Upload
buikhanh
View
232
Download
0
Embed Size (px)
Citation preview
Assumptions
• Axisymmetric flow• Gradient and hydrostatic balance above
PBL• Troposphere neutral to slantwise moist
convection outside eye• Moist adiabatic lapse rate in eye above
inversion• Well developed anticyclone at storm top
Local energy balance (from previous lecture):
( )2
*b o
b
M dsT Tr dM
≅ − −
Definitions:
( )( )( )( ) ( )( )( )
2 2
* *
*
*0
2 2*
constant
s o a
s o a a a
s s o a a
f fR M rV r
T T s s
T T s s s s
T T s s
χ
χ
χ
≡ = +
≡ − −
≡ − − =
≡ − − =
“potential radius”
Scaling:
( )
( )
*, *,
, ,
s
sR r R rf
χ χ χ χ χ
χ
→
→
Scaled equations:
2 3
2 2
2
1 2 * ,
2 2
*2
r R RR rV r rV
RVR
χ
χ
∂= −
∂= +
∂→ −
∂
(core)
(1)
Conservation of angular momentum (dimensional):
dM grdt p
θτ∂= −∂
Integrate over depth of PBL:
2
2
b s s D
sD
d s
dMp gr gr C Vdt
pgr C VR T
θτ ρ∆ = − ≅ −
≅ −
Scaling for time:
11 2d sD b s
s
R Tt C p tgp
χ −−→ ∆
Nondimensional angular momentum equation:2
But
12
2
dR Vrdt R
Rr2V
dR RVdt
= −
→ − (2)
Nondimensional PBL entropy equation:
( )* 30 ,k
bD
s o
s
Cd V V Fdt C
T TT
χ χ χ ε
ε
= − + −
−≡
Time derivative in R space:
d Rdt R P
ωτ∂ ∂ ∂
= + +∂ ∂ ∂
(3)
Assume Χ well mixed in boundary layer,
use 1 :2
R RV= −
Also assume that Fb balances source terms outside of eyewall:
( )* 30
12
0
k
D
CRV V V eyewallR C
elsewhere
χ χ χ ε
χτ
∂+ − +
∂∂
=∂
2 *2 2R RBut V in eyewall
R Rχ χ∂ ∂
− = −∂ ∂
( ) ( )* 30 1 ,
10
k
D
C V VC
in eyewallelsewhere
χ β χ χ ετ
ββ
∂→ = − − − ∂ ==
(Steady state solution:)
( )2 *0
11
k
D
CVC
χ χε
= −−
(4)
Differentiate (4) with respect to R and use 2 :2RVRχ∂
−∂
( ) ( )
( ) ( )
2 *0
2
2 *0
3 14
2
14
k
D
k
D
k
D
CV R V VV R CC VC
CR VR C
β ε χ χτ
β
β ε χ χ
∂ ∂= − − − ∂ ∂
−
∂+ − − − ∂
First term: Propagation; Second term: damping;
Third term: Amplification
Note that first term steepens V gradient when 2 2maxV V>
0 necessary for amplificationRβ∂<
∂V gradient cannot steepen indefinitely:
( )
( )
,
1 1
1
1
V Vr rR r V V r
r r R R r r R R RV r Vr R R
V r Vr R Rr VR R
ς
ς
ς ς
ς
∂= +
∂∂ ∂ ∂ ∂ ∂ ∂ = = + + = + ∂ ∂ ∂ ∂ ∂ ∂
∂→ = + +
∂∂
+∂=∂
−∂
2V R VwhenR r R
ς ∂→∞ → ≅
∂
Eyewall undergoes frontal collapse!
This can only be prevented by 3-D eddies
Simplified amplification model:
( ) ( )* 30 1 ,
10
k
D
C V VCin eyewallelsewhere
χ β χ χ ετ
ββ
∂= − − − ∂
==
* 20
11 12
AP A Vχ χ = − = + +
2 *2RV
Rχ∂
= −∂
*Enforce χ χ≤
How to handle frontal collapse in model?
