Settlements and Elastic Stress Distribution (SEP 2011 Color)

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  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    1

    CE 5101 Lecture 5 SETTLEMENTS and Stress

    Distribution

    Sep 2011Prof Harry Tan

    1

    Outline Foundation Requirements

    Elastic Stress DistributionElastic Stress Distribution

    Concept of Effective Stress

    Settlements of Soils - Immediate, Delayed, and Creep Compression

    Hand Calculations

    SPREADSHEET Calculations (UNISETTLE)

    Finite Element Analysis (PLAXIS)2

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    2

    Requirements for Foundation Design

    Adequate Safety (degree of utilisation of soil strength)

    Acceptable Deformations Acceptable Deformations(Movements and Settlements limits)

    3

    What is Adequate Safety(Lambe and Whitman Pg 196)

    -2.000 -1.000 0.000 1.000 2.000 3.000 4.000 5.000 6.000 7.000 8.000 9.000 10.000 11.000 12.000

    9 000 Failure Load = 866 kPaAA

    4.000

    5.000

    6.000

    7.000

    8.000

    9.000

    E

    Stress

    Strain

    2c

    Failure Load 866 kPa

    Yielded

    0.000

    1.000

    2.000

    3.000

    Plastic Points

    Plastic Mohr-Coulomb point Tension cut-off point

    E = 34.48 MN/m2

    c=167.6 kN/m2

    = 0.3

    Yielded Zone

    4

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    3

    0.00

    Footing CL Settlement [m]

    Chart 1

    Load vs Settlement Behaviour of Flexible Footing

    Settlement (m)

    -0.20

    -0.15

    -0.10

    -0.05

    Point A

    First Yield Local Shear

    Failure

    0 200 400 600 800 1.00E+03-0.35

    -0.30

    -0.25

    Footing Load (kPa)

    General Shear Failure

    Load (kPa)5

    4 5

    Factor of Strength Reduction

    Chart 2

    Factor of Safety as Measure of Degree of Utilisation of Soil Strength

    2.5

    3.0

    3.5

    4.0

    4.5

    Point AFS = 4.338; q = 200 kPa; qult = 868 kPa

    FS = 2 164; q = 400 kPa; qult = 866 kPa

    0 0.05 0.10 0.15 0.20 0.25 0.30 0.351.0

    1.5

    2.0

    Settlement (m)

    FS = 2.164; q = 400 kPa; qult = 866 kPa

    FS = 1.291; q = 670 kPa; qult = 865 kPa

    6

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    4

    What is Allowable Settlements

    Effects on:

    Appearance of Structure

    Utility of Structure

    Damage to Structure

    7

    Types of Settlements

    Uniform settlement

    Non-uniform settlement

    Angular distortion = /L

    L

    L

    Angular distortion = /(L/2)

    8

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    5

    Allowable Settlements

    Controlled by type of settlements (Sowers 1962)y yp ( )

    Total settlements

    Tilting

    Differential settlements

    9

    Limiting Angular Distortions (Bjerrum, 1963)1/150 - Considerable cracking in panel and brick walls, safe limit for flexible brick wall h/l

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    6

    Limiting Angular Distortions (Bjerrum ,1963)

    Max Distortion (/L) vs Max Differential Settlement :

    1/500 vs 25 mm For Stiff Footing,1/500 vs 25 mm

    1/300 vs 45 mm

    1/200 vs 70 mm

    1/100 vs 150 mm

    g,

    Max Diff Sett = 1/4 Max Sett

    For Flexible Footing,

    Max Diff Sett = 1/2 Max Sett

    Typical Foundation Design,

    Max Diff Sett < 25 mm

    11

    Limiting Angular Distortions (Bjerrum ,1963)

    350 mm

    200 mm

    Stiff Footing max diff sett =1/4 max sett Flexible Footing max diff sett=1/2 max sett

    12

    100 mm

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    7

    ER2010 Review Paper by Ed Cording et al Assessment of excavation-induced building damage Damage is due to combined effects of:effects of: Angular distortion; Lateral strain Bending strain

    13

    Basic Soil Phase RelationshipsMASSVOLUME Densities (kg/m3)

    Air

    Water

    Solids

    0

    Mw Mt

    Ms

    Mw

    Va

    Vw

    Vs

    Vv

    Vt

    Total, t = Mt/VtDry, d = Ms/VtSolids, s = Ms/VsWater, t = Mw/VwSaturated, sat Ratios= (Ms+Mw+ w Va)/VtWater content, w = Mw/Ms

    Void ratio, e = Vv/Vs

    Porosity, n = Vv/Vt

    Degree of saturation = Vw/Vv 14

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    8

    Basic Soil Phase RelationshipsDefine Vs=1, Vv=e

    MASSVOLUME Densities (kg/m3)

    eS w = w s

    Air

    Water

    Solids

    0 t

    s

    Mw

    (1-e)S

    eS

    1

    e

    1+e

    Total, t = s (1+w)/(1+e)= d (1+w)

    Dry, d = s /(1+e)Saturated, sat = (Ms+Mw+ w Va)/VtRatios

    Water content, w = t/ d - 1 Void ratio, e = s/d - 1Porosity, n = e/(1+e)

