewheel is supplied through a pipe from a lake

as indicated in Fig. E12.6a. Determine the nozzle diameter, Das indicated in Fig. E12.6a. Determine the nozzle diameter, D11, that, that

will give the maximum power output. Include the head loss due towill give the maximum power output. Include the head loss due tofriction in the pipe, but neglect minor losses. Also determine tfriction in the pipe, but neglect minor losses. Also determine thishis

maximum power and the angular velocity of the rotor at thismaximum power and the angular velocity of the rotor at this

condition.condition.


( )(51) )cos1)(VU(QUW βρ&

8/20/2019 Pumps & Turbines 01 150730

112/156

112

The nozzle exit speed, VThe nozzle exit speed, V11, can be obtained by applying the, can be obtained by applying theenergy equation between a point on the lake surface (whereenergy equation between a point on the lake surface (where

VV00=p=p00=0) and the nozzle outlet (where z=0) and the nozzle outlet (where z11=p=p11=0) to give=0) to give

(51)(51)

g2V

Df hh

g2Vz

2

LL

2

10l

=+=

)cos1)(VU(QUW 1shaft β−−ρ=

41

21

41

0 D1521

5.113

g2

V

D

D

Df 1z

+=

⎥⎥⎦

⎤

⎢⎢⎣

⎡

⎟ ⎠

⎞

⎜⎝

⎛ += l

4/VDQ 121π=

8/20/2019 Pumps & Turbines 01 150730

113/156


Th d h i di i bTh t d t th i diti b

8/20/2019 Pumps & Turbines 01 150730

114/156

114

The rotor speed at the maximum power condition can beThe rotor speed at the maximum power condition can be

obtained fromobtained from

rpm295R 2

V

2

VR U 11 ==ω=ω=

Example 12.7 Maximum Power Output for aExample 12.7 Maximum Power Output for a

PeltonPelton Wheel TurbineWheel Turbine

Water flo s thro gh theWater flows through the PeltonPelton heel t rbine sho n in Fig 12 24wheel turbine shown in Fig 12 24

8/20/2019 Pumps & Turbines 01 150730

115/156

115

Water flows through theWater flows through the PeltonPelton wheel turbine shown in Fig. 12.24.wheel turbine shown in Fig. 12.24.

For simplicity we assume that the water is turned 180For simplicity we assume that the water is turned 180ºº by the blade. by the blade.

Show, based on the energy equation, that the maximum powerShow, based on the energy equation, that the maximum poweroutput occurs when the absolute velocity of the fluid exiting thoutput occurs when the absolute velocity of the fluid exiting thee

turbine is zero.turbine is zero.


(51)(51) )UVU(Q2)cos1)(VU(QUW 12

1h f −ρ=β−−ρ=&

8/20/2019 Pumps & Turbines 01 150730

116/156

116

For this impulse turbine withFor this impulse turbine with

ββ== 180180ºº , the velocity, the velocitytriangles simplify into thetriangles simplify into the

diagram types shown in Fig.diagram types shown in Fig.

E12.7. Three possibilities areE12.7. Three possibilities areindicated:indicated:

(a) The exit absolute velocity,(a) The exit absolute velocity,

VV22, is directed back toward, is directed back toward

the nozzle.the nozzle.

(51)(51) )UVU(Q2)cos1)(VU(QUW 11shaft −ρ=β−−ρ=


(b) Th b l l i h i i(b) Th b l l i h i i

8/20/2019 Pumps & Turbines 01 150730

117/156

117

(b) The absolute velocity at the exit is zero, or (b) The absolute velocity at the exit is zero, or

(c) The exiting stream flows in the direction of the incoming st(c) The exiting stream flows in the direction of the incoming stream.ream.

The maximum power occurs when U=VThe maximum power occurs when U=V11/2./2.

If viscous effects are negligible, when WIf viscous effects are negligible, when W11=W=W22 and we have U=Wand we have U=W22,,

which giveswhich gives VV22=0=0

Consider the energy equation for flow across the rotor we haveConsider the energy equation for flow across the rotor we have

L

22

21

T

LT2

222

1

211

hg2

VVh

hhz

g2

V pz

g2

V p

−−

=⇒

++++

γ

=++

γVV22=0=0

Second Type of Impulse TurbinesSecond Type of Impulse Turbines 1/31/3

8/20/2019 Pumps & Turbines 01 150730

118/156

118

AA multinozzlemultinozzle, non, non--PeltonPelton wheel impulse turbinewheel impulse turbine

commonly used with air as the working fluid.commonly used with air as the working fluid.


A circumferential series of fluid jetsA circumferential series of fluid jets

8/20/2019 Pumps & Turbines 01 150730

119/156

119

A circumferential series of fluid jetsA circumferential series of fluid jets

strikes the rotating blades which, asstrikes the rotating blades which, as

with thewith the PeltonPelton wheel, alter both thewheel, alter both thedirection and magnitude of thedirection and magnitude of the

absolute velocity.absolute velocity.

The inlet and exit pressure are equal.The inlet and exit pressure are equal.

The magnitude of the relativeThe magnitude of the relative

velocity is unchanged as the fluidvelocity is unchanged as the fluid

slides across the blades.slides across the blades.


