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The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

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Page 1: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9
Page 2: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

The Mole Concept: “How Chemist’s Measure”

and Stoichiometry: “Balancing of

Chemical Rxns”

Ch# 3, Ch#7, Ch#9

Page 3: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

I. Chemistry = Quantitative Science

A. Quantitative: Analyze/describe via definite numeric results. Ex:___________________

B. Qualitative: Analyze via nonnumeric or descriptive results (words) Ex:____________________

C. We measure the amt. of matter to do calculations relating quantities of reactants to products to chemical equations.

REACTANTS PRODUCTSYields

Page 4: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

D. We often use very small and very large numbers in chemistry.

E. Scientific notation is a method to express these numbers in a manageable fashion.

-Thus 0.000 000 1 cm can be written 1 x 10-7 cm.

F. Scientific notation expresses a number as the product of two factors, the first falling between 1

and 10 and the second being a power of 10.

Page 5: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Format is Mantissa x Base Power

We just move the decimal point around.

Decimal part of original number

Decimal you moved

6.02 x 1023

602000000000000000000000

Page 6: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

G. Converting into scientific notation:

1. Move decimal until there’s 1 digit to its left. Places moved = exponent.

2. If number converting is:

a) Large # (>1) positive exponent

b) Small # (<1) negative exponent

3. Only include sig. figs.

0 . 0 0 0 0 2 2 0 5

2,500,080,000

Page 7: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

H. Powers of 10 to know: Metric

• 0.000 000 001 or

• 0.000 001 or

• 0.001 or

• 0.01 or

• 0.1

• 1000 or

Page 8: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Symbols Used in Chemical Equations

“Yields”; indicates result of reaction

Used to indicate a reversible reaction

A reactant or product in the solid state; also used to indicate a precipitate

Alternative to (s), but used only to indicate a precipitate

A reactant or product in the liquid state

A reactant or product in an aqueous solution (dissolved in water)

A reactant or product in the gaseous state

(s)

(l)

(aq)

(g)

Page 9: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Additional Symbols Used in Chemical Equations

Alternative to (g), but used only to indicate a gaseous product

Reactants are heated

Pressure at which reaction is carried out, in this case 2 atm

Pressure at which reaction is carried out exceeds normalatmospheric pressure

Temperature at which reaction is carried out, in this case 0 oC

Formula of catalyst, in this case manganese (IV) oxide, used to alter the rate of the reaction , NOT

CONSUMED

Example: H2O2(aq) H2O (l) + O2 (g)

2 atm

pressure

0 oC

MnO2

MnO2

Page 10: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

II. Measuring Matter

A. Measure by:1) Counting (How many Ss are in this class?)

2) Weighing (Au sells for $25/gram)

3) Volume (The National Ave. for gas is $3.05/gal)

4) Sometimes by each (bananas 10¢/ea , by lb., by quart)

B. Chemists needed a counting unit: mole = Amt. of Substance

Page 11: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

III. The Mole (Counting)A. Matter is made of Particles: (Representative)

1) Elements = Atoms2) Ionic Cmpds = Formula unit (3D/ Cube)3) Molecular Cmpds = Molecules4) 1 mole is the amount of substance that contains as

many particles (atoms or molecules) as there are in 12.0 g of C-12.

B. Count them using Avagadro’s Number:1) Dozen (doz) eggs = 12 eggs2) 1 mole = 6.02 X 1023 Particles

Page 12: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Pics of Particles/Pieces

Page 13: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

3. Amedeo Avagadro (1766-1856) – Italian scientist & lawyer who first tried to experimentally determine the # of particles in a mole.– never knew his own number; – it was named in his honor by a French

scientist in 1909. – its value was first estimated by Josef Loschmidt, an Austrian chemistry teacher, in 1895.

Page 14: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

How Big is a Mole?One mole of marbles would cover the entire Earth (oceans included) for a depth of two miles.

One mole of $1 bills stacked one on top of another would reach from the Sun to Pluto and back 7.5 million times.

It would take light 9500 years to travel from the bottom to the top of a stack of 1 mole of $1 bills.

Page 15: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Welcome to Mole Island

1 mole = 22.4 L @ STP

1 mol = molar mass

1 mol = 6.02 x 1023 particles

Page 16: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Mass, Volume, Mole Relationship

Page 17: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

IV. Particle Conversions:

A. Particles Moles & Moles Particles1. How many moles of Mg is 3.01X1022 Atoms of Mg?

Unknown =

Known =

Conv:

Soln: 3.01 x 1022 Atoms Mg X 1 Mol Mg

6.02 x 1023Atoms Mg

= 5.00 X 10-2 Mol Mg

Page 18: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

2. How many moles are 1.20 X 1025 atoms of phosphorus?

3. How many atoms are in 0.750 mol of zinc?

Page 19: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

4. How many molecules are there in 4.00 mol of glucose, C6H12O6?

Atoms, F. U.’s, or Molecules

Page 20: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

B. Analogy: Have a doz. packages of pencils.

How many pencils do you have?