    Degree of saturation = S = ws / ew 15

    Common soil mineral densitiesMineral Type Solid Density, kg/m3

    Calcite 2800

    Quartz 2670

    Mica 2800

    Pyrite 5000

    Kaolinite 2650

    Montmorillonite 2750

    Illite 270016

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    9

    Typical range of saturated densitiesSoil Type Saturated Density, kg/m3

    Sands;gravels 1900-2300

    Silts 1500-1900

    Soft Clays 1300-1800

    Firm Clays 1600-2100

    Peat 1000-1200

    Organic Silt 1200-1900

    Granular Fill 1800-220017

    The Textbooks on Foundations They come no better

    This is one of the few showingmore than one soil layer

    18

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    10

    The Reality With a bit of needed W add-on

    19

    The Reality Getting closer, at least

    20

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    11

    So, with this food for thought, , g ,on to the Fundamental

    Principles

    21

    Determining the effective stress is the key to geotechnical analysis

    The not-so-good method:method:

    h '' )'(' hz

    = buoyant unit weight

    )1(' iwt 22

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    12

    It is much better to determine, separately, the total stress and the pore pressure. The effective stress is then the total stress minus the pore pressureminus the pore pressure.

    )( hz uz '

    23

    Determining pore pressure

    u = w hu w hThe height of the column of water (h; the head representing the water pressure)is usually not the distance to the ground surface nor, even, the distance to thegroundwater table. For this reason, the height is usually referred to as thephreatic height or the piezometric height to separate it from the depth belowthe groundwater table or depth below the ground surface.

    The pore pressure distribution is determined by applying the facts that

    (1) in stationary conditions, the pore pressure distribution can be assumed to be linear in each individual soil layer

    SAND Hydrostatic distribution

    GW

    PRESSURE

    (2) in pervious soil layers that are sandwiched between less pervious layers, the pore pressure is hydrostatic (that is, the vertical gradient is unity)

    CLAY Non-hydrostatic distribution, but linear

    SAND Hydrostatic distribution Artesian phreatic head

    DEPTH

    24

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    13

    Distribution of stress below a a small load area

    The 2:1 method

    )()(0 zLzBLBqqz

    The 2:1-method can only be used for distributions directly under the centerof the footprint of the loaded area. It cannot be used to combine (add)stresses from adjacent load areas unless they all have the same center. it isthen only applicable under the area with the smallest footprint. 25

    Boussinesq Method for stress from a point load

    2/522

    3

    )(23

    zrzQqz

    26

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    14

    Newmarks method for stress from a loaded area

    Newmark (1935) integrated the Boussinesq equation over a finite area and obtained a relation for the stress under the corner of aarea and obtained a relation for the stress under the corner of a uniformly loaded rectangular area, for example, a footing

    40CBAIqqz

    2222

    22

    112nmnm

    nmmnA

    (1)

    12

    22

    22

    nmnmB

    2222

    22

    112arctannmnm

    nmmnC

    m = x/zn = y/zx = length of the loaded areay = width of the loaded areaz = depth to the point under the corner

    where the stress is calculated

    27

    Eq. 1 does not result in correct stress values near the ground surface. To represent the stress near the ground surface, Newmarks integration applies an additional equation:

    40CBAIqqz

    F h 2 + 2 + 1 2 2

    (2)

    For where: m2 + n2 + 1 m2 n2

    28

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    15

    Stress distribution below the center of a square 3 m wide footing

    0 0.25Eq. (2) Eq. (2)

    -4

    -2

    DE

    PTH

    (m)

    0.10

    0.15

    0.20

    INFL

    UE

    NC

    E F

    AC

    TOR

    , IEq. (1)

    Eq. (1)

    0 20 40 60 80 100-6

    STRESS (KPa)0.01 0.10 1.00 10.00

    0.00

    0.05

    m and n (m = n)

    29

    00 25 50 75 100

    STRESS (%)

    Boussinesq

    Westergaard

    00 25 50 75 100

    SETTLEMENT (%)

    Boussinesq

    Westergaard

    1

    2

    3

    EPTH

    (di

    amet

    ers)

    2:1

    1

    2

    3

    EPTH

    (di

    amet

    ers)

    q

    2:1

    Comparison between Boussinesq, Westergaard, and 2:1 distributions

    4

    5

    DE

    4

    5

    DE

    30

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    16

    00 25 50 75 100

    STRESS (%)

    Westergaard

    00 25 50 75 100

    SETTLEMENT (%)

    Westergaard

    1

    2

    3

    PTH

    (di

    amet

    ers)

    Boussinesq

    1

    2

    3

    PTH

    (di

    amet

    ers)

    Boussinesq

    4

    5

    DEP 2:1

    4

    5

    DEP

    2:1

    31

    0

    1

    0 25 50 75 100

    STRESS (%)

    Westergaard

    0

    1

    0 25 50 75 100

    SETTLEMENT (%)

    Westergaard

    1

    2

    3

    EPTH

    (di

    amet

    ers)

    2:1

    Boussinesq

    Characteristic Point; 0.37b from center

    1

    2

    3

    EPTH

    (di

    amet

    ers)

    Boussinesq

    2:1 Characteristic Point; 0.37b from center

    4

    5

    D

    4

    5

    D

    Below the characteristic point, stresses for flexible and stiff footings are equal 32

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    17

    Now, if the settlement distributions are so similar, why do we persist in using

    Boussinesq stress distribution instead of the much simpler 2:1 distribution?

    Because a footing is not alone in this world; near by, there are other footings, and fills,near by, there are other footings, and fills,

    and excavation, etc., for example:

    33

    The settlement imposed

    00 25 50 75 100

    SETTLEMENT (%)

    BoussinesqOutside Point Boussinesq

    Center PointThe settlement imposed outside the loaded

    foundation is often critical

    1

    2

    3

    PTH

    (di

    amet

    ers)

    Center Point

    4

    5

    DE

    Loaded area

    34

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    18

    Calculations using Boussinesq distribution can be used to determine how stressapplied to the soil from one building may affect an adjacent existing building.

