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STEADY STATE AC CIRCUIT ANALYSISSTEADY STATE AC CIRCUIT ANALYSIS
Previously we have analyzed circuits with time-independent sources – voltage and current that do not change with time
DC circuit analysis
x(t) = x(t +nT), where n = 1,2 3, … and T is the period of the signal
Introduction
In this section we will analyze circuits containing time-dependent sources – voltage and current vary with time
One of the important classes of time-dependent signal is the periodic signals
Introduction
Typical periodic signals normally found in electrical engineering:
t
tt
Sawtooth wave Square wave
Triangle wavepulse wave
t
Introduction
In SEE 1003 we will deal with one of the most important periodic signal of all :- sinusoidal signals
Signals that has the form of sine or cosine function
t
Introduction
In SEE 1003 we will deal with one of the most important periodic signal of all :- sinusoidal signals
Circuit containing sources with sinusoidal signals (sinusoidal sources) is called an AC circuit. Our analysis will be restricted to the steady state behavior of AC circuit.
Signals that has the form of sine or cosine function
Why do we need to study sinusoidal AC circuit ?Why do we need to study sinusoidal AC circuit ?
• Dominant waveform in the electric power industries worldwide – household and industrial appliations
• ALL periodic waveforms (e.g. square, triangular, sawtooth, etc) can be represented by sinusoids
• You want to pass SEE1003 !
Sinusoidal waveformSinusoidal waveform
Let a sinusoidal signal of a voltage is given by: v(t) = Vm sin (t)
2 3 4 t
v(t)
Vm
– the angular frequency (radian/second)
t – the argument of the sine function
Vm – the amplitude or maximum value
Sinusoidal waveformSinusoidal waveform
Let a sinusoidal signal of a voltage is given by: v(t) = Vm sin (t)
T/2 T (3/2)T 2T t
v(t)
Vm
The voltage can also be written as function of time: v(t) = Vm sin (t)
Sinusoidal waveformSinusoidal waveform
Let a sinusoidal signal of a voltage is given by: v(t) = Vm sin (t)
T/2 T (3/2)T 2T t
v(t)
Vm
The voltage can also be written as function of time: v(t) = Vm sin (t)
• In T seconds, the voltage goes through 1 cycle
• In 1 second there are 1/T cycles of waveform
• The number of cycles per second is the frequency f
T
1f
The unit for f is Hertz
T is known as the period of the waveform
Sinusoidal waveformSinusoidal waveform
A more general expression of a sinusoidal signal is v1(t) = Vm sin (t + )
is called the phase angle, normally written in degrees
t
v(t)
Vm
v2(t) = Vm sin (t - )v1(t) = Vm sin (t + )
Let a second voltage waveform is given by: v2(t) = Vm sin (t - )
Sinusoidal waveformSinusoidal waveform
t
v(t)
Vm
v2(t) = Vm sin (t - )v1(t) = Vm sin (t + )
Sinusoidal waveformSinusoidal waveform
t
v(t)
Vm
v2(t) = Vm sin (t - )v1(t) = Vm sin (t + )
v1 is said to be leadingleading v2 by (-) or ( + )
v2 is said to be lagginglagging v1 by (-) or ( + )
alternatively,
v1 and v2 are said to be out of phaseout of phase
Sinusoidal waveformSinusoidal waveform
t
v(t)
Vm
-Vm sin (t) Vm sin (t)
Some important relationships in sinusoidals
Sinusoidal waveformSinusoidal waveform
t
v(t)
Vm
-Vm sin (t) Vm sin (t)
Some important relationships in sinusoidals
180180oo
Sinusoidal waveformSinusoidal waveform
t
v(t)
-Vm sin (t)
Some important relationships in sinusoidals
Therefore, VVmmsin (sin (t t 180 180oo) = -V) = -Vmmsin (sin (t )t )
180180oo
Sinusoidal waveformSinusoidal waveform
Some important relationships in sinusoidals
Vmsin (t) = Vmsin (t 360o)
Therefore, Vmsin (t + ) = Vmsin (t + 360o)
VVmmsin (sin (t + t + )) = V= Vmmsin (sin (t t (360 (360o o ))))
e.g., Vmsin (t + 250o) = Vmsin (t (360o 250o))
= Vm sin (t 110o)
t
v(t)
Vm
250o 110o
Sinusoidal waveformSinusoidal waveform
Some important relationships in sinusoidals
It is easier to compare two sinusoidal signals if:
• Both are expressed sine or cosine
• Both are written with positive amplitudes
• Both have the same frequency
Sinusoidal waveformSinusoidal waveform
Average and effective value of a sinusoidal waveform
An average value a periodic waveform is defined as:
Tt
tave dt)t(x
T
1X
e.g. for a sinusoidal voltage,
2
mave )t(d)tsin(V2
1V
0Vave
Sinusoidal waveformSinusoidal waveform
Average and effective value of a sinusoidal waveform
An effective value or Root-Mean-Square (RMS) a periodic current (or voltage) is defined as:
The value of the DC current (or voltage) which, flowing through a R-ohm resistor delivers the same average power as does the periodic current (or voltage)
Ieffec
RVdc
Rv(t)
i(t)Average power:(absorbed)
dtRiT
1P
T
0
2
RIP 2effecAverage power:
(absorbed)
Power to be equal:
dtRiT
1RI
T
0
22effec
dtiT
1I
T
0
2effec
Sinusoidal waveformSinusoidal waveform
Average and effective value of a sinusoidal waveform
For a sinusoidal wave, RMS value is :
2
VV m
rms or2
II mrms
PhasorsPhasors
A phasorphasor: A complex number used to represent a sinusoidal waveform. It contain the information about the amplitude and phase angle of the sinusoid.
