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Kungfu Math

Name:________________________ Class:_______ Date:________

Scroll: Measurement >> Area & Perimeter of Composite Figure >> ps (2904)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

1) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

30 cm

Answer:_______________ cm

http://www.kungfu-math.com/worksheets/grade6-measurement.html[26/1/2015 6:10:01 PM]

Answer:_______________ cm2

2) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

36 cm

Answer:_______________ cm

Answer:_______________ cm2

3) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

http://www.kungfu-math.com/worksheets/grade6-measurement.html[26/1/2015 6:10:01 PM]

16 cm

Answer:_______________ cm

Answer:_______________ cm2

4) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

34 cm

Answer:_______________ cm

http://www.kungfu-math.com/worksheets/grade6-measurement.html[26/1/2015 6:10:01 PM]

Answer:_______________ cm2

5) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

26 cm

Answer:_______________ cm

Answer:_______________ cm2

6) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

http://www.kungfu-math.com/worksheets/grade6-measurement.html[26/1/2015 6:10:01 PM]

22 cm

Answer:_______________ cm

Answer:_______________ cm2

7) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

32 cm

Answer:_______________ cm

http://www.kungfu-math.com/worksheets/grade6-measurement.html[26/1/2015 6:10:01 PM]

Answer:_______________ cm2

8) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

28 cm

Answer:_______________ cm

Answer:_______________ cm2

9) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

http://www.kungfu-math.com/worksheets/grade6-measurement.html[26/1/2015 6:10:01 PM]

24 cm

Answer:_______________ cm

Answer:_______________ cm2

10) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

18 cm

Answer:_______________ cm

http://www.kungfu-math.com/worksheets/grade6-measurement.html[26/1/2015 6:10:01 PM]

Answer:_______________ cm2

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1) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

30 cm

Answer : 124 cm

Answer : 353 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 30 cm

= 60.000 cm

Step 2: Circumference of quarter circle → x π x 60.000 cm

= 47.13 cm

Step 3: Circumference of semi circle → x π x 30 cm

= 47.130 cm

Step 4: Perimeter of shaded part → 47.13 cm + 47.130 cm + 30 cm

= 124.260 cm

≈ 124 cm

Step 5: Area of quarter cicle → x π x 30 cm x 30 cm

= 706.950 cm 2

Step 6 : Radius of semi circle → 30 cm ÷ 2

= 15 cm

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Step 7: Area of semi circle → x π x 15 cm x 15 cm