    EXISTING NEW 0 20 40 60 80 100STRESS (%)

    ADJACENT BUILDING

    BUILDING WITH LARGE LOAD OVER FOOTPRINT

    AREA

    2 m2 m 4 m

    0

    5

    10

    15

    DEP

    TH (

    m) STRESSES

    UNDER THE FOOTPRINT OT THE LOADED BUILDING

    STRESSES UNDER AREA

    BETWEEN THE TWO BUILDINGS

    20

    25

    30

    STRESSES ADDED TO THOSE UNDER THE FOOTPRINT OF THE ADJACENT BUILDING

    35

    Calculation of Stress DistributionDepth 0 u0 0 1 u1 1(m) (KPa) (KPa) (KPa (KPa) (KPa) (KPa)

    Layer 1 Sandy silt = 2,000 kg/m30.00 0.0 0.0 0.0 30.0 0.0 30.0STRESS (KPa)0.00 0.0 0.0 0.0 30.0 0.0 30.0

    GWT 1.00 20.0 0.0 20.0 48.4 0.0 48.42.00 40.0 10.0 30.0 66.9 10.0 56.93.00 60.0 20.0 40.0 85.6 20.0 65.64.00 80.0 30.0 50.0 104.3 30.0 74.3

    Layer 2 Soft Clay = 1,700 kg/m34.00 80.0 30.0 50.0 104.3 30.0 74.35.00 97.0 40.0 57.0 120.1 43.5 76.66.00 114.0 50.0 64.0 136.0 57.1 79.07.00 131.0 60.0 71.0 152.0 70.6 81.48.00 148.0 70.0 78.0 168.1 84.1 84.09.00 165.0 80.0 85.0 184.2 97.6 86.6

    10.00 182.0 90.0 92.0 200.4 111.2 89.211.00 199.0 100.0 99.0 216.6 124.7 91.912.00 216.0 110.0 106.0 232.9 138.2 94.613.00 233.0 120.0 113.0 249.2 151.8 97.414.00 250.0 130.0 120.0 265.6 165.3 100.315.00 267.0 140.0 127.0 281.9 178.8 103.116.00 284.0 150.0 134.0 298.4 192.4 106.0

    0

    5

    10

    15

    0 100 200 300 400 500

    ( )

    DEP

    TH (m

    )

    SAND

    CLAY

    17.00 301.0 160.0 141.0 314.8 205.9 109.018.00 318.0 170.0 148.0 331.3 219.4 111.919.00 335.0 180.0 155.0 347.9 232.9 114.920.00 352.0 190.0 162.0 364.4 246.5 117.921.00 369.0 200.0 169.0 381.0 260.0 121.0

    Layer 3 Silty Sand = 2,100 kg/m321.00 369.0 200.0 169.0 381.0 260.0 121.022.00 390.0 210.0 180.0 401.6 270.0 131.623.00 411.0 220.0 191.0 422.2 280.0 142.224.00 432.0 230.0 202.0 442.8 290.0 152.825.00 453.0 240.0 213.0 463.4 300.0 163.4

    20

    25

    SAND

    HYDROSTATIC PORE PRESSURE DISTRIBUTION

    36

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    19

    Calculation of Stress DistributionSTRESS DISTRIBUTION (2:1 METHOD) BELOW CENTER OF EARTH FILL (Calculations by means of UniSettle)

    ORIGINAL CONDITION (no earth fill) FINAL CONDITION (with earth fill and artesian pore pressure in sand)

    Depth 0 u0 0 1 u1 1(m) (KPa) (KPa) (KPa (KPa) (KPa) (KPa)

    Layer 1 Sandy silt = 2,000 kg/m30.00 0.0 0.0 0.0 30.0 0.0 30.0

    GWT 1 00 20 0 0 0 20 0 48 4 0 0 48 4GWT 1.00 20.0 0.0 20.0 48.4 0.0 48.42.00 40.0 10.0 30.0 66.9 10.0 56.93.00 60.0 20.0 40.0 85.6 20.0 65.64.00 80.0 30.0 50.0 104.3 30.0 74.3

    Layer 2 Soft Clay = 1,700 kg/m34.00 80.0 30.0 50.0 104.3 30.0 74.35.00 97.0 40.0 57.0 120.1 43.5 76.66.00 114.0 50.0 64.0 136.0 57.1 79.07.00 131.0 60.0 71.0 152.0 70.6 81.48.00 148.0 70.0 78.0 168.1 84.1 84.09.00 165.0 80.0 85.0 184.2 97.6 86.6

    10.00 182.0 90.0 92.0 200.4 111.2 89.211.00 199.0 100.0 99.0 216.6 124.7 91.912.00 216.0 110.0 106.0 232.9 138.2 94.613.00 233.0 120.0 113.0 249.2 151.8 97.414.00 250.0 130.0 120.0 265.6 165.3 100.315 00 267 0 140 0 127 0 281 9 178 8 103 115.00 267.0 140.0 127.0 281.9 178.8 103.116.00 284.0 150.0 134.0 298.4 192.4 106.017.00 301.0 160.0 141.0 314.8 205.9 109.018.00 318.0 170.0 148.0 331.3 219.4 111.919.00 335.0 180.0 155.0 347.9 232.9 114.920.00 352.0 190.0 162.0 364.4 246.5 117.921.00 369.0 200.0 169.0 381.0 260.0 121.0

