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Slab Shear Capacity Page 1 This program calculates Shear Capacity of a beam without shear reo. 1 1 1 b 1000 d 400 Ast 1000mm2 This program calculates Shear Capacity f'c 20MPa in accordance with Equation 19.9 Vuc 147.4kN Vuc 304.1kN 0.7Vuc 103.2kN 0.7Vuc 212.9kN b1 b2 b3

Singly Reinforced Concrete Beams AS3600

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Slab Shear CapacityThis program calculates Shear Capacityof a beam without shear reo.b11b21b31b1000d400Ast1000mm2This program calculates Shear Capacityf'c20MPain accordance with Equation 19.9Vuc147.4kNVuc304.1kN0.7Vuc103.2kN0.7Vuc212.9kN

Short ColumnsThis program calculates the axial load capacity of a short columnb350D720Ag252000mm2Ast8000mm2okfsy400MPaf'c32MPa

Nuo10054.4kNPhi0.6Phi Nuo6032.6kNBearing Stress24MPa

SymbolsSymbolSymbolaaAAbbBBccCCddDDeeEEffFFggGGhhHHIIIIjjJJkkKKllLLmmMMnnNNooOOppPPqqQQrrRRssSSttTTuuUUvvVVwwWWxxXXyyYYzzZZ

Deflections

JOB No:3312656Level 8, 68 Grenfell Street ADELAIDE SA 5000DATE:8/5/10TELEPHONE (08) 8235 6600FACSIMILE (08) 8235 6694DESIGN:GABEMAIL [email protected]:Beam Deflections of reinforced concrete beamsShort term loadG45.0kN/mys0.7Q15.0kN/mG+ysQ55.5kN/mSpan Lef15.0mMo1560.9kNmML234.0kNmMR1171.0kNmMM858.4kNm

Phi MuoThis spreadsheet calculates the moment capacity of a singly reinforced concrete beam to AS3600-2001 amendments 1 & 2The cracking moment Mcr and Ieff, based on the Branson Formula, are calculated in accordance with AS3600

Enter the following data

Ast =2198mm2M*=290.0kNmMs =200.0kNm

fsy =500MPafb =5.41MPaERROR:#NAME?Section Cracked

f'c =40MPaf'cf =
GHD: Characteristic flexural tensile strengthClause 6.1.1.2(a)3.79MPaERROR:#NAME?

f'cm =46.00MPaERROR:#NAME?

D =430mmfcs =
GHD: max shrinkage induced tensile stress Clause 8.5.3.10.70MPaERROR:#NAME?

b =1200mmEc =34290MPaecs =0.0006Es =200000MPaCover =30mmn =5.83ERROR:#NAME?

Lig dia =12mmIg =7.95E+09mm4ERROR:#NAME?

bd =20mmMcr =114.4kNmERROR:#NAME?

d =378mmERROR:#NAME?

g =0.766Z =3.70E+07mm3ERROR:#NAME?

ku =0.0930ERROR:#NAME?ku < 0.4 ie section under-reinforced OK

dn =35.2mmERROR:#NAME?

pmax =0.0208ERROR:#NAME?pmax when ku=0.4

p actual =0.0048pmin slabs supported by columns 9.1.1(a) 0.0025pmin slabs supported by beams/walls 9.1.1(b) 0.002pmin beams 8.1.4.10.0022ERROR:#NAME?

f Muo =320.5kNmERROR:#NAME?> M* OK

Muo =400.6kNmMuo,min =
GHD: Clause 8.1.4.1 AS3600168.4kNmERROR:#NAME?OKa=0.5dn600Calculates dn by equating first moments of the compressive b=nAst12820.1601299671and tensile areas about the neutral axisc=-nAstd-4846020.529127550.5bdn2=nAst(d-dn) or 0.5bdn^2+nAstd-nAstd=0dn =79.8mmsolve quadratic for dnIcr =1.34E+09mm4ERROR:#NAME?Ief =2.58E+09mm4ERROR:#NAME?Ie,max =4.77E+09mm4ERROR:#NAME?Note Ief>Ie,max Use Ie,maxIef, design2.58E+09mm4

Sheet1

~#temp