thiet ke dung cu cat

8/14/2019 thiet ke dung cu cat

1/20

n Dao

PHN I

THIT K DAO TIN NH HNH

1. Phn tch chi tit gia cng :

d1

1x45o

l

l

l

l

l

d2

d3

d4

d5

1 2 3456

1

2

3

4

5

Chi tit gia cng l tr trn xoay gm cc b mt tr v b mt cn.

i vi b mt cn, dao tin nh hnh lng tr s mc phi sai s v khi giacng khng chnh xc c cc b mt cn, nhng li c u im l cng vnghn v cho b mt gia cng c cht lng cao hn dao tin nh hnh hnh trn.

Ng Ngc Lm Lp CTM6 K51 Page 1


2/20

n Dao

Nhng dao tin nh hnh hnh trn li gia cng chnh xc c cc b mt cnvic ch to cng d dng hn, gi thnh cng r hn so vi dao tin nh hnhlng tr.

Vy gia cng chi tit trn ta s dng dao tin nh hnh hnh trn.

- Vt liu gia cng l thp C45, 2/650 mmNb =

Chn cc gc v nh sau

==

o

o

12

25

- d dng cho vic g t ta chn cch g thng- im c s c chn l im xa chun kp nht, i vi trng

hp tin ngoi l im gn tm chi tit nht chn im 1 l im c s.

2. S tnh :



3/20

n Dao

1

2

43 65

44

33

2 2

11

55

6

6

'

'

'

'

'

'

x x'

x

x'

6 '5 '

4'3'

2 '

1'

C

B

A

O

O

d

34

K

Rx

h

3. Tnh ton profil dao trong 2 tit din :

- Ta c chiu su ct ln nht : mmdd

t 72

3448

2

23max =

=

=

- Tra bng ta c kch thc ca dao nh sau :



4/20

n Dao

Tmax D d(A3) d1 bmax K r D1 d2

7 60 16 25 11 3 2 34 5

- Loi dao s dng l cht .- Chiu cao g dao : 237.612sin30sin === oRh

Vi : R bn knh dao ti im c s , R = D/2 = 30 mm

- gc sau ti im c s , = 12o

a. Trong tit din trng mt trc :

=

==

==

11

1

sinsin

cos

cos

x

x

xxx

xxxx

r

rar

rC

rB

BCBC

b. Trong tit din chiu trc :

( )( )

( )( )

( )

( )( )

x

x

xx

dxxx

xx

x

d

xx

dx

RRgar

RKxK

xK

KOgar

RR

RKOKO

R

+

+=

+==

==+

+

+=

+=+

=

sin

sintan

sin1

tan

sin

sin

sin,sin

1

1

1

1

1

c. Tnh ti cc im nh sau :

- Ti im 1 & 2 :

1 = 2 = 0 , C1 = C2 = r1cos1 = 17cos25o

= 15.4071 = 2 = 25o



5/20

n Dao

R1 = R2 = 60cm

- Ti im 3 & 4 :

3 = 4 = C3 B = C4 B ( C3 = C4 )

( )( )

( )533.25

sin

sin

45cos

sin

915.5322.313718sinsin

3

143

31

1

43

33

'

1

3

1

43

=+

==

=+

+==

===

==

RRR

R

Rarctg

Cr

rar

o

o

- Ti im 5 & 6 :

5 = 6 = C5 B = C6 B ( C5 = C6 )

( )( )

( )436.24

sin

sin

3747cos

sin

492.7899.282517sinsin

5

165

'

51

165

55

'

1

5

1

65

=+

==

=+

+==

===

==

RRR

R

Rarctg

Cr

rar

o

o

- Ta c bng kt qu nh sau :

TT rx x Cx x Rx

1 17 25o 15.407 0 30

2 17 25o 15.407 0 30

3 22.5 18o37 21.322 5.915 25.533

4 22.5 18o37 21.322 5.915 25.533

5 24 17o25 22.899 7.492 24.436

6 24 17o25 22.899 7.492 24.436



6/20

n Dao

- Profil dao trong tit din trng mt trc :

7.4

92

5.9

15

6 ' 5 '

1 ' 2 '

3 ' 4 '

228

10

16

22

28

51

20?