    Layer 3 Silty Sand = 2,100 kg/m321.00 369.0 200.0 169.0 381.0 260.0 121.022.00 390.0 210.0 180.0 401.6 270.0 131.623.00 411.0 220.0 191.0 422.2 280.0 142.224.00 432.0 230.0 202.0 442.8 290.0 152.825.00 453.0 240.0 213.0 463.4 300.0 163.4

    Aquifer with artesian head

    37

    Stress Distribution

    00 100 200 300 400 500

    STRESS (KPa)

    00 100 200 300 400 500

    STRESS (KPa)Stress from Fill

    5

    10

    15DEP

    TH (m

    )

    5

    10

    15DEP

    TH (m

    )

    SAND

    CLAY

    20

    25

    20

    25

    SAND

    Artesian Pore Pressure HeadThe distribution for the hydrostatic case

    38

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    20

    Effective Stress Concept

    Effective stress = Total stress - Pore pressure

    = - uUnit weight = g (kN/m3)g assumed to be 10 m2/s

    T t l ti l t b dTotal vertical stress or overburden stress, z = t.z

    39

    Pore Water Pressure (PWP)

    Pore water pressure u = uw = uss + uexcuss = Steady state condition, hydrostatic or steady seepage

    uexc = Excess pwp due to soil loading

    Buoyant unit weight

    = t - w for hydrostatic condition = t - w + i wi = hydraulic gradient (head diff/ distance)

    i is negative for upward artesian flow 40

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    21

    Elastic Stress Distribution with DepthQ

    QqL

    B

    1(H):2(V)zL+z

    B+z

    qo

    qz

    BLQqo

    ))(( zLzBBLqq oz

    Only can be used for stress at centre ofOnly can be used for stress at centre of loaded area

    Cannot use for combined effects of two or more loaded areas, unless they have same centres

    41

    Boussinesq Distribution (1885)Assumes: isotropic linear elastic halfspace, Poisson ratio = 0.5

    Q

    z

    For Point load Q kN

    2/522

    3

    )(2)3(zrzQqz

    Integrate for Line Load, P kN/m

    32Pr

    qz 222

    3

    )(2

    rzzPqz

    Integrate for Rectangular Area, get Fadums Influence Chart Fig.1; for Circular Area, get Foster and Alvin Chart Fig.2

    42

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    22

    Weastergaard Distribution (1938)Assumes: isotropic linear elastic halfspace, Poisson ratio = 0, rigid horizontal layers

    Q

    z

    , g y

    For Point load Q kN

    2/322 ))/(21( zrzQqz

    Differences with Boussinesq is

    rqz

    qsmall

    For wide flexible loaded areas Westergaard method is preferred

    43

    UniSettle 2.4 21 Jan 2000EX02.STL page 1

    Effective Stress Comparison, ( 4.11 , 8.11 )-----------------------------------------------------------------

    BOUSSINESQ WESTERGAARD 2:1Depth Ini. Fin. Ini. Fin. Ini. Fin.

    Stress Stress Stress Stress Stress Stress(m) (kPa) (kPa) (kPa) (kPa) (kPa) (kPa)

    -----------------------------------------------------------------

    Comparison of stresses under a 3m square footing below its

    Layer 1 Any Soil 0. kg/m^30.00 100.0 0.0 100.0 0.0 100.0 0.00.10 97.9 0.0 89.3 0.0 93.7 0.00.20 94.3 0.0 79.4 0.0 87.9 0.00.30 89.4 0.0 71.4 0.0 82.6 0.00.40 83.2 0.0 64.4 0.0 77.9 0.00.50 76.8 0.0 58.4 0.0 73.5 0.00.60 70.9 0.0 53.2 0.0 69.4 0.00.70 65.6 0.0 48.9 0.0 65.7 0.00.80 61.1 0.0 45.1 0.0 62.3 0.00.90 57.2 0.0 41.9 0.0 59.2 0.01.00 53.7 0.0 39.1 0.0 56.3 0.01 10 50 8 0 0 36 7 0 0 53 5 0 0

    q gcharacteristic point

    Characteristic point is point where vertical stress is equal for both rigid and flexible footing, this point is located at 0.37B and 0.37L from centre of rectangular footing, or 0.37R of 1.10 50.8 0.0 36.7 0.0 53.5 0.0

    1.20 48.1 0.0 34.5 0.0 51.0 0.01.30 45.8 0.0 32.5 0.0 48.7 0.01.40 43.7 0.0 30.8 0.0 46.5 0.01.50 41.7 0.0 29.2 0.0 44.4 0.01.60 40.0 0.0 27.8 0.0 42.5 0.01.70 38.3 0.0 26.4 0.0 40.7 0.01.80 36.8 0.0 25.2 0.0 39.1 0.01.90 35.4 0.0 24.1 0.0 37.5 0.02.00 34.0 0.0 23.0 0.0 36.0 0.0

    g g,circular footing

    Results show that under characteristic point 2:1 method is similar to Boussinesq result

    44

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    23

    AA

    -1.000 0.000 1.000 2.000 3.000 4.000 5.000 6.000

    Elastic Stress Bulb for Circular Footing

    BCDEFGHIJKLMNOPQRS

    2.000

    3.000

    4.000

    5.000

    [ kN/m2]

