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Solucionario Capitulo 8 Thomas Calculo
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CHAPTER 8 TECHNIQUES OF INTEGRATION
8.1 BASIC INTEGRATION FORMULAS
1. ; 2 u C 2 8x 1 Cu 8x 1du 16x dx' '16x dx du
8x 1 u ##
#
2. ; 2 u C 2 1 3 sin x Cu 1 3 sin xdu 3 cos x dx' '3 cos x dx du
1 3 sin x u
3. 3 sin v cos v dv; 3 u du 3 u C 2(sin v) Cu sin vdu cos v dv' ' 23 $# $#
4. cot y csc y dy; u ( du) C Cu cot ydu csc y dy' '$ # $
# u4 4cot y% %
5. ; ln u ln 10 ln 2 ln 5u 8x 2du 16x dx
x 0 u 2, x 1 u 10' '
0 2
1 1016x dx du8x 2 u#
#
"!#
c dk k
6. ; du ln u ln 3 ln 1 ln 3u tan z
du sec z dzz u 1, z u 3
' '1
1
4 1
3 3 31
sec z dztan z u
4 3
#
c dk k
# "
1 1
7. ; 2 ln u C 2 ln x 1 Cu x
du dx2 du
' 'dx 2 dux x 1 x
dxx
u
"#
k k
"
8. ; 2 ln u C 2 ln x 1 Cu x 1du dx2 du
' ' 'dx dx 2 dux x x x 1 x
dxx
u
"#
k k
9. cot (3 7x) dx; cot u du ln sin u C ln sin (3 7x) Cu 3 7xdu 7 dx' ' k k k k" " "7 7 7
10. csc ( x 1) dx; csc u ln csc u cot u Cu x 1du dx' '11
1
k k du1 1"
ln csc ( x 1) cot ( x 1) C "1
k k1 111. e csc e 1 d ; csc u du ln csc u cot u C ln csc e 1 cot e 1 Cu e 1du e d
' ') ) ) ) k k ) ))
)
12. dx; cot u du ln sin u C ln sin (3 ln x) Cu 3 ln xdu' 'cot (3 ln x)
x dxx
k k k k
494 Chapter 8 Techniques of Integration
13. sec dt; 3 sec u du 3 ln sec u tan u C 3 ln sec tan Cu
du' 't 3 t t
3 3 3
t
dt3
k k
14. x sec x 5 dx; sec u du ln sec u tan u Cu x 5du 2x dx' 'a b k k # # " "# #
ln sec x 5 tan x 5 C "## #k ka b a b
15. csc (s ) ds; csc u du ln csc u cot u C ln csc (s ) cot (s ) Cu sdu ds' '
1 1 11 k k k k
16. csc d ; csc u du ln csc u cot u C ln csc cot Cu
du' '" " " "
"
) ) ) ))
)
)
#
#
) k k d
17. 2xe dx; e du e e e 2 1 1u x
du 2x dxx 0 u 0, x ln 2 u ln 2
' '0 0
ln 2 ln 2u u ln 2ln 2
0
x# c d
#
!
18. sin (y) e dy; e du e du e 1 eu cos y
du sin y dyy u 0, y u 1
' ' '1
1
2 0 1
1 0ucos y u u e
e
c d
1
#
!"
" "
1
19. e sec v dv; e du e C e Cu tan vdu sec v dv' 'tan v u u tan v#
#
20. ; 2e du 2e C 2e Cu t
du' 'e dt
t dt2 t
u u tt
21. 3 dx; 3 du 3 C Cu x 1du dx' 'x 1 u u
ln 3 ln 33 " x 1
22. dx; 2 du C Cu ln xdu
' '2 2 2x ln ln dx
x
uln x u ln x # #
23. ; 2 du C Cu w
du' '2 dw 2 2
w dww
ln ln w u w
##
# #
u
24. 10 d ; 10 du C Cu 2du 2 d' '2 u 10 10
ln 10 ln 10))
)
) " "# # #u 2)
25. ; 3 tan x C 3 tan 3u Cx 3udx 3 du' '9 du 3 dx
1 9u 1 x " "# #
26. ; 2 tan u C 2 tan (2x 1) Cu 2x 1du 2 dx' '4 dx 2 du
1 (2x 1) 1 u " "# #
27. ; sin u 0u 3x
du 3 dxx 0 u 0, x u
' '0 0
1 6 1 2 dx du1 9x 1 u
63 3 3 6 18 " "
#
" " "" "#
!# #
1 1
Section 8.1 Basic Integration Formulas 495
28. sin sin 0'0
1 dt t4 t 6
" "# #
"
!"#
1
29. ; sin u C sin s Cu sdu 2s ds' '2s ds du
1 s 1 u #
" " #% #
30. ; sin u C sin (2 ln x) Cu 2 ln xdu' '2 dx du
x 1 4 ln x 1 u2 dxx
" "# #
31. 5 sec 5x C 6 sec 5x C' '6 dx 6 dx 6x 25x 1 5x x 5 # # "#
" " 5
k k k k
32. sec C' dr rr r 9 3 3 #
" "
33. ; tan u C tan e Cu edu e dx' ' 'dx e dx du
e e e 1 u 1x x 2xx
" " #
x
xx
34. ; sec u C sec e Cu edu e dy' ' 'dy e dy
e 1 u u 1e e 1du a b2y
y
y y
" " # # k k
y
yy
35. ; sec u du ln sec u tan uu ln xdu
x 1 u 0, x e u' ' '
1dx du
x cos (ln x) cos udxx
3
e 3 3
30 0
13 c dk k
1
1 1
1
1$!
ln sec tan ln sec 0 tan 0 ln 2 3 ln (1) ln 2 3 k k 1 13 336. ; ln 1 4u C ln 1 4 ln x Cu ln xdu ln x dx
' ' 'ln x dx ln x dx dux 4x ln x x 1 4 ln x 1 4u 8 82
x #
#" " " ## #
a b k k a b
37. 8 ; 8 8 tan uu x 1du dx
x 1 u 0, x 2 u' ' '
1 18 dx dx du
x 2x 2 1 (x 1) 1 u2 2 1
0# # # " "
!
"
c d
8 tan 1 tan 0 8 0 2 a b " " 14 1
38. 2 ; 2 2 tan uu x 3du dx
x 2 u 1, x 4 u 1' ' '
2 2 1
4 4 12 dx dx du
x 6x 10 (x 3) 1 u 1# # # " "
"
c d
2 tan 1 tan ( 1) 2 c d " " 1 14 4 139. ; sin u C sin (t 2) Cu t 2du dt' ' '
dt dt dut 4t 3 1 (t 2) 1 u
" "#
#
#
40. ; sin u C sin ( 1) Cu 1du d' ' 'd d du
2 1 u1 ( 1)) )
) ) ) " "# #
#
) ) )
41. ; sec u C sec x 1 C,u x 1du dx' ' 'dx dx du
(x 1) x 2x (x 1) (x 1) 1 u u 1 " " # ##
k k k k
u x 1 1k k k k
496 Chapter 8 Techniques of Integration
42. ; sec u Cu x 2du dx' ' 'dx dx du
(x 2) x 4x 3 (x 2) (x 2) 1 u u 1 " # ##
k k
sec x 2 C, u x 2 1 " k k k k k k43. (sec x cot x) dx sec x 2 sec x cot x cot x dx sec x dx 2 csc x dx csc x 1 dx' ' ' # # # # #a b a b' ' tan x 2 ln csc x cot x cot x x C k k44. (csc x tan x) dx csc x 2 csc x tan x tan x dx csc x dx 2 sec x dx sec x 1 dx' ' ' ' ' # # # # #a b a b cot x 2 ln sec x tan x tan x x C k k45. csc x sin 3x dx (csc x)(sin 2x cos x sin x cos 2x) dx (csc x) 2 sin x cos x sin x cos 2x dx' ' ' a b# 2 cos x cos 2x dx [(1 cos 2x) cos 2x] dx (1 2 cos 2x) dx x sin 2x C ' ' 'a b#46. (sin 3x cos 2x cos 3x sin 2x) dx sin (3x 2x) dx sin x dx cos x C' ' '
47. dx 1 dx x ln x 1 C' 'xx 1 x 1
" k k48. dx 1 dx x tan x C' 'x
x 1 x 1#
# # " "
49. dx 2x dx x ln x 1 (9 ln 8) (2 ln 1) 7 ln 8' '
2 2
3 3 32
2x 2xx 1 x 1$
# # # # c dk k
50. dx (2x 3) dx x 3x ln 2x 3 (9 9 ln 9) (1 3 ln 1) ln 9 4' ' 1 1
3 34x 7 22x 3 2x 3#
# $" c dk k
51. dt (4t 1) dt 2t t 2 tan C' '4t t 16t 4 tt 4 t 4$ #
# #
#
# " 52. d 1 d ln 2 5 C' '2 7 7 5 52 5 2 5 3) ) ) ) )) )$ # $ #
# ##
) ) ) ) ) ) a b k k53. dx sin x 1 x C' ' '1 x dx x dx
1 x 1 x 1 x
" # # # #
54. dx (x 1) ln x C' ' 'x 2 x 12x x 1 2 x 1
dx dxx
"# k k
55. dx sec x sec x tan x dx tan x sec x 1 2 ( 1) 2' '0 0
4 41 1 1 sin x
cos x # %
!# ! a b c d 1
56. dx dx tan (2x) ln 1 4x' '0 0
1 2 1 2 2 8x 2 8x1 4x 1 4x 1 4x
" # "#!# # # c dk k
tan 1 ln 2 tan 0 ln 1 ln 2 a b a b" " 1457. dx dx sec x sec x tan x dx tan x sec x C' ' ' 'dx1 sin x 1 sin x cos x
(1 sin x) (1 sin x)
# a b# # a b58. 1 cos x 1 cos 2 2 cos sec dx tan C x x dx dx x x1 cos x 2 cos# # # # ## #"' ' '##
x
59. d d ; ln u C ln 1 sin Cu 1 sin du cos d' ' '"
sec tan udu
) )) ) )
)
) )
k k k k
Section 8.1 Basic Integration Formulas 497
60. d d ; ln u C ln 1 cos Cu 1 cos du sin d' ' '"
csc cot 1 cos usin du
) ) )
)) ) )
)
) )
k k k k
61. dx dx 1 dx 1 dx 1 csc x dx' ' ' ' '" " #1 sec x cos x 1 cos x 1 sin x sin xcos x 1 cos x cos x # # 1 csc x csc x cot x dx x cot x csc x C ' a b#62. dx dx 1 dx 1 dx' ' ' '" " 1 csc x sin x 1 sin x 1 (sin x 1) (sin x 1)sin x sin x 1 1 dx 1 sec x dx 1 sec x sec x tan x dx x tan x sec x C ' ' ' a b1 sin x sin x
cos x cos x # ## #
63. dx sin dx; sin dx 2 cos 2(cos cos 0)sin 0for 0 2' ' '0 0 02 2 21 1 1 1 cos x x x xx x# # # ##
#
#
!
11
1
( 2)( 2) 4
64. 1 cos 2x dx 2 sin x dx; 2 sin x dx 2 cos xsin x 0for 0 x' ' '
0 0 0
1 1 1 k k 1 1! 2 (cos cos 0) 2 2 165. 1 cos 2t dt 2 cos t dt; 2 cos t dt 2 sin tcos t 0for t
' ' '1 1 1
1 1 1
2 2 2 k k 1 11# #1
2 sin sin 2 1 1#66. 1 cos t dt 2 cos dt; 2 cos dt 2 2 sin cos 0for t 0
' ' ' 1 1 1
0 0 0
t t tt
# # ##
!
1 1
2 2 sin 0 sin 2 2 1#67. 1 cos d sin d ; sin d cos cos 0 cos ( )sin 0for 0' ' ' 1 1 1
0 0 0 k k c d # !) ) ) ) ) ) ) 1)1 ) 1 1 ( 1) 2
68. 1 sin d cos d ; cos d sin sin sin 1cos 0for ' ' '1 1 1
1 1 1
2 2 2 k k c d # # # #) ) ) ) ) ) ) 1
)
) 11
1
1
1
69. tan y 1 dy sec y dy; sec y dy ln sec y tan ysec y 0for y' ' '
1 1 1
1 1 1
4 4 4
4 4 4 k k c d k k# % % 1 1 1 14 4 ln 2 1 ln 2 1
70. sec y 1 dy tan y dy; tan y dy ln cos y lntan y 0for y 0' ' ' 1 1 14 4 4
0 0 0 k k c d k k # ! % " 1 14 2 ln 2 71. (csc x cot x) dx csc x 2 csc x cot x cot x dx 2 csc x 1 2 csc x cot x dx' ' '1 1 1
1 1 1
4 4 4
3 4 3 4 3 4 # # # #a b a b
2 cot x x 2 csc x 2 cot 2 csc 2 cot 2 csc c d $ %%11 1 1 1 1 1 13 3 34 4 4 4 4 4 2( 1) 2 2 2(1) 2 2 4 34 41 1 1#
498 Chapter 8 Techniques of Integration
72. (sec x 4 cos x) dx sec x 8 16 dx tan x 16x 4 sin 2x' '0 0
4 41 1 # # #
%!