= 353.475 cm 2

Step 8: Area of shaded part → 706.950 cm2 - 353.475 cm 2

= 353.475 cm 2

≈ 353 cm2

2) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

36 cm

Answer : 149 cm

Answer : 509 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 36 cm

= 72.000 cm

Step 2: Circumference of quarter circle → x π x 72.000 cm

= 56.556 cm

Step 3: Circumference of semi circle → x π x 36 cm

= 56.556 cm

Step 4: Perimeter of shaded part → 56.556 cm + 56.556 cm + 36 cm

= 149.112 cm

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≈ 149 cm

Step 5: Area of quarter cicle → x π x 36 cm x 36 cm

= 1018.008 cm 2

Step 6 : Radius of semi circle → 36 cm ÷ 2

= 18 cm

Step 7: Area of semi circle → x π x 18 cm x 18 cm

= 509.004 cm 2

Step 8: Area of shaded part → 1018.008 cm2 - 509.004 cm 2

= 509.004 cm 2

≈ 509 cm2

3) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

16 cm

Answer : 66 cm

Answer : 101 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 16 cm

= 32.000 cm

Step 2: Circumference of quarter circle → x x 32.000 cm

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π

= 25.136 cm

Step 3: Circumference of semi circle → x π x 16 cm

= 25.136 cm

Step 4: Perimeter of shaded part → 25.136 cm + 25.136 cm + 16 cm

= 66.272 cm

≈ 66 cm

Step 5: Area of quarter cicle → x π x 16 cm x 16 cm

= 201.088 cm 2

Step 6 : Radius of semi circle → 16 cm ÷ 2

= 8 cm

Step 7: Area of semi circle → x π x 8 cm x 8 cm

= 100.544 cm 2

Step 8: Area of shaded part → 201.088 cm2 - 100.544 cm 2

= 100.544 cm 2

≈ 101 cm2

4) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

34 cm

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Answer : 141 cm

Answer : 454 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 34 cm

= 68.000 cm

Step 2: Circumference of quarter circle → x π x 68.000 cm

= 53.414 cm

Step 3: Circumference of semi circle → x π x 34 cm

= 53.414 cm

Step 4: Perimeter of shaded part → 53.414 cm + 53.414 cm + 34 cm

= 140.828 cm

≈ 141 cm

Step 5: Area of quarter cicle → x π x 34 cm x 34 cm

= 908.038 cm 2

Step 6 : Radius of semi circle → 34 cm ÷ 2

= 17 cm

Step 7: Area of semi circle → x π x 17 cm x 17 cm

= 454.019 cm 2

Step 8: Area of shaded part → 908.038 cm2 - 454.019 cm 2

= 454.019 cm 2

≈ 454 cm2

5) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

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26 cm

Answer : 108 cm

Answer : 265 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 26 cm

= 52.000 cm

Step 2: Circumference of quarter circle → x π x 52.000 cm

= 40.846 cm

Step 3: Circumference of semi circle → x π x 26 cm

= 40.846 cm

Step 4: Perimeter of shaded part → 40.846 cm + 40.846 cm + 26 cm

= 107.692 cm

≈ 108 cm

Step 5: Area of quarter cicle → x π x 26 cm x 26 cm

= 530.998 cm 2

Step 6 : Radius of semi circle → 26 cm ÷ 2

= 13 cm

Step 7: Area of semi circle → x π x 13 cm x 13 cm

= 265.499 cm 2

Step 8: Area of shaded part → 530.998 cm2 - 265.499 cm 2

= 265.499 cm 2

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≈ 265 cm

6) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

22 cm

Answer : 91 cm

Answer : 190 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 22 cm

= 44.000 cm

Step 2: Circumference of quarter circle → x π x 44.000 cm

= 34.562 cm

Step 3: Circumference of semi circle → x π x 22 cm

= 34.562 cm

Step 4: Perimeter of shaded part → 34.562 cm + 34.562 cm + 22 cm

= 91.124 cm

≈ 91 cm

Step 5: Area of quarter cicle → x π x 22 cm x 22 cm

= 380.182 cm 2

Step 6 : Radius of semi circle → 22 cm ÷ 2

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= 11 cm

Step 7: Area of semi circle → x π x 11 cm x 11 cm

= 190.091 cm 2

Step 8: Area of shaded part → 380.182 cm2 - 190.091 cm 2

= 190.091 cm 2

≈ 190 cm2

7) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

32 cm

Answer : 133 cm

Answer : 402 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 32 cm

= 64.000 cm

Step 2: Circumference of quarter circle → x π x 64.000 cm

= 50.272 cm

Step 3: Circumference of semi circle → x π x 32 cm

= 50.272 cm

Step 4: Perimeter of shaded part → 50.272 cm + 50.272 cm + 32 cm

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= 132.544 cm

≈ 133 cm

Step 5: Area of quarter cicle → x π x 32 cm x 32 cm

= 804.352 cm 2

Step 6 : Radius of semi circle → 32 cm ÷ 2

= 16 cm

Step 7: Area of semi circle → x π x 16 cm x 16 cm

= 402.176 cm 2

Step 8: Area of shaded part → 804.352 cm2 - 402.176 cm 2

= 402.176 cm 2

≈ 402 cm2

8) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

28 cm

Answer : 116 cm

Answer : 308 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 28 cm

= 56.000 cm

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Step 2: Circumference of quarter circle → x π x 56.000 cm

= 43.988 cm

Step 3: Circumference of semi circle → x π x 28 cm

= 43.988 cm

Step 4: Perimeter of shaded part → 43.988 cm + 43.988 cm + 28 cm

= 115.976 cm

≈ 116 cm

Step 5: Area of quarter cicle → x π x 28 cm x 28 cm

= 615.832 cm 2

Step 6 : Radius of semi circle → 28 cm ÷ 2

= 14 cm

Step 7: Area of semi circle → x π x 14 cm x 14 cm

= 307.916 cm 2

Step 8: Area of shaded part → 615.832 cm2 - 307.916 cm 2

= 307.916 cm 2

≈ 308 cm2

9) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

24 cm

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Answer : 99 cm

Answer : 226 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 24 cm

= 48.000 cm

Step 2: Circumference of quarter circle → x π x 48.000 cm

= 37.704 cm

Step 3: Circumference of semi circle → x π x 24 cm

= 37.704 cm

Step 4: Perimeter of shaded part → 37.704 cm + 37.704 cm + 24 cm

= 99.408 cm

≈ 99 cm

Step 5: Area of quarter cicle → x π x 24 cm x 24 cm

= 452.448 cm 2

Step 6 : Radius of semi circle → 24 cm ÷ 2

= 12 cm

Step 7: Area of semi circle → x π x 12 cm x 12 cm

= 226.224 cm 2

Step 8: Area of shaded part → 452.448 cm2 - 226.224 cm 2

= 226.224 cm 2

≈ 226 cm2

10) The figure below is made up of a semi-circle and a quadrant.

Find the perimeter and area of the shaded part, rounding your answers to the nearest whole number.

π = 3.142

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18 cm

Answer : 75 cm

Answer : 127 cm 2

SOLUTION 1 :

Step 1: Diameter of quarter circle → 2 x 18 cm

= 36.000 cm

Step 2: Circumference of quarter circle → x π x 36.000 cm

= 28.278 cm

Step 3: Circumference of semi circle → x π x 18 cm

= 28.278 cm

Step 4: Perimeter of shaded part → 28.278 cm + 28.278 cm + 18 cm

= 74.556 cm

≈ 75 cm

Step 5: Area of quarter cicle → x π x 18 cm x 18 cm

= 254.502 cm 2

Step 6 : Radius of semi circle → 18 cm ÷ 2

= 9 cm

Step 7: Area of semi circle → x π x 9 cm x 9 cm

= 127.251 cm 2

Step 8: Area of shaded part → 254.502 cm2 - 127.251 cm 2

= 127.251 cm 2

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≈ 127 cm