    A : -0.900

    B : -0.850

    C : -0.800

    D : -0.750

    E : -0.700

    F : -0.650

    G : -0.600

    H : -0.550

    I : -0.500

    J : -0.450

    K : -0.400

    L : -0.350

    M : -0.300

    N : -0.250

    O : -0.200

    P : -0.150

    -0.000

    1.000

    E ffective mean stressesExtrem e effec tive mean stress -882.98*10

    -3 kN/m

    2

    Q : -0.100

    R : -0.050

    S : 0.000

    T : 0.050

    45

    Elastic Settlement for Circular Flexible LoadSurface settlements is given by Terzaghi,1943 as:

    R

    q

    R

    D =

    3.),( FigseerfisI

    IEqR

    Edge settlement = 0.7 centre settlement

    Centre settlement is :

    footingFlexibleforERqz )1(2

    2

    footingRigidforERqz )1(2

    2 46

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    24

    Flexible and Rigid Footing

    -0.300 -0.200 -0.100 0.000 0.100 0.200 0.300 0.400 0.500 0.600 0.700 0.800 0.900 1.000 1.100

    Flexible Footing-0.300 -0.200 -0.100 0.000 0. 100 0.200 0.300 0.400 0.500 0.600 0.700 0.800 0.900 1.000 1.100

    Rigid Footing

    0.08 0.16 0.24 0. 32 0.40 0.48 0.56 0.64 0.72 0.80 0.88 0.96 1.04

    10.40

    10.48

    A

    A

    9.300

    9.400

    9.500

    9.600

    9.700

    9.800

    9.900

    10.000

    10.100

    10.200

    9.200

    9.300

    9.400

    9.500

    9.600

    9.700

    9.800

    9.900

    10.000

    10.100

    10.200

    0.08 0. 16 0.24 0.32 0.40 0.48 0.56 0.64 0.72 0.80 0.88 0.96 1.04

    10 40

    10.48

    AA*

    9.76

    9.84

    9.92

    10.00

    10.08

    10.16

    10.24

    10.32

    E=1000 kPa, =0, q=10 kPa, sett= 20 mm

    AA*

    9.76

    9.84

    9.92

    10.00

    10.08

    10.16

    10.24

    10.32

    10.40

    E=1000 kPa, =0, q=10 kPa, sett= 16 mm47

    Approximate Ratio at corner, centre and edge to average settlement

    Flexible Load Area RigidgFooting

    FoundationDepth

    Corner/Ave

    Edge/Ave

    Centre/Ave

    Rigid/Ave

    H/L= 0.6 0.9 1.2 0.9H/L=1 0.5 0.7 1.3 0.8

    H/L=1/4 0.4 0.7 1.3 0.8

    48

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    25

    Elastic Settlement for Other Flexible LoadCorner settlements is given by Terzaghi,1943 as:

    B

    D =

    4.)/(

    )1( 2

    FigseeLBfisI

    IE

    qB

    Points other than corner for any combination of rectangles can be obtained by superposition

    qL

    For centre of square loaded area:

    )1(12.1 2 EBqz

    49

    Superpostion Principle for Rectangles

    = + + +z

    - - +=z

    50

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    26

    Elastic Settlement for Other Flexible Load

    For Flexible Rectangular Loaded area, Corner settlement , g , ,with finite depth of elastic layer, use Steinbrenner chart

    )21()1(

    )1(

    22

    2

    FFI

    IE

    qB B

    qL

    5.

    )21()1(

    21

    22

    12

    FigingivenFandFFFI

    FiniteD

    51

    Equivalent Footings for Pile Groups SettlementsGround level

    Soft Clay

    Ground level

    L2/3L

    Equivalent FtgL

    2/3L

    Soft Clay

    Equivalent Ftg

    2

    1Homogeneous Clay

    2

    1Firm Layer

    52

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    27

    The end result of a geotechnical design analysis

    is

    Settlement

    53

    Movement, Settlement, and CreepMovement occurs as a result of an increase of stress, but the term should be reservedto deformation due to increase of total stress. Movement is the result of a transfer ofstress to the soil (the movement occurs as necessary to build up the resistance to theload), and when the involved, or influenced, soil volume successively increases as thestress increases. For example, when adding load increments to a pile or to a plate in astatic loading test (where, erroneously, the term "settlement" is often used). As a term,mo ement is sed hen the in ol ed or infl enced soil ol me increases as the loadmovement is used when the involved, or influenced, soil volume increases as the loadincreases.

    Settlement is volume reduction of the subsoil as a consequence of an increase ineffective stress. It consists of the sum of "elastic" compression and deformation due toconsolidation. The elastic compression is the compression of the soil grains (soilskeleton) and of any free gas present in the voids, The elastic compression is oftencalled "immediate settlement. It occurs quickly and is normally small (theelastic compression is not associated with expulsion of water). The deformation due toconsolidation on the other hand is volume change due to the compression of the soilconsolidation, on the other hand, is volume change due to the compression of the soilstructure associated with an expulsion of waterconsolidation. In the process, theimposed stress, initially carried by the pore water, is transferred to the soil structure.Consolidation occurs quickly in coarse-grained soils, but slowly in fine-grained soils. Asa term, settlement is used when the involved, or influenced, soil volume stays constantas the effective stress increases.

    54

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    28

    Movement, Settlement, and Creep

    Creep is compression occurring without an increase of effective stress.Creep is usually small, but may in some soils add significantly to thecompression of the soil skeleton and, thus, to the total deformation of thesoil It is then acceptable to talk in terms of creep settlement

    The term "settlement" is normally used for the deformation resulting from thecombined effect of load transfer, increase of effective stress, and creep duringlong-term conditions. It is incorrect to use the term settlement to meanmovement due to increase of load such as in a loading test.

    soil. It is then acceptable to talk in terms of creep settlement.

