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Signal Proces sing Toolbox Signal Processing Toolbox Examples
Measuring Signal Similarities
This example s hows how to meas ure signal sim ilarities. It will help you answer questions s uch as: How do I compare signals with
different lengths or different sampling rates? How do I find if there is a signal or just noise in a measurement? Are two signals related?
How to meas ure a delay between two signals (and how do I align them )? How do I compare the frequency content of two signals?
Similarities can also be found in different sections of a signal to determine if a signal is periodic.
Comparing Signals w ith Different Sampling Rates
Consider a database of audio signals and a pattern matching application where you need to identify a song as it is playing. Data is
commonly stored at a low sampling rate to occupy less memory.
% Load data
load relatedsig.mat;
figure
ax(1) = subplot(311);
plot((0:numel(T1)-1)/Fs1,T1,'k'); ylabel('Template 1'); grid on
ax(2) = subplot(312);
plot((0:numel(T2)-1)/Fs2,T2,'r'); ylabel('Template 2'); grid on
ax(3) = subplot(313);
plot((0:numel(S)-1)/Fs,S,'b'); ylabel('Signal'); grid on
xlabel('Time (secs)');
linkaxes(ax(1:3),'x')
axis([0 1.61 -4 4])
The first and the second subplot show the template signals from the database. The third subplot shows the signal which we want to
search for in our databas e. Just by looking at the time se ries, the signal does not seem to m atch to any of the two templates . A closer
inspection reveals that the signals actually have different lengths and sampling rates.
[Fs1 Fs2 Fs]
ans =
4096 4096 8192
Different lengths prevent you from calculating the d ifference between two signals but this can easi ly be remedied by extracting the comm on
part of signals . Furthermore, it is not always necess ary to equalize lengths. Cross-correlation can be pe rformed between signals wi th
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different lengths, but it is essential to ensure that they have identical sampling rates. The safest way to do this is to resample the signal
with a lower sampling rate. The resamplefunction applies an anti-aliasing(low-pass) FIR filter to the signal during the resampling
process.
[P1,Q1] = rat(Fs/Fs1); % Rational fraction approximation
[P2,Q2] = rat(Fs/Fs2); % Rational fraction approximation
T1 = resample(T1,P1,Q1); % Change sampling rate by rational factor
T2 = resample(T2,P2,Q2); % Change sampling rate by rational factor
Finding a Signal in a Measurement
We can now cross-correlate signal S to templates T1 and T2 with the xcorrfunction to determine if there is a match.
[C1,lag1] = xcorr(T1,S);
[C2,lag2] = xcorr(T2,S);
figure
ax(1) = subplot(211);
plot(lag1/Fs,C1,'k'); ylabel('Amplitude'); grid on
title('Cross-correlation between Template 1 and Signal')
ax(2) = subplot(212);
plot(lag2/Fs,C2,'r'); ylabel('Amplitude'); grid on
title('Cross-correlation between Template 2 and Signal')
xlabel('Time(secs)');
axis(ax(1:2),[-1.5 1.5 -700 700 ])
The first subplot indicates that the signal and template 1 are less correlated while the high peak in the second subplot indicates that signal
is present in the second template.
[~,I] = max(abs(C2));
timeDiff = lag2(I)/Fs
timeDiff =
0.0609
The peak of the cross correlation implies that the signal is present in template T2 starting after 61 ms.
Measuring Delay Between Signals and Aligning Them
Consider a situation where you are collecting data from different sensors, recording vibrations caused by cars on both sides of a bridge.
When you analyze the signa ls, you may need to align them . Assume you have 3 sensors working at same s ampling rates and they are
measuring s ignals caused by the sam e event.
figure,
ax(1) = subplot(311); plot(s1,'b'); ylabel('s1'); grid on
ax(2) = subplot(312); plot(s2,'k'); ylabel('s2'); grid on
ax(3) = subplot(313); plot(s3,'r'); ylabel('s3'); grid on
xlabel('Samples')
linkaxes(ax,'xy')
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The maximum value of the cross-correlations between s1 and s2 and s1 and s3 indicate time leads /lags.
[C21,lag1] = xcorr(s2,s1);
[C31,lag2] = xcorr(s3,s1);
figure
subplot(211); plot(lag1,C21/max(C21)); ylabel('C21');grid on
title('Cross-Correlations')
subplot(212); plot(lag2,C31/max(C31)); ylabel('C31');grid on
xlabel('Samples')
[~,I1] = max(abs(C21)); % Find the index of the highest peak
[~,I2] = max(abs(C31)); % Find the index of the highest peak
t21 = lag1(I1) % Time difference between the signals s2,s1
t31 = lag2(I2) % Time difference between the signals s3,s1
t21 =
-350
t31 =
150
t21 indicates that s2 lags s1 by 350 samples, and t31 indicates that s3 leads s1 by 150 samples. This information can now used to align
the 3 signals.