- Profil dao trong tit din chiu trc :



7/20

n Dao

5.5

51

4.4

67

6 ' 5'

1 ' 2 '

3 ' 4 '

228

10

16

22

28

51

20?

4. Cc kch thc khc :- Chiu rng li ct ph : a = 2 mm- Chiu rng phn ct xn mt u : c = 2 mm- Gc vt : = 45o

- Chiu rng li ct t : b = 5 mm- Chiu rng phn khng tham gia ct : d = 1 mm- Gc vt : = 20o

- Tng chiu di li ct : Ld = Lc + a + b + c + d = 38 mm

5. iu kin k thut :

- Vt liu phn ct : P18- cng : phn ct : 60 . 62 HRC

Phn thn : thp 45 , 35 40 HRC

- nhm : mt trc : Ra = 0.32 m



8/20

n Dao

Mt sau : Ra = 0.63 m

L nh v : Ra = 0.63 m

- Sai lch gc khi mi : 15 30

- Nhn hiu : P18 25o 12o - HBKHN



9/20

n Dao

PHN II

THIT K DAO PHAY NH HNH

1. Phn tch chi tit gia cng:

b

=6

30

R6

- Chi tit gia cng nh hnh v, nu dng dao phay thngthng th s gp kh khn khi gia cng b mt cong v phi tho lp daov g t nhiu ln, nn vi chi tit gia cng dng ny ta dng dao phaynh hnh l hp l nht.

- Vi chiu su phay ln nht b = 6, tra bng ta c ngknh ln nht ca dao :

Dmax = D = 80 mm v s rng Z = 10 rng



10/20

n Dao

- Vt liu gia cng l thp 45, 2/650 mmNb = nn chn gc trc

= 15o v gc sau = 12o .

- Lng ht lng : 5.53.5 === KtgZ

DK

2. S tnh :

1'1

1d

2d2

2'

14 14'

14d

i i'id

1

1d

14

14

iid

2d2

1d

2d

14d

id

h

Od

ti

hhsii

A

B

R=40

Ri

Ro

3. Tnh profil dao trong 2 tit din :

- Ta c :



11/20

n Dao

( ) ( )

=

=

=++==

sinarcsinsinarcsin

sinsinsinsin

ii

i

i

iiio

hR

R

R

R

R

RRRR

- Trong tit din chiu trc :

iidisiii

oo

i

iiidis

hhK

Z

Kvhh

6283.0

5.5

6283.0

5.5

36360

,

===

===

=

- Trong tit din trng mt trc :

( )

sinsin

sinsinsinsin

iidit

iid

i

dit

hRh

hRRBOh

=

===

- Chiu su phay ln nht b=6, chia u b thnh 12 im tng ngcch u nhau 0.5mm.



12/20

n Dao

b

=6

30

R6

h

L

14

i

1

i

i

- Vi : ( )22

icti hbRL =

- Ti im 2 ( im c s ) :

==

===

0,0

0,0,0

22

2

tdsd hh

- Ti im 1 :

( ) ( ) 2515.615sin

432sin

640sin

sin

5833.54167.06

4167.00476.06283.0

5.5

6283.0

5.5

)(0476.04321515sin640

40arcsin

'1

11

111

11

'1

===

===

===

==

=

o

o

td

sd

ooo

hRh

hh

rad



13/20

n Dao

- Ti im 3 :

( ) ( ) 5178.015sin

110sin5.040

sin

sin

4703.00297.05.0

0297.000340.0

6283.0

5.5

6283.0

5.5

)(00340.01101515sin5.040

40arcsin

'3

33

333

33

'3

===

===

===

==

=

o

o

td

sd

ooo

hRh

hh

rad

- Cc im cn li ta tnh tng t, v c bng s liu sau :