    55

    StrainLinear Elastic Deformation (Hookes Law)

    E'

    = induced strain in a soil layer= imposed change of effective stress in the soil layer

    E = elastic modulus of the soil layer (Youngs Modulus)

    Youngs modulus is the modulus for when lateral expansion is allowed, which may be the case for soil loaded by a small footing, but not when the load is applied over a large area. In the latter case, the lateral expansion is constrained (or confined). The constrained modulus, D, is larger than the E-modulus. The constrained modulus is also called the oedometer modulus. For ideally elastic soils, the ratio between D and E is:

    '

    )21()1()1(

    ED

    = Poissons ratio56

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    29

    Stress-Strain

    57

    Stress-strain behavior is non-linear for most soils. The non-linearity cannot be disregarded when analyzing compressible soils, such as silts and clays, that is, the elastic modulus approach is not appropriate for these soils.

    Non-linear stress-strain behavior of compressible soils, is conventionally modeled as follows.

    where = strain induced by increase of effective stress from 0 to 1

    0

    1

    0

    1

    0 ''

    lg''

    lg1

    CR

    eCc

    y 0 1Cc = compression indexe0 = void ratio0 = original (or initial) effective stress1 = final effective stressCR = Compression Ratio = (MIT)

    01 eCCR c

    58

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    30

    In overconsolidated soils (most soils are)

    )''lg

    ''

    lg(1

    1 100 p

    cp

    cr CCe

    where p = preconsolidation stressp pCcr = re-compression index

    59

    The Janbu Method

    The Janbu tangent modulus approach, proposed by Janbu (1963; 1965; 1967; 1998), and referenced by the Canadian Foundation Engineering Manual, CFEM (1985; 1992), applies the same basic principles of linear and non-linear stress-strain behavior. The method applies to all soils, clays as well as sand. By this method, the relation between stress and strain is a function of two non-dimensional parameters which are unique for a soil: a stress exponent, j, and a modulus number, m.

    Janbus general relation is

    ])'()'[(1 01 jj ])'

    ()'

    [( 01 jr

    j

    rmj

    where r is a reference stress = 100 KPa

    j > 0

    60

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    31

    The Janbu Method

    Dense Coarse-Grained Soil j = 1

    '1)''(1 01 mm

    '1)''(1

    KPa

    ksf

    Cohesive Soil j = 00

    1

    ''ln1

    m

    2)(

    2 01

    mmksf

    )''(51

    01 m KPaSandy or Silty Soils j = 0.5

    pm''(2 1 ksf

    61

    There are direct mathematical conversions

    between m and the E and Cc-e0

    For E given in units of KPa (and ksf), the relation between the modulus number and the E-modulus is

    m = E/100 (KPa)m = E/2 (ksf)

    For Cc-e0, the relation to the modulus number is

    22

    00 69.02lg10ln13.21

    10ln

    cc Ce

    Cem

    62

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    32

    Typical and Normally Conservative Virgin Modulus Numbers

    SOIL TYPE MODULUS NUMBER STRESS EXP.

    Till, very dense to dense 1,000 300 (j = 1)

    Gravel 400 40 (j = 0.5)

    Sand dense 400 250 (j = 0.5)compact 250 150 - " -loose 150 100 - " -

    Silt dense 200 80 (j = 0.5)compact 80 60 - " -loose 60 40 - " -

    Silty clay hard, stiff 60 20 (j = 0)and stiff, firm 20 10 - -

    Clayey silt soft 10 5 - -

    Soft marine claysSoft marine claysand organic clays 20 5 (j = 0)

    Peat 5 1 ( j= 0)

    For clays and silts, the recompression modulus, mr, is often five to tentimes greater than the virgin modulus, m, listed in the table

    63

    1 00

    1.20

    p'c 20

    25

    Evaluation of compressibility from oedometer results

    0.40

    0.60

    0.80

    1.00

    10 100 1 000 10 000

    Voi

    d R

    atio

    (- -

    )

    m = 12(CR = 0.18)

    0

    5

    10

    15

    10 100 1,000 10,000

    Stra

    in (

    %)

    p 10p

    Cc

    Cc = 0.37

    e0 = 1.01 p'c

    p 2.718p

    1/m

    Slope = m = 12

    10 100 1,000 10,000

    Stress (KPa) log scale Stress (KPa) log scale

    Void-Ratio vs. Stress and Strain vs. Stress Same test data

    64

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    33

    Comparison between the Cc/e0 approachand the Janbu method

    0 30

    0.35

    30

    35

    m

    0.05

    0.10

    0.15

    0.20

    0.25

    0.30

    CO

    MPR

    ESSI

    ON

    IND

    EX, C

    c Do these values indicate a

    compressible soil, a medium compressible

    soil, or a non-compressible soil?5

    10

    15

    20

    25

    30

    VIR

    GIN

    MO

    DU

    LUS

    NU

    MB

    ER, m

    Data from a 20 m thick sedimentary deposit of medium compressibility.

    0.000.40 0.60 0.80 1.00 1.20

    VOID RATIO, e0

    00.400.600.801.001.20

    VOID RATIO, e0

    65

    75

    100

    125

    150

    OR

    MA

    LIZE

    D C

    c (%

    )

    75

    100

    125

    150

    OR

    MAL

    IZED

    m (

    %)

    The Cc-e0 approach implies that the the compressibility varies by 30 %.