s2 = [zeros(abs(t21),1);s2];
s3 = s3(t31:end);
figure
ax(1) = subplot(311); plot(s1); grid on; title('s1'); axis tight
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ax(2) = subplot(312); plot(s2); grid on; title('s2'); axis tight
ax(3) = subplot(313); plot(s3); grid on; title('s3'); axis tight
linkaxes(ax,'xy')
Comparing the Frequency Content of Signals
A power spectrum disp lays the power pres ent in each frequency. Spectral coherence identi fies frequency-dom ain corre lation between
signals. Coherence values tending towards 0 indicate that the corresponding frequency components are uncorrelated while values
tending towards 1 i ndicate that the corresponding frequency componen ts are correlated. Consider two signals and their respective power
spectra.
Fs = FsSig; % Sampling Rate
[P1,f1] = periodogram(sig1,[],[],Fs,'power');
[P2,f2] = periodogram(sig2,[],[],Fs,'power');
figure
t = (0:numel(sig1)-1)/Fs;
subplot(221); plot(t,sig1,'k'); ylabel('s1');grid on
title('Time Series')
subplot(223); plot(t,sig2); ylabel('s2');grid on
xlabel('Time (secs)')
subplot(222); plot(f1,P1,'k'); ylabel('P1'); grid on; axis tight
title('Power Spectrum')subplot(224); plot(f2,P2); ylabel('P2'); grid on; axis tight
xlabel('Frequency (Hz)')
The mscoherefunction calculates the spectral coherence between the two signals . It confirms that sig1 and sig2 have two correlated
components around 35 Hz and 165 Hz. In frequencies where spectral coherence is high, the relative phas e between the correlated
components can be es timated with the cross spectrum phas e.
[Cxy,f] = mscohere(sig1,sig2,[],[],[],Fs);
Pxy = cpsd(sig1,sig2,[],[],[],Fs);
phase = -angle(Pxy)/pi*180;
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[pks,locs] = findpeaks(Cxy,'MinPeakHeight',0.75);
figure
subplot(211);
plot(f,Cxy); title('Coherence Estimate');grid on;
set(gca,'xtick',f(locs),'ytick',.75);
axis([0 200 0 1])
subplot(212);
plot(f,phase); title('Cross Spectrum Phase (deg)');grid on;
set(gca,'xtick',f(locs),'ytick',round(phase(locs)));
xlabel('Frequency (Hz)');
axis([0 200 -180 180])
The phase lag between the 35 Hz components is close to -90 degrees, and the phase lag between the 165 Hz components is close to -60
degrees.
Finding Periodicities in a Signal
Consider a set of temperature measurements in an office building during the winter season. Measurements were taken every 30 minutes
for about 16.5 weeks.
load officetemp.mat % Load Temperature Data
Fs = 1/(60*30); % Sample rate is 1 sample every 30 minutes
days = (0:length(temp)-1)/(Fs*60*60*24);
figure
plot(days,temp)
title('Temperature Data')
xlabel('Time (days)'); ylabel('Temperature (Fahrenheit)')
grid on
With the temperatures in the low 70s , you need to remove the mean to analyze sm all fluctuations in the signal. The xcovfunction removes
the mean of the signal before computing the cross -correlation. It returns the cross-covariance. Limit the maximum lag to 50% of the signal
to get a good estim ate of the cross -covariance.
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maxlags = numel(temp)*0.5;
[xc,lag] = xcov(temp,maxlags);
[~,df] = findpeaks(xc,'MinPeakDistance',5*2*24);
[~,mf] = findpeaks(xc);
figure
plot(lag/(2*24),xc,'k',...
lag(df)/(2*24),xc(df),'kv','MarkerFaceColor','r')
grid on
set(gca,'Xlim',[-15 15])
xlabel('Time (days)')
title('Auto-covariance')
Observe dominant and minor fluctuations i n the auto-covariance. Dominant and minor peaks appear equidistant. To verify if they are,
compute and plot the difference between the locations of subsequent peaks.
cycle1 = diff(df)/(2*24);
cycle2 = diff(mf)/(2*24);
subplot(211); plot(cycle1); ylabel('Days'); grid on
title('Dominant peak distance')
subplot(212); plot(cycle2,'r'); ylabel('Days'); grid on
title('Minor peak distance')
mean(cycle1)
mean(cycle2)
ans =
7
ans =
1.0000
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The minor peaks indicate 7 cycle/week and the dominant peaks indicate 1 cycles per week. This m akes s ense gi ven that the data comes
from a tem perature-controlled building on a 7 day calendar. The first 7-day cycle indicates that there is a weekly cyclic behavior of the
building temperature where temperatures l ower during the weekends and go back to normal during the week days. The 1-day cycle
behavior indicates that there is also a daily cyclic behavior - temperatures l ower during the night and increase during the day.
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