c d1 cos 2x 1 tan 4 4 sin (tan 0 0 4 sin 0) 5 4 1 14 1 1#73. cos csc (sin ) d ; csc u du ln csc u cot u Cu sin du cos d' ') ) )
)
) ) k k
ln csc (sin ) cot (sin ) C k k) )74. 1 cot (x ln x) dx; cot u du ln sin u C ln sin (x ln x) Cu x ln xdu 1 dx' ' k k k k " "x
x
75. (csc x sec x)(sin x cos x) dx (1 cot x tan x 1) dx cot x dx tan x dx' ' ' ' ln sin x ln cos x C k k k k76. 3 sinh ln 5 dx sinh u du 6 cosh u C 6 cosh ln 5 Cu ln 52 du dx
' x x2 x2 ' ' #
77. ; 12 tan u C 12 tan y Cu y
du dy' '6 dy
y (1 y) 1 u2 y
12 du "" " #
78. ; sec u C sec 2x Cu 2xdu 2 dx' ' 'dx 2 dx du
x 4x 1 u u 12x (2x) 1 # ## " "
k k k k
79. ; 7 sec Cu x 1du dx' ' '7 dx 7 dx 7 du u
(x 1) x 2x 48 u u 49(x 1) (x 1) 49 7 7 " " # #
#
sec C " " x 780. ; sec u Cu 2x 1du 2 dx
' ' 'dx dx du(2x 1) 4x 4x (2x 1) (2x 1) 1 2u u 1
"#
" # ##
k k
sec 2x 1 C "#" k k
81. sec t tan (tan t) dt; tan u du ln cos u C ln sec u C ln sec (tan t) Cu tan tdu sec t dt' '#
# k k k k k k
82. csch C' dx xx x $
"$
"$#
83. (a) cos d (cos ) 1 sin d ; 1 u du u C sin sin Cu sin du cos d' ' '$ # # $") ) ) ) ) ) )
)
) )
a b a b u3 3$ (b) cos d (cos ) 1 sin d 1 u du 1 2u u du u u C' ' '& # # # % $# #) ) ) ) ) a b a b a b' 2 u3 5& sin sin sin C ) ) )23 5
$ &"
(c) cos d cos (cos ) d 1 sin (cos ) d' ' '* ) # %) ) ) ) ) ) ) ) a b a b84. (a) sin d 1 cos (sin ) d ; 1 u ( du) u Cu cos du sin d' ' '
$ # #) ) ) ) )
)
) )
a b a b u3$ cos cos C ) )" $3 (b) sin d 1 cos (sin ) d 1 u ( du) 1 2u u du' ' ' '& # # # %# #) ) ) ) ) a b a b a b cos cos cos C ) ) )23 5
$ &"
(c) sin d 1 u ( du) 1 3u 3u u du cos cos cos C' ' '( # # % ' $ &$) ) ) ) ) a b a b 3 cos5 7( )
Section 8.1 Basic Integration Formulas 499
(d) sin d sin (sin ) d 1 cos (sin ) d' ' '"$ "# # ') ) ) ) ) ) ) ) a b a b85. (a) tan d sec 1 (tan ) d sec tan d tan d tan tan d' ' ' '$ # # #"#) ) ) ) ) ) ) ) ) ) ) ) ) a b ' tan ln cos C "#
#) )k k
(b) tan d sec 1 tan d tan sec d tan d tan tan d' ' ' ' '& # $ $ # $ % $") ) ) ) ) ) ) ) ) ) ) ) ) a b a b 4 (c) tan d sec 1 tan d tan sec d tan d tan tan d' ' ' ' '( # & & # & ' &") ) ) ) ) ) ) ) ) ) ) ) ) a b a b 6 (d) tan d sec 1 tan d tan sec d tan d ;' ' ' '2k 1 2k 1 2k 1 2k 1 ) ) ) ) ) ) ) ) ) ) a b a b# # u du tan d u tan d tan tan du tan du sec d )) ) ) ) ) ) ) ) )# " "#' ' ' '2k 1 2k 1 2k 2k 1 2k 2k 1 2k k86. (a) cot d csc 1 (cot ) d cot csc d cot d cot cot d' ' ' ' '$ # # #"#) ) ) ) ) ) ) ) ) ) ) ) ) a b cot ln sin C "#
#) )k k
(b) cot d csc 1 cot d cot csc d cot d cot cot d' ' ' ' '& # $ $ # $ % $") ) ) ) ) ) ) ) ) ) ) ) ) a b a b 4 (c) cot d csc 1 cot d cot csc d cot d cot cot d' ' ' ' '( # & & # & ' &") ) ) ) ) ) ) ) ) ) ) ) ) a b a b 6 (d) cot d csc 1 cot d cot csc d cot d ;' ' ' '2k 1 2k 1 2k 1 2k 1 ) ) ) ) ) ) ) ) ) ) a b a b# # u du cot d u cot du cot du csc d )) ) ) ) ) )# "#' ' '2k 1 2k 1 2k 2k 1 k cot cot d "2k
2k 2k 1) ) )'
87. A (2 cos x sec x) dx 2 sin x ln sec x tan x '
1
1
4
4 c dk k 11
% %
2 ln 2 1 2 ln 2 1 2 2 ln 2 2 ln 22 1 2 12 1" #
2 2 ln 3 2 2
88. A (csc x sin x) dx ln csc x cot x cos x '1
1
6
2 c dk k 11
#'
ln 1 0 ln 2 3 ln 2 3 k k 3 3# #
89. V (2 cos x) dx sec x dx 4 cos x dx sec x dx ' ' ' '
1 1 1 1
1 1 1 1
4 4 4 4
4 4 4 41 1 1 1
# # # #
2 (1 cos 2x) dx tan x 2 x sin 2x [1 ( 1)] 1 1 1 1'
1
1
4
4 c d 11
1
1
% %
"#
%
%
2 2 2 1 2 1 1 1 1 1 1 1 14 4" "# # # #90. V csc x dx sin x dx csc x dx (1 cos 2x) dx ' ' ' '1 1 1 1
1 1 1 1
6 6 6 6
2 2 2 21 1 1
# # ##1
cot x x sin 2x 0 3 0 1 1c d 11
1 1 1 11
1
#' # # # # # #
" "#
' 63
3 1 1 1 1 1# 26 4 8 63 7 3
500 Chapter 8 Techniques of Integration
91. y ln (cos x) tan x sec x 1; L 1 dx dy dy dydx cos x dx dxsin x # ## # 'ab 1 sec x 1 dx sec x dx ln sec x tan x ln 2 3 ln 1 0 ln 2 3 ' '
0 0
3 31 1 a b c d k kk k # $!1
92. y ln (sec x) tan x sec x 1; L 1 dx dy dy dydx sec x dx dxsec x tan x # ## # 'ab sec x dx ln sec x tan x ln 2 1 ln 1 0 ln 2 1 '
0
41 c d k kk k 1%!93. M sec x (sec x) dx sec x dxx 4 4
4 4 ' '
1 1
1 1 " "# #
#
tan x 1 ( 1) 1; " "# #%
%c d c d1 1 M sec x dx ln sec x tan x '
1
1
4
4 c dk k 11
% %
ln 2 1 ln 2 1 ln 22 1" ln ln 3 2 2 ; x 0 by 2 1"##
symmetry of the region, and y MM ln 3 2 2x "
94. M csc x (csc x) dx csc x dxx 6 65 6 5 6
' '1 1
1 1
" "# #
#
cot x 3 3 3; " "# #& ''c d 11
M csc x dx ln csc x cot x '1
1
6
5 6 c dk k & ''11 ln 2 3 ln 2 3 ln 2 3
2 3
ln 2 ln 2 3 ; x by symmetry 2 34 3 ##
1
of the region, and y MM3
2 ln 2 3x
95. csc x dx (csc x)(1) dx (csc x) dx dx;' ' ' ' csc x cot x csc x csc x cot xcsc x cot x csc x cot x
#
ln u C ln csc x cot x Cu csc x cot xdu csc x cot x csc x dx a b k k k k # ' duu96. x 1 (x 1) (x 1)(x 1) (x 1) (x 1) (x 1) (x 1) (x 1)c d c da b # # #$ %$ # #$ #$#$ #$ (x 1) (x 1) 1 # #
#$ #$ x 1 2x 1 x 1
(a) x 1 (x 1) dx (x 1) 1 dx; udu dx' 'c da b # ##$ #$
""
2
x 1x 1
(x 1)#
(1 2u) du (1 2u) C 1 C C ' #$ "$# # # "$ "$3 3 2 3 x 1
x 1 x 1
(b) x 1 (x 1) dx (x 1) dx; u' 'c da b # ##$ #$ x 1 x 1x 1 x 1 k du k dx 2k dx; dx du x 1 x 1
x 1 (x 1) (x 1) k x 1(x 1) (x 1) (x 1) (x 1)
# k 1 k 1 c d#
#k 1
k 1
du; then, du du (x 1)2k x 1 x 1 k x 1 k x 1x 1 x 1 x 1 x 1 " " # #
#$# 1 k 1 k 1 3 k ' ' du u du (3k) u C u C C " " " # # # # #
"$
k x 1 k k x 1x 1 3 3 x 1' k 1 3k 1 1 3k 1 1 3k 1 3k '
Section 8.2 Integration by Parts 501
(c) x 1 (x 1) dx (x 1) dx;' c da b # ##$ #$ ' x 1x 1 du;
u tan xx tan udx
"
" "
#$ #$
ducos u
(tan u 1) tan u 1 cos u (sin u cos u) sin u cos utan u 1 du sin u cos u
#
# # #
' '
sin u cos u sin u sin u 2 sin cos usin u cos u sin u sin u 2 cos sin u
1 1 1
1 1 1
#
#
"
4 4
4 42 cos u cos
sin u'#
1
1
4
4u
#$
1
4 du
tan u sec u du tan u C C "# # # #$ # "$
"$' 1 1 14 4 4 1 tan u tan 3 3 tan u tan 1144
C 3 x 1x 1# "$
(d) u tan x tan u x tan u x dx 2 tan u du du ; " # " cos u cos u cos u
2 sin u 2d(cos u)# $ $
x 1 tan u 1 ; x 1 tan u 1 ; # # "sin u cos u 1 2 cos u cos u sin ucos u cos u cos u cos u
# # # # #
# # # #
(x 1) (x 1) dx' #$ %$ " ' a ba b a b1 2 cos u
cos u cos u
2d(cos u)cos u
#
#$
# #
#$ %$
$
1 2 cos u ( 2) cos u d(cos u) 1 2 cos u d 1 2 cos u ' 'a b a b a b# # ##$ #$"# 1 2 cos u C C C 3 3 3 x 1
x 1# # # # "$
"$
"$a b 1 2 cos u
cos u
cos u
#
#
"
#
(e) u tan tan u x 1 2(tan u 1) dx 2d(tan u); " # # x 1 x 1 2 ducos u# (x 1) (x 1) dx (tan u) (tan u 1) 2 2 d(tan u)' ' #$ %$ #$ %$ # 1 d 1 1 C 1 C " " " "# # #
#$ "$ "$' tan u 1 tan u 1 tan u 1 x 1
3 3 2
C 3 x 1x 1# "$
(f) u cos x
x cos u
dx sin u du
"
' 'sin u du sin u ducos u 1 (cos u 1) sin u 2 cos $ # ## %$ #$#
%$a b a b u
' ' 'du du du(sin u) 2 cos 2 sin cos cos
sin cos "$ #$# # #
%$ "$ &$
#
#
#
#
u u uu
u u"#
"$ tan d tan tan C tan C C ' "$ #$ ## # # # # # #
"$ "$ u u 3 u 3 u 3 cos u 1cos u 1
C 3 xx 1# " "$
(g) x 1 (x 1) dx; u cosh xx cosh udx sinh u
' c da b # #$"
' sinh u ducosh u 1 (cosh u 1)$ # ##a b
' ' 'sinh u du du dusinh u (cosh u 1) (sinh u) 4 cosh sinh cosh $ % # $ $% # #
a b "#u u u
tanh d tanh tanh C C C ' u u 3 u 3 cosh u 1 3 x 1cosh u 1 x 1# # # # # #
"$ #$ "$ "$
8.2 INTEGRATION BY PARTS
1. u x, du dx; dv sin dx, v 2 cos ; x x# # x sin dx 2x cos 2 cos dx 2x cos 4 sin C' 'x x x x x# # # # # 2. u , du d ; dv cos d , v sin ; ) ) 1) ) 1)"
1
cos d sin sin d sin cos C' ') 1) ) 1) 1) ) 1) 1) ) )1 1 1 1
" "#
502 Chapter 8 Techniques of Integration
3. cos t
t sin t#
2t cos t
2 sin t
0 t cos t dt t sin t 2t cos t 2 sin t C' # #
4. sin x
x cos x#
2x in xs
2 cos x
0 x sin x dx x cos x 2x sin x 2 cos x C' # #
5. u ln x, du ; dv x dx, v ; dx xx
#
#
x ln x dx ln x 2 ln 2 2 ln 2 ln 4' '1 1
2 2 x x dx x 3 3
x 4 4 4# # #
# #
# #
" "
6. u ln x, du ; dv x dx, v ; dx xx 4
$ %
x ln x dx ln x ' '1 1
e ee e
1 1
$ x x dx e x 3e 14 4 x 4 16 16% % % % %
7. u tan y, du ; dv dy, v y; " dy
1 y#
tan y dy y tan y y tan y ln 1 y C y tan y ln 1 y C' " " " # " #" # ' y dy1 ya b# a b
8. u sin y, du ; dv dy, v y; "
dy1 y #
sin y dy y sin y y sin y 1 y C' " " "
# ' y dy1 y # 9. u x, du dx; dv sec x dx, v tan x; #
x sec x dx x tan x tan x dx x tan x ln cos x C' '# k k
10. 4x sec 2x dx; [y 2x] y sec y dy y tan y tan y dy y tan y ln sec y C' # # ' ' k k 2x tan 2x ln sec 2x C k k11. ex
x e$
x
3x e#
x
6x e
x
6 e
x
0 x e dx x e 3x e 6xe 6e C x 3x 6x 6 e C' $ $ # $ #x x x x x x a b
Section 8.2 Integration by Parts 503
12. ep
p e
% p
4p
e$ p
12p e# p
24p ep
24 e p
0 p e dp p e 4p e 12p e 24pe 24e C' % % $ # p p p p p p p 4p 12p 24p 24 e C a b% $ # p13. ex
x 5x e#
x
2x 5 e
x
2 e
x
0 x 5x e dx x 5x e (2x 5)e 2e C x e 7xe 7e C' a b a b# # # x x x x x x x x 7x 7 e C a b# x14. er
r r 1 e#
r
2r 1 e
r
2 e
r
0 r r 1 e dr r r 1 e (2r 1) e 2e C' a b a b# # r r r r r r 1 (2r 1) 2 e C r r 2 e C c d a ba b# #r r15. ex
x e&
x
5x e%
x
20x e$
x
60x e#
x
120x e
x
120 ee
x
0 x e dx x e 5x e 20x e 60x e 120xe 120e C' & & % $ #x x x x x x x x 5x 20x 60x 120x 120 e C a b& % $ # x
504 Chapter 8 Techniques of Integration
16. e4t
t e# "
44t
2t e
"16
4t
2 e
"64
4t
0 t e dt e e e C e e e C' # "#4t 4t 4t 4t 4t 4t 4t t 2t 2 t t4 16 64 4 8 3# #
e C t t4 8 3# "# 4t17. sin 2)
cos 2) )# "
2
2 sin 2) )
"4
2 cos 2
"8 )
0 sin 2 d cos 2 sin 2 cos 2'0
21) ) ) ) ) )#
# #"
#
! ) ) 1# 4
( 1) 0 ( 1) 0 0 1 1 1 1 1# # #8 4 4 4 8 8 4 " " " #18. cos 2x
x sin 2x$ "
2
3x cos 2x# "
4
6x sin 2x
"8
6 os 2x c
"16
0 x cos 2x dx sin 2x cos 2x sin 2x cos 2x'0
21$
#
#
! x 3x 3x 34 4 8$ # 1
0 ( 1) 0 ( 1) 0 0 0 1 1 1 1 1 1$ # # #16 16 8 8 8 16 4 163 3 3 3 3 3 3 4 a b
19. u sec t, du ; dv t dt, v ; " #
dt tt t 1 ##
t sec t dt sec t 2 ' ' '2 3 2 3 2 3
2 2 2
" "# #
#
# $ t t dt 2 t dt
t t 1 2 t 13 3 6# #
# # 1 1
t 1 3 1 3 5 5 4 5 59 9 3 9 3 9 3 93 3 5 3 31 1 1 1 1 " " "# # ## ## $
20. u sin x , du ; dv 2x dx, v x ; " # #
a b 2x dx1 x %
2x sin x dx x sin x x' ' '0 0 0
1 2 1 2 1 2 " # # " # #" #
!