    However, the Janbu methods shows it to vary only by 10 %. The modulus number, m, ranges from 18 through 22; It would be unusual to find a clay with less variation

    500.40 0.60 0.80 1.00 1.20

    VOID RATIO, e0

    N 500.400.600.801.001.20

    VOID RATIO, e0

    NO

    find a clay with less variation.

    What about Immediate Settlement and Consolidation? 66

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    34

    CE 5101 - SETTLEMENTS AND 1D Compression TheorySettlements of Soils - Immediate, Delayed, and Creep Compressionp p

    Delayed Consolidation Compressionmv methode-logP methodJanbu method

    Terzaghis Theory of 1D ConsolidationTerzaghi s Theory of 1D ConsolidationEffects of Drainage and Initial Stress Distribution

    SPREADSHEET Calculations (UNISETTLE)Finite Element Analysis (PLAXIS)

    67

    Foundation Settlement Issues

    How Much settlements will occur?

    Interested in Ultimate settlements in fully drained state, as well as long-term creep settlements

    How Fast and how long will it take for most of settlements to occur?

    Involved Consolidation and SecondaryInvolved Consolidation and Secondary Compression theories to estimate rate of settlements, and

    Methods to accelerate settlements and minimise long-term settlements

    68

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    35

    Types of Ground Movements and Causes of Settlements

    Compaction - due to vibrations, pile driving, earthquake

    El ti V l t i S ttl t i OC Cl i iElastic Volumetric Settlement in OC Clay in recompression, use E and or recompression index, Cr or Immediate or Undrained Settlement - Distortion without volume change, use Eu and uMoisture changes - Expansive soils, high LL and PI, high swelling and shrinkage

    S ll P t ti l (%) 0 1(PI 10) l ( / )Swell Potential (%) = 0.1(PI-10) log (s/p)

    Effects of vegetation - related to moisture changes by root system

    Effects of GWT lowering - shrinkage ad consolidation

    69

    Types of Ground Movements and Causes of Settlements

    Effects of temperatures - Frost heaving, drying by furnace and boilers

    Effects of seepage and scouring - Erosion byEffects of seepage and scouring - Erosion by piping, scouring and wind action, mineral cement dissolved by GW eg limestone, rock salts and chalk areas

    Loss of lateral support - Footings beside unsupported excavation, movement of natural slopes and cuttings

    Effects of mining subsidence - collapse of ground cavities

    Filled ground - settlements of the fill soils, compaction, consolidation, and creep

    70

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    36

    Shrink/ swell potential is function of Clay Activity = %clay fraction/ PI

    Swell Potential (%) = 0.1(PI-10) log (s/p)

    Where s=suction before construction and p=final bearing pressure71

    1D Settlements

    Soil deformations are of two types: Distortion (change of shape 2D effects)Compression (change of volume)

    Components of Settlements:

    distortionsettlementimmediateswheressss

    i

    scit

    ,

    ncompressiosecondarysncompressiosettlementionconsolidats

    distortionsettlementimmediateswhere

    s

    c

    i

    ,

    ,

    72

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    37

    Undrained Immediate Settlements

    Distortion of clay layer:Calculate by elastic theory eg JanbuCalculate by elastic theory eg Janbu Chart

    by JanbufactorsessdimensionlIandIarealoadedflexibleforsettlementimmediateswhere

    EqBIIs

    i

    i

    )1( 210

    layerclay of ratio sPoisson' layerclay of modulus Undrained E

    B dthfootong wi on loadAverage qby JanbufactorsessdimensionlIandI 10

    73

    Immediate Settlements in Clays by Janbu

    74

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    38

    Example on Janbu Chart: Foundation 4x2m with q=150kPa, located at 1m in Clay layer 5m thick with Eu=40MN/m2. Below is second clay layer of 8m thickness and Eu=75 MN/m2.What is average settlement under foundation? Assume =0.5

    D:MN/m40Ewithlayer,clay upperConsider(1)

    9.0 0.5, 1/2D/B 2;4/2L/B Now2

    u

    0

    H

    DB mm5.35.01

    402*150*7.0*9.0s

    7.0 2,4/2L/B and 24/2H/By ,ypp( )

    21i

    1

    u

    mm3.25.0175

    2*150*85.0*9.0s

    85.0 2,4/2L/B and 612/2H/B:MN/m75E withcombined, layers two Consider (2)

    22i

    1

    2u

    mm9.15.0175

    2*150*7.0*9.0s

    7.0 2,4/2L/B and 24/2H/B:MN/m75E withlayer, upper Consider (1)

    23i

    1

    2u

    mm 3.9 1.9 -2.3 5.3sssss

    ;inciplePrionSuperposit By

    i

    3i2i1ii

    75

    1D Primary Consolidation Settlements

    Time delayed Primary Consolidation Compression:

    water

    solids

    0e

    1

    e0H

    H

    )()(

    00

    0

    volumeverticalc

    0volumevertical

    HHHse1e

    HH

    'vv P where P), vs(e methodm e

    Pe -ility compressib of coeffnav

    a1e0e

    fe

    fP0P P

    0

    v

    0v e1

    aP1

    )e(1e -change volume of coeffnm

    00

    vc

    0v00

    c

    HPe1

    a s

    HPm He1e sH

    76

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    39

    mv and Constrained Modulus D

    For wide loaded area, get 1D compression d K diti l ti d l t lunder Ko condition, elastic modulus to apply

    is called the Constrained Modulus D defined by:

    hlftC ffi ih211

    1Em1D

    v

    0.35)( ratio Poisson drained Soil elasticity of modulus drained Soil E

    changevolume oftCoefficienmwhere v

    77

    Sc by (e vs logP) MethodNormally Consolidated Clays - non-linear stress strain for soil, but linear in logP Pge