8 in a package = 8 x 12 = 96

C. To find the # of atoms in a Mol of a cmpd, must determine the # of atoms in a representative formula of that cmpd.

1) How many Fluoride ions are in 1.46 mol of aluminum fluoride?

Page 21: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

2) How many ammonium ions are in 0.036 mol ammonium phosphate?

3) How many C atoms are in a mixture of 3.00 mol C2H2 and 0.700 mol CO?

Page 22: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

V. Mole (Mass/Weight)

A. Learned - mass of a single atom is given in amu (atomic mass units).

B. Gram Atomic Mass (gam) – # of grams of an element numerically equal to amu (we will use the entire #).Ex. C (gam) = 12.01115 g/mol (grams/mole)

H (gam) = 1.0079 g/molC. The gam = 1 mole = 6.02 x 1023 particles

for a mono-atomic element!!!

Page 23: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

1 Mole of Particles

Do They look alike ? Do you think they will have the same mass if 1 mole?

Page 24: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Ex. What is the mass of 1 mol of each of these monatomic elements?

a. Sodium b. Arsenic c. Uranium

D. What is the mass of 1 mole of a cmpd?1) Formula of a cmpd tells us the # of atoms of each

element in a rep. particle of that cmpd.

2) Calculate the gram molecular mass (gmm) or gram formula mass (gfm) by adding together the atomic masses of the atoms making up a molecule or F.U.

Page 25: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

3) Examples:Sulfur Trioxide:

Ammonium Phosphate:

Aluminum Sulfate:

Page 26: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

E. gam, gfm, & gmm are commonly referred to as molar mass in chemistry.

(1 mol= mass from pd table= 6.02x1023 parts)

F. Mole Mass (g) Conversions use Molar Mass1) Molar mass of an element or cmpd is used to convert

grams of a substance into moles and vice versa.

2) Examples:a) How many grams are in 7.20 mol of dinitrogen trioxide?

Page 27: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

b) Find the number of moles in 922g of iron (III) oxide.

c) What is the mass of 2.65 x 1024 molecules of Carbon Tetrachloride?

Page 28: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

d) A sample of chlorous acid has a mass of 3500.1 grams, how many representative particles are present in this sample?

Page 29: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Each substance is a mole, so why do they look so different?

Page 30: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

.

One mole of NaCl(the solid) mass = 58.45 g

One mole Water, mass= 18.0 goccupies a volume of 18.0 mL.

One mole of the O2 gashas a mass of 32.0 g& 22.4L volume

One mole each of a solid, a liquid, and a gas:

Page 31: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

VI. Mole (Volume of A Gas)

A. Volumes of moles of different substances can be different.

B. Vol of a mole of gas is much more predictable.

C. Vol of a gas is measured at STP (Standard Temperature & Pressure)

1. Standard Temp = 0oC

2. Standard Pressure = 1 atm (atmosphere)

How do we measure pressure?

Page 32: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

D. At STP, 1 mol of any gas occupies a vol of 22.4 L aka molar volume of a gas.

1 mol = 6.02 x 1023 P = Molar Mass ? = 22.4L

E. Problems:1. Determine the volume, in liters, of 0.600 mol of

SO2 gas at STP.

Page 33: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

2. Determine the number of moles in 333.6 mL of He gas.

Page 34: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

3. What is the volume at STP for 3.25 x 1024 molecules of CO2 gas?

Page 35: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Homework Problems:

1. What is the vol at STP of 0.960 mol CH4?

2. Determine the vol (in L) of 127.80 g of Titanium (II) Oxide gas.

Page 36: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

VII. Calculating Percent Composition

A. When a new cmpd is made in a laboratory, we need to determine its formula.

B. So we use percent composition which is simply finding the percent (%) by mass of each element in a compound.

C. The % comp includes as many %’s as there are elements in the cmpd.

Page 37: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

For Example: K2CrO4

% comp: 40.3% K, 26.8% Cr, & 32.9% O (∑=100%)

D. Percent Composition Formula: is the # of grams of the element divided by the grams of the cmpd, multiplied by 100%

Or % Comp = grams of element x 100%

grams of cmpd

We Can Use This Formula 2 Ways!!!!

Page 38: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Most Common Use:

Page 39: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

E. Example Problems:

(given g amts < or > 1 mol use #’s directly)1. An 8.20 g piece of Mg combines completely w/

5.40 g of O to form a cmpd. What is the % comp of this cmpd?