"#
a b c da b 2x dx1 x 2 1 x6 d 1 x% %%1 1 x 1 1 1 11 1 4 1
3 6 3 12# # #
%" #
!
21. I e sin d ; u sin , du cos d ; dv e d , v e I e sin e cos d ; ' ') ) ) ) )) ) ) ) ) ) ) ) )c d u cos , du sin d ; dv e d , v e I e sin e cos e sin dc d ) ) ) ) ) ) ) )) ) ) ) )' e sin e cos I C 2I e sin e cos C I e sin e cos C, where C is ) ) ) ) ) )) ) ) ) ) )w w "# #a b a b Cw another arbitrary constant
Section 8.2 Integration by Parts 505
22. I e cos y dy; u cos y, du sin y dy; dv e dy, v e ' y y yc d I e cos y e ( sin y) dy e cos y e sin y dy; u sin y, du cos y dy; y y y y' 'a b c dv e dy, v e I e cos y e sin y e cos y dy e cos y e sin y I Cd a b y y y y y y y' w 2I e (sin y cos y) C I e sin y e cos y C, where C is another arbitrary constant y y yw "# #a b Cw
23. I e cos 3x dx; u cos 3x; du 3 sin 3x dx, dv e dx; v e ' 2x 2x 2x "# I e cos 3x e sin 3x dx; u sin 3x, du 3 cos 3x, dv e dx; v e " "# # #
2x 2x 2x 2x3 ' I e cos 3x e sin 3x e cos 3x dx e cos 3x e sin 3x I C " " "# # # # #
w2x 2x 2x 2x 2x3 3 3 94 4 '
I e cos 3x e sin 3x C (3 sin 3x 2 cos 3x) C, where C C 13 3 e 44 4 13 13"# w w2x 2x2x
24. e sin 2x dx; [y 2x] e sin y dy I; u sin y, du cos y dy; dv e dy, v e' ' 2x y y y "# c d I e sin y e cos y dy u cos y, du sin y; dv e dy, v e "# c d y y y y' I e sin y e cos y e ( sin y) dy e (sin y cos y) I C " " "# # # w y y y y a b' 2I e (sin y cos y) C I e (sin y cos y) C (sin 2x cos 2x) C, where " "# w y y4 4e2x
C Cw#
25. e ds; e x dx xe dx; u x, du dx; dv e dx, v e ;3s 9 xds x dx' ' '3s 9 x x x x c d
#
23
2 23 3
xe dx xe e dx xe e C 3s 9 e e C2 2 2 23 3 3 3' a b x x x x x 3s 9 3s 9 ' 26. u x, du dx; dv 1 x dx, v (1 x) ; 23 $ x 1 x dx (1 x) x (1 x) dx (1 x)' '
0 0
1 1 2 2 2 2 43 3 3 5 15$ $"! ! "
27. u x, du dx; dv tan x dx, v tan x dx dx dx dx # # "' ' ' ' 'sin x cos x dxcos x cos x cos x
# #
# # #
tan x x; x tan x dx x(tan x x) (tan x x) dx 3 ln cos x ' '0 0
3 31 1 # $
! #
$
!c d k k 1 1 1 13 3 x#
3 ln ln 2 1 1 1 113 3 18 3 183 "# # #
28. u ln x x , du ; dv dx, v x; ln x x dx x ln x x x dx a b a b a b '# # # "(2x 1) dxx x x(x 1)2x# ' x ln x x x ln x x dx x ln x x 2x ln x 1 C a b a b a b k k# # # " ' '(2x 1) dx 2(x 1)x 1 x 1
29. sin (ln x) dx; du dx (sin u) e du. From Exercise 21, (sin u) e du e Cu ln x
dx e du'
" #x
sin u cos u
u
u u u' '
x cos (ln x) x sin (ln x) C "# c d
506 Chapter 8 Techniques of Integration
30. z(ln z) dz; du dz e u e du e u du;u ln z
dz e du' ' '# # #"
z
u u 2u
u
e2u
u e# "
22u
2u
e
"4
2u
2 e
"8
2u
0 u e du e e e C 2u 2u 1 C' # ## # "2u 2u 2u 2u u u e4 4# 2u c d
2(ln z) 2 ln z 1 C z4# c d#
31. (a) u x, du dx; dv sin x dx, v cos x; S x sin x dx [ x cos x] cos x dx [sin x]" ! ! ' '0 01 1
1 11 1
(b) S x sin x dx [ x cos x] cos x dx 3 [sin x] 3# # # ' '1 1
1 12 2 c d1 11 11 1 (c) S x sin x dx [ x cos x] cos x dx 5 [sin x] 5$ $ $# # ' '2 2
3 3
1 1
1 1
1 1
1 11 1
(d) S ( 1) x sin x dx ( 1) [ x cos x] [sin x]8" n 1 n 1 n 1 n 1n
n 1
n n
'1
1
1 1
1 1
c d ( 1) (n 1) ( 1) n ( 1) 0 (2n 1) n 1 n n 1 c d1 1 132. (a) u x, du dx; dv cos x dx, v sin x; S x cos x dx [x sin x] sin x dx [cos x] 2" # # ' '1 1
1 1
1 1
1 1
2 2
3 2 3 23 2 3 22 2 31 1 1
(b) S x cos x dx [x sin x] sin x dx [cos x] 4# # # ' '3 2 3 25 2 5 2
2 22 21 1
1 1
1 1
1 1
& &
$ $
5 31 1 1 (c) S x cos x dx [x sin x] sin x dx [cos x] 6$ # # ' '5 2 5 2
7 2 7 22 22 21 1
1 1
1 1
1 1
( (
& &
7 51 1 1 (d) S ( 1) x cos x dx ( 1) [x sin x] sin x dxn n n n2n 1 2 2n 1 2
2n 1 2 2n 1 2n 1 2
2n 1 2 ' '
#
1 1
1 1
1
1
( 1) ( 1) ( 1) [cos x] (2n 2n ) 2n n n n 1 n 1 22n 1 2 (2n 1) (2n 1) # # #"1 1 # 11 1 1 1 1 133. V 2 (ln 2 x) e dx 2 ln 2 e dx 2 xe dx ' ' '
0 0 0
ln 2 ln 2 ln 2x x x
1 1 1
(2 ln 2) e 2 xe e dx 1 1c d c d x x xln 2 ln 20 0 0ln 2' 2 ln 2 2 2 ln 2 e 2 ln 2 2 2 (1 ln 2) 1 1 1 1 1 c dx ln 20
34. (a) V 2 xe dx 2 xe e dx ' '0 0
1 1x x x
1 1 c d "!
2 e 2 1 1 1 c d " " ""!e e ex 2 1 4
e1
Section 8.2 Integration by Parts 507
(b) V 2 (1 x)e dx; u 1 x, du dx; dv e dx, '0
1x x
1
v e ; V 2 (1 x) e e dx x x x0
11 c da b "! '
2 [0 1( 1)] e 2 1 1 1 1 c d x "! "e e21
35. (a) V 2 x cos x dx 2 [x sin x] sin x dx ' '0 0
2 21 1 1 1 1#!
2 [cos x] 2 0 1 ( 2) 1 1 1 1 1 11# ##!
(b) V 2 x cos x dx; u x, du dx; dv cos x dx, v sin x; '0
211 1 1# #
V 2 x sin x 2 sin x dx 0 2 [ cos x] 2 (0 1) 2 1 1 1 1 1 1 1 1# #! #!'0 21
36. (a) V 2 x(x sin x) dx; '0
1
1
sin x
x cos x#
2x in xs
2 cos x
0 V 2 x sin x dx 2 x cos x 2x sin x 2 cos x 2 4 1 1 1 1'0
1
# # #!c d a b1
(b) V 2 ( x)x sin x dx 2 x sin x dx 2 x sin x dx 2 [ x cos x sin x] 2 8 ' ' '0 0 0
1 1 1
1 1 1 1 1 1 1# # # $
!1 a b
8 1
37. (a) av(y) 2e cos t dt "#1 '02
t1
e " ##
!1
1 t sin t cos t (see Exercise 22) av(y) 1 e "#1 a b21
(b)
38. (a) av(y) 4e (sin t cos t) dt "#1'02
t1
e sin t dt e cos t dt 2 21 1' '
0 0
2 2t t1 1
e e 2 sin t cos t sin t cos t1
1 t t # #
#
!
e sin t 0 21
1c dt #!
(b)
39. I x cos x dx; u x , du nx dx; dv cos x dx, v sin x ' n n nc d" I x sin x nx sin x dx n n' "
508 Chapter 8 Techniques of Integration
40. I x sin x dx; u x , du nx dx; dv sin x dx, v cos x ' n n nc d" I x cos x nx cos x dx n n' "
41. I x e dx; u x , du nx dx; dv e dx, v e ' n ax n n ax axa
" " I e x e dx, a !x e n
a aax n axn ax ' "
42. I ln x dx; u ln x , du dx; dv dx, v x " ' a b a b n n n ln xx
a bn"
I x ln x n ln x dx a b a bn n' "
43. sin x dx x sin x sin y dy x sin x cos y C x sin x cos sin x C' '" " " " " a b44. tan x dx x tan x tan y dy x tan x ln cos y C x tan x ln cos tan x C' '" " " " " k k k ka b45. sec x dx x sec x sec y dy x sec x ln sec y tan y C' '" " " k k x sec x ln sec sec x tan sec x C x sec x ln x x 1 C " " " " #k ka b a b
46. log x dx x log x 2 dy x log x C x log x C' '2 2 2 2y 2 xln ln y
# #
47. Yes, cos x is the angle whose cosine is x which implies sin cos x 1 x ." " #a b 48. Yes, tan x is the angle whose tangent is x which implies sec tan x 1 x ." " #a b 49. (a) sinh x dx x sinh x sinh y dy x sinh x cosh y C x sinh x cosh sinh x C;' '" " " " " a b check: d x sinh x cosh sinh x C sinh x sinh sinh x dxc d a ba b " " " "
" x1 x 1 x # #
sinh x dx "
(b) sinh x dx x sinh x x dx x sinh x 1 x 2x dx' ' '" " " #" " #
"# a b1 x#
x sinh x 1 x C " # "#a b check: d x sinh x 1 x C sinh x dx sinh x dx a b" # " ""#
x x
1 x 1 x # #
50. (a) tanh x dx x tanh x tanh y dy x tanh x ln cosh y C' '" " " k k x tanh x ln cosh tanh x C; " "k ka b check: d x tanh x ln cosh tanh x C tanh x dxc dk ka b " " " " x1 x cosh tanh x 1 xsinh tanh x# " #"a ba b tanh x dx tanh x dx " " x x1 x 1 x# # (b) tanh x dx x tanh x dx x tanh x dx x tanh x ln 1 x C' ' '" " " " # # #" " x 2x1 x 1 x# # k k check: d x tanh x ln 1 x C tanh x dx tanh x dx k k" # " ""# x x1 x 1 x# #8.3 INTEGRATION OF RATIONAL FUNCTIONS BY PARTIAL FRACTIONS
1. 5x 13 A(x 2) B(x 3) (A B)x (2A 3B)5x 13 A B(x 3)(x 2) x 3 x 2
B (10 13) B 3 A 2; thus, A B 52A 3B 13 5x 13 2 3(x 3)(x 2) x 3 x #
Section 8.3 Integration of Rational Functions by Partial Fractions 509
2. 5x 7 A(x 1) B(x 2) (A B)x (A 2B)5x 7 5x 7 A Bx 3x 2 (x 2)(x 1) x 2 x 1
#
B 2 A 3; thus, A B 5A 2B 7 5x 7 3 2x 3x 2 x 2 x 1 #
3. x 4 A(x 1) B Ax (A B) A 1 and B 3;A 1A B 4x 4 A B
(x 1) x 1 (x 1) # #
thus, x 4 1 3(x 1) x 1 (x 1) # #
4. 2x 2 A(x 1) B Ax ( A B) A 2A B 22x 2 2x 2 A B
x 2x 1 (x 1) x 1 (x 1)
# # #
A 2 and B 4; thus, 2x 2 2 4
x 2x 1 x 1 (x 1)
# #
5. z 1 Az(z 1) B(z 1) Cz z 1 (A C)z ( A B)z Bz 1 A B Cz (z 1) z z z 1
# ## #
B 1 A 2 C 2; thus, A C 0A B 1
B 1
z 2 2z (z 1) z z z 1
" " # #
6. 1 A(z 2) B(z 3) (A B)z (2A 3B)z A Bz z 6z z z 6 (z 3)(z 2) z 3 z $ # # #
" "
5B 1 B A ; thus, A B 02A 3B 1 " " 5 5 z z 6z z 3 z 2z$ # " "5 5
7. 1 (after long division); t 8 5t 2 5t 2 5t 2 A Bt 5t 6 t 5t 6 t 5t 6 (t 3)(t 2) t 3 t 2#
# # #
5t 2 A(t 2) B(t 3) (A B)t ( 2A 3B) B (10 2) 12A B 52A 3B 2
B 12 A 17; thus, 1 t 8 17 12t 5t 6 t 3 t 2#
#
8. 1 1 (after long division); t 9 9t 9 9t 9 9t 9 A B Ct Dt 9t t 9t t t 9 t t 9 t t t 9% # # #
% # % # # # # # # #
a b a b 9t 9 At t 9 B t 9 (Ct D)t (A C)t (B D)t 9At 9B # # # # $ #a b a b A 0 C 0; B 1 D 10; thus, 1
A C 0B D 9
9A 09B 9
t 9 10
t 9t t t 9%
% # # #
"
9. 1 A(1 x) B(1 x); x 1 A ; x 1 B ;" " " # #1 x 1 x 1 xA B# ln 1 x ln 1 x C' ' 'dx dx dx1 x 1 x 1 x # # #" " "# c dk k k k10. 1 A(x 2) Bx; x 0 A ; x 2 B ;" " " # #x 2x x x 2A B# ln x ln x 2 C' ' 'dx dx dx
x 2x x x 2# # # #" " " c dk k k k
11. x 4 A(x 1) B(x 6); x 1 B ; x 6 A ;x 4 A B 5 2 2x 5x 6 x 6 x 1 7 7 7
#
dx ln x 6 ln x 1 C ln (x 6) (x 1) C' ' 'x 4 2 dx 5 dx 2 5x 5x 6 7 x 6 7 x 1 7 7 7
"
#
k k k k k k12. 2x 1 A(x 3) B(x 4); x 3 B 7 ; x 4 A 9;2x 1 A B 7 9
x 7x 12 x 4 x 3 1 1
#
dx 9 7 9 ln x 4 7 ln x 3 C ln C' ' '2x 1 dx dxx 7x 12 x 4 x 3
(x 4)(x 3)
#*
(
k k k k
510 Chapter 8 Techniques of Integration
13. y A(y 1) B(y 3); y 1 B ; y 3 A ;yy 2y 3 y 3 y 1 4 4 4A B 1 3# " ln y 3 ln y 1 ln 5 ln 9 ln 1 ln 5' ' '
4 4 4
8 8 8y dy dy dyy 2y 3 4 y 3 4 y 1 4 4 4 4 4 4
3 3 3 3#
" " " ")
% k k k k
ln 5 ln 3 " "# # #ln 15
14. y 4 A(y 1) By; y 0 A 4; y 1 B 3 ;y 4y y y y 1 1A B 3 # dy 4 3 4 ln y 3 ln y 1 (4 ln 1 3 ln 2) 4 ln 3 ln ' ' '
1 2 1 2 1 2
1 1 1
y 4 dy dyy y y y 1
3 # #
""#
"#
c dk k k k ln ln ln ln 16 ln " " "8 16 8 8 8 4
27 27 27 15. 1 A(t 2)(t 1) Bt(t 1) Ct(t 2); t 0 A ; t 2" " #t t 2t t t 2 t 1A B C$ # B ; t 1 C ; 1 dt dt dt dt6 3 t t 2t t 6 t 2 3 t 1
" " " " #
' ' ' '$ #
ln t ln t 2 ln t 1 C " " "# k k k k k k6 316. (x 3) A(x 2)(x 2) Bx(x 2) Cx(x 2); x 0 A ; x 2x 3 A B C 32x 8x x x 2 x 8 " # # $ B ; x 2 C ; dx " " 16 16 2x 8x 8 x 16 x 2 16 x 2
5 x 3 3 dx dx 5 dx' ' ' '$
ln x ln x 2 ln x 2 C ln C 3 58 16 16 16 x(x 2) (x 2)k k k k k k " " &'
17. (x 2) (after long division); 3x 2 A(x 1) Bx 3x 2 3x 2 A Bx 2x 1 (x 1) (x 1) x 1 (x 1)$
# # # #
Ax (A B) A 3, A B 2 A 3, B 1; '0
1x dx
x 2x 1$
#
(x 2) dx 3 2x 3 ln x 1 ' ' '0 0 0
1 1 1dx dx xx 1 (x 1) x 1 #
""
!#
# k k 2 3 ln 2 (1) 3 ln 2 2 " "# #18. (x 2) (after long division); 3x 2 A(x 1) Bx 3x 2 3x 2 A B
x 2x 1 (x 1) (x 1) x 1 (x 1)$
# # # #
Ax ( A B) A 3, A B 2 A 3, B 1; '1
0x dx
x 2x 1$
#
(x 2) dx 3 2x 3 ln x 1 ' ' ' 1 1 1
0 0 0dx dx xx 1 (x 1) x 1 #
"!