    0e

    fe

    indexncompressioCc

    0

    fc0fc P

    PlogCPlogPlogCe

    0

    f

    0

    c0c P

    Plog

    e1CHHs

    fP0P Plog

    0

    cc e1

    CC CRRatio, nCompressio

    78

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    40

    Sc by (e vs logP) MethodOver-Consolidated Clays (Pf < Pc), Preconsolidation Pressure

    e

    0efe

    fP0P Plog

    indexncompressioCc

    0

    fr0fr P

    PlogCPlogPlogCe

    0

    f

    0

    r0c

    ssettlementsmallPP

    loge1

    CHHs cP

    indexswellingCindexionrecompressC

    s

    r

    f0 Plog

    cr C than smaller times10 to5 is C asssettlementsmall

    0

    rr e1

    CC RR, Ratio ncompressioRe

    c

    79

    Sc by (e vs logP) MethodOver-Consolidated Clays (Pf > Pc), Preconsolidation Pressure

    Pe0ece

    fP0P Plog

    cC

    0

    cr0cr1 P

    PlogCPlogPlogCe

    e1eeHHs 210c

    cP

    sr CorC

    fe

    c

    fccfc2 P

    PlogCPlogPlogCe

    f0 Plog

    ssettlementlarge mean willThisPP

    logCPPlogC

    e1H

    e1

    c

    fc

    0

    cr

    0

    0

    0

    c

    80

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    41

    Sc by Janbu Tangent Modulus MethodCanadian Foundation Manual 1985

    Janbu (1963, 1965,1967,1998); For Cohesionless Soils; j>0

    Th i d i P U iS ttl (b UNISOFT C d )Theory is used in Program UniSettle (by UNISOFT, Canada)

    P stresseffective vertical initial

    stresseffective vertical inchange by induced strain vertical where

    mj1 get to Integrate m'M

    0,

    0

    v

    j

    ,

    r

    ,

    0

    j

    ,

    r

    ,

    fv

    j1

    'r

    ''rt

    kPa100 stresseffective verticalReference

    test field or lab from obtained number, modulus Janbu mexponent stress Janbuj

    P stresseffective vertical final

    ,

    r

    f,

    f

    0

    81

    Cohesionless Sands and Silts; j=0.5Normally Consolidated Cohesionless Soils

    ,0,fv

    ,

    r

    5m1

    kPa100 0.5j SOIL TYPE mSAND DENSE 400-250

    MEDIUM 250-150

    LOOSE 150-100

    SILT DENSE 200-80

    MEDIUM 80-60

    LOOSE 60-40

    82

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    42

    Cohesionless Sands and Silts; j=0.5Over-Consolidated Cohesionless Soils

    kPa100 'P'f

    ,

    r0.5j; for CASE

    ,

    0

    ,

    fr

    v

    ,

    r

    'p

    'f

    5m1

    kPa,100 ; for CASE ,0.5j

    m than larger times10 to5 usually is m number, modulus OC

    kPa inpressure dationpreconsoli

    where5m

    15m

    1

    f

    r

    ,

    P

    ,

    P

    ,

    f

    ,

    0

    ,

    Pr

    v

    r

    83

    Cohesive Soils; j=0

    Normally Consolidated Clays

    , kPa1000j SOIL TYPE mSILTY HARD, 60-20

    c

    0

    c

    0

    ,

    0

    ,

    f

    0

    c,

    0

    ,

    fv

    r

    Ce13.2

    Ce110lnm

    loge1

    Clnm1

    kPa100 0j

    SILTY

    CLAYSHARD,STIFF

    60 20

    AND STIFF,FIRM

    20-10

    CLAYEYSILT

    FIRM TOSOFT

    10-5

    SOFTMARINEC S

    20-5

    CLAYSORGANICCLAYS

    10-3

    PEAT 5-1

    84

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    43

    Over-consolidated Clays; j=0Over- Consolidated Clays

    ,

    P

    ,

    f

    0

    c,

    0

    ,

    P

    0

    rv

    ,

    P

    ,

    f,

    0

    ,

    P

    rv

    loge1

    Cloge1

    C

    lnm1ln

    m1

    r

    0

    r

    0r

    c

    0

    c

    0

    Ce13.2

    Ce110lnmand

    Ce13.2

    Ce110lnm

    85

    Linear Elastic Soil; j=1

    j,j,

    Em100E,therefore

    m1001

    mj1 ,

    0

    ,

    f,

    r

    ,

    0,

    r

    fv

    100Em

    86

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    44

    Janbu compared to e-logP

    87

    Oedometer Results in linear scale by Janbu

    88

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    45

    Calculation of Settlement

    Determine soil profile to get initial effective stresses

    Determine soil compressibility parameters, e-logP, Cc, Cr and Pc OR Janbu modulus number, m and mr

    Determine final effective stresses due to imposed loads, excavations, fills, GWT changes etc

    Divide each soil layer into sublayers, calculate strain caused by change from initial to final effective stresses in each sublayer

    Calculate the settlement for each sublayer and the accumulated settlement

    89

    UNISETTLE Calculation of Settlement

    90

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    46

    Hand Calculation

    91

    UniSettle Input

    92

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    47

    InputLoading and Excavation

    93

    Results

    94

  • CE5101 Consolidation and SeepageLecture 5

    Prof Harry TanSEP 2011

    48

    Settlements Distribution

    95

    Alternative Conditions

    96