Why used phasors ?
Analysis of AC circuit will be much more easier using phasors
In steady state condition, the sinusoidal voltage or current will have the same frequency. The differences between sinusoidal waveforms are only in the magnitudes and phase angles
PhasorsPhasors
How do we transform sinusoidal waveforms to phasors ??
Phasor is rooted in Euler’s identity:
sinjcose j
jecos cos is the real part of je
jesin sin is the imaginary part of je
Real Imaginary
Supposed v(t) = Vm cos (t + )
This can be written as )t(jm eV v(t) =
PhasorsPhasors
How do we transform sinusoidal waveforms to phasors ??
)t(jm eV v(t) =
PhasorsPhasors
How do we transform sinusoidal waveforms to phasors ??
)t(jm eV v(t) =
)t(jmeV =
v(t) = jjm eeV
jjm eeV=
jmeV is the phasor transform of v(t)
v(t) = Vmcos (t +) phasor transform jmeVV
PhasorsPhasors
jmeVV
PhasorsPhasors
jmeVV
omV V
Polar forms
sinjVcosV mmV Rectangular forms
We will use these notations
va(t) = Vmcos (t -)o
mV aV
Some examples ….
i(t) = Imcos (t +)o
mI I
vx(t) = Vmsin (t +) vx(t) = Vmcos (t + - 90o) )90(V oom xV
PhasorsPhasors
jmeVV
omV V
Polar forms
sinjVcosV mmV Rectangular forms
We will use these notations
Phasors can be graphically represented using Phasor Diagrams
omV V
mV
o
Im
Re
PhasorsPhasors
jmeVV
omV V
Polar forms
sinjVcosV mmV Rectangular forms
We will use these notations
Phasors can be graphically represented using Phasor Diagrams
omV V
cosVm
o
sinVm
Im
Re
PhasorsPhasors
jmeVV
omV V
Polar forms
sinjVcosV mmV Rectangular forms
We will use these notations
Phasors can be graphically represented using Phasor Diagrams
Draw the phasor diagram for the following phasors:
o125201Vo100402V 5j5 3V
PhasorsPhasors
To summarize …
• va(t) = Vmcos (t -) phasor transform omV aV sinjVcosV mm
• It is also possible to do the inverse phasor transform:
omV V inverse phasor transform v(t) = Vmcos (t + )
• If v1(t), v2(t), v3(t), v4(t), ….vn(t) are sinusoidals of the same frequency and
V = V1 + V2 + V3 +V4 + …+Vn
v(t) = v1(t) + v2(t) + v3(t) + v4(t) + ….+vn(t) , in phasors this can be written as:
Phasor Relationships for R, L and CPhasor Relationships for R, L and C
The relationships between V and I for R, L and C are needed in order for us to do the AC circuit analysis
+ vR
iR
RiRRv
If iR = Im cos (t + i)
vR = R (Im cos (t + i))
RR
IR
+ VR
iR I I
vmiR VRI V
vvRR and i and iRR are in phase ! are in phase !
Phasor Relationships for R, L and CPhasor Relationships for R, L and C
The relationships between V and I for R, L and C are needed in order for us to do the AC circuit analysis
+ vL
iL
dt
diL LLv
If iL = Im cos (t + i)
vL = L (Im (-sin (t + i)))
LL
IL
+ VL
imL I I
imR LIj V
vvLL leads i leads iLL by 90 by 90oo ! !
vL = L (Im cos (t + I +90o))
)90(LI oim
vmV
Phasor Relationships for R, L and CPhasor Relationships for R, L and C
The relationships between V and I for R, L and C are needed in order for us to do the AC circuit analysis
+ vc
ic
dt
dvC cCi
If vc = Vm cos (t + v)
ic = C (Vm( -sin (t + v)))
CC
Ic
+ Vc
vmc V V
vmc CVj I
iicc leads v leads vcc by 90 by 90oo ! !
ic = C (Vm cos (t + v +90o))
)90(CV ovm
imI