Upload
spamail73887
View
239
Download
1
Embed Size (px)
DESCRIPTION
Rods
Citation preview
1
1
3 Rod and beam elementsHow to analyze structures shown in pictures using FEM:
2
3 Rod and beam elementsRod (spar, truss element) and beam, definitions:
• Rod elements can only extend or compressaxially (two-force system!)
• Beam elements can carry bending momentsand (and torsion in 3D) in additio to axialloads
rod
rod
beam
2
3
3.1 RodThe stiffness matrix of a rod element has already been
defined (spring!):
Thus the basic equation is
General definition: columns of stiffness matrix arenodal loads imposed on the elements resulting unitdisplacement in corresponding degree of freedomand keeping other degrees of freedom zero.
1 1 11
1 1 2
,k k U
K uk k U
N1 N2
A,EL
U1 U2
2
1
2
1
1111
FF
uu
LAE
,i
i ekvi
A Ekl
4
3.1 RodMore formal definition comes from integral
where B is strain-displacement matrix, E on material matrix or constitutive matrix. Matrix B is obtained by defining the displacement field in the rod using linear interpolation
where N is so-called shape function matrix.
N1 N2
A,EL
u1 u2
Nduuu
Lx
LxLxu or)(
2
1
V
dVk EBBT
3
5
3.1 Rod
Strain is the gradient of axial displacement, i.e.
Notice that strain-displacement matrix is derivative of the shape function vector.
Thus the stiffness matrix can be derived as
2
1,11,uu
LLdxd
dxdu
x dBBdN
111111
/1/1
0 LAEAdx
LLE
LL
dVkL
V
EBBT
6
3.2 2D Beam2 dimensional Beam element has for degrees of freedom, i.e. rotations at the end of the beam as well as transverse displacements:
In the development of the stiffness matrix the assumption is a prismatic and materiallyhomogenous beam.Notice that axial deformations are excluded fromthe definition but they can be readily incorporatedin stiffness matrix from rod element previouslydefined.
2
2
1
1
v
v
d
4
7
3.2 2D BeamThe stiffness matrix of a two-dimensional prismaticbeam made of homogenous material can bederived using integral
in which the strain-displacement matrix B is obtained from curvature d2v/dx2 using third orderpolynomial, which describes the displacement fieldas:
V
dVEIk BBT
34
2321 xxxv
8
3.2 2D BeamUsing four shape functions, i.e. each for corresponding dof, leads to formulation
and strain-displacement function B is obtainedfrom curvature d2v/dx2
2
2
1
1
4321)(v
v
NNNNxv
BdN2
2
2
2
dxd
dxvd
EIM
dxd
2
2
Engineering beam theory:
5
9
3.2 2D BeamThe shape functions are obtained from beam theory:
jossa
10
3.2 2D beamThus the derivatives of the shape functions shown in the previous slide result the strain-displacement matrix
And the integration
results
22
22
3
4626612612
2646612612
LLLLLL
LLLLLL
LEIdVEIk
V
BBT
T2211 vvd
2322326212664126Lx
LLx
LLx
LLx
LB
BdN2
2
2
2
dxd
dxvd
6
11
3.3 Transformation
Stiffness matrix of a rod in local coordinate system (a)Transformation from local to global system (b)
3.3 Transformation
The global stiffness matrix of a rod can be derived as
where
cos,sin,
22
22
22
22
cs
scsscscsccscscsscscsccsc
LAETk'Tk T
sincos0000sincos
T
1111
LAEk'
7
13
3.3 Transformation
Example: calculate the displacements and stresses of the structure shown in figure, when A = 300 mm2 for allrods and E = 200 GPa.