"#
# k k 0 0 3 ln 1 2 3 ln 2 2 3 ln 2 " " " # #( 1) ( )19. 1 A(x 1)(x 1) B(x 1)(x 1) C(x 1) D(x 1) ;"
# # # #
a bx 1A B C D
x 1 x 1 (x 1) (x 1)# # # #
x 1 C ; x 1 D ; coefficient of x A B A B 0; constant A B C D " " $4 4 A B C D 1 A B ; thus, A B ; " " "# 4 4
dxx 1
' a b# # ln C " " " " " 4 x 1 4 x 1 4 (x 1) 4 (x 1) 4 x 1 2 x 1
dx dx dx dx x 1 x' ' ' '# # #
a b20. x A(x 1) B(x 1)(x 1) C(x 1); x 1x A B C(x 1) x 2x 1 x 1 x 1 (x 1)#
# # # #a b
C ; x 1 A ; coefficient of x A B A B 1 B ; " " # 2 4 4 (x 1) x 2x 13 x dx' ##a b
ln x 1 ln x 1 C " " " " # 4 x 1 4 x 1 2 (x 1) 4 4 (x 1)dx 3 dx dx 3' ' '#
k k k k C ln (x 1)(x 1)4 2(x 1)
k k "
$
21. 1 A x 1 (Bx C)(x 1); x 1 A ; coefficient of x1 A Bx C(x 1) x 1 x 1 x 1 # "# #a b# # a b A B A B 0 B ; constant A C A C 1 C ; 1 dx2 (x 1) x 1
"# '
0
1
a b#
Section 8.3 Integration of Rational Functions by Partial Fractions 511
dx ln x 1 ln x 1 tan x " " " " " # # # # " "
!2 x 1 x 1 4dx ( x 1)' '
0 0
1 1
#
k k a b ln 2 ln 2 tan 1 ln 1 ln 1 tan 0 ln 2 " " " " " " " "# # # # #" " 4 4 4 4 8( 2 ln 2)1 122. 3t t 4 A t 1 (Bt C)t; t 0 A 4; coefficient of t3t t 4 A Bt Ct t t t 1#
$ #
# # # a b A B A B 3 B 1; coefficient of t C C 1; dt '
1
3 3t t 4t 1#
$
4 dt 4 ln t ln t 1 tan t ' '1 1
3 3 dtt t 1 2
( t 1)
" # " $
"# k k a b
4 ln 3 ln 4 tan 3 4 ln 1 ln 2 tan 1 2 ln 3 ln 2 ln 2 " " "# # #" " 1 13 4 2 ln 3 ln 2 ln "# # #
1 1
1 19
2
23. y 2y 1 (Ay B) y 1 Cy Dy 2y 1 Ay B Cy Dy 1 y 1y 1#
# #
# ##
# #
a b a b a b Ay By (A C)y (B D) A 0, B 1; A C 2 C 2; B D 1 D 0; $ # dy dy 2 dy tan y C' ' 'y 2y 1 y
y 1 y 1y 1 y 1#
# #
# ## #
" "
"a b a b
24. 8x 8x 2 (Ax B) 4x 1 Cx D8x 8x 2 Ax B Cx D4x 1 4x 14x 1#
# #
# ##
# #a b a b a b
4Ax 4Bx (A C)x (B D); A 0, B 2; A C 8 C 8; B D 2 D 0; $ # dx 2 8 tan 2x C' ' '8x 8x 2 dx x dx
4x 1 4x 14x 1 4x 1#
# #
# ## #
"
"a b a b
25. 2s 22s 2 As B C D Es 1 (s 1) s 1 s 1 (s 1) (s 1)
a b# $ # # $
(As B)(s 1) C s 1 (s 1) D s 1 (s 1) E s 1 $ # # # #a b a b a b As ( 3A B)s (3A 3B)s ( A 3B)s B C s 2s 2s 2s 1 D s s s 1 c d a b a b% $ # % $ # $ # E s 1 a b# (A C)s ( 3A B 2C D)s (3A 3B 2C D E)s ( A 3B 2C D)s ( B C D E) % $ #
summing all eq
A C 03A B 2C D 0
3A 3B 2C D E 0 A 3B 2C D 2 B C D E 2
uations 2E 4 E 2;
summing eqs (2) and (3) 2B 2 0 B 1; summing eqs (3) and (4) 2A 2 2 A 0; C 0 from eq (1); then 1 0 D 2 2 from eq (5) D 1; ds 2 (s 1) (s 1) tan s C' ' ' '2s 2 ds ds ds
s 1 (s 1) s 1 (s 1) (s 1)
# " "a b# $ # # $
26. s 81 A s 9 (Bs C)s s 9 (Ds E)ss 81 A Bs C Ds Es s 9 s 9s s 9%
# #
# ##
% # ##
a b a b a b a b A s 18s 81 Bs Cs 9Bs 9Cs Ds Es a b a b% # % $ # # (A B)s Cs (18A 9B D)s (9C E)s 81A 81A 81 or A 1; A B 1 B 0; % $ # C 0; 9C E 0 E 0; 18A 9B D 0 D 18; ds 18 ' ' 's 81 ds s ds
s s 9 s 9s%
# #
# #
a b a b
ln s C k k 9s 9a b#
27. 2 5 8 4 (A B) 2 2 C D2 5 8 4 A B C D 2 2 2 2 2
) ) ) ) )
) ) ) )) )
$ #
# #
# ##
#
$ # #a b a b ) ) ) ) ) ) )a b
A (2A B) (2A 2B C) (2B D) A 2; 2A B 5 B 1; 2A 2B C 8 C 2; ) ) )$ # 2B D 4 D 2; d d d ' ' '2 5 8 4 2 1 2 2
2 2 2 2 2 2) ) ) ) )
) ) ) )) )
$ #
# #
# ##
a b a ba b) ) )
d ' ' ' ' '2 2 d d 2 2 2 2 ( 1) 1 2
d 2 2 d 2 2 2 2
) ) )
) ) ) ) ) ) ) ) )
) ) ) )
) )
" # # #
# # # # #
# #
#
#
)a b a b
a b
512 Chapter 8 Techniques of Integration
ln 2 2 tan ( 1) C " # # ") )# 2 a b) ) )28. 4 2 3 1) ) ) ) ) ) )
) ) ))
% $ #
# # #
$ # $#
4 2 3 1 A B C D E F 1 1 1 1
% $ #a b a b a b ) ) ) )
(A B) 1 (C D) 1 E F (A B) 2 1 C D C D E F ) ) ) ) ) ) ) ) ) ) ) )a b a b a b a b# # % # $ ## A B 2A 2B A B C D C D E F a b a b) ) ) ) ) ) ) ) )& % $ # $ # A B (2A C) (2B D) (A C E) (B D F) A 0; B 1; 2A C 4 ) ) ) ) )& % $ # C 4; 2B D 2 D 0; A C E 3 E 1; B D F 1 F 0;
d 4 tan 2 1 1 C' ' ' ') ) ) ) ) ) ) ) )) ) ))
% $ #
# # #
$ # $#
4 2 3 1 d d d 1 1 1 1 4
"
" # #" #
a b a b a b) ) ) ) a b a b29. 2x 2x ; 1 A(x 1) Bx; x 0 A 1;2x 2x 1 A B
x x x x x(x 1) x(x 1) x x 1$ #
# #
" " "
x 1 B 1; 2x dx x ln x ln x 1 C x ln C ' ' ' '2x 2x 1 dx dx x 1x x x x 1 x$ #
#
# #k k k k 30. x 1 x 1 ; 1 A(x 1) B(x 1);x A B
x 1 x 1 (x 1)(x 1) (x 1)(x 1) x 1 x 1%
# # # #" " " a b a b
x 1 A ; x 1 B ; dx x 1 dx " " " "# # # # #' ' ' 'x dx dx
x 1 x 1 x 1%
#
a b x x ln x 1 ln x 1 C x ln C " " " " $ # # # 3 3 x 1
x x 1k k k k $
31. 9 (after long division); 9x 3x 1 9x 3x 9x 3x 1 A B Cx x x (x 1) x (x 1) x x x 1$ # #
$ # # # #
"
9x 3x 1 Ax(x 1) B(x 1) Cx ; x 1 C 7; x 0 B 1; A C 9 A 2; # # dx 9 dx 2 7 9x 2 ln x 7 ln x 1 C' ' ' ' '9x 3x 1 dx dx dx
x x x x x 1 x$
$ # #
" k k k k
32. (4x 4) ; 12x 4 A(2x 1) B16x 12x 4 12x 4 A B4x 4x 1 4x 4x 1 (2x 1) 2x 1 (2x 1)$
# # # #
A 6; A B 4 B 2; dx 4 (x 1) dx 6 2 ' ' ' '16x dx dx4x 4x 1 2x 1 (2x 1)$
# #
2(x 1) 3 ln 2x 1 C 2x 4x 3 ln 2x 1 (2x 1) C, where C 2 C # # "" " "k k k k2x 133. y ; 1 A y 1 (By C)y (A B)y Cy Ay y 1 By Cy y y y 1 y y 1 y y 1A% #
$ # # #
" " # # a b a b a b A 1; A B 0 B 1; C 0; dy y dy ' ' ' 'y y 1 dy y dyy y y y 1% #
$ #
ln y ln 1 y C y#
# #" #k k a b
34. 2y 2 ; 2y By Cy y y 1 y y y 1 y y y 1 y 1 (y 1) y 1 y 12 2 2 A%$ # $ # $ # # #
a b 2 A y 1 (By C)(y 1) Ay A By Cy By C (A B)y ( B C)y (A C) a b a b a b# # # # A B 0, B C 0 or C B, A C A B 2 A 1, B 1, C 1;
dy 2 (y 1) dy dy' ' ' ' '2y dy y dyy y y 1 y 1 y 1 y 1%
$ # # #
(y 1) ln y 1 ln y 1 tan y C y 2y ln y 1 ln y 1 tan y C, # # " # # "" "# #"k k a b k k a b where C C 1 "
35. e y ln C ln C' ' ' 'e dt e 1e 3e 2 y 3y 2 y 1 y 2 y 2 e
dy dy dy y 1t t2t t t #
c d t#
36. dt e dt; dy y dyy edy e dt' ' ' ' 'e 2e e e 2e 1
e 1 e 1 y 1 y 1 2 y 1y 2y 1 y 1 y y4t 2t t 3t t
2t 2t
3 2
tt
t # # # dy ' dyy 1# ln y 1 tan y C e ln e 1 tan e C y2 2
2t 2t t2 " " "# #
# " "a b a b a b
Section 8.3 Integration of Rational Functions by Partial Fractions 513
37. ; [sin y t, cos y dy dt] dt ln C' ' 'cos y dy dysin y sin y 6 t t 6 5 t 2 t 3 5 t 3
t 2# #
" " " " ln C " 5 sin y 3
sin y 2 38. ; cos y ln C ln ' ' ' 'sin d cos 2
cos cos 2 y y 2 3 y 2 3 y 1 3 y 1 3 cos 1dy dy dy y 2) ) )
) ) )# # " " " " c d ) C
ln C ln C " " 3 1 cos 3 cos 22 cos cos 1 ) )
) )
39. dx dx 3 dx' ' '(x 2) tan (2x) 12x 3x tan (2x)4x 1 (x 2) 4x 1 (x 2)x
# " $ "
# # # #a b tan (2x) d tan (2x) 3 6 3 ln x 2 C "# " "' ' 'a b k kdx dx 6x 2 (x 2) 4 x 2tan 2x# " #a b
40. dx dx dx' ' '(x 1) tan (3x) 9x x tan (3x)9x 1 (x 1) 9x 1 (x 1)x
# " $ "
# # # #a b tan (3x) d tan (3x) ln x 1 C " " " 3 x 1 (x 1) 6 x 1dx dx 1tan 3x' ' 'a b k k# " #a b
41. t 3t 2 1; x ln C; Ce ; t 3 and x 0a b # dx dt dt dt t 2 t 2dt t 3t 2 t 2 t 1 t 1 t 1 x' ' '# C e x ln 2 ln t 2 ln t 1 ln 2 " " # #
t 2 t 2t 1 t 1
x k k k k42. 3t 4t 1 2 3; x 2 3 3 3a b % #
dx dt dt dtdt t 13t 4t 1 t
' ' '% #
#
" #
3
3 tan 3t 3 tan t C; t 1 and x C C " " 1 1 3 3 34 4 41 1 1 x 3 tan 3t 3 tan t " " 143. t 2t 2x 2; ln x 1 ln x 1 ln C;a b k k k k' ' # " " " "# # # # # dx dx dt dt dt tdt x 1 t 2t t t 2 t ' ' # t 1 and x 1 ln 2 ln C C ln 2 ln 3 ln 6 ln x 1 ln 6 x 1 " #3 t 2 t
t 6tk k x 1, t 0 6tt #
44. (t 1) x 1 tan x ln t 1 C; t 0 and x tan ln 1 C dx dx dtdt x 1 t 1 4 4# " " ' '# k k k k1 1 C tan 1 tan x ln t 1 1 x tan (ln (t 1) 1), t 1 " "14 k k45. V y dx dx 3 dx 3 ln 3 ln 25 1 1 1 1 1' ' '
