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Q21. Gauss’ Law

Q21. Gauss’ Law. 1.A particle with charge 5.0- C is placed at the corner of a cube. The total electric flux in N m 2 /C through all sides of the cube

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Page 1: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

Q21. Gauss’ Law

Page 2: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

1. A particle with charge 5.0- C is placed at the corner of a

cube. The total electric flux in N m2/C through all sides

of the cube is :

1. 0

2. 7.1 104

3. 9.4 104

4. 1.4 105

5. 5.6 105

Page 3: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

9 6

0

14 9 10 5.0 10

8insideQ

4 27.07 10 /Nm C

The corner of a cube is shared by 8 adjacent cubes.

Only 1/8 of a charge at the corner is inside the cube.

Page 4: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

2. A round wastepaper basket with a 0.15-m radius opening is in a

uniform electric field of 300 N/C, perpendicular to the opening.

The total flux through the sides and bottom, in Nm2/C, is :

1. 0

2. 4.2

3. 21

4. 280 5. can't tell without knowing the

areas of the sides and bottom

Page 5: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

221.2 /Nm C

2300 / 0.15N C

No flux through the sides.

Page 6: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

3. A 3.5-cm radius hemisphere contains a total charge of

6.6 × 10–7 C. The flux through the rounded portion

of the surface is 9.8 × 104 N m2/C. The flux

through the flat base is :

1. 0

2. +2.3 × 104 N

m2/C

3. –2.3 × 104 N

m2/C

4. –4.9 × 104 N

m2/C

5. +4.9 × 104 N

m2/C

Page 7: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

9 7 44 9 10 6.6 10 9.8 10

4 22.33 10 /Nm C

Page 8: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

4. Two large insulating parallel plates carry charge of equal

magnitude, one positive and the other negative, that is

distributed uniformly over their inner surfaces. Rank the

points 1 through 5 according to the magnitude of the electric

field at the points, least to greatest.

1. 1, 2, 3, 4, 5

2. 5, 4, 3, 2, 1

3. 1, 4, and 5 tie, then 2 and 3 tie

4. 2 and 3 tie, then 1 and 4 tie, then

5

5. 2 and 3 tie, then 1, 4, and 5 tie

Page 9: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

1 4 5 0E E E

2 3E E

Page 10: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

5. Two large parallel plates carry positive charge of equal

magnitude that is distributed uniformly over their inner

surfaces. Rank the points 1 through 5 according to the

magnitude of the electric field at the points, least to greatest.

1. 1, 2, 3, 4, 5

2. 5, 4, 3, 2, 1

3. 1, 4, and 5 tie, then 2 and 3 tie

4. 2 and 3 tie, then 1 and 4 tie, then

5

5. 2 and 3 tie, then 1, 4, and 5 tie

Page 11: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

1 4 5E E E

2 3 0E E

Page 12: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

6. A solid insulating sphere of radius R contains a positive

charge that is distributed with a volume charge density that

does not depend on angle but does increase with distance

from the sphere center. Which of the graphs below

correctly gives the magnitude E of the electric field as a

function of the distance r from the center of the sphere :

1. A

2. B

3. C

4. D

5. E

Page 13: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

2 3

0

1 44

3inE r c r r

2

03in

cE r

2out

QE

r

Page 14: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

7. Which of the following graphs represents the magnitude of

the electric field as a function of the distance from the center

of a solid charged conducting sphere of radius R :

1. A

2. B

3. C

4. D

5. E

Page 15: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

2out

QE k

r

0inE

Page 16: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

8. Charge Q is distributed uniformly throughout an insulating

sphere of radius R. The magnitude of the electric field at a

point R/2 from the center is :

1. Q / 40

R2

2. Q / 0 R2

3. 3Q / 40

R2

4. Q / 80

R2

5. none of

these

Page 17: Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube

2 3

30

1 44

42 3 23

R Q RE

R

208

QE

R