14
3.3 Transformation
Element numbering, directions of local coordinates, stiffness matrices and degrees of freedom:
1:C->B
2:B->A
3:C->A
uC vC uB vB
uB vB uA vA
uC vC uA vA
uCvC uB vB
uBvB uA vA
uCvC uA vA
cos,sin,
22
22
22
22
cs
scsscscsccscscsscscsccsc
LAETk'Tk T
8
15
3.3 Transformation
Global stiffness matrix and force vector when loadingand boundary conditions are taken into account:
1:C->B
2:B->A
3:C->A
uC vC uB vB uA vA
A
A
B
B
C
C
vuvuvu
U
16
3.3 Transformation
Solution and results [mm]:
uB = -1,50 mmvB = -11,3 mmvA= - 4,00 mm
9
17
3.3 Transformation
Formulate the stiffness matrix of the structure shown in figure. E = 210 GPa and cross-section is RHS 100x100x4. Axial stiffness of beam BC = The stiffnes matrix of beam AB in global coordinatesystem is
and of beams BD and DC:
B
B
A
A
AB
vuvu
scsscscsccscscsscscsccsc
LAE
1
22
22
22
22
1 , uk
D
D
B
B
BDBDBDBD
DBBD
BDBDBDBD
BDBD
BD v
v
LLLLLL
LLLLLL
LEI
2
22´
22
32 ,
4626612612
2646612612
uk
C
C
D
D
DCDCDCDC
DCDC
DCBCDCDC
DCDC
DC v
v
LLLLLL
LLLLLL
LEI
3
22
22
33 ,
4626612612
2646612612
uk
D
D
D
B
B
v
v
D
D
B
B
v
v
B
B
A
A
vuvu
1u
18
3.3 Transformation
Taking into account the boundary conditions and the axialstiffness of beam BC (infinite!) results
22
22
22
22
31
scsscscsccscscsscscsccsc
LAE
AB
k
22
22
32
4626612612
2646612612
BDBDBDBD
BDBD
BDBDBDBD
BDBD
Bd
LLLLLL
LLLLLL
LEIk
D
22
22
33
4626612612
2646612612
DCDCDCDC
DCDC
DCDCDCDC
DCDC
DC
LLLLLL
LLLLLL
LEIk
10
19
3.3 Transformation
Global stiffness matrix is then
C
D
D
B
B
DCDCDC
DCDCBDDCBDBDBD
DCDCBDDCBDBDBD
BDBDBDBD
BDBDBDBDAB
G v
v
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEI
LEIs
LAE
dk ,
42600
2446626
6661212612
02646
0612612
2
222
2223323
22
23232
D
20
3.3 Transformation
The solution results
Backsubstitution gives element forces, example is element BD:
D
Displacement vector
11
21
3.3 Transformation of 2D beam element
Global stiffness matrix of a 2D beam element, when alsoaxial stiffness is taken into account is
Tk'Tk T
2
2
2
1
1
1
v
u
v
u
U
1000000cossin0000sincos0000001000000cossin0000sincos
T
v1
1
u1
v2 u22
Y
X
22
3.2 2D beam: exampleCalculate the maximum displacement and maximumnormal stress in the frame shown in picture. Crane beamis IPE 300 and column is HEA200. Neglect self-weight.
12
23
3.2 2D beam: exampleElement model and degrees of freedom (notice assumptions of model!):E = 210 GPaAIPE300 = 5380 mm2
IIPE300 = 83,6E6 mm4
AHEA20 = 5380 mm2
IHEA200 = 36,9E6 mm21 2
3
1 2 3
4
mmmmmmmmmmmmmmmmmmmmmmlmlmllllmmmmlmlmllllmmmmlmlmllll
llllklklkkkkllllklklkkkkllllklklkkkk
kkkkkkkkkkkkkkkkkk
G
000000000000000000
000000000
000000000000000000000000000
k
4
4
4
3
3
3
2
2
2
1
1
1
vu
vu
vu
vu
U
u
v
24
3.2 2D beam: exampleDistributed loading, e.g. self-weght in a beam element
is changed to nodal loads and moments at nodes:
2wL
2wL
12
2wL12
2wL
w