0 5 0 5 0 5
2 5 2 5 2 5
#
" " #&
!&9 x
3x x x 3 x x 3#
46. V 2 xy dx 2 dx 4 dx 1 1 1' ' '0 0 0
1 1 12x 2
(x 1)(2 x) 3 x 1 3 2 x " " "
ln x 1 2 ln 2 x (ln 2) a bk k k k4 43 31 1"!47. A tan x dx x tan x dx ' '
0 0
3 330
" "c d x1 x#
ln x 1 ln 2; 1 1 3 33 3 a b"# # 30 x x tan x dx " "A '0
3
x tan x dx " " "# # # "
A 1 xx 30 0 3' # #
x tan x " "# #"
A a b1 30 1.10 " "# # #A 6 A 3
3 32 1 1 1
514 Chapter 8 Techniques of Integration
48. A dx 3 2 3 ln x ln x 3 2 ln x 1 ln ; ' ' ' '3 3 3 3
5 5 5 54x 13x 9 dx dx dx 125x 2x 3x x x 3 x 1 9#
$ #
&$c dk k k k k k
x dx 4x 3 2 (8 11 ln 2 3 ln 6) 3.90 " " " & $A x 2x 3x A x 3 x 1 Ax 4x 13x 9 dx dx' ' '3 3 35 5 5a b#$ #
c d49. (a) kx(N x) k dt k dt ln kt C;dx dx dx dx xdt x(N x) N x N N x N N x ' ' ' ' ' " " " k , N 1000, t 0 and x 2 ln C ln ln " " " " "250 1000 998 1000 1000 x 250 1000 499
2 x t ln 4t e 499x e (1000 x) 499 e x 1000e x a b499x 499x 1000e1000 x 1000 x 499 e4t 4t 4t 4t 4t4t (b) x N 500 500 500 499 500e 1000e e 499 t ln 499 1.55 days " "# 1000e499 e 44t 4t 4t
4t4t
50. k(a x)(b x) k dtdx dxdt (a x)(b x) (a) a b: k dt kt C; t 0 and x 0 C kt ' 'dx(a x) a x a a x a " " " "# a x x a " " a x a akt 1 akt 1 akt 1
akt a a a kt#
(b) a b: k dt k dt ln kt C; ' ' ' ' 'dx dx dx b x(a x)(b x) b a a x b a b x b a a x " " " t 0 and x 0 ln C ln (b a)kt ln e " b a a a x a a x ab b x b b x b b a kt x
ab 1 ea be
b a kt
b a kt
51. (a) dx x 4x 5x 4x 4 dx' '0 0
1 1x (x 1)
x 1 x 1 74 22% %# #
' & % # 1 (b) 100% 0.04%227 1
1
(c) The area is less than 0.003
52. P(x) ax bx c, P(0) c 1 and P (0) 0 b 0 P(x) ax 1. Next, # w # ; for the integral to be a function, we must have A 0 andax 1 A B C D E
x (x 1) x x x x 1 (x 1)#
$ # # $ #
rational
D 0. Thus, ax 1 Bx(x 1) C(x 1) Ex (B E)x (C 2B)x (B 2C)x C # # # $ $ #
E B; x 1 a 1 E; therefore, 1 2B a 1 2E a 1 2(a 1) aB E 0
C 2B aC
"
a 3
Section 8.4 Trigonometric Integrals 515
8.4 TRIGONOMETRIC INTEGRALS
1. sin x dx sin x sin x dx cos x sin x dx 2cos x cos x sin x dx' ' ' '0 0 0 0
1 1 1 1/2 /2 /2 /25 4 " " a b a b a b# # ## #
sin x dx 2cos x sin x dx cos x sin x dx cos x # ' ' '0 0 0 0
1 1 1 1/2 /2 /24 cos x cos x
3 5
/2# 3 5
! " a b # " )$ & "& 2. sin dx (using Exercise 1) sin dx 2cos sin dx cos sin dx' ' ' '
0 0 0 0
1 1 1 15 4x x x x x x
2 2 2 2 2 2 #
cos cos cos # ! # a bx x x2 3 2 5 23 5% # % # "'$ & "&10 3. cos x dx cos x cos x dx sin x cos x dx cos x dx sin x cos x dx' ' ' ' '
# # #
1 1 1 1 1
1 1 1 1 1
/2 /2 /2 /2 /2
/2 /2 /2 /2 /23 " a b a b
sin x " " sin x33 11
#
#
" " %$ $ $
4. 3cos 3x dx cos 3x cos 3x 3dx sin 3x cos 3x 3dx sin 3x sin 3x cos 3x 3dx' ' ' '0 0 0 0/6 /6 /6 /6
51 1 1 1
" " # a b a b a b# # # %# # cos 3x 3dx sin 3x cos 3x 3dx sin 3x cos 3x 3dx sin 3x # # ' ' '0 0 0
/6 /6 /6sin 3x sin 3x
3 5
61 1 1 1# %
3 50
" ! a b2$ & "&" )
5. sin y dy sin y sin y dy cos y sin y dy sin y dy cos y sin y dy' ' ' ' '0 0 0 0 0/2 /2 /2 /2 /2
7 6 2 21 1 1 1 1
" $a b$ cos y sin y dy cos y sin y dy cos y $ $ $ ! " " ' '0 0
/2 /24 6 cos y cos y cos y
3 51 1 1 a b 3 & (( & ( $ $ " "'0
6. 7cos t dt (using Exercise 5) 7 cos t dt sin t cos t dt sin t cos t dt sin t cos t dt' ' ' ' '0 0 0 0 0/2 /2 /2 /2 /2
7 2 4 61 1 1 1 1
$ $ 7 sin t 7 7 $ $ " " ! a bsin t sin t sin t3 53 & (( & ( $ " "'10 7. sin x dx dx cos x cos x dx dx cos x dx dx' ' ' ' ' '
0 0 0 0 0 0
1 1 1 1 1 1
) ) # " # # # # # # # #4 cos x cos 4x a b" # "# ## # x sin x dx cos 4x dx x sin 4x # # # # # $c d 1 1 1 10 0 0 0' ' 1 1 1 1"# 8. cos 2 x dx dx cos 4 x cos 4 x dx dx cos 4 x dx dx' ' ' ' ' '
0 0 0 0 0 0
1 1 1 1 1 1) ) # " # # % #4 cos 4 x cos x1 1 1 1 a b" " )# ## #1 1
x sin 4 x dx cos x dx x sin x # ) # ) # " $ " "" ")1 11 1 10 0 01 1 0' '
9. 16 sin x cos x dx 16 dx cos x dx dx dx' ' ' ' '
# # #" # " # "# # #1 1 1 1 1
1 1 1 1 1
/4 /4 /4 /4 /4
/4 /4 /4 /4 /4cos x cos x cos 4x % " # % % a b
4x dx cos 4x dx 2x =2 # # c d 11 1 1
1 11
1
1 1/4/4 /4 /4
/4 /4sin 4x
2/4
/4 # #' ' 1 1 1 1
10. 8 sin y cos y dy 8 dy dy cos y dy cos y dy cos y dy' ' ' ' ' '0 0 0 0 0 0
1 1 1 1 1 14 cos y cos y# # $" # " #
# #
# # # #
y sin 2y dy sin y cos y dy dy cos 4y dy cos y dy " # # # a b" " "" # # ##2 cos 4y1 1 1 1 1 10 0 0 0 0 0' ' ' ' '1 sin y cos y dy y sin 4y sin 2y # # '
0 0
1 11 1# " " " "
# ) # # # #1 1 sin 2y33
516 Chapter 8 Techniques of Integration
11. 35 sin x cos x dx 35 sin x sin x cos x dx 35 sin x cos x dx 35 sin x cos x dx' ' ' '0 0 0 0
1 1 1 1/2 /2 /2 /24 3 4 4 6 " a b#
35 35 7 5 ! # a b a bsin x sin x5 7 /25 7 1012. cos 2x sin 2x dx'
0 0
1 12 cos 2x
3 ! " " "# ' '3
13. 8cos 2 sin 2 d 8 cos 2'0 0
0
1)
11
/43 4cos 2
4
/4 /4) ) ) ) ! " " c d a b a b"# 4
14. sin 2 cos 2 d sin 2 sin 2 cos 2 d sin 2 cos 2 d sin 2 cos 2 d' ' ' '0 0 0 0
1 1 1 1/2 /2 /2 /22 3 2 2 2 4) ) ) ) ) ) ) ) ) ) ) ) ) " a b
! " "# #sin 2 sin 23 5 /23 5) ) 1015. dx sin dx sin dx cos ' ' '
0 0 0 0
2 2 2cos x x x x 2
1 1 11 "# # # # # # # %
16. cos 2x dx sin 2x dx sin 2x dx cos 2x' ' '0 0 0 0
1 1 1 1 " # l l # # # # # #
17. sin t dt cos t dt cos t dt cos t dt sin t sin t' ' ' '0 0 0 0
1 1 1 1
1
1 1
1 c d c d" l l " ! ! " ## /2 /2 /2 /2
18. cos d sin d sin d cos ' ' '0 0 0 0
1 1 11 c d" l l " " ##) ) ) ) ) ) )
19. tan x dx sec x dx sec x dx ln sec x tan x ln ln' ' '
#1 1 1
1 1 11
1/4 /4 /4
/4 /4 /4 /4/4
c d " l l l l # " # " ln ln # " # #"#"20. sec x dx tan x dx tan x dx tan x dx ln sec x ln sec x ' ' ' '
!#
!!
!1 1 1
1 1 11
/4 /4 /4
/4 /4 /4 /4 c d c d " l l l l l l1/4
ln ln ln ln ln ln " # # " # # #a b a b 21. cos 2 d sin d sin d cos sin ' ' '
0 0 0 0
1 1 11
/2 /2 /2 /2) ) ) ) ) ) ) ) ) ) ) ) c d a b" # l l # # # " #
22. cos t dt sin t dt sin t dt sin t dt sin t dt cos t sin t dt' ' ' ' ' ' !
# # $ $ $ #$# $#! !
1 1 1 1 1
1 1 1 1a b a b a b " " cos t sin t dt sin t dt cos t sin t dt sin t dt cos t sin t dt cos t " ' ' ' ' '
! ! !# # #
! ! !
1 1 1
1 1 1
a b cos t33 cos t " " " " cos t33 1! " " " " )$ $ $ $ $23. 2 sec x dx; u sec x, du sec x tan x dx, dv sec x dx, v tan x;'
!$ #
1/3
2 sec x dx 2 sec x tan x sec x tan x dx sec x sec x dx' ' '
! ! !$ !
$1 1 11/3 /3 /32 2 # # " ! # # $ # "c d a b
sec x dx sec x dx; 2 2 sec x dx ln sec x + tan x % $ # # % $ # l l c d' ' '
! ! !$ $ !
$1 1 1 1/3 /3 /3
2 2 sec x dx ln + ln ln '
!$
1/3 % $ # l " !l # l # $ l % $ # # $
2 sec x dx ln '
!$
1/3 # $ # $
Section 8.4 Trigonometric Integrals 517
24. e sec e dx; u sec e , du sec e tan e e dx, dv sec e e dx, v tan e .' x x x x x x x x x$ #a b a b a b a b a b a b e sec e dx sec e tan e sec e tan e e dx' 'x x x x x x x$ #a b a b a b a b a b sec e tan e sec e sec e e dx "a b a b a ba ba bx x x x x' # sec e tan e sec e e dx sec e e dx a b a b a b a bx x x x x x' '$ e sec e dx sec e tan e ln sec e tan e C# ' x x x x x x$a b a b a b a b a b e sec e dx sec e tan e ln sec e tan e C' x x x x x x$ "#a b a b a b a b a b 25. sec d tan sec d sec d tan sec d tan ' ' ' '
! ! ! !
!
1 1 1 1)
1/4 /4 /4 /44 2 2 2 2 2 tan
3
4) ) ) ) ) ) ) ) ) ) ) " a b 3
" ! a b" %$ $26. 3sec 3x dx tan 3x sec 3x 3dx sec 3x 3dx tan 3x sec 3x 3dx' ' ' '
! ! ! !