TT hi i i hdis hdit Li

1 6 0.0476 0.4168 5.5832 6.2492 3.464

2 0 0 0 0 0.0000 0

3 0.5 0.0034 0.0297 0.4703 0.5179 2.398

4 1 0.0069 0.0602 0.9398 1.0362 3.317

5 1.5 0.0105 0.0916 1.4084 1.5551 3.969

6 2 0.0141 0.1237 1.8763 2.0744 4.4727 2.5 0.0179 0.1568 2.3432 2.5943 4.873

8 3 0.0218 0.1908 2.8092 3.1147 5.196

9 3.5 0.0258 0.2258 3.2742 3.6356 5.454

10 4 0.0299 0.2618 3.7382 4.1571 5.657

11 4.5 0.0341 0.2988 4.2012 4.6792 5.809

12 5 0.0385 0.3370 4.6630 5.2019 5.916

13 5.5 0.0430 0.3763 5.1237 5.7252 5.97914 6 0.0476 0.4168 5.5832 6.2492 6

- Profil dao trong tit din chiu trc :



14/20

n Dao

0.4

703

0.9

398

1.4085

1.8

764

2.3

432

2.8

092

3.2

743

3.7

383

4.2

012

4.6

631

5.1

238

5.5

833

2.398

3.317

3.969

4.472

4.873

5.196

5.454

5.657

5.809

5.916

5.979

63

- Profil dao trong tit din trng mt trc



15/20

n Dao

0.5

718

1.0

362

1

.5551

2.0

745

2.5

944

3.1

149

3.6

360

4.1

577

4.6

801

5.2

032

5.7

270

6.2

515

2.398

3.317

3.969

4.472

4.873

5.196

5.4545.657

5.809

5.916

5.979

63

4. Cc kch thc kt cu khc :

- Chiu rng dao phay : B = 10 mm- Chiu cao chn rng : H = K + hct + r = 5.5 + 6 +1.5 = 13 mm- Bn knh ln rnh rng : r = 1.5 mm- ng knh l then : d = 22 mm- Chiu su rnh then tnh c ng knh l then : t = 24.1 mm- Gc rnh rng : = 25 o

- Bng thng s dao nh sau :

D Z d t hct r K H B80 10 22 24.1 6 1.5 5.5 13 25 o 10

5. iu kin k thut :

- Vt liu lm dao : P18- cng phn ct sau khi nhit luyn : 62 65 HRC



16/20

n Dao

- nhm : Mt sau : Ra 1.25 m

Mt trc : Ra = 0.32 m

Mt cn li : Ra = 20 m

- Sai lnh cho php ca cc kch thc :

Sai lch chiu cao profil dao : 0.05

Sai lch chiu rng profil : 0.05

Sai lch gc trc : 15

- Sai lch v tr :

o hng knh ca cc li ct : 0.04 o mt u : 0.02

o hng tm : 0.09

- K hiu dao : P18-15o-Rm(10.35)-HBKHN

PHN III



17/20

n Dao

THIT K DAO PHAY A MUN

1. Thng s hnh hc ca bnh rng gia cng :

- Theo bi ta c : m= 3 , = 20o , No = 4 , tra bng ta c ngknh nh dao v s rng dao phay modun nh sau : D = 70 mm, Zdao = 12 rng

- S rng ca bnh rng gia cng l : Z = 21 25 rng, vy chn srng cu bnh rng gia cng khi ch to dao l Z = 21 rng

- Bc rng : tp = m = 9.424 mm- Chiu dy rng :

712.42

== m

S

- Bn knh vng chia :

5.312

213

2=== mZRc

- Bn knh vn nh rng :

25.352

)5.221(3

2

)5.2( =+=+= ZmRe

- Bn knh vng chn rng :

75.272

)5.221(3

2

)5.2( === ZmRi

- Bn knh vng c s :

