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Review
Probabilities– Definitions of experiment, event, simple event,
sample space, probabilities, intersection, union compliment
– Finding Probabilities– Drawing Venn Diagrams – If A and B are two events then
P(A or B) = P(A) + P(B) - P(A and B),
P(not A) = 1 - P(A). – Two events A and B are mutually exclusive if P(A and
B) = 0.
Example
Suppose P (E) = 0.4, P (F) = 0.3, and
P(E or F)=0.6. Find:
P(E and F) P(EC or FC)
P(EC and FC) P(EC and F)
Example
Suppose P (E) = 0.4, P (F) = 0.3, and
P(E or F)=0.6. Find:
P(E and F) =0.1 P(EC or FC)
P(EC and FC) P(EC and F)
Example
Suppose P (E) = 0.4, P (F) = 0.3, and
P(E or F)=0.6. Find:
P(E and F) =0.1 P(EC or FC)=0.9
P(EC and FC) P(EC and F)
Example
Suppose P (E) = 0.4, P (F) = 0.3, and
P(E or F)=0.6. Find:
P(E and F) =0.1 P(EC or FC)=0.9
P(EC and FC)=0.4 P(EC and F)
Example
Suppose P (E) = 0.4, P (F) = 0.3, and
P(E or F)=0.6. Find:
P(E and F) =0.1 P(EC or FC)=0.9
P(EC and FC)=0.4 P(EC and F)= 0.2
3.15
2 1 2 3 1 3 2 2 1 2
2 1 1 1 3 2 3 1 2 1
BB ,BR ,BR ,BR ,BR
,BR ,BR ,RR ,RR ,RR a)
each 10
1 b)
; 10
3;
10
6;
10
1 c)
3.20
Rhino. Whiteand
RhinoBlack :pickyou rhino theofcolour The a)
)RhinoBlack (
)Rhino White(
s.frequencie relative Useb)
P
P
3.20
Rhino. Whiteand
RhinoBlack :pickyou rhino theofcolour The a)
764.84002600
8400)RhinoBlack (
236.84002600
2600)Rhino White(
s.frequencie relative Useb)
P
P
3.44
up. added
iesprobabilit with theDiagramVenn theDraw
.69 f) .31 e) .97 d) .5 c) .19 b) .53 a)
empty.not
ison intersecti therebecausenot are they No g)
3.45
Low Medium High Total
On 0.50 0.10 0.05 0.65
Off 0.25 0.07 0.03 0.35
Total 0.75 0.17 0.08 1
}High{D Low}, and {OffC On},or {Med.B {On},A
3.45
Low Medium High Total
On 0.50 0.10 0.05 0.65
Off 0.25 0.07 0.03 0.35
Total 0.75 0.17 0.08 1
}High{D Low}, and {OffC On},or {Med.B {On},A
B) andP(A , B)or P(A , )P(A
P(D), P(C), P(B) , P(A)C
3.45
Low Medium High Total
On 0.50 0.10 0.05 0.65
Off 0.25 0.07 0.03 0.35
Total 0.75 0.17 0.08 1
}High{D Low}, and {OffC On},or {Med.B {On},A
65.0 B) andP(A , P(B)) (see 0.72 B)or P(A
0.350.65-1P(A)-1 )P(A
0.08 P(D), 25.0P(C)
0.720.10-0.650.17 P(B) , 0.65 P(A)
C
3.54
on.intersecti no haveThey YES. g)
intersectThey NO. f)
.843 e)
0.64476/6488 d)
.569
787/7488670/74882806/74883) P(below c)
.1921438/7488 weapon)P(carried b)
175.7488/1307P(5) a)
Conditional Probability
You are dealt two cards from a deck. What is the probability the first card dealt is a Jack?
Conditional Probability
You are dealt two cards from a deck. What is the probability the first card dealt is a Jack?
13
1:Answer
Conditional Probability
You are dealt two cards from a deck. What is the probability of the second card was a jack given the first card was not a jack is called card dealt is a Jack?
Conditional Probability
You are dealt two cards from a deck. What is the probability of the second card was a jack given the first card was not a jack is called card dealt is a Jack?
Conditional Probability
You are dealt two cards from a deck. What is the probability of the second card was a jack given the first card was not a jack is called card dealt is a Jack?
51
4:Answer
Conditional Probability
You are dealt two cards from a deck. What is the probability of the second card was a jack given the first card was not a jack is called card dealt is a Jack?
The probability of drawing jack given the first card was not a jack is called conditional probability. A key words to look for is “given that.”
Conditional Probability
The probability of drawing jack given the first card was not a jack is called conditional probability. A key words to look for is “given that.”
The probability that the event A occurs, given that B occurs is denoted:
This is read the probability of A given B.).|( BAP
Conditional Probability
You are dealt two cards from a deck. What is the probability the second card dealt is a Jack?
Conditional Probability
You are dealt two cards from a deck. What is the probability the second card dealt is a Jack?