In order for the absolute velocity of the fluid to beIn order for the absolute velocity of the fluid to be

8/20/2019 Pumps & Turbines 01 150730

120/156

120

In order for the absolute velocity of the fluid to beIn order for the absolute velocity of the fluid to be

changed as indicated during its passage across the blade,changed as indicated during its passage across the blade,

the blade must push on the fluid in the direction oppositethe blade must push on the fluid in the direction oppositeof the blade motion.of the blade motion.

The fluid pushes on the blade in the direction f theThe fluid pushes on the blade in the direction f the

blades motion blades motion – – the fluid does work on the blade.the fluid does work on the blade.

Example 12.8 NonExample 12.8 Non--PeltonPelton Wheel ImpulseWheel Impulse

TurbineTurbine 1/21/2

An air turbine used to drive the highAn air turbine used to drive the high--speed drill used by your dentistspeed drill used by your dentist

8/20/2019 Pumps & Turbines 01 150730

121/156

121

An air turbine used to drive the highAn air turbine used to drive the high speed drill used by your dentistspeed drill used by your dentist

is shown in Fig. E12.8a. Air exiting from the upstream nozzle hois shown in Fig. E12.8a. Air exiting from the upstream nozzle holesles

force the turbine blades to move in the direction shown. Estimatforce the turbine blades to move in the direction shown. Estimate thee theshaft energy per unit mass of air flowing through the turbine unshaft energy per unit mass of air flowing through the turbine underder

the following conditions. The turbine rotor speed is 300,000 rpmthe following conditions. The turbine rotor speed is 300,000 rpm,,

the tangential component of velocity out of the nozzle is twicethe tangential component of velocity out of the nozzle is twice thethe

blade speed, and the tangential component of the absolute veloci blade speed, and the tangential component of the absolute velocitytyout of the rotor is zero.out of the rotor is zero.

Example 12.8 NonExample 12.8 Non--PeltonPelton Wheel ImpulseWheel Impulse

TurbineTurbine 2/22/2

8/20/2019 Pumps & Turbines 01 150730

122/156

122

Example 12.8Example 12.8 SolutionSolution

For simplicity we analyze this problem using an arithmetic meanFor simplicity we analyze this problem using an arithmetic mean radiusradius

8/20/2019 Pumps & Turbines 01 150730

123/156

123

(5)(5)

lbm/lbft9640...shaft

m

21

2211shaft

w

s/ft394...r U

0VU2V

VUVUw

⋅−==

θθ

θθ

==ω=

==

+−=

For simplicity we analyze this problem using an arithmetic meanFor simplicity we analyze this problem using an arithmetic mean radiusradius

)r r (r io21

m +=

Reaction TurbinesReaction Turbines 1/21/2

Best suited for higherBest suited for higher flowrateflowrate abdabd lower head situationslower head situations

8/20/2019 Pumps & Turbines 01 150730

124/156

124

Best suited for higherBest suited for higher flowrateflowrate abdabd lower head situationslower head situations

such as are often encountered in hydroelectric powersuch as are often encountered in hydroelectric power

plants associated with a dammed river. plants associated with a dammed river.

The working fluid completely fills the passagewaysThe working fluid completely fills the passageways

through which it flows.through which it flows.

The angular momentum, pressure, and the velocity of theThe angular momentum, pressure, and the velocity of the

fluid decrease as it flows through the turbine rotorfluid decrease as it flows through the turbine rotor – – thethe

turbine rotor extracts energy from the fluid.turbine rotor extracts energy from the fluid.

Reaction TurbinesReaction Turbines 2/22/2

The variety of configurations: radialThe variety of configurations: radial--flow, mixed flow,flow, mixed flow,

8/20/2019 Pumps & Turbines 01 150730

125/156

125

The variety of configurations: radialy g flow, mixed flow,, ,

and axialand axial--flow.flow.

((aa) Typical radial) Typical radial--flowflow

Francis turbine. (Francis turbine. (bb) typical) typical

axialaxial--flow Kaplan turbine.flow Kaplan turbine.

Dimensionless Parameters for TurbinesDimensionless Parameters for Turbines 1/21/2

As with pumps, incompressible flow turbine performanceAs with pumps, incompressible flow turbine performance

8/20/2019 Pumps & Turbines 01 150730

126/156

126

p p , p pp p p pis often specified in terms of appropriate dimensionlessis often specified in terms of appropriate dimensionless

parameters parameters

22 TH D

ghC ω=Head rise coefficientHead rise coefficient

53shaft

p

D

WC

ρω

=&

Power coefficientPower coefficient

The flow coefficientThe flow coefficient 3Q D

QC

ω=

Dimensionless Parameters for TurbinesDimensionless Parameters for Turbines 2/22/2

On the other head, turbine efficiency is the inverse ofOn the other head, turbine efficiency is the inverse of

8/20/2019 Pumps & Turbines 01 150730

127/156

127

, y, y

pump efficiency pump efficiency

T

shaft

gQh

W

ρ=η

&

Similarity Laws for TurbinesSimilarity Laws for Turbines

For geometrically similar turbines and for negligibleFor geometrically similar turbines and for negligible

8/20/2019 Pumps & Turbines 01 150730

128/156

128

g y g gg y g g

Reynolds number and surface roughness difference effects,Reynolds number and surface roughness difference effects,

the relationship between the dimensionless parameters arethe relationship between the dimensionless parameters aregivengiven

)C()C(C)C(C Q3Q2 pQ1H φ=ηφ=φ=

Power Specific SpeedPower Specific Speed 1/21/2

The design engineer has a variety of turbine ty

Documents

Pumps & Turbines 01 150730