5.2920cos2

213cos

20 =

== omZR



18/20

n Dao

2. S tnh :

A=11

M(x,y)

M

1=B

O

O

c

Rr

rr Re

x

cO i

oxc

x

y1

x

x

c

c

x

max

- Trn s n tnh, on AB la on thn khai hay l on lm viccn on O1B la on khng lam vic, thuc khe h chn rng hay on cong



19/20

n Dao

chuyn tip. Ta ch tnh ton ta ca tng im nm trn profil dao ctphn lm vic ca bnh rng, v dao c gc trc = 0 nn profil ca dao strng vi profil ca chi tit, nn ch tnh ta ca cc im nm trn phn lmvic ca bnh rng.

- t h trc ta xOy c gc O trng vi tam bnh rng gia cng,ti mi im M(x,y) bt k trn profil vi bn knh rx ta s xc nh c mtim M tng ng.

ccc

cco

o

ccoc

xxxxoxox

xx

xx

invZ

invr

Sinv

inv

tginvry

rx

===

=+=

=+=+=

=

=

22

20;

;;cos

sin

+=

+=

===

==

xcx

xcx

c

x

xccco

x

oxxxo

invinvZ

ry

invinvZ

rx

r

mZar

mZrr

r

rarrr

2cos

2sin

cos2

coscos2

cos

coscos

- rx = ro Re = 29.5 35.25 chia thnh 10 on tng ng c11 im x = 1 11

3. Xc nh profil dao :

- T cc cng thc trn ta c bng kt qu tnh nh sau :

TT rx x invx x x y S=2x t=y-ri1 29.5 0 0 0.0599 1.7669 29.447 3.5338 1.69712 30.075 0.1779 0.0019 0.0618 1.8585 30.018 3.7171 2.26763 30.65 0.2625 0.0062 0.0661 2.0258 30.583 4.0515 2.83314 31.225 0.3240 0.0118 0.0717 2.2398 31.145 4.4796 3.3947



20/20

n Dao

5 31.8 0.3741 0.0185 0.0784 2.4927 31.702 4.9854 3.95246 32.375 0.4170 0.0260 0.0859 2.7804 32.256 5.5608 4.50577 32.95 0.4548 0.0342 0.0941 3.1002 32.804 6.2005 5.05438 33.525 0.4887 0.0430 0.1029 3.4504 33.348 6.9009 5.5976

9 34.1 0.5195 0.0524 0.1123 3.8297 33.885 7.6595 6.135210 34.675 0.5478 0.0623 0.1222 4.2371 34.416 8.4741 6.666511 35.25 0.5740 0.0726 0.1325 4.6717 34.941 9.3434 7.1909

- Chiu cao phn u rng dao phay : h1 = (f+c)m=1.25x3=3.75- Chiu cao phn chn rng dao phay : h2 = (f+c)m=1.25x3=3.75- Chiu cao ca rng dao : h = h1 + h2 = 7.5 mm

- Bn knh ln chn rng : r = 1,5 mm- Bn knh v u rng : r 1 = 0.8 mm- ng knh vng nh dao : D = 70 mm- S rng dao phay : Zdao = 12 rng- Gc sau ti nh rng : = 10o

- Lng ht lng 1 ln : 5.310 == otgZ

DK

- Chiu cao rnh thot phoi : H = h + K + r = 12.5 mm

- ng knh l trc dao : d = 22 mm- Chiu cao l tnh c then : t = 24.1 mm- Chiu rng dao phay : B = 10 mm- Gc thot phoi : = 25o

4. iu kin k thut :

- Vt liu lm dao : P18- Nhit luyn t cng : 62 65 HRC- do hng knh ca li ct : 0.04- o mt u : 0.03- o hng tm mt trc : 0.06- nhm : mt trc R z = 0.32 m

- Nhn hiu : P18 - m=3 = 20

o

N

o

4/8 HBKHN

Documents

thiet ke dung cu cat