One-Step Towards Success

2014

PROFIT AND LOSS Quantitative Aptitude For: *Bank PO,SBI PO,IBPS PO Exams…

*Postal & Sorting Assistant Exams…

*SSC Combined Graduate Level Exams…

*LIC AAO and All other competitive examinations… Gateway to Knowledge

PROFIT & LOSS Definitions: Cost Price: The price at which an article is purchased is called the cost price or C.P. Selling Price: The price at which an article is sold is called the selling price or S.P. Marked (List) Price: The Price that is indicated or marked on the article is called marked price or M.P. Profit (Gain): If S.P. is greater than C.P., the seller is said to have a profit (gain). Loss: If S.P. is less than C.P., the seller is said to have a loss. Discount: It is reduction given on the Marked Price or List Price of an article.

Formulae: 1. Gain= (SP)-(CP)

2. Loss= (CP)-(SP)

3. Gain %= (Gain x 100

CP)

4. Loss %= (Loss x 100

CP)

5. SP= 100+Gain %

100 x CP

6. SP= (100−Loss %)

100 x CP

7. CP= 100

(100+Gain %) x SP

8. CP= 100

(100−Loss %) x SP

9. Discount= MP-SP

10. Discount%= (D

M.P. x 100)

11. SP= (100−D%

100x MP)

12. If a trader professes to

sell his goods at Cost Price,

but uses false weight, then

Gain (Profit) Percent,

= [Error

True Value −(Error) x 100]%

13. If a trade gets x% profit and x% loss in selling two similar articles, then in over all transaction, there is always a loss which is

Loss %= (𝑥

10)2

14. If an article is sold at a gain of 49%, then SP= 149% of CP. 15. If an article is sold at a loss of 49%, then SP= 51% of CP.

Mostly Asked Questions

(Fully Solved) Que.:- If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is: Sol.:- Let C.P. of each pen be Rs.1. Then, C.P. of 8 pens= Rs.8 S.P. of 8 pens= Rs.12.

∴ Gain%= (Gain

C.P. x 100)

= (4

8 x 100) %

= 50%. Que.:- A shopkeeper purchased 70 kg of potatoes for Rs. 420 and sold the whole lot at the rate of Rs.6.50 per kg. What will be his gain percent? Sol.:- C.P. of 1kg potatoes,

= Rs. (420

70) = Rs. 6.

S.P. of 1kg potatoes, = Rs. 6.50.

∴ Gain%= (Gain

C.P. x 100)

= (0.50

6 x 100) %

= 25

3 % or 8

1

3 %.

Que.:- 100 oranges are bought at the rate of Rs.350 and sold at the rate of Rs.48 per dozen. The percentage of profit or loss is: Sol.:-

C.P. of 1 orange= Rs. (350

100)

= Rs. 3.50.

S.P. of 1 orange= Rs. (48

12)

= Rs. 4. Here, CP < SP

∴ Gain%= (Gain

C.P. x 100)

= (0.50

3.50 x 100) %

= 100

7 % or 14

2

7 %.

Que.:-A man gains 20% by selling an article for a certain price. If he sells it at double the price, the percentage of profit will be: Sol.:-

Let C.P. = Rs. x. Then, S.P. = Rs. (120% of C.P.) = Rs. (120% of x)

= Rs. 6𝑥

5

New S.P. = Rs. (2 x 6𝑥

5)

= Rs. 12𝑥

5

Profit = (SP-CP)

Profit = Rs. (12𝑥

5− 𝑥)

= Rs. 7𝑥

5

∴ Profit% = (7𝑥

5 x

1

𝑥 x 100) %

= 140%. Que.:- Some articles were bought at 6 for Rs. 5 and sold at 5 for Rs. 6. Gain percent is: Sol.:- Suppose, number of articles Bought = L.C.M. of 6 & 5 = 30. C.P. of 30 articles,

= Rs. (5

6 x 30) = Rs. 25.

S.P. of 30 articles,

= Rs. (6

5 x 30) = Rs. 36.

∴ Gain%= (Gain

C.P. x 100)

= (11

25 x 100) %

= 44%. Que.:- A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is: Sol.:- Suppose he has 100 items. Let C.P. of each item be Rs.1. Total cost= Rs.100. No. of items left after theft = 80. S.P. of each item= Rs. 1.10 ∴ Total sale = Rs. (1.10 x 80) = Rs. 88. Hence,

Loss%= (Loss x 100

CP)

=(12

100 x 100)% or 12%.