1 1 1 1/12 /12 / /124 2 2 2 2 2a b a b a b a b a b a ba b "
tan 3x " ! a b a b tan 3x3 123a b 1! " %$ $27. csc d cot csc d csc d cot csc d cot' ' ' '
1 1 1 1
1 1 1 1)
1
1/4 /4 /4 /4
/2 /2 /2 /24 cot
3
2
/4) ) ) ) ) ) ) ) ) ) ) " a b # # # # # $
! " a b " %$ $28. csc d cot csc d csc d cot csc d cot' ' ' '
1 1 1 1
1 1 1 1) ) ) ) ) ) )
1
1/2 /2 /2 /24 cot
3 2$ $ " $ $ ' '# # # # # # #
# # # # #
) ) ) ) $ #)
' ! # ! ' " # " )a b a b29. 4 tan x dx 4 sec x tan x dx 4 sec x tan x dx 4 tan x dx ln sec x' ' ' '0 0 0 0
/4 /4 /4 /43 tan x
41 1 1 1 1 " % % l la b # # # !#
2 ln ln ln " % # # ! % " # # #a b 30. 6 tan x dx 6 sec x tan x dx 6 sec x tan x dx 6 tan x dx' ' ' '
# #
1 1 1 1
1 1 1 1
/4 /4 /4 /4
/4 /4 /4 /44 2 2 2 " a b
6 sec x tan x dx 6 sec x 1 dx 6 sec x dx 6 dx ' ' ' ' ' $
#1 1 1 1
1 1 1 11
1/4 /4 /4 /4
/4 /4 /4 /42 2 2 tan x
4
4a b $
tan x x # " " ' ' % ' " " $ )a b c d c d a ba b a b1 11 1
1 1
$ $# #
4 44 4 1
31. cot x dx csc x cot x dx csc x cot x dx cot x dx ln csc x' ' ' '1 1 1 1
1 1 1 1 1
1/6 /6 /6 /6
/3 /3 /3 /33 2 2 cot x
3
6 " l la b ##
ln ln ln $ # $" " # %# $ $$ 32. 8 cot t dt 8 csc t cot t dt 8 csc t cot t dt 8 cot t dt' ' ' '
1 1 1 1
1 1 1 1
/4 /4 /4 /4
/2 /2 /2 /24 2 2 2 2 2 " a b
8 8 csc t dt cot t t " ! " ) ) ) ! " % # # a b a b c d c d a bcot t3 324 /4/2
2 2 24 4
3 1
1 1
11 1
1 1
) ) "' $ $
' 1 1 1
33. sin 3x cos 2x dx sin x sin 5x dx cos x cos 5x' '
! !" " " " " " '# # & # & & &
!
1 1 1 " " a b
34. sin 2x cos 3x dx sin x sin 5x dx cos x cos 5x' '! !
" " " " " " ## # & # # & &
!
1 11
2 2 2 ! " a b a b a ba b
518 Chapter 8 Techniques of Integration
35. sin 3x sin 3x dx cos cos 6x dx dx cos 6x dx x sin 6x' ' ' '
" " " " "# # # # "# # #1 1 1 1
1 1 1 11
1
1 1 ! ! a b 136. sin x cos x dx sin sin 2x dx sin 2x dx cos 2x' ' '
! ! !
" " " " "# # % % #
#!
1 1 11
2 2 2 ! " " a b c d a b
37. cos 3x cos 4x dx cos x cos 7x dx sin x sin 7x 0 0' '! !
" " " "# ( !
1 11
a b a b a ba b 2 238. cos 7x cos x dx cos 6x cos 8x dx sin 6x sin 8x 0' '
" " " "#
1 1
1 11
12 2
2 2
2 6 82
2 a b 39. x t t x ; y y ; t x 2 ; ! # ! #$ # $ #$# #
t x# $
A x dx; u du uu xdu 9x dx
# " " "
' '! !# % $
* #% %%
$
* $#
*
!
2 2x
9
9 9
2#$ #$$
#$
1 a b1 1 2 " * "##(
#$ $#1
40. y ln cos x ; y tan x; y tan x; tan x dx sec x dx ln sec x tan x " l l l la b a b c dw w # #! !
#
!sin x
cos x
3 3 /3' '1 1 1
ln 2 ln ln 2 $ " ! $ a b
41. y ln sec x ; y tan x; y tan x; tan x dx sec x dx ln sec x tan x " l l l la b a b c dw w ##! !
#
!sec x tan x
sec x
4 4 /4' '1 1 1
ln ln ln # " ! " # " a b
42. M sec x dx ln sec x tan x ln ln ln l l # " l # "l '
#"
#"1
11
14
4 /44c d
y dx tan x " " " " " "
#
ln ln ln ln
#" #" #" #"
#" #" #" #"
'1
11
14
4sec x 4
4#
# #
c d a ba b x, y ln !a b #"#" "
43. V sin x dx dx dx cos 2x dx x sin 2x ! ! ! 1 1 1' ' ' '! ! ! !
# "# # # # #! !
1 1 1 11 1 1 1 1 1 11 1cos 2x
2 4 4c d c d a b a b #
44. A cos 4x dx cos 2x dx cos 2x dx cos 2x dx cos 2x dx " # l l # # #' ' ' ' '! ! ! % $ %
% $ %1 1 1 1 1
1 1
sin 2x sin 2x sin 2x " ! " " ! " # # # # # # # # # ## # # # # #
% $ %! % $ %
c d c d c d a b a b a b 1 11
1
1
45. (a) m n m n and m n sin mx sin nx dx cos m n x cos m n x dx# ## #
"# ! !
' 'k k
k k1 1 c da b a b sin m n x sin m n x " " "#
# a b a bm n m n
k 1k
sin m n k sin m n k sin m n k sin m n k # # " " " " " "# # a b a b a b a ba ba b a ba b a b a bm n m n m n m n1 1 sin m n k sin m n k sin m n k sin m n k !" " " "# # # # a b a b a b a bm n m n m n m na b a b a b a ba b a b a b a b sin mx and sin nx are orthogonal.
(b) Same as part since cos dx . m n m n and m n cos mx cos nx dx"## #
# #' 'k k
k k1 1! ! ! 1
cos m n x cos m n x dx sin m n x sin m n x " " " "# # # #'
k
k
m n m n
k1 1c d a b a ba b a b k
sin m n k sin m n k sin m n k sin m n k # # " " " "# # # # a b a b a b a bm n m n m n m na b a b a b a ba ba b a ba b a b a b1 1 sin m n k sin m n k sin m n k sin m n k !" " " "# # # # a b a b a b a bm n m n m n m na b a b a b a ba b a b a b a b
Section 8.5 Trigonometric Substitutions 519
cos mx and cos nx are orthogonal.
(c) Let m n sin mx cos nx sin sin m n x and sin dx and sin m n x dx 0 ! ! ! " " "# # ## #a b a ba b a ba b ' 'k kk k1 1
sin mx and cos nx are orthogonal if m n. Let m n.
sin mx cos nx dx sin m n x sin m n x dx cos m n x cos m n x' 'k kk k
m n m n
k# #" " " "# #
#1 1 1 c d a b a ba b a b
k
cos m n k cos m n k cos m n k cos m n k # # " " " "# # # # a b a b a b a bm n m n m n m na b a b a b a ba ba b a ba b a b a b1 1 cos m n k cos m n k cos m n k cos m n k !" " " "# # # # a b a b a b a bm n m n m n m na b a b a b a ba b a b a b a b sin mx and cos nx are orthogonal.
46. f x sin mx dx sin nx sin mx dx. Since sin nx sin mx dx ,for m n1 for m n" "
"
1 1 11 1 1
1 1 1' ' 'a b ! ! nN
an
the sum on the right has only one nonzero term, namely sin mx sin mx dx a .a mm1 11'
8.5 TRIGONOMETRIC SUBSTITUTIONS
1. y 3 tan , , dy , 9 y 9 1 tan ) ) )1 1 ) )) )
)
# ## # "
3 d 9 cos
cos cos 3 39 ycos # #
#
a b k k because cos 0 when ; ) ) 1 1# # 3 ln sec tan C ln C ln 9 y y C' ' 'dy y9 y
cos d d3 cos cos 3 3
9 y
w w ##
#
#
) ) )) )
k k ) ) 2. ; 3y x ; x tan t, t , dx , 1 x ;' '3 dy1 9y
dx dt1 x cos t cos t # # #
"#
#
#
c d 1 1 ln sec t tan t C ln x 1 x C ln 1 9y 3y C' 'dx dt
1 x cos t # ##
#
"
cos t
k k
3. tan tan 1 tan ( 1)' # # # # # #
" " " " "" " "#
#2
2 dx x4 x 4 4 4# 1 1 1
4. tan tan 1 tan 0 0' '0 0
2 2dx dx x8 2x 4 x 4 16 # # # # # # # # #
" " " " " " " "" " "#
!# # 1 1
5. sin sin sin 0 0'0
23 dx x9 x 3 6 6
" " "$#
!"# # 1 1
6. ; t 2x sin t sin sin 0 0' '0 0
1 2 2 1 2 2 1 20
2 dx dt1 4x 1 t 2 4 4
" " ""# #
c d c d 1 1
7. t 5 sin , , dt 5 cos d , 25 t 5 cos ; ) ) ) ) )1 1# # # 25 t dt (5 cos )(5 cos ) d 25 cos d 25 d 25 C' ' ' ' # # # #) ) ) ) ) )1 cos 2 sin 24) ) ) sin cos C sin C sin C 25 25 t t 25 t5 5 5 5
25 t t 25 t# # # #
" " a b ) ) ) # #
8. t sin , , dt cos d , 1 9t cos ; " "# # #3 3) ) ) ) )1 1
1 9t dt (cos )(cos ) d cos d sin cos C sin (3t) 3t 1 9t C' ' ' a b # #" " " "# "3 3 6 6) ) ) ) ) ) ) ) 9. x sec , 0 , dx sec tan d , 4x 49 49 sec 49 7 tan ; 7 7# # # # #) ) ) ) ) ) )
1 sec d ln sec tan C ln C' 'dx 2x
4x 49 sec tan d
7 tan 7 74x 49
#
#
#
" " "# # #
7
) ) )
)' ) ) ) )k k
520 Chapter 8 Techniques of Integration
10. x sec , 0 , dx sec tan d , 25x 9 9 sec 9 3 tan ; 3 35 5) ) ) ) ) ) )1
## #
sec d ln sec tan C ln C' '5 dx 5x25x 9
5 sec tan d3 tan 3 3
25x 9 #
#
35 ) ) )
)' ) ) ) )k k
11. y 7 sec , 0 , dy 7 sec tan d , y 49 7 tan ; ) ) ) ) ) )1# # dy 7 tan d 7 sec 1 d 7(tan ) C' 'y 49y 7 sec (7 tan )(7 sec tan ) d# # # ) ) ) )
)' ') ) ) ) ) )a b
7 sec C y 497 7y# "12. y 5 sec , 0 , dy 5 sec tan d , y 25 5 tan ; ) ) ) ) ) )1# # dy tan cos d sin d (1 cos 2 ) d' ' ' ' 'y 25y 125 sec 5 5 10(5 tan )(5 sec tan ) d#
$ $
" " "# # # ) ) ) ))
) ) ) ) ) ) )
sin cos C sec C C " " " #10 10 5 y y 10 yy y 25 y 255 seca b ) ) ) # #"#
y5
13. x sec , 0 , dx sec tan d , x 1 tan ; ) ) ) ) ) )1# # sin C C' ' 'dx sec tan d d
x x 1 sec tan sec xx 1# #
#
#
) ) ) )) ) )
)
14. x sec , 0 , dx sec tan d , x 1 tan ; ) ) ) ) ) )1# # 2 cos d 2 d sin cos C' ' ' '2 dx 2 tan sec d 1 cos 2
x x 1 sec tan $ # $ #
# ) ) ) )
) )) ) ) ) ) )
tan cos C sec x x 1 C sec x C ) ) )# " "# " # x x
x 1 ##
15. x 2 tan , , dx , x 4 ; ) )1 1 )) )# #
#2 d 2cos cos #
8 8 ;' ' ' 'x dx sin d
x 48 tan (cos ) d cos 1 ( sin ) d
cos cos cos
$ $
#
$ #
# % % a b a b ) ) ) ) ) )
)
) )
) )
t cos 8 dt 8 dt 8 C 8 sec Cc d ) )' 't 1 sect tt t 3t 3# $% %# $ " " " " ) 8 C x 4 4 x 4 C a b a bx 4 x 48 3 3# # $## " # $# #16. x tan , , dx sec d , x 1 sec ; ) ) ) ) )1 1# #
# # C C' ' 'dx sec d cos d
x x 1 tan sec sin sin xx 1# #
#
# #
#
" ) ) ) )) ) ) )
17. w 2 sin , , dw 2 cos d , 4 w 2 cos ; ) ) ) ) )1 1# # # 2 2 cot C C' ' '8 dw 8 2 cos d d
w 4 w 4 sin 2 cos sin w2 4 w# #
# #
#
) ) )
) ) ))
18. w 3 sin , , dw 3 cos d , 9 w 3 cos ; ) ) ) ) )1 1# # # dw cot d d csc 1 d' ' ' ' '9 w
w 9 sin sin3 cos 3 cos d 1 sin # ### # #
#
) ) ) )) )
) ) ) ) ) a b cot C sin C ) ) 9 w
w 3w "#
19. x sin , 0 , dx cos d , 1 x cos ; ) ) ) ) )13 a b# $$# 4 d 4 sec 1 d' ' ' '
0 0 0 0
3 2 3 3 3 4x dx 4 sin cos d 1 cos
1 x cos cos# # #
#
$#
$ #a b # 1 1 1
) ) ) )
) ) a b) ) )
4 tan 4 3 c d ) ) 1 1$! 43
Section 8.5 Trigonometric Substitutions 521
20. x 2 sin , 0 , dx 2 cos d , 4 x 8 cos ; ) ) ) ) )16 a b# $$# tan ' ' '
0 0 0
1 6 6dx 2 cos d d4 x 8 cos 4 cos 4 12
34 3a b
" " "'!#
$#
$ #
1 1
) ) )
) )
