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Target Strength reflected wave incident wave a 2 i r I 4 rI r i I TS 10log I scattering crosssection 2 TS 10log 10log 4r 4 At r = 1 yd.

Target Strength

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reflected wave. a. incident wave. Target Strength. At r = 1 yd. Factors Determining Target Strength. the shape of the target the size of the target the construction of the walls of the target the wavelength of the incident sound the angle of incidence of the sound. R 2. R 1. - PowerPoint PPT Presentation

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Target Strength

reflected wave

incident wave

a

2i rI 4 r I

r

i

ITS 10log

I

scattering cross section

2TS 10log 10log

4 r 4

At r = 1 yd.

Factors Determining Target Strength

• the shape of the target

• the size of the target

• the construction of the walls of the target

• the wavelength of the incident sound

• the angle of incidence of the sound

Target Strength of a Convex Surface

i 1 2dP I ds ds

R1

R2

1d1ds

2d

2ds

i 1 1 2 2dP I R d R d

Incident Power

Large objects compared to the wavelength

Reflected Intensity

12 11R

11

r

1 1ds r2d

1 2 1 2dA ds ds r2d r2d

i 1 1 2 2 i 1 2r 2

1 2

dP I R d R d I R RI

dA r2d r2d 4r

R1

R2

1d1ds

2d

2ds

r

i

ITS 10log

I

1 2R RTS 10log

4

(At r = 1 m)

Special Case – Large Sphere

1 2R R a

2a aTS 10log 20log

4 2

a

Note: 2a

4 4

2a

Large means circumference >> wavelength

ka 1

TS positive only if a > 2 yds

Large Spheres (continued)

2 2 2 2r12

i

I 1a a cot J ka sin

I 4 r 2

a

0o180o

Example

• An old Iraqi mine with a radius of 1.5 m is floating partially submerged in the Red Sea. Your minehunting sonar is a piston array and has a frequency of 15 kHz and a diameter of 5 m. 20 kW of electrical power are supplied to the transducer which has an efficiency of 40%. If the mine is 1000 yds in front of you, what is the signal level of the echo. Assume spherical spreading.

Scattering from Small Spheres (Rayleigh Scattering)

22 2r

4 2i

I V 3cos 1

I r 2

4 225TS 10log ka a

36

ka 1

Scattering from Cylinders

L

2a

22 2

2

aL sin cosTS 10log

2 1yd

2 Lsin

2

2

aL 1TS 10log

2 1yd

o0

Dimensions (L,a) large compared to wavelength

Gas Bubbles

• Damping effect is due to the combined effects of radiation, shear viscosity and thermal conductivity. A good approximation is

• where fk is the frequency in kHz.

3

22

20

0

1

resonant frequency

damping term

bs

a

f

f

f

0

3

5

31 3.251 0.1

2

1000 kg/m

hydrostatic pressure in Pa 10 1 0.1

depth in meters

adiabatic constant for air ( 1.4)

w

w

w

w

Pf z

a a

P z

z

0.30.03 for 1 kHz< 100 kHzk kf f

Fish

• Main contribution for fish target strength comes from the swim bladder.

• This gas-filled bladder shows a very strong impedance contrast with the water and fish tissues. It behaves either as a resonator (frequencies of 500 Hz-2 kHz depending on fish size and depth) or as a geometric reflector (> 2 kHz). This swim bladder behaves very similar to gas bubbles. The difference in target strength between fish with and without swim bladder can be 10-15 dB.

• A semi-empirical model most often used is:

• Love (1978)• This formula is valid for dorsal echoes at wavelengths smaller than

fish length L.

19.1log 0.9 log 24.9fish kTS L f

421aa

2r

4

4

2

7.61V

2

ar

ra

2

449

2

2aL

22 2sinaL cos

2

2a

4

2

22

cossin

ab

2

2

a

bc

2

2

12

cos2

Ja

Formt

TS=10log(t)Symbols Direction of incidence Conditions

Any convex surface

a1a2 = principal radii of

curvaturer = rangek = 2/wavelength

Normal to surfaceka1, ka2 >>1

r>a

Large Sphere a = radius of sphere Anyka>>1r>a

Small SphereV = vol. of sphere = wavelength

Anyka<<1kr>>1

Infinitely long thick cylinder

a = radius of cylinderNormal to axis of cylinder

ka>>1r > a

Infinitely long thin cylinder

a = radius of cylinderNormal to axis of cylinder

ka<<1

Finite cylinder

L = length of cylindera = radius of cylinder

Normal to axis of cylinder ka>>1

r > L2/a = radius of cylinder = kLsin At angle with normal

Infinite Plane surface Normal to plane

Rectangular Platea,b = sides of ractangle = ka sin

At angle to normal in plane containing side a

r > a2/kb >> 1a > b

Ellipsoida, b, c = semimajor axis of ellipsoid

parallel to axis of aka, kb, kc >>1r >> a, b, c

Circular Platea = radius of plate = 2kasin At angle to normal

r > a2/ka>>1

Example

• What is the target strength of a cylindrical submarine 10 m in diameter and 100 m in length when pinged on by a 1500 Hz sonar?

2 4 6 8 10

-40

-20

20

40TS

10o5o

Example

• What is the target strength of a single fish 1m in length if the fish finder sonar has a frequency of 5000 Hz?