Que.:- A trader marked the price of his commodity so as to include a profit of 25%. He allowed discount of 16% on the marked price. His actual profit was: Sol.:- Let C.P. be Rs. 100. Then,

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3

Marked price= Rs. 125. S.P. = 84% of Rs. 125

= Rs. (84

100 x 125)

= Rs. 105. ∴Profit% = (SP-CP) % = (105-100) % = 5%. Que.:- A shopkeeper sells 25 articles at Rs. 45 per article after giving 10% discount and earns 50% profit. If the discount is not given, the profit gained is: Sol.:- S.P. of 1 article= Rs. 45. Let marked price of each article be Rs. x. Then, S.P. = 90% of Rs. x

45 = 90𝑥

100

∴ x = Rs. (45 x 100

90)

= Rs. 50.

C.P. = 100

(100+Gain %) x SP

= Rs. (100

150 x 45)

= Rs. 30. ∴ Required Profit%,

= (Gain

C.P. x 100)

= (20

30 x 100) %

= 200

3 % or 66

2

3 %.

Que.:- A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of: Sol.:- Let C.P. =Rs. 100. Then, Marked Price= Rs. 110. S.P. = Rs. 99. Discount = (M.P.-S.P.)

= Rs. (110-99)

= Rs. 11.

∴ Discount% = (D

M.P. x 100)

= (11

110 x 100) %

= 10 %.

Que.:- A trader marked his

goods at 20% above the

cost price. He sold half the

stock at the marked price,

one quarter at a discount

of 20% on the marked

price and the rest at a

discount of 40% on the

marked price. His total

gain is:

Sol.:-

Let Cost Price of whole stock

= Rs.100. Then, Marked Price

of whole Stock= Rs. 120.

M.P. of 1

2 stock= Rs. 60.

M.P. of 1

4 stock= Rs. 30.

∴Total S.P. is = Rs. [60+(80% of 30)+(60% of 30)]

= Rs. (60+24+18)

= Rs. 102.

Hence, Gain% = (S.P. – C.P.)%

= (102-100)% = 2%.

Que.:- The marked price of

a watch was Rs. 720. A man

bought the same for Rs.

550.80 after getting two

successive discounts, the

first being 10%. What was

the second discount rate?

Sol.:-

Let the 2nd discount rate be

x %. Then,

(100-x) % of 90 % of 720

= 550.80

∴ (100−𝑥)

100 x

90

100 x 720= 550.80

∴ 100 − 𝑥 = ( 55080

9 x 72) = 85

100 − 𝑥 = 85

∴ x = (100-85) = 15.

∴ 2nd discount rate= 15 %.

Que.:- A fan is listed at Rs.

1500 and a discount of

20% is offered on the list

price. What additional

discount must be offered to

the customer to bring the

net price to Rs. 1104?

Sol.:-

S.P. after 1st discount,

= Rs. (80

100 x 1500)

= Rs. 1200.

Net S.P. = Rs. 1104.

Discount on Rs. 1200= Rs. 96.

∴ Required discount,

= (D

M.P. x 100) %

= (96

1200 x 100) % = 8 %.

Que.:- A cloth merchant

sold half of his cloth at

20% profit, half of the

remaining at 20% loss and

the rest was sold at the cost

price. In the total

transaction, his gain or loss

will be:

Sol.:-

Let C.P. of whole be Rs. x.

C.P. of 1

2 stock= Rs.

𝑥

2

C.P. of 1

4 stock= Rs.

𝑥

4

Total S.P., = Rs. [(120% of

𝑥

2 ) + (80% of

𝑥

4) +

𝑥

4]

= Rs. (3𝑥

5+𝑥

5+

𝑥

4) = Rs.

21𝑥

20

Here, CP < SP

∴ Gain= Rs. (21𝑥

20− 𝑥) = Rs.

𝑥

20

∴ Gain%= (𝑥

20 x

1

𝑥 x 100) %

= 5 %.

Que.:- A man buys an

article for 10% less than its

value and sells it for 10%

more than its value. His

gain or loss percent is:

Sol.:-

Let the article be worth Rs. x.