1c d)21. x sec , 0 , dx sec tan d , x 1 tan ; ) ) ) ) ) )12 a b# $$# C C' ' 'dx sec tan d cos d x
x 1 tan sin sin x 1a b # $# $ # #"
) ) ) ) )
) ) )
22. x sec , 0 , dx sec tan d , x 1 tan ; ) ) ) ) ) )12 a b# & d C C' ' 'x dx sec sec tan d cos x
x 1 3 x 1tan 3 sinsin# # $
# #
$#
& $%a b a b " ) ) ) ) )
) ))
)
23. x sin , , dx cos d , 1 x cos ; ) ) ) ) )1 1# ## $$#a b
cot csc d C C' ' 'a b 1 x dxx sin 5 5 x
cos cos d cot 1 x % # "
$#
' '
$ &
#
) ) ) ))
) ) ) 24. x sin , , dx cos d , 1 x cos ; ) ) ) ) )1 1# #
# "#a b cot csc d C C' ' 'a b 1 x dx
x sincos cos d cot
3 3 x1 x # # "
$#
"#
% %
$
#
) ) ) ))
) ) ) 25. x tan , , dx sec d , 4x 1 sec ; " "# # # #
# # %#) ) ) ) )
1 1 a b 4 cos d 2( sin cos ) C 2 tan 2x C' ' '8 dx 4x
4x 18 sec d
sec 4x 1a b
a b# #"
#
#
% ## "
) )
)) ) ) ) )
26. t tan , , dt sec d , 9t 1 sec ; " "# ## # #
3 3) ) ) ) )1 1
2 cos d sin cos C tan 3t C' ' '6 dt 3t9t 16 sec d
sec 9t 1a b
a b# #"
#
% ## "
3 ) )
)) ) ) ) )
27. v sin , , dv cos d , 1 v cos ; ) ) ) ) )1 1# ## &a b
tan sec d C C' ' 'v dv sin cos d tan v1 v cos 3 3 1 v# # $
#
&
#a b # # "
$
) ) ) ))
) ) ) 28. r sin , ; ) )1 1# # cot csc d C C' ' 'a b 1 r dr
r sin 7 7 rcos cos d cot 1 r ' # "
(#
) )
& (
#
) ) ) ))
) ) ) 29. Let e 3 tan , t ln (3 tan ), tan tan , dt d , e 9 9 tan 9 3 sec ;t 2t ) ) ) ) ) )" "" %$ $ # sectan # )) sec d ln sec tan ' ' '
0 tan 1 3 tan 1 3
ln 4 tan 4 3 tan 4 3tan 4e dt 3 tan sec d
e 9 tan 3 sec t
2t " "" "
"
) ) )
) )
#
) ) ) )c dk k 3tan 1 3 " ln ln ln 9 ln 1 10 5 43 3 3 310 "
30. Let e tan , t ln (tan ), tan tan , dt d , 1 e 1 tan sec ;t 2t ) ) ) ) ) )" " # # 3 4 sec4 3 tan # )) cos d sin ' ' '
ln 3 4 tan 3 4 tan 3 4
ln 4 3 tan 4 3 tan 4 3tan 4
e dt1 e
(tan ) dsec
t
2ta b
$#$
" "
" "
"
) )
)
sectan #
)
)
) ) )c d $%
3tan"
4 35 5 5
"
31. ; u 2 t, du dt ; u tan , , du sec d , 1 u sec ;' '1 12 1 3
1 4 1
2 dt 2 dut 4t t t 1 u 6 4
"
# # #
#
) ) ) ) )1 1
2 2' '1 3 6
1 4
2 du 2 sec d1 u sec 4 6 6
%'# ##
1
1
) ) 1 1 1
)
1
1c d )
522 Chapter 8 Techniques of Integration
32. y e , 0 , dy e sec d , 1 (ln y) 1 tan sec ; tan tan4) )1) ) ) ) )# # # d sec d ln sec tan ln 1 2' ' '
1
e 4 4dyy 1 (ln y) 0 0
e sece sec
%!#
#
1 1 tan
tan
)
)
)
)
1) ) ) ) )c dk k
33. x sec , 0 , dx sec tan d , x 1 sec 1 tan ; ) ) ) ) ) ) )1# # # C sec x C' 'dx sec tan d
x x 1 sec tan #" ) ) )
) ))
34. x tan , dx sec d , 1 x sec ; ) ) ) )# # #
C tan x C' 'dx sec dx 1 sec# ##
" ) )
))
35. x sec , dx sec tan d , x 1 sec 1 tan ; ) ) ) ) ) ) # # sec d tan C x 1 C' ' 'x dx sec sec tan d
x 1 tan ## # ) ) ) )
)
) ) ) 36. x sin , dx cos d , ; ) ) ) )1 1# # C sin x C' 'dx cos d
1 x cos "#
) ))
)
37. x x 4; dy x 4 ; y dx; x 2 sec , 0dx 2 sec tan d
x 4 2 tan
dydx x x
dx x 4
# # #
#
' #) )
) ) )
)
1
y 2 tan d 2 sec 1 d 2(tan ) C ' ' '(2 tan )(2 sec tan ) d2 sec ) ) ) )) # #) ) ) ) ) )a b 2 sec C; x 2 and y 0 0 0 C C 0 y 2 sec x 4 x 4x x# # # # # #" "
38. x 9 1, dy ; y ; yx 3 sec , 0dx 3 sec tan d
x 9 3 tan
#
#
#
dydx 3 tan
dx dx 3 sec tan dx 9 x 9 # #' '
) )
) ) )
)
1
) ) )
)
sec d ln sec tan C ln C; x 5 and y ln 3 ln 3 ln 3 C C 0 ' ) ) ) )k k x3 3x 9 # y ln x3 3x 9 #
39. x 4 3, dy ; y 3 tan C; x 2 and y 0 0 tan 1 Ca b# " " # # # dydx x 4 x 43 dx dx 3 x 3# #' C y tan 3 3 x 38 8
1 1
# #"
40. x 1 x 1, dy ; x tan , dx sec d , x 1 sec ;a b a b# # # $# $##
dydxdx
x 1a b# $# ) ) ) )
y cos d sin C tan cos C C C; x 0 and y 1 ' 'sec d tan xsec sec x 1#
$
#
) ) )
) )) ) ) ) )
1 0 C y 1 xx 1 #
41. A dx; x 3 sin , 0 , dx 3 cos d , 9 x 9 9 sin 3 cos ; '0
3 9 x3
## ## ) ) ) ) ) )
1 A 3 cos d sin cos ' '
0 0
2 21 1 3 cos 3 cos d 3 33 4
) ) ) 11 ##
#!) ) ) ) )c d
Section 8.5 Trigonometric Substitutions 523
42. V dx 4 ; ' '0 0
1 11 1 2 dx1 x x 1 # # # #a b
x tan , dx sec d , x 1 sec ; ) ) ) )# # #
V 4 4 cos d 1 1 ) )' '0 0
4 41 1 sec d
sec
#
%
) )
)
#
2 (1 cos 2 ) d 2 1 1 ) ) 1 ) 1'0
41 sin 2) 11# #
%
!
43. C C' ' 'dx 2 dz 2 21 sin x (1 z) 1 z1 1 tan 2 dz
1 z2z
1 z
#
#
#
#
x
44. ln 1 z C' ' ' 'dx 2 dz dz1 sin x cos x 1 z 2z 1 z 1 z1
2 dz
1 z2z 1 z
1 z 1 z
#
# #
#
# #
k k ln tan 1 C x#45. (1 2) 1' ' '
0 0 0
2 1 11 dx 2 dz 21 sin x (1 z) 1 z1
"
!
2 dz
1 z2z
1 z
#
#
#
46. 3 1' ' '1
1
3 1 3 1 3
2 1 1dx dz 11 cos x z z1
"
" $
2 dz
1 z1 z1 z
#
#
#
#
47. tan tan ' ' ' '0 0 0 0
2 1 1 11 d 2 dz 2 dz 2 z 22 cos 2 2z 1 z z 32 3 3 3 3
)
)
" ""
!
" 2 dz
1 z1 z1 z
#
#
#
# # #
1 1
3 339
48. ' ' ' '1
1
2 1 1 1
2 3 3 3 3cos d 1
sin cos sin 2z 2z 2z 2z2 1 z dz) )
) ) )
a b1 z 2 dz1 z 1 z2z 1 z
1 z
2z1 z
#
# #
#
#
# #
#
$ $
z2z#
dz
ln z ln 3 0 (ln 3 2) ln 3 1 " " " " " "# # # #$"z 3 ln 34 4 4 4 4#
49. ln C' ' ' 'dt 2 dz 2 dzsin t cos t 2z 1 z (z 1) 2 2 z 1 2
z 1 2
"
2 dz1 z2z 1 z
1 z 1 z
#
# #
#
# #
ln C "
2 tan 1 2
tan 1 2 tt##
50. ' ' ' 'cos t dt1 cos t 1 z 1 z 1 z12 1 z dz 2 1 z dz
1 z 1 z 1 z
a b a ba b a b a b a b a b
1 z 2 dz1 z 1 z
1 z1 z
#
# #
#
#
# #
# # #
# # # #
2 2 tan z C cot t C ' ' ' ' 'a ba b a b1 z dz1 z z z 1 z 1 z z z 1 zdz dz dz dz t #" "#
# # # # # # #
51. sec d' ' ' ' ' ' ') ) d 2 dz 2 dz dz dzcos 1 z (1 z)(1 z) 1 z 1 z)
)
2 dz1 z1 z1 z
#
#
#
#
ln 1 z ln 1 z C ln C k k k k 1 tan1 tan )
)
#
#
52. csc d ln z C ln tan C' ' ' ') ) d dzsin z) )
)
2 dz1 z
2z1 z
#
#
k k #
524 Chapter 8 Techniques of Integration
8.6 INTEGRAL TABLES AND COMPUTER ALGEBRA SYSTEMS
1. tan C' dx 2 x 3x x 3 3 3
" (We used FORMULA 13(a) with a 1, b 3)
2. ln C ln C' dxx x 4 x 4 24 x 4 4
x 4 4 x 4 2
" "
#
(We used FORMULA 13(b) with a 1, b 4)
3. 2 x 2 dx 2 x 2 dx' ' ' ' 'x dx dxx 2 x 2 x 2
(x 2) dx
" "
2 x 2 4 C 2 21 3 1 1 3x 2 x 2 2(x 2) $ "
(We used FORMULA 11 with a 1, b 2, n 1 and a 1, b 2, n 1)
4. ' ' ' ' 'x dx 3 dx dx 3 dx(2x 3) (2x 3) (2x 3)(2x 3) dx
2x 3 2x 3 " "# # # #
$# $# $#
$
2x 3 dx 2x 3 dx C " "# # # # # #
" $ ' ' 3 2 3 22x 3 2x 31 ( 1) " " (2x 3 3) C C "
#
2x 3 2x 3(x 3)
(We used FORMULA 11 with a 2, b 3, n 1 and a 2, b 3, n 3)
5. x 2x 3 dx (2x 3) 2x 3 dx 2x 3 dx 2x 3 dx 2x 3 dx' ' ' ' ' " "# # # #$ "3 3 C 1 C C " # # # # # 2 3 2 2x 32x 3 2x 35 3 5 5(2x 3) (2x 3) (x 1) & $
$# $#
(We used FORMULA 11 with a 2, b 3, n 3 and a 2, b 3, n 1)
6. x(7x 5) dx (7x 5)(7x 5) dx (7x 5) dx 7x 5 dx 7x 5 dx' ' ' ' ' $# $# $#" " & $7 7 7 75 5 C 2 C " 7 7 7 7 7 5 49 72 5 27x 5 7x 5 (7x 5) 2(7x 5) ( & C (7x 5)49 714x 4 (We used FORMULA 11 with a 7, b 5, n 5 and a 7, b 5, n 3)
7. dx C' ' 9 4x 9 4xx x ( 4) dxx 9 4x
# #
(We used FORMULA 14 with a 4, b 9) 2 ln C 9 4x 9 4x 9x 9 9 4x 9
"
(We used FORMULA 13(b) with a 4, b 9) ln C
9 4x 9 4x 3x 32 9 4x 3
8. C' 'dx 4 dxx 4x 9 x 4x 9
4x 9( 9)x 18#
(We used FORMULA 15 with a 4, b 9) tan C 4x 99x 9 92 2 4x 99
" (We used FORMULA 13(a) with a 4, b 9) tan C 4x 99x 27 94 4x 9 "
Section 8.6 Integral Tables and Computer Algebra Systems 525
9. x 4x x dx x 2 2x x dx sin C' ' # # # #" (x 2)(2x 3 2) 2 2 x x6 2 x 2 # $ 4 sin C 4 sin C (x 2)(2x 6) 4x x (x 2)(x 3) 4x x6 3
x 2 x 2 " " # #
# #
(We used FORMULA 51 with a 2)
10. dx dx 2 x x sin C x x sin (2x 1) C' ' x xx x
2 x x x " " "# # #
# #" "#"
#
#
"
#
"
#
We used FORMULA 52 with a "#
11. ln C ln C' 'dx dxx 7 x
x 7 x 7 7
7 7 x
x x
7 7 x
" "
#
#
#
#
#
#
We used FORMULA 26 with a 7
12. ln C ln C' 'dx dxx 7 x
x 7 x 7 7
7 7 x
x x
7 7 x
" "
# #
#
#
#
#
We used FORMULA 34 with a 7 13. dx dx 2 x 2 ln C 4 x 2 ln C' ' 4 x 2 x 2 2 x 2 4 x
x x x x # # ## # # # # #
(We used FORMULA 31 with a ) #
14. dx dx x 2 2 sec C x 4 2 sec C' ' x 4 x 2x x
x x# # # # # #" "# #
(We used FORMULA 42 with a ) #
15. 25 p dp 5 p dp 5 p sin C 25 p sin C' ' # # # # # ## # # #" "p p p p5 255 5# (We used FORMULA 29 with a 5)
16. q 25 q dq q 5 q dq sin q 5 q 5 2q C' '# # " # ## # # # #" a b 58 5 8q% sin q 25 q 25 2q C 6258 5 8
q" #" # a b (We used FORMULA 30 with a 5)
17. dr dr sin r 2 r C 2 sin r 4 r C' 'r r 2 r r4 r 2 r# # #
# # #
# # # # #" "" "# # #
(We used FORMULA 33 with a 2)
18. cosh C ln s s 2 C ln s s 2 C' 'ds ds ss 2
s 2 2 # # #
" # ##
We used FORMULA 36 with a 2 19. tan tan C tan tan C' d 2 5 4 25 4 sin 2 5 4 4 3 3 42 25 16
) 1 ) 1
) # " "
" " )
(We used FORMULA 70 with b 5, c 4, a 2)
20. ln C ln C' d 1 5 4 sin 2 3 cos 24 5 sin 2 4 5 sin 2 6 4 5 sin 22 25 165 4 sin 2 25 16 cos 2) ) )
) ) )
) )
"
(We used FORMULA 71 with a 2, b 4, c 5)
526 Chapter 8 Techniques of Integration
21. e cos 3t dt (2 cos 3t 3 sin 3t) C (2 cos 3t 3 sin 3t) C' 2t e e2 3 132t 2t# #
(We used FORMULA 108 with a 2, b 3)
22. e sin 4t dt ( 3 sin 4t 4 cos 4t) C ( sin 4t 4 cos 4t) C' 3t $ e e( 3) 4 25
# #
3t 3t
(We used FORMULA 107 with a 3, b 4)