Conditional Probability
You are dealt two cards from a deck. What is the probability the second card dealt is a Jack?
13
1:Answer
Example
A local union has 8 members, 2 of whom are women. Two are chosen by a lottery to represent the union.
Example
A local union has 8 members, 2 of whom are women. Two are chosen by a lottery to represent the union.
a) What is the probability they are both male?
Example
A local union has 8 members, 2 of whom are women. Two are chosen by a lottery to represent the union.
a) What is the probability they are both male?
M)|P(M(M):Answer P
Example
A local union has 8 members, 2 of whom are women. Two are chosen by a lottery to represent the union.
a) What is the probability they are both male?
536.07
5
8
6:Answer
Example
A local union has 8 members, 2 of whom are women. Two are chosen by a lottery to represent the union.
b) What is the probability they are both female?
Example
A local union has 8 members, 2 of whom are women. Two are chosen by a lottery to represent the union.
b) What is the probability they are both female?
036.07
1
8
2F)|P(F*P(F):Answer
Conditional Probability
How would we draw the event A given B?
Since we know B has occurred, we ignore everything else.
A B A
and B
Conditional Probability
How would we draw the event A given B?
Since we know B has occurred, we ignore everything else.
A B A
and B
Conditional ProbabilityHow would we draw the event A given B?
Since we know B has occurred, we ignore everything else.
With some thought this tells us:
B A
and B
)(
) and ()|(
BP
BAPBAP
Conditional ProbabilitySince we know B has occurred, we ignore everything else.
Or rearranging:
B A
and B
)|()() and ( BAPBPBAP
Example
Find the probability of selecting an all male jury from a group of 30 jurors, 21 of whom are men.
Example
Find the probability of selecting an all male jury from a group of 30 jurors, 21 of whom are men.
Solution: P(12 M) =P(M)*P(M|M)*P(M|MM) * ….
= 21/30 * 20/29 * 19/28 * 18/27 * … 10/19
= 0.00340
Independent Events
Two events A and B are independent if the occurrence of one does not affect the probability of the other.
Independent Events
Two events A and B are independent if the occurrence of one does not affect the probability of the other.
Two events A and B are independent then P(A|B) = P(A).
Independent Events
Two events A and B are independent if the occurrence of one does not affect the probability of the other.
Two events A and B are independent then P(A|B) = P(A).
Two events which are not independent are dependent.
Multiplication Rule
Multiplication Rule:
For any pair of events:
P(A and B) = P(A) * P(B|A)
For any pair of independent events:
P(A and B) = P(A) * P(B)
Multiplication RuleFor any pair of events:
P(A and B) = P(A) * P(B|A)
For any pair of independent events:
P(A and B) = P(A) * P(B)
If P(A and B) = P(A) * P(B), then A and B are independent.
Multiplication RuleMultiplication Rule:
P(A and B) = P(A) * P(B) if A and B are independent.
P(A and B) = P(B) * P(A|B) if A and B are dependent.
Note: The multiplication rule extends to several events: P(A and B and C) =P(C)*P(B|C)*P(A|BC)
ExampleA study of 24 mice has classified the mice by two categories
Black White Grey
Eye Colour
Red Eyes 3 5 2
Black Eyes 1 7 6
Fur Colour
A study of 24 mice has classified the mice by two categories
a) What is the probability that a randomly selected mouse has white fur?
b) What is the probability it has black eyes given that it has black fur?
c) Find pairs of mutually exclusive and independent events.
Black White Grey
Eye Colour
Red Eyes 3 5 2
Black Eyes 1 7 6
Fur Colour
A study of 24 mice has classified the mice by two categories
a) What is the probability that a randomly selected mouse has white fur? 12/24=0.5
b) What is the probability it has black eyes given that it has black fur?
c) Find pairs of mutually exclusive and independent events.
Black White Grey
Eye Colour
Red Eyes 3 5 2
Black Eyes 1 7 6
Fur Colour
A study of 24 mice has classified the mice by two categories
a) What is the probability that a randomly selected mouse has white fur? 12/24=0.5
b) What is the probability it has black eyes given that it has black fur? 1/4=0.25
c) Find pairs of mutually exclusive and independent events.
Black White Grey
Eye Colour
Red Eyes 3 5 2
Black Eyes 1 7 6
Fur Colour
b) What is the probability it has black eyes given that it has black fur? 1/4=0.25
c) Find pairs of mutually exclusive and independent events.
ME: Black eyes and Red eyes
IND: White Fur and Red Eyes; Black Fur and Red Eyes
Black White Grey
Eye Colour
Red Eyes 3 5 2
Black Eyes 1 7 6
Fur Colour
Descriptive Phrases
Descriptive Phrases require special care!
– At most– At least– No more than– No less than
62
Homework
• Review Chapter 3
• Read Chapter 4.1-4.4
• Quiz on Tuesday on Chapters 1 and 2
• Problems on next slide