C.P. = 90% of Rs. x

= Rs. 9𝑥

10

S.P. = 110% of Rs. x

= Rs. 11𝑥

10

Here, CP < SP

∴ Gain= Rs. (11𝑥

10−

9𝑥

10)

= Rs. 𝑥

5

∴ Gain%= (Gain x 100

CP)

= (𝑥

5 x

10

9𝑥 x 100) %

= 22 2

9 %.

Que.:- A man bought apples

at the rate of 8 for Rs. 34

and sold them at the rate of

12 for Rs. 57. How many

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Race Express/One-Step Towards Success

4

apples should be sold to

earn a net profit of Rs. 45?

Sol.:-

C.P. of 1 apple= Rs. (34

8)

= Rs. 4.25.

S.P. of 1 apple= Rs. (57

12)

= Rs. 4.75.

Profit on each apple,

= (S.P. – C.P.)

= (4.75 – 4.25)

= Rs. 0.50.

∴ No. of apples required,

= (45

0.50) = 90.

Que.:- A man buys two

dozen bananas at Rs. 16

per dozen. After selling 18

bananas at the rate of Rs.

12 per dozen, the

shopkeeper reduced the

rate to Rs. 4 per dozen. The

percent loss is:

Sol.:-

C.P. = Rs. (16 x 2) = Rs. 32.

S.P. = Rs. (12 x 1.5 + 4 x 0.5)

= Rs. (18+2) = Rs. 20.

∴ Loss%= (Loss x 100

CP)

= (12

32 x 100) %

= 37.5 %.

Que.:- A man buys a cycle

for Rs. 1400 and sells it at a

loss of 15%. What is the

S.P. of the cycle?

Sol.:- S.P. = 85 % of C.P.

= 85 % of Rs. 1400

= Rs. (85

100 x 1400)

= Rs. 1190.

Que.:- When a plot is sold

for Rs.18,700 the owner

loses 15 %. At what price

must the plot be sold in

order to gain 15%?

Sol.:-

Let new S.P. be Rs. x.

Then, (100-loss%) : (1st S.P.)=(100+gain%) : (2nd S.P.)

(100-15%):(18,700)=(100+15%): x

85 : 18,700 = 115 : x

∴ x = (18,700 x 115

85) = 25,300.

∴ S.P. = Rs. 25,300.

Que.:- A person incurs 5%

loss by selling a watch for

Rs. 1140. At what price

should the watch be sold to

earn 5% profit?

Sol.:-

Let new S.P. be Rs. x. Then, (100-loss%):(1st S.P.) = (100+gain%):(2nd S.P.)

(100-5%):(1140)=(100+5%): x

95 : 1140 = 105 : x

∴ x = (1140 x 105

95) = 1260.

∴ S.P. = Rs. 1260.

Que.:- A man loses 10% by

selling an article for Rs.

180. At what price should

he sell it to gain 10%?

Sol.:-

Let new S.P. be Rs. x. Then, (100-loss%):(1st S.P.) = (100+gain%):(2nd S.P.)

(100-10%):(180)=(100+10%):x

90:180=110: x

∴ x = (180 x 110

90) = 220.

∴ SP = Rs. 220.

Que.:- A tradesman sold an

article at a loss of 20%. If

the SP had been increased

by Rs. 100, there would

have been a gain of 5%.

What was the cost price of

the article?

Sol.:-

Let the C.P. be Rs. x. Then,

(105% of x) - (80% of x)=100

∴ 25% of x = 100

∴ 25𝑥

100 = 100

∴ 𝑥

4 = 100

∴ x = 400.

So, C.P. = Rs. 400.

Que.:- A man bought a

horse and a carriage for Rs.

3000. He sold the horse at

a gain of 20% and the

carriage at a loss of 10%,

thereby gaining 2% on the

whole. Find the cost of the

horse.

Sol.:-

Let the C.P. of the horse be

Rs. x.

Then, C.P. of the carriage =

Rs. (3000- x).

∴20% of x – 10% of (3000- x)

= 2% of 3000

∴ 20𝑥

100 –

3000−𝑥

10 = 60

∴ 𝑥

5 –

3000−𝑥

10 = 60

∴ 10 x – 15000 + 5 x = 3000

∴ 15x = 15000+3000 = 18000

∴ x = 18000

15 = 1200.

Hence, C.P. of the horse = Rs.

1200.

Que.:- On selling 17 balls at

Rs. 720, there is a loss

equal to the cost price of 5

balls. The cost price of a

ball is:

Sol.:-

CP of 17 balls - SP of 17 balls

= CP of 5 balls.