23. x cos x dx x cos x dx cos x cos x' ' ' '" " " " " # #" " x x dx x x dx1 1 1 1 1 x 1 x
1 1 1 1
# #
# #
(We used FORMULA 100 with a 1, n 1) cos x sin x x 1 x C cos x sin x x 1 x C x x 4 4# #
# # # # # #" " " "" " " " " "# #
(We used FORMULA 33 with a 1)
24. x tan x dx x tan x dx tan x tan x' ' ' '" " " " " # # " " " " " a b a bx x dx x x dx1 1 1 1 1 x1 x1 1 1 1 a b# # # # # (We used FORMULA 101 with a 1, n 1) tan x dx (after long division) " x 1 x#
## # " " "'
tan x dx dx tan x x tan x C x tan x x C " x x1 x# #
## # # # # # #" " " # "" " " " " "' ' a ba b
25. ln C' 'ds ds s s 39 s 3 s 2 3 3 s 4 3 s 3a b a b a b " # $ #
# # # # #
3 (We used FORMULA 19 with a 3) ln C s s 318 9 s 108 s 3a b " # 26. ln C' 'd d
22 2 2 2 4 2
22
) ) )
)) )
)
)a b
"
## #
#
#
# #
#
3 We used FORMULA 19 with a 2 ln C )
)
)
)4 2 8 2 22a b
"
#
27. dx' ' 4x 9 4x 9x x 24 dxx 4x 9
#
(We used FORMULA 14 with a 4, b 9) 2 ln C ln C
4x 9 4x 9 9 4x 9 4x 9 3x x 39 4x 9 9
24x 9 3
"
(We used FORMULA 13(b) with a 4, b 9)
28. dx C' ' 9x 4 9x 4x x 29 dxx 9x 4
#
(We used FORMULA 14 with a 9, b 4) tan C tan C 9x 4 9x 4 9x 4x 4 x9 2 9x 4 94
# # #
" " (We used FORMULA 13(a) with a 9, b 4)
29. dt 2 3t 4 ( 4)' ' 3t 4t dtt 3t 4
(We used FORMULA 12 with a 3, b 4) 2 3t 4 4 tan C 2 3t 4 4 tan C 2 3t 4
4 43t 4
" " #
(We used FORMULA 13(a) with a 3, b 4)
Section 8.6 Integral Tables and Computer Algebra Systems 527
30. dt 2 3t 9 9' ' 3t 9t dtt 3t 9
(We used FORMULA 12 with a 3, b 9) 2 3t 9 9 ln C 2 3t 9 3 ln C 19 3t 9 93t 9 9 3t 9 33t 9 3 (We used FORMULA 13(b) with a 3, b 9)
31. x tan x dx tan x dx tan x dx' ' '# " " " " " x x x x2 1 2 1 1 x 3 3 1 x2 1 2 1 $ $# #
(We used FORMULA 101 with a 1, n 2); dx x dx ln 1 x C x tan x dx' ' ' 'x x dx x1 x 1 x$ #
# # # #" # # " a b
tan x ln 1 x C x x3 6 6$ #" #" a b
32. dx x tan x dx tan x dx tan x dx' ' ' 'tan x x x x xx ( 2 1) ( 2 1) 1 x ( 1) 1 x" " "
# # #
# " " " " 2 1 2 1 a b
(We used FORMULA 101 with a 1, n 2); ln x ln 1 x C' ' ' 'x dx dx dx x dx1 x x 1 x x 1 x"
# # # #" # a b k k a b
dx tan x ln x ln 1 x C ' tan xx x
"
#
" "" ##k k a b
33. sin 3x cos 2x dx C' cos 5x cos x10 # (We used FORMULA 62(a) with a 3, b 2)
34. sin 2x cos 3x dx C' cos 5x cos x10 # (We used FORMULA 62(a) with a 2, b 3)
35. 8 sin 4t sin dx sin sin C 8 C' t 8 7t 8 9t7 9 7 9sin sin
# # # 7t 9t# # (We used FORMULA 62(b) with a 4, b ) "#
36. sin sin dt 3 sin sin C' t t t t3 6 6 # (We used FORMULA 62(b) with a , b ) " "3 6
37. cos cos d 6 sin sin C' ) ) ) )3 4 12 7 16 7) # (We used FORMULA 62(c) with a , b ) " "3 4
38. cos cos 7 d sin sin C C' ) ) )2 13 2 15 13 1513 1 15sin sin
) ) " # 13 15) )# # (We used FORMULA 62(c) with a , b 7) "2
39. dx' ' ' ' 'x x 1 x dx dx dxx 1 x 1 x 1x 1 x 1
d x 1$# # #
# # ## #
# " #
a b a b a ba b
ln x 1 tan x C " "# ## "a b x2 1 xa b#
(For the second integral we used FORMULA 17 with a 1)
40. dx 3 3' ' ' ' ' ' 'x 6x dx 6x dx 3 dx dx dxx 3 x 3 x 3 x 3x 3 x 3
d x 3
x 3
#
# # # #
# # # # # ##
#
#
#
#
a b a b a b a b
a b
528 Chapter 8 Techniques of Integration
tan 3 tan C " "" "
a b 3 3 3x 3 x x
x 32 3 3 x 2 3
# # # # $ For the first integral we used FORMULA 16 with a 3; for the third integral we used FORMULA 17 with a 3 tan C " " 2 3 3
x 3 xx 3 2 x 3 a b # #
41. sin x dx; 2 u sin u du 2 sin u duu x
x u
dx 2u du' ' '" " " "#
"
u u1 1 1 1 1 u1 1 1 1
#
u sin u # "
' u du1 u#
#
(We used FORMULA 99 with a 1, n 1) u sin u sin u u 1 u C u sin u u 1 u C # " " # "" " " "# # # ## # (We used FORMULA 33 with a 1) x sin x x x C " "# #" #
42. dx; 2u du 2 cos u du 2 u cos u 1 u Cu x
x u
dx 2u du' ' 'cos x
x
cos uu 1"
"
# " " " #
(We used FORMULA 97 with a 1) 2 x cos x 1 x C "
43. dx; du 2 du 2 sin u u 1 u Cu x
x u
dx 2u du' ' '
x
1 xu 2u u1 u 1 u
#
" "# #
" #
# #
#
sin u u 1 u C " # (We used FORMULA 33 with a 1) sin x x 1 x C sin x x x C " " #
44. dx; 2u du 2 2 u duu x
x u
dx 2u du' ' ' 2 xx
2 uu
# #
#
#
2 2 u sin C u 2 u 2 sin C u u u2 2 2# ## # #" " #
We used FORMULA 29 with a 2 2x x 2 sin C # " #x
45. (cot t) 1 sin t dt ; u sin tdu cos t dt' ' ' # 1 sin t (cos t) dtsin t u1 u du# #
1 u ln C # 1 1 uu
#
(We used FORMULA 31 with a 1) 1 sin t ln C # 1 1 sin t
sin t#
Section 8.6 Integral Tables and Computer Algebra Systems 529
46. ; ln Cu sin tdu cos t dt' ' 'dt cos t dt du
(tan t) 4 sin t (sin t) 4 sin t u 4 u2 4 u
u
"#
# # #
#
(We used FORMULA 34 with a 2) ln C "#
2 4 sin tsin t
#
47. ; ln u 3 u Cu ln yy e
dy e du' ' 'dy
y 3 (ln y)e du du
e 3 u 3 u ## # #
uu
u
u
ln ln y 3 (ln y) C # We used FORMULA 20 with a 3
48. ; ln u 5 u C ln sin 5 sin Cu sin du cos d' 'cos d du
5 sin 5 u) )
) # ## # )) ) ) ) We used FORMULA 20 with a 5
49. ; ln u u 1 C ln 3r 9r 1 Cu 3rdu 3 dr' '3 dr du
9r 1 u 1 # # # # (We used FORMULA 36 with a 1)
50. ; ln u 1 u C ln 3y 1 9y Cu 3ydu 3 dy' '3 dy
1 9ydu
1 u # ## # (We used FORMULA 20 with a 1)
51. cos x dx; 2 t cos t dt 2 cos t dt t cos t dtt xx t
dx 2t dt' ' ' '" " " # "#
# #"
t t t1 t 1 t# # #
# #
(We used FORMULA 100 with a 1, n 1) t cos t sin t t 1 t C # " "" "# # # (We used FORMULA 33 with a 1) x cos x sin x x 1 x C x cos x sin x x x C " " " "" " " "# # # # #
52. tan y dy; 2 t tan t dt 2 tan t dt t tan t dtt yy t
dy 2t dt' ' ' '" " " # "#
# # "
t t t1 t 1 t# # #
# #
(We used FORMULA 101 with n 1, a 1) t tan t dt t tan t t tan t C y tan y tan y y C # " # " " " " ' 't 1 dtt 1 1 t#
# #
53. sin 2x dx sin 2x dx sin 2x dx' ' '& $# # sin 2x cos 2x 5 1 sin 2x cos 2x 4 sin 2x cos 2x 3 15 5 10 5 3 3% % #
(We used FORMULA 60 with a 2, n 5 and a 2, n 3) sin 2x cos 2x cos 2x C C sin 2x cos 2x 2 8 sin 2x cos 2x 2 sin 2x cos 2x 4 cos 2x10 15 15 10 15 15% % ## "
#
54. sin d sin d sin cos sin d' ' '& $ %# # # # # ) ) ) ) )) ) ) sin cos sin cos
5 35 1 2 4 3 1
5 5 5 3% #
# # # #
" "
# #
) ) ) )
We used FORMULA 60 with a , n 5 and a , n 3 " "# # sin cos sin cos 2 cos C sin cos sin cos cos C 2 8 8 2 8 165 15 15 5 15 15
% # % ## # # # # # # # # #) ) ) ) ) ) ) ) ) )
530 Chapter 8 Techniques of Integration
55. 8 cos 2 t dt 8 cos 2 t dt' '% #1 1 cos 2 t sin 2 t 4 14 2 4$ 1 11 (We used FORMULA 61 with a 2 , n 4) 1 6 C cos 2 t sin 2 t t sin (2 2 t)4 2$
1 1
1 1
1 # (We used FORMULA 59 with a 2 ) 1 3t C 3t C cos 2 t sin 2 t 3 sin 4 t cos 2 t sin 2 t 3 cos 2 t sin 2 t4 2$ $
1 1 1 1 1 1 1
1 1 1 1
56. 3 cos 3y dy 3 cos 3y dy' '& $ cos 3y sin 3y5 3 55 1% cos 3y dy cos 3y sin 3y cos 3y sin 3y5 5 3 3 3
12 3 1% #
'
(We used FORMULA 61 with a 3, n 5 and a 3, n 3) cos 3y sin 3y cos 3y sin 3y sin 3y C " % #5 15 15
4 8
57. sin 2 cos 2 d sin 2 cos 2 d' '# $ ## #) ) ) ) ) ) sin 2 cos 2 3 1(2 3) 3 $ #
) )
(We used FORMULA 69 with a 2, m 3, n 2) sin 2 cos 2 d sin 2 d(sin 2 ) C sin 2 cos 2 2 sin 2 cos 2 2 sin 2 cos 2 sin 210 5 10 5 10 15$ # $ # $ # $
) ) ) ) ) ) )' '# #"#) ) ) ) )
58. 9 sin cos d 9 sin cos d' '$ $# $#
) ) ) ) ) ) sin cos 3 13 3 # # #
) ) 3 3 2 sin cos 4 cos sin d # $#) ) ) ) )' We used FORMULA 68 with a 1, n 3, m 3# 2 sin cos 4 cos d(cos ) 2 sin cos 4 cos C # $# # ) ) ) ) ) ) )' 25 2 cos sin C #) ) 4559. 2 sin t sec t dt 2 sin t cos t dt 2 cos t dt' ' '# % # % % sin t cos t 2 12 4 2 4$ (We used FORMULA 68 with a 1, n 2, m 4) sin t cos t cos t dt sin t cos t sec t dt sin t cos t sec t dt $ % $ % $ #
' ' ' sec t tan t 4 24 1 4 1# (We used FORMULA 92 with a 1, n 4) sin t cos t tan t C sec t tan t tan t C tan t sec t 1 C $ # # a bsec t tan t 2 2 2 23 3 3 3 3# tan t C 23
$
An easy way to find the integral using substitution:
2 sin t cos t dt 2 tan t sec t dt 2 tan t d(tan t) tan t C' ' '# % # # # $ 23
60. csc y cos y dy sin y cos y dy sin y cos y dy' ' '# & # & # $ # "sin y cos y
5 2 5 5 1%
sin y cos y dy " "sin y sin ycos y cos y
3 3 3 2 3 4 3 1% # # #'
(We used FORMULA 69 with n 2, m 5, a 1 and n 2, m 3, a 1) cos y sin y d(sin y) C "
sin y cos y3 3 sin y 3 3 sin y 3 sin y 3 sin y
4 8 8cos y 4 cos y%
% # " # #'
61. 4 tan 2x dx 4 tan 2x dx tan 2x 4 tan 2x dx' ' '$ ## tan 2x2# (We used FORMULA 86 with n 3, a 2) tan 2x ln sec 2x C tan 2x 2 ln sec 2x C # ##
4 k k k k
Section 8.6 Integral Tables and Computer Algebra Systems 531
62. tan dx tan dx tan tan dx' ' '% # $ ## # # # x x 2 x xtan(4 1) 3 $ #"#
x
(We used FORMULA 86 with n 4, a ) "# tan 2 tan x C 2 x x3
$# #
(We used FORMULA 84 with a ) "#
63. 8 cot t dt 8 cot t dt' '% # cot t3$ (We used FORMULA 87 with a 1, n 4) 8 cot t cot t t C " $3 (We used FORMULA 85 with a 1)
64. 4 cot 2t dt 4 cot 2t dt cot 2t 4 cot 2t dt' ' '$ # cot 2t2(3 1)#