Three methods:
1: Zero diffusion model:
For r < rm:0*
Vconstantχ χ
== =
Does not prevent frontal collapse
2. Minimum diffusion model: Just enough radial diffusion to prevent failure of coordinate transformation.
From expression for vertical component of vorticity, we enforce
2V VR R∂
≤∂
Inside the outermost radius, Rcrit, where this is violated, we take
2
2
critcrit
V VR R
RV VR
∂=
∂
→ =
By integration of2* 2V
R Rχ∂
= −∂
421* 1 ,
2
*
crit crit critcrit
crit
RV for R RR
for R R
χ χ
χ χ
= + − <
= ≥
3. Maximum diffusion model: 3-D turbulence perfectly efficient in establishing constant angular velocity inside rm:
max maxm m
r RV V Vr R
= =
22* 1 ,
*
m max mm
m
RV for R RR
for R R
χ χ
χ χ
= + − <
= ≥
Tropical Cyclone Structure
• Hydrostatic and gradient balance above PBL everywhere
• Moist adiabatic lapse rates on angular momentum surfaces above PBL everywhere
• Boundary layer quasi-equilibrium (with horizontal entropy advection and dissipative heating) in rain area
• Radiative-subsidence balance in outer region
Assume that boundary layer entropy changes slowly in angular momentum space:
ds s dM sdt dt Mτ
∂ ∂= +∂ ∂
( ) ( )( )* 3| | | | .s k s D u b m ss dM shT C k k C M w h h hT
dt Mτ∂ ∂
= − + − − − −∂ ∂
V V
PBL angular momentum: | |DdMh C r Vdt
= − V
( ) ( )( )* 3| | | | | | .s k s D u b m s Ds shT C k k C M w h h T C r V
Mτ∂ ∂
= − + − − − +∂ ∂
V V V
(1)
In rain area, 0, *:uM s s> =
Use thermal wind balance, neglecting
| | | | .ss D D
s o
Ts MT C r V C VM T T r∂
−∂ −
V V
2
1 :or
Use in (1), approximating | | :M by V and by Vr
V
( )* 31 .ou k s D
b m s o
TM w C V k k C Vh h T T
= + − − − −
(2)
Closure for convective updraft mass flux.
Free tropopshere thermodynamic balance:
( )* d d radu d
m
s Qs M M wz Tτ
Γ ∂∂= − − + ∂ Γ ∂
Representation of downdrafts:
(1 ) ,d uM Mε= −
(3)
Steady state version of (3):
,rad uw w Mε= − +
radrad
d
Qw sTz
≡ − ∂∂
(4)
Outside rain area,
01
rad uw w Mr r
ψ=
∂= = −
∂
Within rain area, substitute (2) into (4):
( ) ( )* 311 0.orad k s D u
b m s o
Tw C V k k C V Mr r h h T T
ψ εε ∂
− = − + − − > ∂ − −
System closed using PBL angular momentum balance:
2 2 ,DM C r Vr
ψ ∂=
∂
or, equivalently,
(5)
(6)
( ) 2 2
.DrV C r V frr ψ
∂= −
∂
Apply scaling:
max ,V v V→
max ,vr rf
→
3max2 ,D
vCf
ψ ψ→
max ,rad D Qw C v w→
max ,u D uM C v M→
Nondimensional system:
( ) 2 2
,rV r V rr ψ
∂= −
∂
1 0,Q uw for Mr r
ψ∂= − =
∂
( )31 0,Q uw V V for Mr rε ψ ε− ∂
= − + Λ − >∂
( )311u QM w V V
ε = − +Λ − −
*k s
D b m
C k kC h h
−Λ ≡
−
(7)
(8)
(9)
(10)
Boundary condition: 00 at r rψ = =
From (7): 00V at r r= =
Simple case: , , constantQwεΛ
Outside rain area, solution to (8) is then
( )2 212 Q ow r rψ = −
Substitute into (7):
( )( )2 2
2 2
2
Q o
rV r V rr w r r
∂= −
∂ −
For wQ << 1, dominant balance is
2 22 12
oQr rV wr−
≈
For 2 20 ,r r<<
12V r
−≈
In rain area, assume that QV wεΛ >> 2 1V <<
,1
rVrψ ε
ε∂ Λ∂ −
( )2 2
.r VrVr ψ∂∂
(11)
(12)
(11) and (12) have power law solution:
nV r−≈
( )( )2 1
.1
nε εε εΛ − −
≡Λ − −
Realistic only if
12 .εε−
Λ >
(In numerical solutions to be presented, 23n = )
Numerical solution of (7)-(10): March inward from 0 :r r=
Note: longer tail in R&E model owing to different formulation of Q
1Λ =
0.8ε =
0.1Qw =
0.25or =
Curve fit to numerical solutions:
( )( )( )
( )2 22 2 0
2 120
1 1 2,
1 2
m
m mn mm m
mm
b n m b mr r rV Vr r r rr mn m
rr
++
− + + − = + − ++