∴ CP of 17 balls - CP of 5 balls

= SP of 17 balls.

∴CP of 12 balls=SP of 17 balls

= Rs. 720.

∴ CP of 1 ball = Rs. (720

12)

= Rs. 60.

Que.:- A pair of articles was

bought for Rs. 37.40 at a

discount of 15%. What

must be the marked price

of each of the articles?

Sol.:-

SP of each article = Rs. (37.40

2)

= Rs. 18.70

Let MP be Rs. x. Then,

SP = 85% of x

18.70 = 85𝑥

100

∴ x = (18.70 x 100

85) = 22.

∴ MP = Rs. 22.

Que.:- List price of an

article at a showroom is Rs.

2000 and it is being sold at

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5

successive discounts of

20% and 10%. Its net

selling price will be:

Sol.:-

S.P.= 90% of 80% of Rs. 2000

= Rs. (90

100 x

80

100 x 2000)

= Rs. 1440.

Que.:- The price of an

article is raised by 30%

and then two successive

discounts of 10% each are

allowed. Ultimately, the

price of the article is:

Sol.:-

Let the original price be Rs.

100. Then,

Marked price = Rs. 130.

Final price = 90% of 90% of

Rs. 130

= Rs. (90

100 x

90

100 x 130)

= Rs. 105.30.

∴ Increase in price

= (105.30-100)% = 5.3 %.

Que.:- By selling an article

at 𝟐

𝟓 of the marked price,

there is a loss of 25%. The

ratio of the marked price

and the cost price of the

article is:

Sol.:-

Let cost price = Rs. 100.

Then,

2

5 of (Marked Price) = 75

∴ Marked Price = Rs. (75 x 5

2)

= Rs. 375

2

∴ Required Ratio,

= 375

2 : 100

= 375 : 200

= 15 : 8.

Que.:- A shopkeeper sells a

badminton rackets, whose

marked price is Rs. 30, at a

discount of 15% and gives

a shuttle cock costing Rs.

1.50 free with each racket.

Even then he makes a

profit of 20%. His cost

price per racket is:

Sol.:-

Marked Price = Rs. 30.

S.P. = Rs. [(85

100 x 30) - 1.50]

= Rs. (25.50 - 1.50)

= Rs. 24.

Let C.P. be Rs. x. Then,

120% of x = 24

∴ x = (24

120 x 100)

= Rs. 20.

Que.:- A shopkeeper sold

sarees at Rs. 266 each after

giving 5% discount on

labelled price. Had he not

given the discount, he

would have earned a profit

of 12% on the cost price.

What was the cost price of

each saree?

Sol.:-

S.P. of 1 saree = Rs. 266.

Let the labelled price of each

saree be Rs. x. Then, 95𝑥

100 = 266

∴ x = Rs. (266

95 x 100) = Rs. 280.

Now,S.P.=Rs.280,profit=12%.

∴ C.P. of 1 saree,

= Rs. (100

112 x 280) = Rs. 250.

Que.:- An item when sold

for Rs. 1,690 earned 30%

profit on the cost price.

Then the cost price is:

Sol.:-

Cost price = Rs. (100

130 x 1,690)

= Rs. 1,300.

Que.:- A dealer purchased a

washing machine for Rs.

7,660. After allowing a

discount of 12% on its

marked price, he still gains

10%. Find the marked

price of the washing

machine.

Sol.:-

Cost price = Rs. 7,660.

S.P. = 110% of Rs. 7,660

= Rs. (110

100 x 7,660)

= Rs. 8,426.

Let marked price be Rs. x.

Then, S.P. = 88% of x

8,426 = (88𝑥

100)

∴ x = (8,426 x 100

88)

∴ x = Rs. 9,575.

∴ Marked Price = Rs. 9,575.

Que.:- A dealer marks his

goods 20% above cost

price. He then allows some

discount on it and marks a

profit of 12%. The rate of

discount is:

Sol.:-

Let Cost Price= Rs. 100. Then,

M.P. = Rs. 120, S.P. = Rs. 112.

∴ Discount = (MP-SP)

= Rs. (120-112)

= Rs. 8.

∴ Discount% = (D

M.P. x 100)

= (8

120 x 100) %

= 20

3 % or 6

2

3 %.