Page 40: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

2. Calculate the % comp of ethane, C2H6.

(Given no #’s so you assume 1 mol & use molar mass)

Page 41: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

VIII. Determining Formulas from % Comp:

A. Empirical Formula: formula showing the smallest whole number ratio of elements present.

C6H12O6 = Molecular Formula

CH2O = Empirical Formula

Page 42: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

B. Finding Empirical Formula:

1. Find % Composition:

-Unknown has 63% Mn & 37% O

2. Convert % to moles:(Assume 100g sample)

Mn: 63 g Mn x 1 mole Mn = 1.1 mole Mn

54.9 g Mn

O:

Page 43: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

3. Convert Moles to Whole Numbers:

Method: divide all molar amounts by the smallest molar amount

Mn: 1.1 mol Mn = 1 mol Mn

1.1

MnO2

O: 2.3 mol O = 2.1 mol O

1.1

Rule: round #’s to nearest whole # unless….

If answer is 0.4, 0.5, 0.6 then double ALL!

Page 44: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Practice Problem 1Given the following data, find the correct empirical formula:

49.0% C, 2.70% H, 48.2% Cl

Page 45: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Practice Problem 2

Given the following data find the empirical formula:

N = 26.2%, H = 7.50%, Cl = 66.4%

Page 46: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

C. Molecular Formula:

1.First find the empirical formula.

2.Then compare the formula mass for your empirical formula with the formula mass for the molecular formula.

3.You may have to multiply the subscripts in your empirical formula by some factor.

Page 47: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Example #1:

Given: 38.7% C, 9.70% H, 51.6% O and a Molecular mass

of (gmm=62.0g) find the true molecular formula:

1.Empirical Formula:

2. gmm of E.F.:

3. Divide Masses:

4. Multiply E.F. by Factor:

Page 48: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Practice Problem #2Given the following data, find the correct molecular formula:

24.3% C, 4.1% H, 71.6% Cl: gmm = 99.0g

Page 49: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Practice #3

Given the following data, find the correct molecular formula:

54.6% C, 9.00% H, 36.4% O and gmm: 176g

Page 50: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

IX. Balancing Chemical Equations

A. All equations we have written have been correct in Qualitative sense but not Quantitative.

B. Equation must be balanced so that they are quantitatively correct.

--balanced equation: each side of the equation has the same number of atoms of each element.

Law of Conservation of Mass!!!Atoms can’t be created or destroyed just

REARRANGED!

Page 51: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

C. Sometimes we write equations and it will already be balanced:

C (s) + O2 (g) CO2 (g)

D. Other equations we must correct or balance the quantities of reactant atoms to product atoms:

C (s) + O2 (g) CO (g)

H2(g) + O2(g) -----> H2O (l)Pt

Page 52: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

E. The numbers in front are called STOICHIOMETRIC

COEFFICIENTS– These tell us the # of moles/subscripts =________

F. Guidelines For Balancing: Mostly Trial and Error

Do Not Change Subscripts!!!!1. Count the number of atoms on each side

2. Polyatomic ion unchanged (consider it one unit and balance first)

3. Even / odd (make all even)

4. Single Elements last

5. Make sure all coefficients are in simplest (lowest) ratio

AgNO3(aq) + Cu(s) Cu(NO3)2 (aq) + Ag (s)

Page 53: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

More Examples: (notice no physical states)

(NH4)3PO4 + Mg(OH)2 Mg3(PO4)2 + NH4OH

AlCl3 + Li2CO3 Al2(CO3)3 + LiCl

P + O2 P2O5

Page 54: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

X. Mole Ratio is The KEY

A. Balanced equations show proportions:Synthesis of Water – 2H2 + O2 2H2O

For Every 2 H molecules we need 1 O molecule!

B. Calculations involved in chemical rxns use the proportions to find the quantity of reactant and product.

- Assume all Rxns go to completion

Page 55: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

C. Since Avogadro’s # relates molecules to moles the coefficients also tells us the # of moles needed for a rxn to progress successfully.

D. Stoichiometry-the proportional relationship between 2 or more substances during a chemical rxn.

Page 56: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

E. Converting Between Amounts in Moles

1. Identify the amount in moles you know.

2. Using coefficient from eqn., set up mole ratio with Known on Bottom

3. Multiply the original amount by the mole ratio and finish problem.

Known

Unknown

Page 57: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Example:Consider the rxn for the commercial prep of

Ammonia.

N2 + 3H2 2NH3

How many moles of Hydrogen are needed to prepare 312 moles of ammonia?

Page 58: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Example:What mass of NH3 can be made from 1221 g H2 and excess N2?

Plan:

Page 59: The Mole Concept: “How Chemist’s Measure” and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

Use: Fe2O3 + 2Al 2Fe + Al2O3

1.How many g of Al are needed for 135g Fe2O3?

2.How many g of Al2O3 can form when 23.6g Al with excess Fe2O3?

3.How many g of Fe2O3 react with excess Al to make 475g Fe?

4.How many g of Fe will form when 97.6g Al2O3 form?