Que.:- A trader marked his

product 20% higher than

his cost price and then

gives 20% discount on the

marked price. The profit or

loss for selling the product

is:

Sol.:-

Let Cost Price= Rs. 100. Then,

Marked Price = Rs. 120.

S.P. = (100−D%

100x MP)

= (100−20%

100x 120)

= Rs. 96.

Here, CP > SP

∴ Loss = (CP-SP)

= (100-96) = 4

∴ Loss% = (Loss x 100

CP)

= (4 x 100

100) % = 4 %.

Que.:- A man sold an article

at a loss of 20%. If he could

sell it for Rs. 200 more, he

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6

would make a profit of 5%.

The cost price of the article

is:

Sol.:-

Let cost price be Rs. x. Then,

SP = (105% of x) - (80% of x)

200 = 25% of x

200 = 25𝑥

100

∴ x = Rs. (200 x 100

25) = Rs. 800.

Que.:- A man purchased an

article and sold it to B at a

profit of 25% and B sold it

to C at a loss of 10% and C

paid Rs. 675 for it. For how

much did A purchase it (in

Rs.)?

Sol.:-

125% of 90% of A = Rs. 675

∴ 125

100 x

90

100 x A = 675

∴ 45

40 x A = 675

∴ A = 675 x 40

45 = Rs. 600.

Que.:- A sells a bicycle to B

at a profit of 20%. B sells it

to C at a profit of 25%. If C

pays Rs. 225 for it, the cost

price of the bicycle for A is:

Sol.:-

125% of 120% of A = Rs. 225

∴ 125

100 x

120

100 x A = 225

∴ 30

20 x A = 225

∴ A = 225 x 20

30 = Rs. 150.

Que.:- A fair price

shopkeeper takes 10%

profit on his goods.

He lost 20% goods during

theft. His loss percent is:

Sol.:-

Suppose he has 100 items.

Let C.P. of each item be Rs. 1.

Total cost = Rs. 100. Number

of items left after theft = 80.

S.P. of each item = Rs. 1.10.

∴ Total sale = Rs. (1.10 x 80)

= Rs. 88.

Hence,

Loss%= (12

100 x 100) %= 12%.

Que.:- At what percent

above the cost price must a

shopkeeper mark his

goods so that he gains 20%

even after giving a discount

of 10% on the marked

price?

Sol.:-

Let C.P. = Rs. 100. Then,

S.P. = Rs. 120.

Let marked price be Rs. x.

Then, S.P. = 90% of x

120 = 90𝑥

100

∴ x = (120 x 100

90) = 133

1

3

∴ Marked Price,

= 133 1

3 % above CP.

Que.:- A man sold 18 cots

for Rs. 16,800, gaining

thereby the cost price of 3

cots. The C.P. of a cot is:

Sol.:- (S.P. of 18 cots) - (C.P. of 18 cots)

= (CP of 3 cots)

∴ (CP of 21 cots) = (SP of 18 cots)

= Rs. 16,800.

∴ (CP of 1 cot),

= Rs. (16,800

21) = Rs. 800.

Que.:- A dishonest dealer

uses a scale of 90 cm

instead of a metre scale

and claims to sell at cost

price. His profit is:

Sol.:- Gain% = (Gain x 100

CP)

= (10

90 x 100) %

= 11 1

9 %.

Que.:- 300 bananas were

purchased at Rs. 128 a

hundred. What should be

the selling price per dozen,

if a profit of Rs.66 is to be

made?

Sol.:-

Cost Price of 300 Bananas,

= 128

100 x 300 = Rs. 384

Profit = Rs. 66 … Given

∴ S.P. of 300 Bananas,

= 384 + 66 = Rs. 450

∴ Selling Price per dozen,

= 450

300 x 12 = Rs. 18.

Que.:- A sells an article to B

at a gain of 10%. B sells it

to C at a gain of 7 𝟏

𝟐 %. C

disposes of it at a loss of

25%. If the prime cost to

the manufacturer A was Rs.

3200,then find the price

obtained by C.

Sol.:-

A buys an article for Rs. 3200

and sells it at a gain of 10%.

∴ Cost Price to B,

= Rs. (3200 x 110

100)

B sells it at a gain of 15

2 %,

∴ Cost Price to C,

=Rs. (3200 x 110 x107.5

(100 x 100))

C sells it at a loss of 25 %,

∴ Price Obtained by C is

= Rs. (3200 x 110 x 107.5 x 75

(100 x 100 x 100))

= Rs. (3200 x 1.1 x 1.075 x 0.75)

= Rs. 2838.

Que.:- A sold a tape-

recorder to B for Rs. 4,860

at a loss of 19%. Again B

sold it to C at a price that

would give A, a profit of

17%. The gain of B is:

Sol.:-

Cost of tape-recorder paid by

A = 4860 x 100

81

= Rs. 6000.

Cost of tape-recorder paid by

C = 6000 x 117

100

= Rs. 7020.

∴ Gain of B = Rs. (7020-4860)

= Rs. 2160.

∴ Gain % = (Gain x 100

CP)

= (2160 x 100

4860)

= 400

9 % or 44

4

9 %.

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Que.:- If the selling price of

a product is increased by

Rs. 162, then the

businessman will make a

profit of 17% instead of a

loss of 19%. The cost price

of the product is:

Sol.:-

Let the cost price be Rs. x.

∴ if loss is 19%, then the

selling Price would have

been, x - 19% of x, i.e., 81𝑥

100

∴ 81𝑥

100 + 162 = x + 17% of x =

117𝑥

100

∴ 36 x = 16200

∴ x = Rs. 450.

Que.:- It costs Re. 1 to

photocopy a sheet of paper.

However, 2% discount is

allowed on all photocopies

done after first 1000

sheets. How much will it

cost to copy 5000 sheets of

paper?

Sol.:- Total cost,

=Rs. [1x1000+(100-2)% of 1x4000]

=Rs. (1000+0.98 x 4000)

=Rs. (1000+3920)

=Rs. 4920.

Que.:- If by selling 110

apples, the C.P. of 120

apples is realised, the gain

percentage is:

Sol.:-

Let C.P. of each apple be Rs.1.

C.P. of 110 apples = Rs. 110

S.P. of 110 apples = Rs. 120

∴ Gain % = (10

110 x 100) %

= 9 1

11 %.

Que.:- By selling 12 toffees

for a rupee, a man loses

20%. How many for a

rupee should he sell to get

a gain of 20%?

Sol.:-

Let S.P. of 12 toffees be Rs. x.

Then, 80 : 1 = 120 : x

∴ x = (120

80) =

3

2 .

For Rs. 3

2 , toffees sold = 12.

For Rs. 1 , toffees sold,

= (12 x 2

3) = 8.

Que.:- The cash difference

between the selling prices

of an article at a profit of

4% and 6% is Rs. 3. The

ratio of the two selling

prices is:

Sol.:-

Let C.P. of the article be Rs. x.

Then, Required ratio,

= 104% 𝑥

106% 𝑥 =

104

106 =

52

53 = 52:53.

Que.:- Peter bought an item

at 20% discount on its

original price. He sold it

with 40% increase on the

price he bought it. The new

sale price is by what

percent more than the

original price?

Sol.:-

Let the original price be Rs.

100. Then, C.P. = Rs. 80.

∴ S.P. = 140% of Rs. 80

= Rs. (140

100 x 80)

= Rs. 112.

∴ Required Percentage,

= (112 - 100) % = 12%.

Que.:- A dishonest dealer

professes to sell his goods

at cost price. But he uses a

false weight and thus gains

6 𝟏𝟖

𝟒𝟕 %. For a kg, he uses a

weight of:

Sol.:-

Let error = x gms. Then,

𝑥

1000−𝑥 x 100 = 6

18

47

∴ 100𝑥

1000−𝑥 =

300

47

∴ 47 x = 3 (1000 - x)

∴ 50 x = 3000

∴ x = 60.

∴ Weight used = (1000 - 60)

= 940 gms.

Que.:- A shopkeeper cheats

to the extent of 10% while

buying as well as selling, by

using false weights. His

total gain is:

Sol.:-

Rule:

Gain % = (100+𝑐𝑜𝑚𝑚𝑜𝑛 𝑔𝑎𝑖𝑛 %)2

100− 100

∴ Gain %= [ (100+10)2

100− 100] %

= (12100−10000

100) %

= 21 %.

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This is a compilation of chapterwise questions of Quantitative Aptitude that have been

recently asked in the various Competitive Examinations by SSC, IBPS, SBI, Railway,

Airforce, etc. This is a rare collection of more than 50 questions (On Profit & Loss) and

their respective explanations by Race Express.